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Monday, Monday… Course Project Report #4 is due! Course Project Report #5 guidelines to hand out! On Wednesday, I’ll give you guidelines for the final term paper/presentation. Let’s wrap up vowels today… And then get into sonorant acoustics for the rest of the week. First: fun videos + clips! Mumford and Sons T-Pain Auditory Scene Analysis
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Vowels + Music
March 18, 2013
Monday, Monday…• Course Project Report #4 is due!
• Course Project Report #5 guidelines to hand out!
• On Wednesday, I’ll give you guidelines for the final term paper/presentation.
• Let’s wrap up vowels today…
• And then get into sonorant acoustics for the rest of the week.
• First: fun videos + clips!
• Mumford and Sons
• T-Pain
• Auditory Scene Analysis
Theory #2• The second theory of vowel production is the two-tube model.
• Basically:
• A constriction in the vocal tract (approximately) divides the tract into two separate “tubes”…
• Each of which has its own characteristic resonant frequencies.
• The first resonance of one tube produces F1;
• The first resonance of the other tube produces F2.
Open up and say...• For instance, the shape of the articulatory tract while producing the vowel resembles two tubes.
• Both tubes may be considered closed at one end...
• and open at the other.
back tube
front tube
Resonance at Work• An open tube resonates at frequencies determined by:
• fn = (2n - 1) * c
4L• If Lf = 9.5 cm:
• F1 =
35000 / 4 * 9.5
• = 921 Hz
Resonance at Work• An open tube resonates at frequencies determined by:
• fn = (2n - 1) * c
4L• If Lb = 8 cm:
• F1 =
35000 / 4 * 8
• = 1093 Hz
for :
• F1 = 921 Hz
• F2 = 1093 Hz
Switching Sides• Note that F1 is not necessarily associated with the front tube;
• nor is F2 necessarily determined by the back tube...
• Instead:
• The longer tube determines F1 resonance
• The shorter tube determines F2 resonance
Switching Sides
Switching Sides
A Conundrum• The lowest resonant frequency of an open tube of length 17.5 cm is 500 Hz. (schwa)
• In the tube model, how can we get resonant frequencies lower than 500 Hz?
• One option:
• Lengthen the tube through lip rounding.
• But...why is the F1 of [i] 300 Hz?
• Another option:
• Helmholtz resonance
Helmholtz Resonance
Hermann von Helmholtz (1821 - 1894)
• A tube with a narrow constriction at one end forms a different kind of resonant system.
• The air in the narrow constriction itself exhibits a Helmholtz resonance.
• = it vibrates back and forth “like a piston”
• This frequency tends to be quite low.
Some Specifics• The vocal tract configuration for the vowel [i] resembles a Helmholtz resonator.
• Helmholtz frequency:
€
f = c2π
AbcVabLbc
An [i] breakdown
• Helmholtz frequency:
€
f = c2π
AbcVabLbc
Volume(ab) = 60 cm3
Length(bc) = 1 cm
Area(bc) = .15 cm2
€
f = 350002π
.1560*1
≈ 280Hz
An [i] Nomogram
Helmholtz resonance
• Let’s check it out...
Slightly Deeper Thoughts
• Helmholtz frequency:
€
f = c2π
AbcVabLbc
• What would happen to the Helmholtz resonance if we moved the constriction slightly further back...
• to, oh, say, the velar region?
Volume(ab)
Length(bc)
Area(bc)
Ooh!• The articulatory configuration for [u] actually produces two different Helmholtz resonators.
• = very low first and second formant
F1 F2
Size Matters, Again
• Helmholtz frequency:
€
f = c2π
AbcVabLbc
• What would happen if we opened up the constriction?
• (i.e., increased its cross-sectional area)
• This explains the connection between F1 and vowel “height”...
Theoretical Trade-Offs• Perturbation Theory and the Tube Model don’t always make the same predictions...
• And each explains some vowel facts better than others.
• Perturbation Theory works better for vowels with more than one constriction ([u] and )
• The tube model works better for one constriction.
• The tube model also works better for a relatively constricted vocal tract
• ...where the tubes have less acoustic coupling.
• There’s an interesting fact about music that the tube model can explain well…
Some Notes on Music• In western music, each note is at a specific frequency
• Notes have letter names: A, B, C, D, E, F, G
• Some notes in between are called “flats” and “sharps”
261.6 Hz 440 Hz
Some Notes on Music• The lowest note on a piano is “A0”, which has a fundamental frequency of 27.5 Hz.
• The frequencies of the rest of the notes are multiples of 27.5 Hz.
• Fn = 27.5 * 2(n/12)
• where n = number of note above A0
• There are 87 notes above A0 in all
Octaves and Multiples• Notes are organized into octaves
• There are twelve notes to each octave
• 12 note-steps above A0 is another “A” (A1)
• Its frequency is exactly twice that of A0 = 55 Hz
• A1 is one octave above A0
• Any note which is one octave above another is twice that note’s frequency.
• C8 = 4186 Hz (highest note on the piano)
• C7 = 2093 Hz
• C6 = 1046.5 Hz
• etc.
Frame of Reference• The central note on a piano is called “middle C” (C4)
• Frequency = 261.6 Hz
• The A above middle C (A4) is at 440 Hz.
• The notes in most western music generally fall within an octave or two of middle C.
• Recall the average fundamental frequencies of:
• men ~ 125 Hz
• women ~ 220 Hz
• children ~ 300 Hz
Harmony• Notes are said to “harmonize” with each other if the greatest common denominator of their frequencies is relatively high.
• Example: note A4 = 440 Hz
• Harmonizes well with (in order):
• A5 = 880 Hz (GCD = 440)
• E5 ~ 660 Hz (GCD = 220) (a “fifth”)
• C#5 ~ 550 Hz (GCD = 110) (a “third”)
....
• A#4 ~ 466 Hz (GCD = 2) (a “minor second”)
• A major chord: A4 - C#5 - E5
Extremes• Not all music stays within a couple of octaves of middle C.
• Check this out:
• Source: “Der Rache Hölle kocht in meinem Herze”, from Die Zauberflöte, by Mozart.
• Sung by: Sumi Jo
• This particular piece of music contains an F6 note
• The frequency of F6 is 1397 Hz.
• (Most sopranos can’t sing this high.)