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Vietoris–Rips Thickenings of the Circle and Centrally–Symmetric Orbitopes Advisor: Dr. Henry Adams Committee: Dr. Amit Patel, Dr. Gloria Luong Johnathan Bush Master’s thesis defense – October 19 th , 2018

Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

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Page 1: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Vietoris–Rips Thickenings of the Circle

and Centrally–Symmetric Orbitopes

Advisor: Dr. Henry Adams

Committee: Dr. Amit Patel, Dr. Gloria Luong

Johnathan Bush

Master’s thesis defense – October 19th, 2018

Page 2: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Background

Page 3: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

The Vietoris–Rips Complex

In[69]:= Demo[data1, 0, .41]

Out[69]=

Cech simplicialcomplex

Appearance

draw one simplices

draw Cech complex

draw Rips complex

Filtrationparameter

t 0

CechRips.nb 3

Definition

Let X be a metric space and r > 0 a scale parameter. The

Vietoris–Rips complex of X, denoted VR(X; r), has vertex set

X and a simplex for every finite subset σ ⊆ X such that

diam(σ) ≤ r.2

Page 4: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

The Vietoris–Rips Complex

In[70]:= Demo[data1, 0, .41]

Out[70]=

Cech simplicialcomplex

Appearance

draw one simplices

draw Cech complex

draw Rips complex

Filtrationparameter

t 0.14

4 CechRips.nb

Definition

Let X be a metric space and r > 0 a scale parameter. The

Vietoris–Rips complex of X, denoted VR(X; r), has vertex set

X and a simplex for every finite subset σ ⊆ X such that

diam(σ) ≤ r.2

Page 5: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

The Vietoris–Rips Complex

In[71]:= Demo[data1, 0, .41]

Out[71]=

Cech simplicialcomplex

Appearance

draw one simplices

draw Cech complex

draw Rips complex

Filtrationparameter

t 0.192

CechRips.nb 5

Definition

Let X be a metric space and r > 0 a scale parameter. The

Vietoris–Rips complex of X, denoted VR(X; r), has vertex set

X and a simplex for every finite subset σ ⊆ X such that

diam(σ) ≤ r.2

Page 6: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

The Vietoris–Rips Complex

In[72]:= Demo[data1, 0, .41]

Out[72]=

Cech simplicialcomplex

Appearance

draw one simplices

draw Cech complex

draw Rips complex

Filtrationparameter

t 0.267

6 CechRips.nb

Definition

Let X be a metric space and r > 0 a scale parameter. The

Vietoris–Rips complex of X, denoted VR(X; r), has vertex set

X and a simplex for every finite subset σ ⊆ X such that

diam(σ) ≤ r.2

Page 7: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

The Vietoris–Rips Complex

In[73]:= Demo[data1, 0, .41]

Out[73]=

Cech simplicialcomplex

Appearance

draw one simplices

draw Cech complex

draw Rips complex

Filtrationparameter

t 0.338

CechRips.nb 7

Definition

Let X be a metric space and r > 0 a scale parameter. The

Vietoris–Rips complex of X, denoted VR(X; r), has vertex set

X and a simplex for every finite subset σ ⊆ X such that

diam(σ) ≤ r.2

Page 8: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

The Vietoris–Rips Complex

In[74]:= Demo[data1, 0, .41]

Out[74]=

Cech simplicialcomplex

Appearance

draw one simplices

draw Cech complex

draw Rips complex

Filtrationparameter

t 0.41

8 CechRips.nb

Definition

Let X be a metric space and r > 0 a scale parameter. The

Vietoris–Rips complex of X, denoted VR(X; r), has vertex set

X and a simplex for every finite subset σ ⊆ X such that

diam(σ) ≤ r.2

Page 9: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

The Vietoris–Rips Complex

In applications of persistent homology, we consider

Vietoris–Rips complexes at all scale parameters.

In[71]:= Demo[data1, 0, .41]

Out[71]=

Cech simplicialcomplex

Appearance

draw one simplices

draw Cech complex

draw Rips complex

Filtrationparameter

t 0.192

CechRips.nb 5

In[74]:= Demo[data1, 0, .41]

Out[74]=

Cech simplicialcomplex

Appearance

draw one simplices

draw Cech complex

draw Rips complex

Filtrationparameter

t 0.41

8 CechRips.nb

3

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Hausmann’s Theorem

Theorem

Let M be a compact Riemannian manifold and r > 0 be

sufficiently small. Then, VR(M ; r) 'M . [4]

• Downsides of the proof:

� Hausmann’s map VR(M ; r)→M depends upon a

total order of all points in M .

� VR(M ; r) does not inherit the metric of M . In

particular, the inclusion M ↪→ VR(M ; r) is not

continuous.

4

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Hausmann’s Theorem

Theorem

Let M be a compact Riemannian manifold and r > 0 be

sufficiently small. Then, VR(M ; r) 'M . [4]

• Downsides of the proof:

� Hausmann’s map VR(M ; r)→M depends upon a

total order of all points in M .

� VR(M ; r) does not inherit the metric of M . In

particular, the inclusion M ↪→ VR(M ; r) is not

continuous.

4

Page 12: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Hausmann’s Theorem

Theorem

Let M be a compact Riemannian manifold and r > 0 be

sufficiently small. Then, VR(M ; r) 'M . [4]

• Downsides of the proof:

� Hausmann’s map VR(M ; r)→M depends upon a

total order of all points in M .

� VR(M ; r) does not inherit the metric of M . In

particular, the inclusion M ↪→ VR(M ; r) is not

continuous. 4

Page 13: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Latschev’s Theorem

Theorem

Let M be a closed Riemannian manifold and X a metric space

δ–close to M in the Gromov-Hausdorff distance. Then,

VR(X; r) 'M for r > 0 sufficiently small. [5]

• Generalization of Hausmann’s theorem. Applies, in

particular, to samplings X ⊆M .

• Again, the value of “sufficiently small” r > 0 depends on

the curvature of M .

• The value of δ depends on r.

• Same downsides as Hausmann’s proof.

5

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Latschev’s Theorem

Theorem

Let M be a closed Riemannian manifold and X a metric space

δ–close to M in the Gromov-Hausdorff distance. Then,

VR(X; r) 'M for r > 0 sufficiently small. [5]

• Generalization of Hausmann’s theorem. Applies, in

particular, to samplings X ⊆M .

• Again, the value of “sufficiently small” r > 0 depends on

the curvature of M .

• The value of δ depends on r.

• Same downsides as Hausmann’s proof.

5

Page 15: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Latschev’s Theorem

Theorem

Let M be a closed Riemannian manifold and X a metric space

δ–close to M in the Gromov-Hausdorff distance. Then,

VR(X; r) 'M for r > 0 sufficiently small. [5]

• Generalization of Hausmann’s theorem. Applies, in

particular, to samplings X ⊆M .

• Again, the value of “sufficiently small” r > 0 depends on

the curvature of M .

• The value of δ depends on r.

• Same downsides as Hausmann’s proof.

5

Page 16: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Latschev’s Theorem

Theorem

Let M be a closed Riemannian manifold and X a metric space

δ–close to M in the Gromov-Hausdorff distance. Then,

VR(X; r) 'M for r > 0 sufficiently small. [5]

• Generalization of Hausmann’s theorem. Applies, in

particular, to samplings X ⊆M .

• Again, the value of “sufficiently small” r > 0 depends on

the curvature of M .

• The value of δ depends on r.

• Same downsides as Hausmann’s proof.

5

Page 17: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

VR(X; r) for large scale parameters

Theorem (Adamszek, Adams)

Let S1 be the circle of unit circumference. Then,

VR(S1; r) '

S2`+1 if `2`+1 < r < `+1

2`+3 for ` ∈ N. [1]

0

S1 S3 S5 S7

13

25

3749

r =1

3 r =2

5r =

3

7

6

Page 18: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

VR(X; r) for large scale parameters

Theorem (Adamszek, Adams)

Let S1 be the circle of unit circumference. Then,

VR(S1; r) '

S2`+1 if `2`+1 < r < `+1

2`+3∨∞ S2` if r = `2`+1

for ` ∈ N. [1]

0

S1 S3 S5 S7

13

25

3749

r =1

3 r =2

5r =

3

7

6

Page 19: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

VR(X; r) for large scale parameters

Theorem (Adamszek, Adams)

Let S1 be the circle of unit circumference. Then,

VR(S1; r) '

S2`+1 if `2`+1 < r < `+1

2`+3∨∞ S2` if r = `2`+1

for ` ∈ N. [1]

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6 Torus.nb

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Torus.nb 5

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4 Torus.nb

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Torus.nb 3

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2 Torus.nb

r =1

3 r =2

5r =

3

76

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Metric Vietoris–Rips Thickenings

Definition (Adamaszek, Adams, Frick)

For a metric space X and r ≥ 0, the Vietoris–Rips thickeningVRm(X; r) is the set

VRm(X; r) =

{k∑

i=0

λixi | k ∈ N, xi ∈ X, and diam({x0, . . . , xk}) ≤ r

}

equipped with the 1-Wasserstein metric. [2]

1/3 1/3 1/61/6

1/31/3 1/3

7

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Metric Vietoris–Rips Thickenings

• An analogue of Hausmann’s theorem holds for the

Vietoris–Rips metric thickening VRm(M ; r).

• Notably, this theorem admits a nicer proof:

� The homotopy equivalence VRm(M ; r)→M is

canonically defined.

� The inclusion M ↪→ VRm(M ; r) is continuous.

8

Page 22: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Results

Page 23: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem

Theorem (Adams, B.)

Let S1 be the circle of unit circumference, and let r = 13 . Then,

the Vietoris–Rips metric thickening thickening VRm(S1; r) is

homotopy equivalent to S3.

• 1/3 is the side length of an inscribed equilateral triangle.

• Recall that VR(S1; 13) '

∨∞ S2

9

Page 24: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem

Theorem (Adams, B.)

Let S1 be the circle of unit circumference, and let r = 13 . Then,

the Vietoris–Rips metric thickening thickening VRm(S1; r) is

homotopy equivalent to S3.

• 1/3 is the side length of an inscribed equilateral triangle.

• Recall that VR(S1; 13) '

∨∞ S2

9

Page 25: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem (proof)

We construct a homotopy equivalence via

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

where SM4 : S1 → R4 is defined by

SM4(θ) = (cos(θ), sin(θ), cos(3θ), sin(3θ)) ,

p is radial projection, B4 = conv(SM4(S1)) ⊆ R4 is the (second)

Barvinok–Novik orbitope, and ι is inclusion.

10

Page 26: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem (proof)

We construct a homotopy equivalence via

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

where SM4 : S1 → R4 is defined by

SM4(θ) = (cos(θ), sin(θ), cos(3θ), sin(3θ)) ,

p is radial projection, B4 = conv(SM4(S1)) ⊆ R4 is the (second)

Barvinok–Novik orbitope, and ι is inclusion.

10

Page 27: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem (proof)

We construct a homotopy equivalence via

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

where SM4 : S1 → R4 is defined by

SM4(θ) = (cos(θ), sin(θ), cos(3θ), sin(3θ)) ,

p is radial projection,

B4 = conv(SM4(S1)) ⊆ R4 is the (second)

Barvinok–Novik orbitope, and ι is inclusion.

10

Page 28: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem (proof)

We construct a homotopy equivalence via

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

where SM4 : S1 → R4 is defined by

SM4(θ) = (cos(θ), sin(θ), cos(3θ), sin(3θ)) ,

p is radial projection, B4 = conv(SM4(S1)) ⊆ R4 is the (second)

Barvinok–Novik orbitope,

and ι is inclusion.

10

Page 29: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem (proof)

We construct a homotopy equivalence via

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

where SM4 : S1 → R4 is defined by

SM4(θ) = (cos(θ), sin(θ), cos(3θ), sin(3θ)) ,

p is radial projection, B4 = conv(SM4(S1)) ⊆ R4 is the (second)

Barvinok–Novik orbitope, and ι is inclusion.

10

Page 30: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Barvinok–Novik Orbitopes

Fix k ≥ 1 and define the symmetric moment curve

SM2k : R/2πZ→ R2k

θ 7→ (cos(θ), sin(θ), cos(3θ), sin(3θ), . . . , cos((2k − 1)θ), sin((2k − 1)θ)).

Define the k-th Barvinok–Novik orbitope by

B2k = conv(SM2k(S1)).

The precise facial struc-

ture of B2k is unknown

for k > 2.

Our proof technique in-

volves the faces of B4.

11

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Barvinok–Novik Orbitopes

Fix k ≥ 1 and define the symmetric moment curve

SM2k : R/2πZ→ R2k

θ 7→ (cos(θ), sin(θ), cos(3θ), sin(3θ), . . . , cos((2k − 1)θ), sin((2k − 1)θ)).

Define the k-th Barvinok–Novik orbitope by

B2k = conv(SM2k(S1)).

The precise facial struc-

ture of B2k is unknown

for k > 2.

Our proof technique in-

volves the faces of B4.

11

Page 32: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Barvinok–Novik Orbitopes

Fix k ≥ 1 and define the symmetric moment curve

SM2k : R/2πZ→ R2k

θ 7→ (cos(θ), sin(θ), cos(3θ), sin(3θ), . . . , cos((2k − 1)θ), sin((2k − 1)θ)).

Define the k-th Barvinok–Novik orbitope by

B2k = conv(SM2k(S1)).

The precise facial struc-

ture of B2k is unknown

for k > 2.

Our proof technique in-

volves the faces of B4.11

Page 33: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Barvinok–Novik Orbitopes

Theorem (4.1 of [3])

The proper faces and subfaces of B4 are

• 0-dimensional faces, SM4(t) for t ∈ S1,

• 1-dimensional faces, conv(SM4({t1, t2})) where t1 6= t2 are

the edges of an arc of S1 of length less than or equal to 13 ,

• 2-dimensional faces, conv(SM4({t, t+ 13 , t+ 2

3})) for t ∈ S1.

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2 Torus.nb

By contrast, the simplicies of VRm(S1; 13) are

• Vertices, t ∈ S1,

• All simplices of the form conv({t1, . . . , tl}),where t1, . . . , tm belong to an arc of S1 of

length less than or equal to 13,

• 2-simplices, conv({t, t+ 13, t+ 2

3}) for t ∈ S1.

12

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Barvinok–Novik Orbitopes

Theorem (4.1 of [3])

The proper faces and subfaces of B4 are

• 0-dimensional faces, SM4(t) for t ∈ S1,

• 1-dimensional faces, conv(SM4({t1, t2})) where t1 6= t2 are

the edges of an arc of S1 of length less than or equal to 13 ,

• 2-dimensional faces, conv(SM4({t, t+ 13 , t+ 2

3})) for t ∈ S1.

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��

��

��

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2 Torus.nb

By contrast, the simplicies of VRm(S1; 13) are

• Vertices, t ∈ S1,

• All simplices of the form conv({t1, . . . , tl}),where t1, . . . , tm belong to an arc of S1 of

length less than or equal to 13,

• 2-simplices, conv({t, t+ 13, t+ 2

3}) for t ∈ S1.

12

Page 35: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

13

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

13

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

13

Page 38: Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric …adams/advising/JohnBush... · 2018-10-20 · Vietoris{Rips Thickenings of the Circle and Centrally{Symmetric Orbitopes

Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

13

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

14

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

15

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).∑

i λiθi 7→∑

i λiSM2k(θi)

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

15

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).∑

i λiθi 7→∑

i λiSM2k(θi)

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

16

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Steps:

(1) Prove ι is well-defined and continuous.

(2) Extend SM4 to VRm(S1; r).∑

i λiθi 7→∑

i λiSM2k(θi)

(3) Prove SM4

(VRm(S1; r)

)misses the origin.

(4) Prove p ◦ SM4 and ι are homotopy inverses.

17

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Main Theorem (proof) – Prove p◦SM4 and ι are h. inverses

• (p ◦ SM4) ◦ ι = id∂B4 .

• To show ι ◦ (p ◦ SM4) ' idVRm(S1;r) we use a linear

homotopy H.

• H is well-defined only if ι ◦ (p ◦ SM4) does not “increase

diameter” too much.

18

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Main Theorem (proof) – Prove p◦SM4 and ι are h. inverses

• (p ◦ SM4) ◦ ι = id∂B4 .

• To show ι ◦ (p ◦ SM4) ' idVRm(S1;r) we use a linear

homotopy H.

• H is well-defined only if ι ◦ (p ◦ SM4) does not “increase

diameter” too much.

18

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Main Theorem (proof) – Prove p◦SM4 and ι are h. inverses

• In general, this “non-diameter increasing” property of p

depends on the facial structure of B2k.

• We use Farkas’ Lemma to exclude certain cases.

• Continuity of H follows from the fact that VRm(S1; r) is a

metric r-thickening.

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Main Theorem (proof) – Prove p◦SM4 and ι are h. inverses

• In general, this “non-diameter increasing” property of p

depends on the facial structure of B2k.• We use Farkas’ Lemma to exclude certain cases.

• Continuity of H follows from the fact that VRm(S1; r) is a

metric r-thickening.

19

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Main Theorem (proof) – Prove p◦SM4 and ι are h. inverses

• In general, this “non-diameter increasing” property of p

depends on the facial structure of B2k.• We use Farkas’ Lemma to exclude certain cases.

• Continuity of H follows from the fact that VRm(S1; r) is a

metric r-thickening.

19

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Thus, ι ◦ (p ◦SM4) ' idVRm(S1;r) and VRm(S1; 1/3) ' ∂B4 ∼= S3.

• Geometric proof of the homotopy type of a Vietoris–Rips

metric thickening.

• Conjecture: for k−12k−1 ≤ r <

k2k+1 ,

p2k ◦ SM2k : VRm≤ (S1; r)→ ∂B2k

is a homotopy equivalence.

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Thus, ι ◦ (p ◦SM4) ' idVRm(S1;r) and VRm(S1; 1/3) ' ∂B4 ∼= S3.

• Geometric proof of the homotopy type of a Vietoris–Rips

metric thickening.

• Conjecture: for k−12k−1 ≤ r <

k2k+1 ,

p2k ◦ SM2k : VRm≤ (S1; r)→ ∂B2k

is a homotopy equivalence.

20

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Main Theorem (proof)

VRm(S1; 1/3)SM4−−−→ R4 \ {~0} p−→ ∂B4

ι−→ VRm(S1; 1/3)

Thus, ι ◦ (p ◦SM4) ' idVRm(S1;r) and VRm(S1; 1/3) ' ∂B4 ∼= S3.

• Geometric proof of the homotopy type of a Vietoris–Rips

metric thickening.

• Conjecture: for k−12k−1 ≤ r <

k2k+1 ,

p2k ◦ SM2k : VRm≤ (S1; r)→ ∂B2k

is a homotopy equivalence.

20

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References

[1] M. Adamaszek and H. Adams, The vietoris–rips complexes of a circle, Pacific Journal of

Mathematics, 290 (2017), pp. 1–40.

[2] M. Adamaszek, H. Adams, and F. Frick, Metric reconstruction via optimal transport, To appear

in the SIAM Journal on Applied Algebra and Geometry, (2018).

[3] A. Barvinok and I. Novik, A centrally symmetric version of the cyclic polytope, Discrete &

Computational Geometry, 39 (2008), pp. 76–99.

[4] J.-C. Hausmann, On the vietoris-rips complexes and a cohomology theory for metric spaces,

Ann. Math. Studies, 138 (1995), pp. 175–188.

[5] J. Latschev, Vietoris–Rips complexes of metric spaces near a closed Riemannian manifold,

Archiv der Mathematik, 77 (2001), pp. 522–528.

Thank you!

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