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LESSON PLAN
A. Identity
Unit of Education : Senior High School
Grades : X
Semester : I
Program : -
Subject : Physics
Topic : Physical quantities and units
Sub Topic : Vector
Time Allocation : 5 x 45 minutes (3 meetings)
Standard Competency :
1. Applying the concepts of physical quantities and its
measurement
Basic Competency :
1.2 Adding two or more vectors
Indicators :
1. Students are able to distinguish between scalar quantities and vector quantities
in physics
2. Students are able to draw the vector both in Cartesian and polar coordinate
3. Students are able to determine the resultant of two or more vectors
geometrically
4. Students are able to determine the resultant of two vectors analytically
5. Students are able to determine the dot product and the cross product of two
vectors
B. Learning Objectives
1. Discussing scalar and vector quantities in physics
2. Drawing vector geometrically
3. Drawing vector both in Cartesian coordinate and polar coordinate
4. Determining the resultant of two vector or more geometrically
5. Determining the resultant of two vector analytically
6. Calculating the dot product of two vectors
7. Calculating the cross product of two vectors
C. Learning Materials
Fundamental Concept of Vector
A.1 Vectors
A.1.1 Introduction
Certain physical quantities such as mass or the absolute temperature at some point
only have magnitude. These quantities can be represented by numbers alone, with the
appropriate units, and they are called scalars. There are, however, other physical quantities
which have both magnitude and direction; the magnitude can stretch or shrink, and the
direction can reverse. These quantities can be added in such a way that takes into account
both direction and magnitude. Force is an example of a quantity that acts in a certain
direction with some magnitude that we measure in Newton. When two forces act on an
object, the sum of the forces depends on both the direction and magnitude of the two forces.
Position, displacement, velocity, acceleration, force, momentum and torque are all physical
quantities that can be represented mathematically by vectors. We shall begin by defining
precisely what we mean by a vector.
A.1.2 Properties of a Vector
A vector is a quantity that has both direction and magnitude. Let a vector be denoted
by the symbol . The magnitude of is . We can represent vectors as geometric
objects using arrows. The length of the arrow corresponds to the magnitude of the vector.
The arrow points in the direction of the vector (Figure A.1.1).
Figure A.1.1 Vector as arrow
AA
There are two defining operations for vectors:
(1) Vector Addition: Vectors can be added.
Let and be two vectors. We define a new vector , the “vector addition” of
and , by a geometric construction. Draw the arrow that represents . Place the tail of
the arrow that represents at the tip of the arrow for as shown in Figure A.1.2(a).
The arrow that starts at the tail of and goes to the tip of is defined to be the “vector
addition”. There is an equivalent construction for the law of vector addition. The vectors
and can be drawn with their tails at the same point. The two vectors form the sides
of a parallelogram. The diagonal of the parallelogram corresponds to the vector
, as shown in Figure A.1.2(b).
Vector addition satisfies the following four properties:
(i) Commutivity: The order of adding vectors does not matter
Our geometric definition for vector addition satisfies the commutivity property (i) since
in the parallelogram representation for the addition of vectors, it doesn’t matter which
side you start with as seen in Figure A.1.3.
Figure A.1.2 Geometric sum of vectors
Figure A.1.3 Commutative property of vectors addition
Figure A.1.4 Associative law
(ii) Associativity: when adding three vectors, it doesn’t matter which two we start with
In Figure A.1.4(a), we add , while in Figure A.1.4(b) we add . We
arrive at the same vector sum in either case.
(iii) Identity element for vector addition: there is a unique vector, , that acts as an
identity element for vector addition. This means that for all vectors :
(iv) Inverse element for vector addition: For every vector , there is a unique inverse
vector:
This means that the vector has same magnitude as vector , , but they
point in opposite directions (Figure A.1.5)
(2) Scalars Multiplication of Vectors: vectors can be multiplied by real numbers.
Let be a vector. Let c be a real positive number. Then the multiplication of by c is a
new vector which we denote by the symbol . The magnitude of is c times the
magnitude of (Figure A.1.6a),
Since , the direction of is the same as the direction of . However, the direction
of is opposite of (Figure A.1.6b).
(i) Assosiative Law for Scalar Multiplication: the order of multiplying numbers
is doesn’t matter. Let and be real numbers. Then,
(ii) Distributive Law for Vector Addition: vector addition satisfies a distributive
law for multiplication by a number. Let c be a real number. Then
Figure A.1.7 illustrates this property.
Figure A.1.5 Additive inverse
A
A
Figure A.1.6 Multiplication of vector by (a) , and (b)
A
Ac Ac
Figure A.1.7 Distributive Law for vector addition
)BA(c
BA
A
B
Ac
Bc
Bc
Ac
(iii) Distributive Law for Scalar Addition: The multiplication operation also
satisfies a distributive law for the addition of numbers.
Let b and c be real numbers. Then,
Our geometric definition of vector addition satisfies this condition as seen in Figure
A.1.8.
(iv) Identity Element for Scalar Multiplication: The number 1 acts as an identity
element for multiplication.
A.1.3 Application of Vectors
When we apply vectors to physical quantities it’s nice to keep in the back of our
minds all these formal properties. However from the physicist’s point of view, we are
interested in representing physical quantities such as displacement, velocity,
acceleration, force, impulse, momentum, torque, and angular momentum as vectors. We
can’t add force to velocity or subtract momentum from torque. We must always
Figure A.1.8 Distributive Law for scalar addition
Ac
A Ab
A)cb(
understand the physical context for the vector quantity. Thus, instead of approaching
vectors as formal mathematical objects we shall instead consider the following essential
properties that enable us to represent physical quantities as vectors.
1) Vectors can exist at any point P in space.
2) Vectors have direction and magnitude.
3) Vector Equality: Any two vectors that have the same direction and magnitude are
equal no matter where in space they are located.
4) Vector Decomposition: Choose a coordinate system with an origin and axes. We can
decompose a vector into component vectors along each coordinate axis.
In Figure A.1.9 we choose Cartesian coordinates for the x-y plane (we ignore the -
direction for simplicity but we can extend our results when we need to). A vector at
P can be decomposed into the vector sum,
where is the x-component vector pointing in the positive or negative x-direction, and
is the y-component vector pointing in the positive or negative y-direction (Figure
A.1.9).
5) Unit vectors: The idea of multiplication by real numbers allows us to define a set of
unit vectors at each point in space. We associate to each point P in space, a set of
three unit vectors ( , , ). A unit vector means that the magnitude is one: ,
, and . We assign the direction of to point in the direction of the increasing
x-coordinate at the point P. We call the unit vector at pointing in the +x-direction. Unit
vector and can be defined in a similar manner (Figure A.1.10).
A
yA
x
y
xA
Figure A.1.9 Vector decomposition
AyA
x
y
xA
Figure A.1.10 Choice of unit vector in Cartesian coordinate
zzA
6) Vector components: Once we have defined unit vectors, we can then define the x-
component and y-component of a vector. Recall our vector decomposition, .
We can write the x-component vector, as:
In this expression the term , (without the arrow above) is called the x-component
of vector . The x-component can be positive, zero, or negative. It is not the
magnitude which is given by . Note the difference between the x-
component, , and the x-component vector, . In a similar fashion we define the
y-component, , and the z-component, , of the vector .
A vector can be represented by its three components . We can also
write the vector as:
7) Magnitude: In Figure A.1.10, we also show the vector components .
Using the Pythagorean theorem, the magnitude of the is,
8) Direction: let us consider a vector . Since the z-component is zero, the
vector lies in the x-y plane. Let denote the angle that the vector makes in the
counterclockwise direction with the positive x-axis (Figure A.1.12). Then the x-
component and y-component are:
We can now write a vector in the x-y plane as:
Once the components of a vector are known, the tangent of the angle can be
determined by
which yields
Clearly, the direction of the vector depends on the sign of and . For example, if
both and , then , and the vector lies in the first quadrant. If,
however, and , then , and the vector lies in the fourth quadrant.
9) Vector addition: Let and be two vectors in the x-y plane. Let and denote the
angles that the vectors and make (in the counterclockwise direction) with the
positive x-axis. Then,
In Figure A.1.13, the vector addition is shown. Let denote the angle that
the vector makes with the positive x-axis.
A
yA
x
y
xAFigure A.1.12 Components of a vector in the x-y plane
A
yAx
y
xA
Figure A.1.12 Vector addition with components
A
BxB
yBB
BAC
C
Then the components of are
,
In term of magnitudes and angles, we have
We can write the vector as
A.2 Dot Product
A.2.1 Introduction
We shall now introduce a new vector operation, called the “dot product” or “scalar
product” that takes any two vectors and generates a scalar quantity (a number). We
shall she that the physical quantity of work can be mathematically described by the dot
product between the force and the displacement vectors.
Let and be two vectors. Since any two non-collinear vectors form a plane, we define
the angle to be the angle between vectors and as shown in Figure A.2.1. Note that
can vary from 0 to .
A.2.2 Definition
A
B
Figure A.2.1 Dot product geometry
The dot product of the vectors and is defined to be product of the magnitude of
the vectors and with the cosine of the angle between the two vectors:
Where and represent the magnitude of and respectively. The dot
product can be positive, zero, or negative, depending on the value of cos . The dot
product is always a scalar quantity.
We can give a geometric interpretation to the dot product by writing the definition as
In this formulation, the term A cos is the projection of vector in the direction of
vector . This projection is shown in Figure A.2.2a. So the dot product is the product of
the projection of the length in the direction of with the length of . Note that we
could also write the dot product as
Now the term B cos is the projection of vector in the direction of vector as shown
in Figure A.2.2b. From this perspective, the dot product is the product of the projection
of the length of in the direction of with the length of .
From our definition of our dot product we see that the dot product of two vectors that
are perpendicular to each other is zero since the angle between the vectors is /2 andπ
cos( /2) = 0. π
A.2.3 Properties of Dot Product
A
B
Figure A.2.2a and A.2.2b Projection of vectors and the dot product
cosB
A
B
cosA
The first property involves the dot product between a vector where c is a scalar and
a vector ,
The second involves the dot product between the sum of two vectors and with a
vector ,
Since the dot product is a commutative operation,
The similar definition holds,
A.2.4 Vector Decomposition and the Dot Product
With these properties in mind we can now develop an algebraic expression for the dot
product in terms of components. Let’s choose a Cartesian coordinate system with the
vector pointing along the positive x-axis with positive x-component , i.e.,
The vector can be written as,
We first calculate that the dot product of the unit vector with itself is unity:
Since the unit vector has the magnitude and cos (0) = 1. We note that the same
role applies for the unit vectors in the y and z directions:
The dot product of the unit vector with the unit vector is zero because the two unit
vectors in the y and z-direction:
Similarly, the dot product of the unit vector with the unit vector , and the unit vector
with the unit vector are also zero:
Based on those explanation, for two vectors and ,
the dot product of them now becomes:
A.3 Cross Product
We shall now introduce our second vector operation, called the “cross product”
that takes any two vectors and generates a new vector. The cross product is a type of
“multiplication” law that turns our vector space (law for addition of vectors) into vector
algebra (laws for addition and multiplication of vectors). The first application of the
cross product will be the physical concept of torque about a point P which can be
described mathematically by the cross product of a vector from P to where the force
acts, and the force vector.
A.3.1 Definition
Let and be two vectors. Since any two vectors form a plane, we define the angle θ
to be the angle between the vectors and as shown in Figure A.3.2.1. The magnitude
of the cross product of the vectors and is defined to be product of the
magnitude of the vectors and with the sine of the angle between the two vectors, θ
where A and B denote the magnitudes of and , respectively. The angle between theθ
vectors is limited to the values 0 ≤ ≤ insuring that sin ≥ 0. θ π θ
The direction of the cross product is defined as follows. The vectors and form a
plane. Consider the direction perpendicular to this plane. There are two possibilities, as
shown in Figure A.3.1. We shall choose one of these two for the direction of the cross
product using a convention that is commonly called the “right-hand rule”.
A.3.2 Right-hand Rule for the Direction of Cross Product
Figure A.3.1 Cross product geometry
The first step is to redraw the vectors and so that their tails are touching. Then draw an
arc starting from the vector and finishing on the vector . Curl our right fingers the same
way as the arc. Our right thumb points in the direction of the cross product (Figure
A.3.2).
We should remember that the direction of the cross product is perpendicular to
the plane formed by and . We can give a geometric interpretation to the magnitude
of the cross product by writing the definition as,
The vectors and form a parallelogram. The area of the parallelogram equals the
height times the base, which is the magnitude of the cross product. In Figure A.3.3, two
different representations of the height and base of a parallelogram are illustrated. As
depicted in Figure A.3.3(a), the term is the projection of the vector in the
direction perpendicular to the vector . We could also write the magnitude of the cross
product as,
Now the term is the projection of the vector in the direction perpendicular to
the vector as shown in Figure A.3.3(b).
Figure A.3.2 Right-hand Rule
A
B
Figure A.3.3 Projection of vectors and the cross product
sinB
A
B
sinA
The cross product of two vectors that are parallel (or anti-parallel) to each other is zero
since the angle between the vectors is 0 (or ) and π sin (0) = 0 (or sin ( ) = 0).π
Geometrically, two parallel vectors do not have any component perpendicular to their
common direction.
A.3.3 Properties of the Cross Product
(1) The cross product is anti-commutative since changing the order of the vectors cross
product changes the direction of the cross product vector by the right hand rule:
(2) The cross product between a vector where c is a scalar and a vector is
Similarly,
(3) The cross product between the sum of two vectors and with a vector is
Similarly,
A.3.4 Vector Decomposition and Cross Product
We first calculate that the magnitude of cross product of the unit vector with :
since the unit vector has magnitude and sin ( /2) = 1. By the right hand rule,π
the direction of is in the as shown in Figure A.3.4. Thus .
Similarly we get,
i
j
Figure A.3.4 Cross product of equals to
j
i
k
k
Listing those results to a table,
0 - -
- 0
- 0
Thus, for two vectors and , the cross product of
them now becomes:
The method above is a complicated mathematic. There is another method which is used
to simply this calculation by using determinant.
So, we get,
D. Learning Approach and Method
The learning approach which is used in this activity is student centered and the
learning method which is used in this activity is direct instruction.
E. Learning Activity
1 st meeting (2 x 45 minutes)
1. Pre Activity (±5 minutes)
a. Greeting the student and checking the student attendance
2. Whilst Activity (±80 minutes)
Learning Steps Teacher activities Students activities
Confirmation
Communicating
the indicators and
motivating the
Explaining the indicators
Motivating the students by
asking them
Paying attention to the
explanation and asking the
teacher what they don’t
students
(10 minutes)
Examples:
- Can you mention some
physical quantities which
has both magnitude and
scalar
- How to say your
position now?
understand
Exploration
Explaining the
material
(50 minutes)
Explaining how to draw
vector and determine the
resultant of two vectors
geometrically
Asking some questions to
motivate the student
Paying attention to the
explanation and asking what
they don’t understand
Elaboration
Disccusing some
problems
(30 minutes)
Asking the student to make
some groups
Demonstrating the
application of vector
adding using two spring
balance hang on a block of
mass and ask the student to
find the resultant
geometrically
Making group consists of 3-4
person
Discussing how to find the
resultant of the two spring
balance
Communicating their answer
3. Post Activity (±5 minutes)
a. Teacher facilitates the students to conclude what the have learnt
b. Teacher evaluates the class and allow some students to ask what they still don’t
understand
c. Teacher tells what will be learnt on the next meeting and gives homework
d. Closing the activity
2 nd meeting (1 x 45 minutes)
1. Post Activity (±2 minutes)
b. Greeting and checking the student attendance
2. Whilst Activity
Teacher Activities Student Activities Time allotment
a. Describing the indicators
b. Introducing the student how
to determine the resultant of
two vectors analytically
a. Remembering their
knowledge before
10 minutes
c. Giving each student a
worksheet
b. Solving the problems in
worksheet
15 minutes
d. Discussing the most difficult
problems in worksheet and
allow the student to asking
what they don’t understand
c. Paying attention in
discussion and asking some
question to the teacher
10 minutes
e. Giving the student quiz to
evaluate their understanding
d. Answer the quiz 5 minutes
3. Post Activity (±3 minutes)
a. Teacher facilitates the students to conclude what the have learnt
b. Teacher evaluates the class and allow some students to ask what they still don’t
understand
c. Closing the activity
3 rd meeting (2 x 45 minutes)
1. Post Activity (±5 minutes)
c. Greeting and checking the student attendance
2. Whilst Activity
Teacher Activities Student Activities Time allotment
a. Explaining the indicators
b. Evaluating the quiz done by
the students last meeting
a. Paying attention to the
students
10 minutes
c. Discussing the dot product
of two vectors and giving the
b. Solving the problems 30 minutes
student exercise individually
d. Discussing the cross product
of two vectors and giving
some example to solve
c. Paying attention in
discussion and solving the
problems
30 minutes
e. Giving the student quiz d. Answer the quiz 5 minutes
3. Post Activity (±10 minutes)
d. Teacher facilitates the students to conclude what the have learnt
e. Teacher evaluates the class and allow some students to ask what they still don’t
understand
f. Closing the activity
F. Learning Resources
1. Sunardi, & Irawan, E. I. 2007. Fisika Bilingual. Bandung: Yrama Widya
2. Marthen Kanginan ( 2007). Fisika. Jakarta: Erlangga
3. Chasanah, Chuswatun. 2008. Kreatif Fisika Xa. Klaten: Viva Pakarindo
4. Haliday, Resnick, and Walker. (2001). Fundamental of Physics. Sixth Edition.
New York: John Wiley & Sons, Inc. (Recommended)
5. Presentation media
6. Spring balance and mass
7. Blog (http:/www.pplreal.wordpress.com)
G. Assessment
Cognitive : Worksheet
Affective : Observation sheet