VBA1 Introduction to VBA Programming

7/26/2019 VBA1 Introduction to VBA Programming

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VBA at a lance

Lecture 6 1Lecture 1


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Activating VBA withinSOLIDWORKS

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VBA

unc on ec ara on

m , , , , s ou e

Dim Message, Title, Default VBA statementMessage = A : Set prompt.

Title = "InputBox" ' Set title.

Default = "0.0" ' Set default.

End Sub End of the function

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Data Declaration

. umer c: n eger, ong, ng e, ou e,Currency

m , , s n eger

2. Stringm y r s r ng

MyStr = SolidWorks

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InputBoxIn utBox r o m t t i t l e d e f a u l t x o s o s

Dim Message, Title, Default

Message = "A : "

Title = "InputBox"

Default = "0.0"A = InputBox(Message, Title, Default)

Title

Message

Default

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MsgBox

MsgBox(p r o m p t[, b u t t o n s] [, t i t l e ] )

Dim Msg, Style, Help, Ctxt, Response, MyString

Ms = "Do ou want to continue ?"

Style = vbYesNo + vbCritical + vbDefaultButton2

Title = "MsgBox Demonstration" , ,

MsgTitle

vbCritical

vbDefaultButton2

Lecture 6 6

(highlighted)


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MSgBox: Style

vbOKOnly Display OK button only

vbOKCancel Display OK and Cancel buttons

vbAbortRetryIgnore Display Abort, Retry, and Ignore buttons

vbYesNoCancel Display Yes, No, and Cancel buttons

vbYesNo Display Yes and No buttons

vbRetryCancel Display Retry and Cancel buttons

vbCritical DisplayCritical Message icon

vbDefaultButton1 First button is default.

.vbDefaultButton3 Third button is default.

vbDefaultButton4 Fourth button is default.

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MsgBox

Dim A As Double

.

Dim Msg, Style, Title, Response

Msg = ASt le = vbOKOnl

Title = Output "

Response = MsgBox(Msg, Style, Title)

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Arithmetic

Numeric+ Add 5+5 10- -

/ Divide 25/5 5\ Integer Division 20\3 6* Multiply 5*4 20^ Exponent (power of) 3^3 27Mod Remainder of division 20 Mod 6 2

& String concatenation "G"&" "&"B" G B+ String concatenation A + B AB

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Mathematical Examples

pi = 4 * atn(1.0)

de = rad * 180.0 i

=rad

180deg

Sub main()

* input the rad

pi = 4 * atn(1.0)

= *

* display the result

End Sub

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pi = 4 * atn(1.0)

rad = de * i 180

=deg pi

rad

Len th calculation

22 yxl += l = sqr ( x^2 + y^2)

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par1 = sqr ( b^2 4 * a * c )

x1 = -b ar1 2 * a

ac4bb 2

x2 = (-b - par1)/(2 * a)a2, 21

Note:

Equations can written using one

equation or using mu tip e equations(depends on individual)

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Mathematical Operators : +

.

Dim A, B As DOUBLE

A = 2

B = 3= = =

Therefore Val is used to convert to numerical

value

C = Val(A) + Val(B) C = 5

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Function: with returned value

Dim length As Doublelength = Hypotenuse(3, 4) Interfacing the function

" "

End Sub

Function Hypotenuse(A As Double, B As Double) As Double

Hypotenuse = Sqr(A ^ 2 + B ^ 2)

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Function: with no returned value

Dim firstfirst = subr1()

End Sub

No As Double or Integer : will not return any value

Function subr1()Dim Msg, Style, Title, Response

Msg = A

Style = vbOKOnly

Response = MsgBox(Msg, Style, Title)

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Tips to write good program

Short source code is easy to comprehend.Main function will the manage the sub function

Sub Main()

func1()

func2()

End Sub

Function func1()

End Function

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: use to write the remark.

Function Declaration

Function Hypotenuse(A As Double, B As Double) As

Double

Hypotenuse = Sqr(A ^ 2 + B ^ 2)

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Sub Main()

Dim A As Double

If rad < 0 Then

rad =

Else If a < 0 Then

dim

End If

End Sub

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r r v r

constant

Dim pi As Double

Sub Main()

pi = 4 * atn(1.0)

End Sub

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Task

a cu a e e coor na es o ainscribed hexagon based on the

.

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Procedure

1. In ut the radius of the circle

2. Calculate all the vertices

o n .x = a cos ang

Point.y = Rad* sin(ang)

w ere ang s , , , , ,

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Programming: Step 1

Dim Message, Title

Dim Default, Rad As Double

Message = Radius of the circle "

e = npu ox

Default = 10.0"

, ,

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Programming: Step 2

Dim pi, p1x, p1y, p2x, p2y As Double

p = n

p1x = Rad

p1y = 0

p2x = Rad * Cos(pi / 3)

p2y = Rad * Sin(pi / 3)

p6x = Rad * Cos(5*pi / 3)

p6y = Rad * Sin(5*pi / 3)

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Programming: Step 3

,

the answer with known radis

Possible amendment: round-off error when rad =10.0

p2x = 5

p2x = Round(Rad * Cos(pi / 3), 2)

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Integration with SolidWorks

record the process of modeling.

Tool Macro Record or Icon

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Macro for line drawing

. e e s e c p ane

2. Set the macro to record

3. Draw the line (single line)

4. Stop the recording5. Save the macro

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' *****************************************************

' C:\DOCUME~1\use\LOCALS~1\Temp\swx2956\Macro1.swb - macro

recorded on 02/22/09 by use' *****************************************************

Dim Part As Object

Dim SelMgr As Object

Dim boolstatus As BooleanDim lon status As Lon lon warnin s As Lon

Dim Feature As Object

Sub main()

Set swA = A lication.SldWorks

Set Part = swApp.ActiveDoc

Part.CreateLine2 -0.0445163235549, 0.08583865080093, 0,

0.07046754356449 -0.05908893171413 0

Lecture 6 27

End Sub


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Createline2 Function

= . , , , , ,p2z)

(double )p1x X value of the line start point(double) p1y Y value of the line start point

double 1z Z value of the line start oint(double) p2x X value of the line end point(double) p2y Y value of the line end point(double) p2z Z value of the line end point

Return:(LPDISPATCH) retval Pointer to a Dispatch object, if the

operation fails, then NULL is returned

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Sub main()

Set swApp = Application.SldWorks

Set Part = swApp.ActiveDoc

Conversion from the macro created

p1x =

p1y =

Part.CreateLine2 p1x, p1y, 0, p2x, p2y, 0

Or

Dim line1 As ObjectSet line1 = Part.CreateLine2 (p1x, p1y, 0, p2x, p2y, 0)

End Sub

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Task 2

r e a program o crea e e exagon

based on user input radius?

Lecture 6 30

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VBA1 Introduction to VBA Programming