22
1 REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT UTS 2017 PEMBAHASAN

UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

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Page 1: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

1 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

UTS 2017PEMBAHASAN

Page 2: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

2

SUPPLY & DEMAND

PABRIK SUPPLY

W 6.000X 7.000Y 8.000Z 5.000

TOTAL 26.000

KOTA DEMAND

A 6.000B 4.000C 5.000D 7.000

TOTAL 22.000

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REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

3

BIAYA TRANSPORTASI

KEDARI

A B C D

W 9 10 8 12X 12 7 21 23Y 14 11 9 19Z 5 7 7 5

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REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

4

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

Page 5: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

5

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

6.000

1.000

6.0002.000

3.0004.000

4.000

Page 6: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

6

HASIL PERHITUNGAN

Z = 6.000 (9) + 4.000 (7) + 3.000 (21) +2.000 (9) + 6.000 (19) + 1.000 (5) + 4.000(0)

Z = 282.000

Page 7: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

7

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

6.000

1.000

6.0002.000

3.0004.000

4.000

Page 8: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

8

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

6.000

4.000

3.0005.000

3.0004.000

1.000

Page 9: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

9

HASIL PERHITUNGANITERASI 1

Z = 6.000 (9) + 4.000 (7) + 3.000 (0) + 5.000(9) + 3.000 (19) + 4.000 (5) + 1.000 (0)

Z = 204.000

Page 10: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

10

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

6.000

4.000

3.0005.000

3.0004.000

1.000

Page 11: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

11

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

3.000

1.000

3.0005.000

3.000 4.000

4.000

3.000

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REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

12

HASIL PERHITUNGANITERASI 2

Z = 3.000 (9) + 3.000 (12) + 3.000 (12) +4.000 (7) + 5.000 (9) + 3.000 (19) + 1.000(5) + 4.000 (0)

Z = 234.000

Page 13: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

13

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

3.000

1.000

3.0005.000

3.000 4.000

4.000

3.000

Page 14: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

14

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

3.000

1.000

5.000

3.000 4.000

4.000

6.000

Page 15: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

15

HASIL PERHITUNGANITERASI 3

Z = 6.000 (12) + 3.000 (12) + 4.000 (7) +3.000 (14) + 5.000 (9) + 1.000 (5) + 4.000(0)

Z = 228.000

Page 16: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5

REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

16

SUPPLY

9 10 8 12 0

12 7 21 23 0

14 11 9 19 0

5 7 7 5 0

DEMAND 26.0006.000 4.000 5.000 7.000 4.000

X

Y

Z

D Dummy

6.000

7.000

8.000

5.000

A

W

B CKE

DARI

4.000

5.000

2.000

5.000

1.0004.000

3.000

2.000

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REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT

17

HASIL PERHITUNGANITERASI 4

Z = 4.000 (9) + 2.000 (12) + 2.000 (12) +4.000 (7) + 1.000 (0) + 5.000 (9) + 1.000(0)+ 5.000 (5)

Z = 182.000

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18 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.

CONTOH SOAL

Perumahan

B = rambu

A

C

REL

V

Hitunglah:Besarnya batas kecepatan pada rambu di B?Bila diketahui:Kecepatan mobil di A=120 km/jam.Waktu PIEV AB = 0,8 detikWaktu PIEV BC = 1,0 detik

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19 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.

CONTOH SOAL

Jarak AB = 148,14 mJarak BC + pengamanan = 186,25 mJarak pengaman = 5 m.Perlambatan mobil 2 m/dt2

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20 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.

JAWABAN

B = rambu

A

C

REL

V

DE

tPIEV

tC

AD St = Vo x t

mxSt 67,268,03600

000.120

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21 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.

JAWABANJarak AB = AD + DB

148,14 = 26,67 + DBDB = 148,14 – 26,67 mDB = 121,47 m

DB St = Vo .t – ½ a t2

2221

3600

000.12047,121 xtxxt

047,12133,33t2 t

165,4

165,29

0)165,429,165)(t(

2

1

t

t

t

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22 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.

JAWABAN

DB Vt = Vo – a.t

t1= 29,165

T2= 4,165

165,2923600

000.120tV

mungkin tidak33,5833,33 tV

165,423600

000.120tV

km/jam9010

900

km/jam10

3625

m/det25

33,833,33

t

t

t

t

V

xV

V

V