University Physics Mastering Physics Ch 35 36

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Chapter 35/36 Assignment

Due: 8:00pm on Wednesday, May 16, 2012

Note: To understand how points are aw arded, read your instructor's Grading Policy.

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Exercise 35.13

Two very narrow slits are spaced 1.81 and are placed 38.0 from a screen.

Part A

What is the distance between the first and second dark lines of the interference pattern whenthe slits are illuminated with coherent light with a wavelength of 550 ? (Hint: The angle in

equation is not small.)

ANSWER: = 0.136

Correct

Exercise 35.15

Coherent light with wavelength of 602 passes through two very narrow slits and the

interference pattern is observed on a screen a distance of 3.00 from the slits. The first-order

bright fringe is a distance of 4.84 from the center of the central bright fringe.

Part A

For what wavelength of light will the first-order dark fringe be observed at this same point on thescreen?

ANSWER: = 1.20

Correct

Exercise 35.23

Two slits spaced 0.240 apart are placed 0.640 from a screen and illuminated by coherent

light with a wavelength of 620 . The intensity at the center of the central maximum is

.

Part A

What is the distance on the screen from the center of the central maximum to the firstminimum?

ANSWER: 8.27×10−4

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= Correct

Part B

What is the distance on the screen from the center of the central maximum to the point wherethe intensity has fallen to

ANSWER: = 4.13×10−4

Correct

Exercise 35.31

A uniform film of , 1036 thick and having index of refraction 2.62, is spread uniformly over

the surface of crown glass of refractive index 1.52. Light of wavelength 495 falls at normal

incidence onto the film from air. You want to increase the thickness of this film so that thereflected light cancels.

Part A

What is the minimum thickness of that you must add so the reflected light cancels as

desired?

ANSWER: = 3.12

Correct

Part B

After you make the adjustment in part (a), what is the path difference between the light reflectedoff the top of the film and the light that cancels it after traveling through the film? Express youranswer in nanometers.

ANSWER: = 2080

Correct

Part C

Express your answer in wavelengths of the light in the film.

ANSWER: = 11.0

Correct

Exercise 35.37

Part A



How far must the mirror (see the figure ) of the Michelson interferometer be moved so that

1810 fringes of He-Ne laser light (633 ) move across a line in the field of

view?

ANSWER: = 0.573

Correct

Problem 35.44

Two radio antennas radiating in phase are located at points and , 200 apart (see the figure

). The radio waves have a frequency of5.80 . A radio receiver is moved out

from point along a line perpendicular to

the line connecting and (line

shown in the figure).

Part A

At what distances from will there be destructive interference? (Note: The distance of the

receiver from the sources is not large in comparison to the separation of the sources, so

equation does not apply.)

Enter your answers in ascending order separated by a comma.

ANSWER: = 20.0,90.0,219,761

Correct



Exercise 36.13

Red light of wavelength 633 from a helium-neon laser passes through a slit 0.400 wide.

The diffraction pattern is observed on a screen 3.35 away. Define the width of a bright fringe as

the distance between the minima on either side.

Part A

What is the width of the central bright fringe?

ANSWER: 1.06×10−2

Correct

Part B

What is the width of the first bright fringe on either side of the central one?

ANSWER: 5.30×10−3

Correct

Exercise 36.17

A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from adistant source passing through a slit 0.110 wide. At the point in the pattern which is an

angular distance of 2.82 from the center of the central maximum, the total phase difference

between wavelets from the top and bottom of the slit is 57.5 .

Part A

What is the wavelength of the radiation?

ANSWER: = 5.91×10−7

Correct

Part B

What is the intensity at this point, if the intensity at the center of the central maximum is ?

ANSWER: = 2.54×10−4

Correct

Exercise 36.23

An interference pattern is produced by light with a wavelength 580 from a distant source



incident on two identical parallel slits separated by a distance (between centers) of 0.570 .

Part A

If the slits are very narrow, what would be the angular position of the first-order, two-slit,interference maxima?

ANSWER: = 1.02×10−3

Correct radians

Part B

What would be the angular position of the second-order, two-slit, interference maxima in thiscase?

ANSWER: = 2.04×10−3

Correct radians

Part C

Let the slits have a width 0.350 . In terms of the intensity at the center of the central

maximum, what is the intensity at the angular position of ?

ANSWER: = 0.236

Correct

Part D

What is the intensity at the angular position of ?

ANSWER: = 2.90×10−2

Correct

Exercise 36.29

Diffraction grating produces its third-order bright band at an angle of 77.4 for light of wavelength

751 .

Part A

Find the number of slits per centimeter for the grating.

ANSWER: = 4330

Correct

Part B



Find the angular location of the first-order bright band.

ANSWER: = 19.0

Correct

Part C

Find the angular location of the second-order bright band.

ANSWER: = 40.6

Correct

Part D

Will there be a fourth-order bright band?

ANSWER:yes

no

Correct

Part E

Explain.

Essay answers are limited to about 500 words (3800 characters maximum, includingspaces).

ANSWER: My Answer:There is not a fourth-order bright band because when using the formulad*sin(Ө)=m*λ for m=4, we get sin(Ө)to be greater than 1. This does not exist.Therefore, there is not a fourth-order bright band.

Exercise 36.39

X rays of wavelength 0.0840 are scattered from the atoms of a crystal. The second-order

maximum in the Bragg reflection occurs when the angle in the figure 36.23 in the textbook is

20.0 .

Part A

What is the spacing between adjacent atomic planes in the crystal?

ANSWER: = 0.246

Correct



Exercise 36.48

A converging lens 7.20 in diameter has a focal length of 300 .

Part A

If the resolution is diffraction-limited, how far away can an object be if points on it 4.00

apart are to be resolved (according to Rayleigh's criterion)? Use .

ANSWER: = 429

Correct

Score Summary:

Your score on this assignment is 100%.You received 24 out of a possible total of 24 points.

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University Physics Mastering Physics Ch 35 36