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Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

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Page 1: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Unit 5 – Chap 10 & 16Solutions & Empirical Formulas (last but definitely not least!)

April

Page 2: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Solutions and Entropy

Page 3: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April
Page 4: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

What do you know already about solutions?

Solutions are:• Solutions of gases, liquids or

solids are everywhere• Homogenous mixture• Solute and Solvent• Is this a solution:

– AIR– CARBON DIOXIDE GAS– CARBONATED BEVERAGE– SALAD DRESSING– 14 KARAT GOLD– 24 KARAT GOLD

Page 5: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Solutions

A solution is a homogenous mixture of 2 or more substances mixed evenly at a particle level.

One part is regarded as the solvent and the others as solute

Page 6: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Solution Terminology

Solute – substance being dissolved (lesser amt)

Solvent – component whose physical state remain the same (greater amt)

Practice: 14.1 - WHICH IS A SOLUTE AND WHICH IS THE SOLVENT? 2 OUNCES OF OIL & 2 GALLONS OF GASOLINE CARBON DIOXIDE IN A SELTZER WATER

Dissolve – to mix uniformly and completely at the molecular level

Miscible – liquids that can dissolve in one another form solution Immiscible - liquids that don’t dissolve in one anotherAqueous solution (aq)

Page 8: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Ionic solutes

Called hydrated ions when the solvent is water

Page 10: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

The dissolving process

• When an ionic compound dissolves in water:– ionic bonds are broken– attraction between water

molecules are broken– attraction between water

and ions are formed

Page 11: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

What happens during dissolving?

• How does arrangement of particles change?

• How does motion of particles change?

Page 12: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Lattice energy and hydration energy

Page 13: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Why do solutions form? • One major driving force is energy• Is dissolving of an ionic compound endothermic

or exothermic? Why?– Example of exothermic dissolving:

• dissolving LiCl in water

– Example of endothermic dissolving:• dissolving NH4Cl in water

• Which bonds/attractions broken during dissolving?• Which bonds/attractions formed during dissolving?• Which are stronger?

Page 14: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Entropy: A new concept that explains a lot

Entropy =

Due to the laws of probability, the entropy of the universe is constantly increasing and never decreases.

Processes that would lead to a decrease in entropy of the universe are not possible.

The universe can be divided into the system and its surroundings.

Page 15: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Why do things happen?

• There are only two reasons for an event to occur (including a chemical process):– Entropy of the system increases

– Entropy of the surroundings increases (exothermic reactions are an increase in the surroundings’ entropy)

Page 16: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

MOLARITY AND DILUTIONSChapter 9

Page 17: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Solution concentration- terms• Dilute

– Small amount of solute• Concentrated

– Large amount of solute

Stock - routinely used solutions prepared in concentrated form.

Page 18: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

How do you quantify concentration of a solution?

• Concentration = amount of solute per amount of solution (or solvent)

• Molarity = moles solute / liters solution• Example problems:

– What is the molarity of a solution if 23 g of KCl are dissolved to make 4 L of solution?

– How many grams of KCl should be dissolved to make 500. mL of a 0.10 M solution?

Page 19: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Solute concentration expressions

• There are a few different ways to calculate the concentration of the solution.

• In Biology, we used: • Mass percent:

(mass solute / mass of solution) * 100

• This year in Chemistry, we will also use:• Molarity(M):

moles solute / Liter solution

Page 20: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

• Molarity (M) = moles of solute per volume of solution in liters:

• Because volume is temperature dependent, molarity can change with temperature.

mol of soluteL of solutionM =

Molarity (M)

6 moles of HCl2 liters of solution

3 M HCl =

Page 21: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Concentration: molarity exampleIf 0.435 g of KMnO4 is dissolved in enough water to give 250. mL of solution, what is the molarity of KMnO4?

Now that the number of moles of substance is known, this can be combined with the volume of solution — which must be in liters — to give the molarity. Because 250. mL is equivalent to 0.250 L .

As is almost always the case, the first step is to convert the mass of material to moles.

0.435 g KMnO4 • 1 mol KMnO4 = 0.00275 mol KMnO4

158.038g KMnO4

Molarity of KMnO4 = 0.00275 mol KMnO4 = 0.0110 M 0.250 L solution

Page 22: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Molarity problems

1. What is the molarity of a solution if 23 g of KCl are dissolved to make 4 L of solution?

2. How many grams of KCl should be dissolved to make 500. mL of a 0.10 M solution?

Page 23: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Molarity problems

3. A truck carrying 22.5 kL of 6.83 M aqueous hydrochloric acid (HCl) used to clean brick has overturned on the highway, and the acid needs to be neutralized. How many moles of HCl have been spilled?

Page 24: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Dilution

• What does it mean to dilute a solution? What is added?– Solvent is added to lower the concentration.

• When a solution is diluted, what is conserved? – The amount of solute remains constant before and after

the dilution.

moles BEFORE = moles AFTER

M1V1 = M2V2

Page 25: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Common Terms of Solution Concentration

Stock - routinely used solutions prepared in concentrated form.

Concentrated - relatively large ratio of solute to solvent. (5.0 M NaCl)

Dilute - relatively small ratio of solute to solvent. (0.01 M NaCl): (MV)initial=(MV)Final

Copyright©2000 by Houghton Mifflin Company. All rights reserved.

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Page 26: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Dilution problems 1. Suppose you have 0.500 M NaCl stock solution. How do you

prepare 250. mL of 0.348 M NaCl solution ?

Concentration 0.500 M NaCl

Page 27: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Copyright©2000 by Houghton Mifflin Company. All rights reserved.

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Figure 4.10: Steps involved in the preparation of a standard aqueous

solution.

Page 28: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Making a solution staring with a solid

Page 29: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

How to make solutions

• Starting with a solid:– Does volume of solute = volume of solution?– What type of glassware is best for accurate

measurement of a certain volume of liquid AND mixing a solution?

• Starting with a concentrated solution:– How does the number of moles of solute change

when a solution is diluted?– What type of glassware is best for accurate delivery

of a liquid with a certain volume?

Page 30: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Dilution problems

2. What is the molarity of a solution of ammonium chloride prepared by diluting 50.00 mL of a 3.79 M solution to 2.00 L?

3. To what volume should 1.19 mL of an 8.00 M solution be diluted in order to obtain a final solution that is 1.50 M?

Page 31: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Copyright©2000 by Houghton Mifflin Company. All rights reserved.

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Figure 4.12: Dilution Procedure (a) A measuring pipet is used to transfer 28.7mL of 17.4 M acetic acid solution to a volumetric flask. (b) Water is added to the flask to the calibration mark. (c) The resulting solution is 1.00 M acetic acid.

Page 32: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Dilution

When a solution is diluted, _____________ are conserved.

Since M = _________, therefore moles = _______

Example problemsWhat is the molarity of a solution of ammonium chloride

prepared by diluting 50.00 mL of a 3.79 M solution to 2.00 L?To what volume should 1.19 mL of an 8.00 M solution be

diluted in order to obtain a final solution that is 1.50 M?

Page 33: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Composition Calculations

Page 34: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Describing the composition of compounds

• Percent composition (by mass) used to describe what elements a compound is made of, in what proportions.

• Experimentally measured

• % mass of element =

– According to formula OR– According to experimental results

Page 35: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Finding experimental percent composition

• A sample of iron oxide with a mass of 4.76 g is found to contain 3.70 g of iron. What is its percent composition?

Page 36: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Calculating theoretical percent composition from formula

• What is the percent composition of aluminum oxide?

Page 37: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Using percent composition to calculate mass

• Calculate the mass of zinc in a 30.00g sample of zinc nitrate.

Page 38: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

50.0g of SF6

• How many grams of sulfur is that?

Page 39: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Empirical formula

• You can use % composition to find out the formula of an unknown compound!

Empirical = determined experimentally Empirical formula = simplest mole ratio

• Examples of empirical formulas:

Page 40: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Empirical formula example #1

• A sample of an iron oxide is 69.94% Fe and 30.06% O. What is the empirical formula?

Page 41: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Empirical formula example #2

• In lab, a student analyzes a sample of nickel chloride and finds that it contains 35% Ni and 65% Cl. What is the empirical formula?

Page 42: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Empirical formula example #3

• A piece of copper ore with a mass of 0.858 grams is found to contain 0.537 g of copper. The remainder of the mass is fluorine. What is the empirical formula of this ore?

Page 43: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Practice problems

Try these problems in small groups:

• What is the percent composition of tin(IV) oxide?• A sample of silver(I) sulfide has a mass of 62.4 g. What

mass of each element could be obtained by decomposing this sample?

• A sample of copper chloride is found to contain 5.46 g of copper and 6.10 g of chloride. What is its percent composition?

Page 44: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

Lab procedures

• Iodine vapor is toxic – keep the beakers covered and don’t breathe fumes.

• Decant:

• Gentle heating:

• Mass of product:

Page 45: Unit 5 – Chap 10 & 16 Solutions & Empirical Formulas (last but definitely not least!) April

PERCENT YIELD• Theoretical Yield – the “calculated” amount. It is

the maximum amount that can be produced by the given reaction.– Reasons for less than 100% yield:

• Incomplete rxn of the limiting reagent• Less than ideal reacting conditions• Reversible rxns• Formation of unwanted reaction products• Loss of product in transferring from one vessel to another

• Actual Yield (experimental) - the quantity of the product that is actually obtained from the reaction.