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Unit 2 Polynomial Quiz Review This quiz is 100% non-calculator!!!!! State if the following functions are polynomials. If they are find the number of zeros, number of possible extrema, and the end behavior.
a) !"#$ % #& ' 9#)
b) !"#$ % )* + 5#
c) !"#$ % '"# ' 1$/"# ' 3$
d) !"#$ % ln"1$
e) !"#$ % 2#) ' #/ ' 18# + 9
f) !"#$ % #"# ' 3$"# + 2$
g) !"#$ % √84#/7
Now graph the above functions that are polynomials
D 5Polynomial Zeros 5 Extrema_4 endbehaviorYYPCx A hjmPCX 0
NOTaPolynomialD 3
Polynomial Zeros 3 extrema_2 end behaviorYYosP 0 4715D oPolynomial zeros NONE extrema_None end behaviorYYosP O KY751 03 as
Polynomial zeros 3 extrema_2 end behaviorYYosP 0 471510 3 bi A
Polynomial Zeros 3 extrema_2 end behaviorYFosP 77NOT aPolynomial
5 9 3 131 2 9 x omof3 x D2 X 3 X lmof2 fullA x 3mot A X 3mof1D11 3mof1 y inty int0,0 0,3
µ a X
V
X Lx 31 1 2e f X 0
2 2 48 9 x 3X 2
III's Sµ
We
Xt3 X 3 2x Dv v
X 311 3yY int10,9
Write the possible equations for the following graphs:
a) b)
Two polynomials P and D are given. Use either synthetic or long division to divide P(x) by D(x).
Use the Factor Theorem to show that x – c is a factor of P(x) for the given value(s) of c. If it is a factor find the remaining zeros.
a.
b.
c.
d.
e.
f.
a.
b.
c.
d.
3
x 5
2 I
k leading Coefficent
y Kx Xt3 X 1 X 5 y Kutz x D2
3J 3 5 4 If I 4 6 1
I 9 12 I 5 I
3 4 I 5 I
3 4 3 X2t5X 1
you can Do synthetic I just 2x t4don't deal w fractions 2L't t 2 1 4 3 0 2 7 94 72 21
2X 3 2 3 3 2 2x to 2 2 7X2 3 1 t2xXtx u
8 92x to 8k73 53
3 2 2 4 52 It 2 3 2 1
2 344 2 8X 3 XZ.at 4x4 4x3tOx X3x43xxfEo5xitY 2
4 tt oxzx3 3xZt4Xt lyt3x t4Xx4t8g y y
If 8 IEXIX3 174 7 11 2 74 78 5772 X 13
13 3115134 I 13 245 34 IOI 3 3 1 0 Factor 1 2 3 10 10
NOT AD 1 3 3 1 Factor
tr l 2 I
I 2 I
XZ 2 1X 1 X I X lM 34 31333 16135 27133163
81 81 414 48 63 0
X 3 i Factor
3 4 31 350 16L35276
2ft 3t7 kYt6 K 5 81 81 144 63 63
tht 3 5 18
Igt 3 5X 3 NOTA facto
16g 3 5
21 3 5 0.0 Factor
2 7 6 5t I 4 5
x kX 2 i
2 8 10 OU
2 2 8 10
21 2 4 54th2
4 22