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Unit 1 Test 2 Review
Please select a Team.
1. Team 12. Team 23. Team 34. Team 45. Team 56. Team 6
1. Find the product: - 3 - 8
1. 242. -243. 114. -11
2. Which equation can be used to find the distance between – 3.3 and 7.1?
a) l -3.3l – l7.1lb) l -3.3 – 7.1lc) - 3.3 – 7.1d) -3.3 + 7.1
3. Courtney had $545 in her bank account. She made two cash withdrawals from her account for $35 each. How much money does she have in her account after making the two cash withdrawals?
a) - $615b) $615c) - $475d) $475
4. Find the quotient: - 25.4 ÷ 0.5
a) 5.8b) - 5.8c) - 50.8d) 50.8
5. Evaluate: (-3)2
a) 9b) -9c) 6d) -6
6. Find the product: -¾ × (-⅖)
a) -15/8b) 15/8c) -3/10d) 3/10
7. Evaluate the expression:-6 × 3 ×(-2)
a) -18b) 18c) -36d) 36
8. The daily low temperatures for three days in February were -5.5°F, 3.2°F, and -4.6°F. What
was the average low temperature for the three days?
a) 2.3°Fb) 4.4°Fc) -2.3°Fd) -4.4°F
9. Three of the expressions below have the same value.
Which expression has a different value from the others?
a) -(4/5)b) -4/5c) 4/-5d) -4/-5
10. If x and y are rational numbers with the same signs, what are the
signs of their product and quotient?
a) The product is positive. The quotient is positive. b) The product is positive. The quotient is negative.c) The product is negative. The quotient is positive.d) The product is negative. The quotient is
negative.
11. The temperature in Dallas, Texas fell from 89° to 69° in 5 hours. What was the average
change in temperature per hour?a) 4°b) 20°.c) - 20°d) - 4°
12. A hiker started down a mountain at an elevation of 505.7
feet and ended at the bottom at an elevation of 234.9 feet. What is the change in elevation from where the
skier started?a) 270.8 feetb) 740.6 feetc) - 270.8 feetd) -740.6 feet
13. Find the sum:3.45 + ( - 22.3) + 13.32a) 39.07b) - 39.07c) - 5.53d) 5.53
14. Subtract: -34.5 – 32.4a) -66.9b) 66.9c) 1.8d) -1.8
15. Find the sum: -⅖ + ⅚a) 3/1b) 7/11c) - 13/30d) 13/30
16. The expression 2 ½ - (-5 ⅔) can be rewritten as which addition statement below?
a) - 2 ½ + (-5 ⅔)b) 2 ½ + 5 ⅔c) 2 ½ + (- 5 ⅔)d) - 2½ + 5 ⅔
17. The temperature on Friday at 10 am was 35 °F. It then fell by
12.4 °F to its current temperature. Which expression can be used to
find the current temperature?a) 35 + 12.4b) -35 – 12.4c) 35 – 12.4d) Answer not given