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FAKULTI KEJURUTERAAN MEKANIKAL UNIVERSITI TEKNIKAL MALAYSIA MELAKA TUTORIAL 3 SOLID MECHANICS 2 (BMCS 2333) SEMESTER 1 SESSI 2007/2008 Stress-Strain Energy & Castigliano’s Theorem - Solution 1. Using P, L, E and I, determine the strain energy due to bending for the beam and loading shown in Figure 1. Ignore the effect due to shear stress. () Solution CD portion: BC portion: AB portion: 2. The aluminum rod AB (G=26 GPa) is bonded to the brass rod BD (G=39 GPa) shown in Figure 2. Knowing that portion CD of the brass rod is hollow and has an inner diameter of 40 mm, determine the total strain energy of the two rods. () Solution , AB portion: BC portion: CD portion: 3. A simply supported beam, AB shown in Figure 3 is subjected to a concentrated load, F at midspan and an uniform distributed load, w N/m. Determine the expression for the elastic strain energy, U due to bending in term of flextural rigidity EI, length L, concentrated load F and uniform distributed load, w. Figure 1 A B C D 250mm 375mm 400mm 36mm 60mm Figure 2 TA= 800 Nm A B 3 L C D L L P P 1 x 1 x M 2 x 2 x M 3 x 3 x M

TUTORIAL 3 - Stress-Strain Energy n Castigliano Theorem-2-Solution

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Page 1: TUTORIAL 3 - Stress-Strain Energy n Castigliano Theorem-2-Solution

FAKULTI KEJURUTERAAN MEKANIKALUNIVERSITI TEKNIKAL MALAYSIA MELAKA

TUTORIAL 3SOLID MECHANICS 2 (BMCS 2333)

SEMESTER 1 SESSI 2007/2008Stress-Strain Energy & Castigliano’s Theorem - Solution

1. Using P, L, E and I, determine the strain energy due to bending for the beam and loading shown in Figure 1. Ignore the effect due to shear stress.

()

SolutionCD portion:

BC portion:

AB portion:

2. The aluminum rod AB (G=26 GPa) is bonded to the brass rod BD (G=39 GPa) shown in Figure 2. Knowing that portion CD of the brass rod is hollow and has an inner diameter of 40 mm, determine the total strain energy of the two rods.

()

Solution,

AB portion:

BC portion:

CD portion:

3. A simply supported beam, AB shown in Figure 3 is subjected to a concentrated load, F at midspan and an uniform distributed load, w N/m. Determine the expression for the elastic strain energy, U due to bending in term of flextural rigidity EI, length L, concentrated load F and uniform distributed load, w.

()

Solution

Figure 1

Figure 3

A BC

D

250mm375mm

400mm

36mm

60mm

Figure 2

TA= 800 Nm

AB

3L

CD

LL

P P

1x1xM

2x2xM

3x3xM

A B

L

w N/mF

x

xM

Page 2: TUTORIAL 3 - Stress-Strain Energy n Castigliano Theorem-2-Solution

4. A pin-joined system of three bars, each having the same cross section A, is loaded as shown in the Figure 4. Determine and of joint B due to applied force P.

()

Solution, ..(1)

, …(2)Solve both equations,

, ,

,

,

5. A planar bent bar of constant EI has the dimensions shown in the Figure 5. Determine and , at the tip due to the application of force P.

()

SolutionPortion 1; ,

,

Portion 2; ,

,

Portion 3; ,

,

Figure 4

Figure 5

60

30 PL

A

B

C

Q

3x3xM

1x1xM

a a a

a/2

a/2

P

5x5xM

2x2xM

4x4xM

Q

M

Page 3: TUTORIAL 3 - Stress-Strain Energy n Castigliano Theorem-2-Solution

FAKULTI KEJURUTERAAN MEKANIKALUNIVERSITI TEKNIKAL MALAYSIA MELAKA

TUTORIAL 3SOLID MECHANICS 2 (BMCS 2333)

SEMESTER 1 SESSI 2007/2008Stress-Strain Energy & Castigliano’s Theorem - Solution

Portion 4; ,

,

Portion 5; ,

,

6. For the prismatic beam shown in Figure 6, determine deflection at point D.

()

Solution

,

,

Portion EB;

,

Portion DE;

Portion AD;

Figure 6

A B

2L

w

2L

2L

D E

Q

1x1xM2x

2xM3x

3xM

M

Page 4: TUTORIAL 3 - Stress-Strain Energy n Castigliano Theorem-2-Solution