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Tues, 3/5 SWBAT… solve absolute value equations Agenda 1. WU (5 min) 2. Binder check (10 min) 3. 5 Examples: absolute value equations (25 min) Warm-Up: 1. Place your test corrections and get ready for the next unit on your desk. 2. Take out your binder. 3. Set-up notes. Topic = “Solving Absolute Value Equations.” HW#1: Absolute value equations

# Tues, 3/5 SWBAT… solve absolute value equations Agenda 1. WU (5 min) 2. Binder check (10 min) 3. 5 Examples: absolute value equations (25 min) Warm-Up:

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Tues, 3/5

SWBAT… solve absolute value equationsAgenda

1. WU (5 min)

2. Binder check (10 min)

3. 5 Examples: absolute value equations (25 min)

Warm-Up:

3. Set-up notes. Topic = “Solving Absolute Value Equations.”

HW#1: Absolute value equations

New unit on Absolute Value & Inequalities(3 weeks) Daily HW, WU, exit slips, weekly quizzes

SWBAT…1. Solve absolute value equations.2. Solve and graph one-step inequalities involving addition,

subtraction, multiplication, and division.3. Solve and graph multi-step inequalities.4. Write inequalities in interval notation.5. Solve and graph compound inequalities.6. Graph inequalities with two variables.7. Graph system of inequalities.

Unit test on Friday, March 22 (before Spring Break)

Solving Absolute Value Equations

You walk directly east from your house one block. How far from your house are you?

1 block1 block

You walk directly west from your house one block. How far from your house are you?

It didn't matter which direction you walked, you were still 1 block from your house.

This is like absolute value. It is the distance from zero. It doesn't matter whether we are in the positive direction or the negative direction, we just care about how far away we are.

2 -7 -6 -5 -4 -3 -2 -1 1 5 7 3 0 4 6 8

44 4 units away from 044 4 units away from 0

Using Absolute Value in Real LifeUsing Absolute Value in Real LifeThe graph shows the position of a diver relative to sea level. Use absolute value to find the diver’s distance from the surface.

Definition of Absolute Value

The distance from any number to zero on the number line.

The value is always positive. Why?Because absolute value is a distance and

distance is always positive.

Ex. #1

|x| = 6x = 6 or x = -6

Check: |x | = 6 or |x| = 6 | 6 | = 6 | -6 | = 6 6 = 6 6 = 6

To solve an absolute value equation:1. Isolate the absolute value on one side of the equal

sign.2. Case 1: Set the inside of the absolute value equal to

a positive of the other given expression. Solve.3. Case 2 : Set the inside the absolute value equal to

the negative of the other given expression. Solve.

4. Check both solutions.

6x What we are after here are values of x such that they are 6 away from 0.

2 -7 -6 -5 -4 -3 -2 -1 1 5 7 3 0 4 6 8

6 and -6 are both 6 units away from 0

6or 6 xx

Ex. #2

|x + 3| = 7

x + 3 = 7 or x + 3 = -7 Subtract 3 from both sides x = 4 or x = -10

Check: |x + 3| = 7 or |x + 3| = 7 | 4 + 3| = 7 | -10 + 3| = 7 |7| = 7 |-7| = 7

7 = 7 7 = 7

To solve an absolute value equation:1. Isolate the absolute value on one side of the equal

sign.2. Case 1: Set the inside of the absolute value equal to

a positive of the other given expression. Solve.3. Case 2 : Set the inside the absolute value equal to

the negative of the other given expression. Solve.

4. Check both solutions.

Ex. #3

|15 – 3x| = 6

15 – 3x = 6 or 15 – 3x = -6 . -3x = -9 -3x = -21 Subtract 15 from both sides.

x = 3 or x = 7 Divide both sides by –3.

Check: |15 – 3x| = 6 |15 – 3x| = 6

|15 – 3(3)| = 6 |15 – 3(7)| = 6 |6| = 6 |–6| = 6 6 = 6 6 = 6

Ex. #4

| x | – 6 = -3 | x | = 3 Add 6 to both sides

x = 3 or x = -3 Check: |x | - 6 = -3 or |x| - 6 = -3 | 3 | = 3 | -3 | = 3 3 = 3 3 = 3

Ex. #5

│-3c│ – 10 = -4 │-3c│ = 6 Add 10 to both sides

-3c = 6 or -3c = -6 Divide both sides by -3

c = -2 or c = 2

Ex. #6

2| x | = -10

| x | = -5

No Solution

Absolute Value and No Solutions

Absolute value is always positive (or zero).  An equation such as │x │= -5 or │x – 4│= -6  is never true.

It has NO Solution.

│x │= -5 has no solution

And this is negativeThis is a distance

Ever heard of a negative distance?

Solve:

1.) │2x + 4│ = 12

2.) 3│x│= 6

3.) │2x + 4│ – 12 = -12

│2x + 4│ = -12

Solve for c and check:

│3c│ – 45 = -18

Exit Slip