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Particle Accelerator Engineering, Spring 2021
Transmission Line Theory
Spring, 2021
Kyoung-Jae Chung
Department of Nuclear Engineering
Seoul National University
2 Particle Accelerator Engineering, Spring 2021
Introduction
β« Transmission line: a bridge between circuit theory and electromagnetic theory.
β« By modeling transmission lines in the form of equivalent circuits, we can use
Kirchhoffβs voltage and current laws to develop wave equations whose solutions
provide an understanding of wave propagation, standing waves, and power
transfer.
β« Fundamentally, a transmission line is a two-port network, with each port
consisting of two terminals. One of the ports, the lineβs sending end, is
connected to a source (also called the generator). The other port, the lineβs
receiving end, is connected to a load.
3 Particle Accelerator Engineering, Spring 2021
Role of wavelength
β« Is the pair of wires between terminals AAβ and and terminals BBβ a transmission
line? If so, under what set of circumstances should we explicitly treat the pair of
wires as a transmission line, as opposed to ignoring their presence?
β’ The factors that determine whether or not we should treat the wires as a
transmission line are governed by the length of the line π and the frequency
π of the signal provided by the generator.
β’ When π/π is very small, transmission-line effects may be ignored, but when Ξ€π π β³ 0.01, it may be necessary to account not only for the phase shift due
to the time delay, but also for the presence of reflected signals that may
have been bounced back by the load toward the generator.
4 Particle Accelerator Engineering, Spring 2021
Example
β« Assume that π = ππ sin 2πππ‘ with π = 1 kHz when A is closed. The
corresponding wavelength is 300 km and is comparable to the distance between
A and B. This voltage signal will not appear instantaneously at point B, as a
certain time is required for the signal to travel from points A to B. β transmission
line
60 km 0.6 m
β« How about B-C? Because the distance between B and C is small, the voltage at
point B will appear almost instantaneously at point C. β electric circuit
β« What if the frequency is increased to 100 MHz?
5 Particle Accelerator Engineering, Spring 2021
Transmission line vs. electric circuit
β« Generally, when the wavelength of the applied
voltage is comparable to or shorter than the
length of the conductors, the conductors must be
treated as a transmission line.
β« A single pulse is composed of an infinite number
of Fourier components with the amplitudes of the
spectrum decreasing for higher frequencies.
π =πΎ
π‘π
where, π‘π is the rise time of the pulse and πΎ is a constant
between 0.35 and 0.45 depending on the shape of the pulse.
β« In pulsed power, the conductors must be treated as transmission line, because
the equivalent wavelength of the pulse in most cases is comparable to the length
of the conductors.
β« Empirical formula to estimate the upper-frequency π of the pulse:
6 Particle Accelerator Engineering, Spring 2021
Dispersive effects
β« A dispersive transmission line is one on which the wave velocity is not constant
as a function of the frequency π.
7 Particle Accelerator Engineering, Spring 2021
Transverse electromagnetic (TEM) and higher-order
transmission lines
8 Particle Accelerator Engineering, Spring 2021
Lumped-element model
β« A transmission line can be represented by a parallel wire configuration,
regardless of its specific shape or constitutive parameters.
β« To obtain equations relating voltages and currents, the line is subdivided into
small differential sections.
9 Particle Accelerator Engineering, Spring 2021
Transmission parameters
10 Particle Accelerator Engineering, Spring 2021
Coaxial transmission line
π β² =π π 2π
1
π+1
πwhere π π =
ππππππ
Surface resistance
β« For all TEM lines,
πΏβ²πΆβ² = πππΊβ²
πΆβ² =π
π
11 Particle Accelerator Engineering, Spring 2021
Transmission line equation
β« Equivalent circuit of a two-conductor transmission line of differential length βπ§.
β« Kirchhoffβs voltage law
β« Kirchhoffβs current law
π£ π§, π‘ β π β²βπ§ π π§, π‘ β πΏβ²βπ§ππ π§, π‘
ππ‘β π£ π§ + βπ§, π‘ = 0
π π§, π‘ β πΊβ²βπ§ π£ π§ + βπ§, π‘ β πΆβ²βπ§ππ£ π§ + βπ§, π‘
ππ‘β π π§ + βπ§, π‘ = 0
12 Particle Accelerator Engineering, Spring 2021
Transmission line equation
β« By rearranging KVL and KCL equations, we obtain two first-order differential
equations known as telegrapherβs equations.
β« Telegrapherβs equation in phasor form
βππ£ π§, π‘
ππ§= π β² π π§, π‘ + πΏβ²
ππ π§, π‘
ππ‘
βππ π§, π‘
ππ§= πΊβ² π£ π§, π‘ + πΆβ²
ππ£ π§, π‘
ππ‘
β« Phasor notation for sinusoidal signals
π£ π§, π‘ = π π[ ΰ·¨π π§ ππππ‘] π π§, π‘ = π π[ απΌ π§ ππππ‘]
βπ ΰ·¨π π§
ππ§= π β² + πππΏβ² απΌ π§
βπ απΌ π§
ππ§= πΊβ² + πππΆβ² ΰ·¨π π§
13 Particle Accelerator Engineering, Spring 2021
Wave propagation on a transmission line
β« The two first-order coupled equations can be combined to give two second-order
uncoupled wave equations, one for ΰ·¨π(π§) and another for απΌ(π§).
π2 ΰ·¨π π§
ππ§2β πΎ2 ΰ·¨π π§ = 0
π2 απΌ π§
ππ§2β πΎ2 απΌ π§ = 0
where πΎ = (π β² + πππΏβ²)(πΊβ² + πππΆβ²)
Propagation constant
β« Complex propagation constant πΎ consists of a real part πΌ, called the attenuation
constant of the line with units of Np/m, and an imaginary part π½, called the phase
constant of the line with units of rad/m.Neper unit: LNp = ln(x1/x2)
1 Np = 20log10e dB ~ 8.686 dBπΎ = πΌ + ππ½
β« The wave equations have traveling wave solutions of the following form:
ΰ·¨π π§ = π0+πβπΎπ§ + π0
βπ+πΎπ§
απΌ π§ = πΌ0+πβπΎπ§ + πΌ0
βπ+πΎπ§
14 Particle Accelerator Engineering, Spring 2021
Wave propagation on a transmission line
β« The voltage-current relationship
whereπ0+
πΌ0+ = π0 = β
π0β
πΌ0β
απΌ π§ = πΌ0+πβπΎπ§ + πΌ0
βπ+πΎπ§ = β1
π β² + πππΏβ²π ΰ·¨π π§
ππ§=
πΎ
π β² + πππΏβ²[π0
+πβπΎπ§ β π0βπ+πΎπ§]
=π0+
π0πβπΎπ§ β
π0β
π0π+πΎπ§
β« Characteristic impedance of the line
Characteristic impedance
π0 =π β² + πππΏβ²
πΎ=
π β² + πππΏβ²
πΊβ² + πππΆβ²Unit: Ohm
β« It should be noted that π0 is equal to the ratio of the voltage amplitude to the
current amplitude for each of the traveling waves individually (with an additional
minus sign in the case of the βπ§ propagating wave), but it is not equal to the
ratio of the total voltage ΰ·¨π π§ to the total current απΌ π§ , unless one of the two
waves is absent.
15 Particle Accelerator Engineering, Spring 2021
Lossless transmission line
β« In many practical situations, the transmission line can be designed to exhibit low
ohmic losses by selecting conductors with very high conductivities (π β² β 0) and
dielectric materials with negligible conductivities (πΊβ² β 0).
β« Propagation constant for lossless line
πΎ = πΌ + ππ½ β πππΏβ² πππΆβ² = ππ πΏβ²πΆβ² πΌ = 0, π½ = π πΏβ²πΆβ²
β« Characteristic impedance of lossless line
π0 βπππΏβ²
πππΆβ² =πΏβ²
πΆβ²
β« Guide wavelength
π =2π
π½=
2π
π πΏβ²πΆβ²=
2π
π ππβ
1
π π0πππ0=π
π
1
ππ=
π0ππ
β« Phase velocity
π’π =π
π½=
1
πΏβ²πΆβ²=
1
ππβ
1
π0πππ0=
1
π0π0
1
ππ=
π
ππindependent on frequency
(nondispersive)
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Characteristic parameters of transmission lines
17 Particle Accelerator Engineering, Spring 2021
Voltage reflection coefficient
β« The load impedance
ΰ·¨π π§ = π0+πβππ½π§ + π0
βπ+ππ½π§
απΌ π§ =π0+
π0πβππ½π§ β
π0β
π0π+ππ½π§
β« With πΎ = ππ½ for the lossless line, the total voltage and current become
ππΏ =ΰ·¨ππΏαπΌπΏ=
π0+ + π0
β
π0+ β π0
β π0
β« At the load (π§ = 0)
ΰ·¨ππΏ = ΰ·¨π π§ = 0 = π0+ + π0
β
απΌπΏ = απΌ π§ = 0 =π0+
π0βπ0β
π0
π§πΏ = Ξ€ππΏ π0
β« Voltage reflection coefficient
Ξ =π0β
π0+ =
ππΏ β π0ππΏ + π0
=π§πΏ β 1
π§πΏ + 1
π0β =
ππΏ β π0ππΏ + π0
π0+
Normalized load impedance
Ξ = βπΌ0β
πΌ0+
18 Particle Accelerator Engineering, Spring 2021
Voltage reflection coefficient
Ξ = Ξ ππππ
β« π0 of a lossless line is a real number, but ππΏ is in general a complex quantity.
Hence, in general Ξ also is complex and given by
β« Matched load (ππΏ = π0) β Ξ = 0 and π0β = 0
β« Open load (ππΏ = β) β Ξ = 1 and π0β = π0
+
β« Short load (ππΏ = 0) β Ξ = β1 and π0β = βπ0
+
Ξ =π0β
π0+ =
ππΏ β π0ππΏ + π0
=π§πΏ β 1
π§πΏ + 1
19 Particle Accelerator Engineering, Spring 2021
Standing waves
20 Particle Accelerator Engineering, Spring 2021
Voltage standing-wave patterns
β« Matched load (ππΏ = π0) β Ξ = 0
β« Open load (ππΏ = β) β Ξ = 1
β« Short load (ππΏ = 0) β Ξ = β1
21 Particle Accelerator Engineering, Spring 2021
Standing waves
β« Open load (ππΏ = β)
β Ξ = 1
β« Short load (ππΏ = 0)
β Ξ = β1
22 Particle Accelerator Engineering, Spring 2021
Standing waves
β« π0 > ππΏ
β β1 < Ξ < 0
β« π0 < ππΏ
β 0 < Ξ < 1
23 Particle Accelerator Engineering, Spring 2021
Standing waves
β« RL load
β« RC load
24 Particle Accelerator Engineering, Spring 2021
Standing waves
ΰ·¨π π§ = π0+(πβππ½π§ + Ξπ+ππ½π§)
απΌ π§ =π0+
π0(πβππ½π§ β Ξπ+ππ½π§)
β« Using π0β = Ξπ0
+, the total voltage and current become
β« Replacing π§ with β π, Magnitude of ΰ·¨π π and απΌ π
ΰ·¨π π = π0+ 1 + Ξ 2 + 2 Ξ cos(2π½π β ππ)
1/2
απΌ π =π0+
π01 + Ξ 2 β 2 Ξ cos(2π½π β ππ)
1/2
β« The sinusoidal patterns are called standing
waves and are caused by the interference of the
two traveling waves.
β’ Maximum values when 2π½π β ππ = 2ππ
β’ Minimum values when 2π½π β ππ = (2π + 1)π
β« With no reflected wave present, there are no
interference and no standing waves.
Only one unknown
π0+
25 Particle Accelerator Engineering, Spring 2021
Voltage standing wave ratio (VSWR)
β« Maximum and minimum values of ΰ·¨π
β’ ΰ·¨ππππ₯
= ΰ·¨π(ππππ₯) = π0+ [1 + Ξ ] at 2π½ππππ₯ β ππ = 2ππ
β’ ΰ·¨ππππ
= ΰ·¨π(ππππ) = π0+ [1 β Ξ ] at 2π½ππππ β ππ = (2π + 1)π
β« Voltage standing wave ratio (VSWR)
π =ΰ·¨ππππ₯
ΰ·¨ππππ
=1 + Ξ
1 β Ξ
β’ A measure of the mismatch between the load and the transmission line.
β’ For a matched load with Ξ = 0, π = 1, and for a line with Ξ = 1, π = β.
β« Measuring ππΏ using slotted-line probe
π =1 + Ξ
1 β ΞΞ =
ππΏ β π0ππΏ + π0
KnownMeasure
26 Particle Accelerator Engineering, Spring 2021
Wave impedance of lossless lines
β« Since the voltage and current magnitudes are oscillatory with position along the
line and in phase opposition with each other, the wave impedance π(π) must
vary with position also.
π π =ΰ·¨π π
απΌ π=π0+(π+ππ½π + Ξπβππ½π)
π0+(π+ππ½π β Ξπβππ½π)
π0 = π01 + Ξπβπ2π½π
1 β Ξπβπ2π½π= π0
1 + Ξπ1 β Ξπ
β« π(π) is the ratio of the total voltage (incident and reflected-wave voltages) to the
total current at any point π on the line, in contrast with the characteristic
impedance of the line π0, which relates the voltage and current of each of the
two waves individually (π0 = π0+/πΌ0
+ = βπ0β/πΌ0
β).
β« Phase-shifted voltage reflection coefficient
Ξπ = Ξπβπ2π½π = Ξ πππππβπ2π½π = Ξ ππ(ππβ2π½π)
β’ Ξπ has the same magnitude as Ξ, but its phase is shifted by 2π½πrelative to that of Ξ.
27 Particle Accelerator Engineering, Spring 2021
Input impedance
β« In the actual circuit (a), at terminals π΅π΅β² at an arbitrary location π on the line,
π(π) is the wave impedance of the line when βlookingβ to the right (i.e., towards
the load). Application of the equivalence principle allows us to replace the
segment to the right of terminals π΅π΅β² with a lumped impedance of value π(π).
28 Particle Accelerator Engineering, Spring 2021
Input impedance
β« Of particular interest in many transmission-line problems is the input impedance
at the source end of the line, at π = π, which is given by
πππ = π π = π01 + Ξπ1 β Ξπ
Ξ =ππΏ β π0ππΏ + π0
Where, Ξπ = Ξπβπ2π½π = Ξ ππ(ππβ2π½π)
β« Using
β« We obtain the input impedance
πππ = π0ππΏ + ππ0 tan π½π
π0 + πππΏ tan π½π
ΰ·¨ππ = απΌππππ =πππ
ππ + πππΰ·¨ππ = ΰ·¨π(βπ)
β« Final solution is
π0+ =
πππππ + πππ
ΰ·¨ππ1
πππ½π + Ξπβππ½π
29 Particle Accelerator Engineering, Spring 2021
Input impedance vs. line length
πππ = π0ππΏ + ππ0 tan π½π
π0 + πππΏ tan π½π
30 Particle Accelerator Engineering, Spring 2021
Short-circuited line
β« Since ππΏ = 0, the input impedance is
ππππ π = π0
ππΏ + ππ0 tanπ½π
π0 + πππΏ tanπ½π= ππ0 tanπ½π
Purely reactive
β« If tan π½π β₯ 0, the line appears inductive to the
source, acting like an equivalent inductor πΏππ
πΏππ =π0 tan π½π
π
β« If tan π½π β€ 0, the input impedance is capacitive, in
which case the line acts like an equivalent
capacitor with capacitance πΆππ
πΆππ = β1
ππ0 tanπ½π
β’ Through proper choice of the length of a short-
circuited line, we can make them into equivalent
capacitors and inductors of any desired reactance.
31 Particle Accelerator Engineering, Spring 2021
Open-circuited line
β« Since ππΏ = β, the input impedance of an open-
circuited line is
πππππ = π0
ππΏ + ππ0 tanπ½π
π0 + πππΏ tanπ½π= βππ0 cot π½π
β« A network analyzer is a radio-frequency (RF)
instrument capable of measuring the impedance
of any load connected to its input terminal.
β« The combination of the two measurements (ππππ π
and πππππ) can be used to determine the
characteristic impedance of the line π0 and its
phase constant π½.
π0 = ππππ ππππ
ππ
tanπ½π = βππππ π
πππππ
32 Particle Accelerator Engineering, Spring 2021
Quarter-wavelength (π/π) transformer
β« If π = ππ/2, where π is an integer, tanπ½π = 0. Then,
πππ = π0ππΏ + ππ0 tan π½π
π0 + πππΏ tan π½π= ππΏ
β’ A half-wavelength line does not modify
the load impedance.
β« If π = Ξ€ππ 2 + Ξ€π 4, where π is 0 or a positive integer, tanπ½π = β. Then,
πππ = π0ππΏ + ππ0 tan π½π
π0 + πππΏ tan π½π=π02
ππΏ
β« Ξ€π 4 transformer (example)
πππ =π022
ππΏ= π01
π02 = π01ππΏ = 70.7 Ξ©
33 Particle Accelerator Engineering, Spring 2021
Properties of standing waves on a lossless transmission
line
34 Particle Accelerator Engineering, Spring 2021
[Optional] Smith chart
β« The Smith chart, developed by P. H. Smith in 1939, is a widely used graphical
tool for analyzing and designing transmission line circuits.
β« Reflection coefficient and normalized load impedance
Ξ = Ξ ππππ = Ξπ + πΞπ
Ξ =Ξ€ππΏ π0 β 1
Ξ€ππΏ π0 + 1=π§πΏ β 1
π§πΏ + 1
π§πΏ =1 + Ξ
1 β Ξ= ππΏ + ππ₯πΏ =
(1 + Ξπ) + πΞπ(1 β Ξπ) β πΞπ
Normalized load resistance
Normalized load reactance
ππΏ =1 β Ξπ
2 β Ξπ2
1 β Ξπ2 + Ξπ
2
π₯πΏ =2Ξπ
1 β Ξπ2 + Ξπ
2
There are many combinations of (Ξπ , Ξπ) that yield
the same value for the normalized load resistance.
Smith chart: graphical evaluation of (ππΏ, π₯πΏ) in the
Ξπ β Ξπ plane
35 Particle Accelerator Engineering, Spring 2021
Smith chart
β« Parametric equation for the circle in the Ξπ β Ξπ plane corresponding to given
values of ππΏ and π₯πΏ.
Ξπ βππΏ
1 + ππΏ
2
+ Ξπ2 =
1
1 + ππΏ
2
Ξπ β 1 2 + Ξπ β1
π₯πΏ
2
=1
π₯πΏ
2
36 Particle Accelerator Engineering, Spring 2021
Wave impedance
β« The normalized wave impedance looking toward the load at a distance π from
the load is
π§ π =π(π)
π0=1 + Ξπ1 β Ξπ
Ξπ = Ξπβπ2π½π = Ξ πππππβπ2π½π = Ξ ππ(ππβ2π½π)
(Phase-shifted voltage reflection coefficient)
β« The transformation from Ξ to Ξπ is achieved by maintaining Ξ constant and
decreasing its phase ππ by 2π½π, which corresponds to a clockwise rotation (on
the Smith chart) over an angle of 2π½π radians.
WTG scale
WTL scale
β« A complete rotation around the Smith chart
2π½π = 2π π =π
2
37 Particle Accelerator Engineering, Spring 2021
Wave impedance
β« Constant- Ξ circle or constant-SWR circle
π =ΰ·¨ππππ₯
ΰ·¨ππππ
=1 + Ξ
1 β Ξ
β« If a line is of length π, its input impedance is πππ = π0π§(π), with π§(π) determined by
rotating a distance π from the load along the WTG scale.
38 Particle Accelerator Engineering, Spring 2021
Impedance to admittance transformation
β« In solving certain types of transmission-line problems, it is often more convenient
to work with admittances than with impedances.
β« Impedance
π = π + ππ
β« Admittance
Resistance
Reactance
Conductance
Susceptance
π =1
π=
1
π + ππ=
π
π 2 + π2 + πβπ
π 2 + π2 = πΊ + ππ΅
β« Normalized admittance
π¦ =π
π0=
πΊ
π0+ π
π΅
π0= π + ππ
39 Particle Accelerator Engineering, Spring 2021
Impedance matching
β« Impedance-matching network: It eliminates reflections at terminals ππβ for
waves incident from the source. Even though multiple reflections may occur
between π΄π΄β and ππβ, only a forward traveling wave exists on the feedline.
β« Matching networks may consist of lumped elements or of sections of
transmission lines with appropriate lengths and terminations.
πππ = ππ + ππ = πΊπ + ππ΅π + ππ΅π = πΊπ + π π΅π + π΅π = π0 πΊπ = π0 π΅π = βπ΅π
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Various types of impedance matching
41 Particle Accelerator Engineering, Spring 2021
Matching network in RF inductive discharges
β« The admittance looking to the right at the terminals π΄βπ΄β² is
ππ΄ = πΊπ΄ + ππ΅π΄ =1
π π + π(π1 + ππ )πΊπ΄ =
π π
π π 2 + π1 + ππ
2
π΅π΄ = βπ1 + ππ
π π 2 + π1 + ππ
2
Conductance
Susceptance
β« Determine the values of πΆ1 and πΆ2
πΊπ΄ =1
π ππ΅2 = ππΆ2 = βπ΅π΄
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Transients on transmission lines
β« The transient response of a voltage pulse on a transmission line is a time record
of its back and forth travel between the sending and receiving ends of the line,
taking into account all the multiple reflections (echoes) at both ends.
β« A single rectangular pulse can be described mathematically as the sum of two
unit step functions:
π π‘ = π1 π‘ + π2 π‘ = π0π’ π‘ β π0π’(π‘ β π)
β« Hence, if we can develop basic tools for describing the transient behavior of a
single step function, we can apply the same tools for each of the two
components of the pulse and then add the results to obtain the response to π(π‘).
43 Particle Accelerator Engineering, Spring 2021
Transient response to a step function
β« The switch between the generator circuit and the transmission line is closed at
π‘ = 0. The instant the switch is closed, the transmission line appears to the
generator circuit as a load with impedance π0. This is because, in the absence of
a signal on the line, the input impedance of the line is unaffected by the load
impedance π πΏ.
πΌ1+ =
ππ
π π + π0
β« The initial condition:
π1+ = πΌ1
+π0 =π0ππ
π π + π0
β’ The combination of π1+ and πΌ1
+
constitutes a wave that travels along the
line with velocity π’π = 1/ ππ ,
immediately after the switch is closed.
44 Particle Accelerator Engineering, Spring 2021
Reflections at both ends
β« At π‘ = π, the wave reaches the load at π§ = π, and because π πΏ β π0, the
mismatch generates a reflected wave with amplitude
π1β = ΞπΏπ1
+ where ΞπΏ =π πΏ β π0π πΏ + π0
β« After this first reflection, the voltage on the line consists of the sum of two waves:
the initial wave π1+ and the reflected wave π1
β.
β« At π‘ = 2π, the reflected wave π1β arrives at the sending end of the line. If π π β π0,
the mismatch at the sending end generates a reflection at π§ = 0 in the form of a
wave with voltage amplitude π2+ given by
π2+ = Ξππ1
β = ΞπΞπΏπ1+ where Ξπ =
π π β π0
π π + π0
β« The multiple-reflection process continues indefinitely, and the ultimate value that
π(π§, π‘) reaches as π‘ approaches +β is the same at all locations on the
transmission line (steady-state voltage).
πβ = π1+ + π1
β + π2+ + π2
β + π3+ + π3
β +β― = π1+ 1 + ΞπΏ + ΞπΏΞπ + ΞπΏ
2Ξπ + ΞπΏ2Ξπ
2 + ΞπΏ3Ξπ
2 +β―
πβ = π1+ 1 + ΞπΏ 1 + ΞπΏΞπ + ΞπΏ
2Ξπ2 +β― = π1
+1 + ΞπΏ1 β ΞπΏΞπ
=π πΏ
π π + π πΏππ
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Reflections at both ends: example
β« π π = 4π0 and π πΏ = 2π0
ΞπΏ =π πΏ β π0π πΏ + π0
=1
3Ξπ =
π π β π0
π π + π0=3
5
46 Particle Accelerator Engineering, Spring 2021
Bounce diagram
47 Particle Accelerator Engineering, Spring 2021
Pulse propagation
β« Q. The transmission-line circuit of Fig. (a) is
excited by a rectangular pulse of duration π =1 ππ that starts at π‘ = 0. Establish the
waveform of the voltage response at the load,
given that the pulse amplitude is 5 V, the phase
velocity is π, and the length of the line is 0.6 m.
β« Solutionπ =
π
π= 2 ππ
ΞπΏ =150 β 50
150 + 50= 0.5 Ξπ =
12.5 β 50
12.5 + 50= β0.6
π1+ =
π0π01π π + π0
=50 Γ 5
12.5 + 50= 4
48 Particle Accelerator Engineering, Spring 2021
Time-domain reflectometer (TDR)
β« Q. If the voltage waveform shown in Fig. (a) is seen on an oscilloscope
connected to the input of a 75 Ξ© matched transmission line, determine (a) the
generator voltage, (b) the location of the fault, and (c) the fault shunt resistance.
The lineβs insulating material is Teflon with ππ = 2.1.
β« Solution (a)
π1+ =
π0ππ
π π + π0=ππ
2ππ = 2π1
+ = 12 π
β« Solution (b)
βπ‘ =2π
π’π=
2π
Ξ€π ππ= 12 ππ π = 1,242 π
β« Solution (c)
π1β = Ξππ1
+ = β3 π Ξπ = β0.5
Ξπ =π πΏπ β π0
π πΏπ + π0π πΏπ = 25 Ξ©
1
π πΏπ=
1
π π+
1
π0π π = 37.5 Ξ©
49 Particle Accelerator Engineering, Spring 2021
Homework
β« A 300 Ξ© feedline is to be connected to a 3 m long, 150 Ξ© line terminated in a 150
Ξ© resistor. Both lines are lossless and use air as the insulating material, and the
operating frequency is 50 MHz. Determine (a) the input impedance of the 3 m
long line, (b) the voltage standing-wave ratio on the feedline, and (c) the
characteristic impedance of a quarter-wave transformer were it to be used
between the two lines in order to achieve π = 1 on the feedline.
β« In response to a step voltage, the voltage waveform shown in the following figure
was observed at the sending end of a lossless transmission line with π π = 50 Ξ©,
π0 = 50 Ξ©, and ππ = 2.25. Determine the following:
(a) The generator voltage.
(b) The length of the line.
(c) The load impedance.