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    Transpose is a function from Rm;n to Rn;m. If A 2 Rm;n; At 2 Rn;m is the matrixwhose (i; j) term is the (j; i) term of A. So row i (column i) of A becomes columni (row i) of At: If A is an n-dimensional row vector, then At is an n-dimensional

    column vector. If A is a square matrix, At is also square.Theorem 1) (At)t = A2) (A + B)t = At + Bt3) If c 2 R; (Ac)t = Atc4) (AB)t = BtAt5) If A 2 Rn, then A is invertible i At is invertible.In this case (A 1)t = (At) 1.Proof of 5) Suppose A is invertible. Then I = It = (AA 1)t = (A 1)tAt.Exercise Characterize those invertible matrices A 2 R2 which have A 1 = At.Show that they form a subgroup of GL2(R).Triangular Matrices

    If A 2 Rn, then A is upper (lower) triangular provided ai;j = 0 for all i > j (allj > i). A is strictly upper (lower) triangular provided ai;j = 0 for all i j (all j i).A is diagonal if it is upper and lower triangular, i.e., ai;j = 0 for all i 6= j: Notethat if A is upper (lower) triangular, then At is lower (upper) triangular.Theorem If A 2 Rn is strictly upper (or lower) triangular, then An = 0.Proof The way to understand this is just multiply it out for n = 2 and n = 3:The geometry of this theorem will become transparent later in Chapter 5 whenthematrix A denes an R-module endomorphism on Rn (see page 93).Denition If T is any ring, an element t 2 T is said to be nilpotent provided 9n

    such that tn = 0. In this case, (1 t) is a unit with inverse 1 + t + t2 + + tn 1.

    Transpose is a function from Rm;n to Rn;m. If A 2 Rm;n; At 2 Rn;m is the matrixwhose (i; j) term is the (j; i) term of A. So row i (column i) of A becomes columni (row i) of At: If A is an n-dimensional row vector, then At is an n-dimensionalcolumn vector. If A is a square matrix, At is also square.Theorem 1) (At)t = A2) (A + B)t = At + Bt3) If c 2 R; (Ac)t = Atc

    4) (AB)t = BtAt5) If A 2 Rn, then A is invertible i At is invertible.In this case (A 1)t = (At) 1.Proof of 5) Suppose A is invertible. Then I = It = (AA 1)t = (A 1)tAt.Exercise Characterize those invertible matrices A 2 R2 which have A 1 = At.Show that they form a subgroup of GL2(R).Triangular MatricesIf A 2 Rn, then A is upper (lower) triangular provided ai;j = 0 for all i > j (allj > i). A is strictly upper (lower) triangular provided ai;j = 0 for all i j (all j i).A is diagonal if it is upper and lower triangular, i.e., ai;j = 0 for all i 6= j: Notethat if A is upper (lower) triangular, then At is lower (upper) triangular.Theorem If A 2 Rn is strictly upper (or lower) triangular, then An = 0.Proof The way to understand this is just multiply it out for n = 2 and n = 3:The geometry of this theorem will become transparent later in Chapter 5 when

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    thematrix A denes an R-module endomorphism on Rn (see page 93).Denition If T is any ring, an element t 2 T is said to be nilpotent provided 9nsuch that tn = 0. In this case, (1 t) is a unit with inverse 1 + t + t2 + + tn 1.

    Transpose is a function from Rm;nto Rn;m. If A 2 Rm;n; At 2 Rn;m is thematrixwhose (i; j) term is the (j; i) term of A.So row i (column i) of A becomescolumni (row i) of At: If A is an n-dimensionalrow vector, then At is an n-dimensionalcolumn vector. If A is a square matrix,At is also square.Theorem 1) (At)t = A2) (A + B)t = At + Bt3) If c 2 R; (Ac)t = Atc4) (AB)t = BtAt5) If A 2 Rn, then A is invertible i At isinvertible.In this case (A 1)t = (At) 1.Proof of 5) Suppose A is invertible.Then I = It = (AA 1)t = (A 1)tAt.Exercise Characterize those invertible

    matrices A 2 R2 which have A 1 = At.Show that they form a subgroup ofGL2(R).Triangular MatricesIf A 2 Rn, then A is upper (lower)triangular provided ai;j = 0 for all i > j(allj > i). A is strictly upper (lower)triangular provided ai;j = 0 for all i j (all ji).A is diagonal if it is upper and lower

    triangular, i.e., ai;j = 0 for all i 6= j:Notethat if A is upper (lower) triangular,then At is lower (upper) triangular.Theorem If A 2 Rn is strictly upper (orlower) triangular, then An = 0.Proof The way to understand this is justmultiply it out for n = 2 and n = 3:The geometry of this theorem willbecome transparent later in Chapter 5when thematrix A denes an R-moduleendomorphism on Rn (see page 93).Denition If T is any ring, an element t 2

    T is said to be nilpotent provided 9nsuch that tn = 0. In this case, (1 t) is aunit with inverse 1 + t + t2 + + tn 1.

    Transpose is a function from Rm;n toRn;m. If A 2 Rm;n; At 2 Rn;m is the matrixwhose (i; j) term is the (j; i) term of A.So row i (column i) of A becomescolumni (row i) of At: If A is an n-dimensionalrow vector, then At is an n-dimensionalcolumn vector. If A is a square matrix,At is also square.Theorem 1) (At)t = A2) (A + B)t = At + Bt3) If c 2 R; (Ac)t = Atc4) (AB)t = BtAt5) If A 2 Rn, then A is invertible i At is

    invertible.In this case (A 1)t = (At) 1.Proof of 5) Suppose A is invertible.Then I = It = (AA 1)t = (A 1)tAt.Exercise Characterize those invertiblematrices A 2 R2 which have A 1 = At.Show that they form a subgroup ofGL2(R).Triangular MatricesIf A 2 Rn, then A is upper (lower)triangular provided ai;j = 0 for all i > j

    (allj > i). A is strictly upper (lower)triangular provided ai;j = 0 for all i j (all ji).A is diagonal if it is upper and lowertriangular, i.e., ai;j = 0 for all i 6= j:Notethat if A is upper (lower) triangular,then At is lower (upper) triangular.Theorem If A 2 Rn is strictly upper (orlower) triangular, then An = 0.Proof The way to understand this is justmultiply it out for n = 2 and n = 3:The geometry of this theorem will

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    become transparent later in Chapter 5when thematrix A denes an R-moduleendomorphism on Rn (see page 93).

    Denition If T is any ring, an element t 2T is said to be nilpotent provided 9nsuch that tn = 0. In this case, (1 t) is aunit with inverse 1 + t + t2 + + tn 1.