Transformando Concreto en Albañilria

8/16/2019 Transformando Concreto en Albañilria

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MURO X3

B=6 x t

B=(6x0.13)=0.78

A Total (axial) = (1.39x0.13)+(2.89x0.13)+ (1.39x0.13)=0.74 m

2

SECCIÓN TRANSFORA!A AREA !E CORTE

A"o#t$=3.1%x0.13=0.41 m2

f =0.74

0.41=1.80

CENTRO DE GRAVEDAD

X Y AREA X/2 ACUM ACG

0.13 1.39 0.1807 0.065 0

0.011745

5

2.89 0.13 0.3757 1.445 0.13

0.591727

5

0.13 1.39 0.1807 0.065 3.02

0.557459

5

0.7371

1.160932

5

Xg= 1.575

I3=

.



MURO X4

B=6 x t

B=(6x0.13)=0.78m

B=2.68/4=0.67m

A Total (axial) = (1.39x0.13)+(2.82x0.13)+ (1.39x0.13)=0.73 m2


A"o#t$=3.08x0.13=0.40 m2

f =0.73

0.40=1.83

CENTRO DE GRAVEDAD


0.13 1.39 0.1807 0.065 0

0.011745

5

2.82 0.13 0.3666 1.41 0.13 0.564564

0.13 0.61 0.0793 0.065 2.95

0.239089

5

0.6266 0.815399

.



Xg=1.30130

705

I=

MURO X6

B=6 x t

B=(6x0.13)=0.78m

B=2.68/4=0.67m

A Total (axial) = (0.&1x0.13)+(2.27x0.13)+ (0.&1x0.13)=0.4% m2


A"o#t$=2.%3x0.13=0.33 m2

f =0.45

0.33

=1.36

CENTRO DE GRAVEDAD


0.13 0.61 0.0793 0.065 0

0.005154

5

2.27 0.13 0.2951 1.135 0.13

0.373301

5

0.13 0.61 0.0793 0.065 2.4

0.195474

5

.



0.4537

0.573930

5

Xg= 1.265

MURO Y1

B=6 x t

B=(6x0.13)=0.78m

B=2.88/4=0.72m

A Total (axial) = (0.78x0.13)+(2.&7x0.13)=0.4% m2


A"o#t$=2.&7x0.13=0.3% m2

f =0.45

0.35=1.29

CENTRO !E 'RAE!A!


.



0.13 2.54 0.3302 0.065 0 0.021463

0.78 0.13 0.1014 0.39 0.13 0.052728

0.4316 0.074191

Xg=0.17189

759

.

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Transformando Concreto en Albañilria