To Do… Electronic homework (Lon-Capa)

HW4 Type 1 due Monday, March 10 by 7 pm; HW4 Type 2 due Wednesday, March 12 by 7 pm

HW5 Type 1 due Monday, March 17 by 7 pm; HW5 Type 2 due Wednesday, March 19 by 7 pm

Exam 2 review: due Wednesday, March 19 by 7pm

Exam #2: Thursday, March 20, 7 pm

Stoichiometry Determine the amount(s) of

reactant(s) or product(s) given amount(s) of reactant(s) or product(s).

We must have a balanced chemical equation.

Reactions occur by numbers of atoms/molecules.

Determine Number of Moles

Use mass and molar masses. Use volume and concentration for

solutions. Use pressure, volume, and

temperature for gases.

Clicker QuestionIf you have 8 moles of hydrogen and all the oxygen you need, how many moles of water can you make?2H2 + O2 → 2H2O

A) 1 molB) 2 molC) 4 molD) 8 molE) 16 mol

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Clicker QuestionIf you have 6 moles of oxygen and all the hydrogen you need, how many moles of water can you make?2H2 + O2 → 2H2O

A) 1 molB) 2 molC) 3 molD) 6 molE) 12 mol

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Clicker QuestionIf you have 8 moles of hydrogen and 6 moles of oxygen, how many moles of water can you make?2H2 + O2 → 2H2O

A) 6 molB) 8 molC) 12 molD) 14 molE) 16 mol

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Starting with Mass…If you have 48.0 g of oxygen gas and all the hydrogen gas you need, what mass of water is produced?

2H2 + O2 → 2H2O7

Solids, Solutions, and Gases

NaHCO3(s) + HC2H3O2(aq) → NaC2H3O2 (aq) + H2O(l) + CO2(g)

Which balloon will be the biggest?

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Trial #

Mass of NaHCO3

Volume of 0.833 M HC2H3O2

1 3.30 g 150.0 mL2 5.70 g 150.0 mL3 10.5 g 150.0 mL4 21.0 g 150.0 mL5 31.8 g 150.0 mL

Solids, Solutions, and Gases

NaHCO3(s) + HC2H3O2(aq) → NaC2H3O2 (aq) + H2O(l) + CO2(g)

Determine the volumes of the balloons.

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Trial #

Mass of NaHCO3

Volume of 0.833 M HC2H3O2

1 3.30 g 150.0 mL2 5.70 g 150.0 mL3 10.5 g 150.0 mL4 21.0 g 150.0 mL5 31.8 g 150.0 mL

Solids, Solutions, and Gases

NaHCO3(s) + HC2H3O2(aq) → NaC2H3O2 (aq) + H2O(l) + CO2(g)

Determine the mass of left-over sodium bicarbonate in Trial #5.

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Trial #

Mass of NaHCO3

Volume of 0.833 M HC2H3O2

1 3.30 g 150.0 mL2 5.70 g 150.0 mL3 10.5 g 150.0 mL4 21.0 g 150.0 mL5 31.8 g 150.0 mL

Solids, Solutions, and Gases

NaHCO3(s) + HC2H3O2(aq) → NaC2H3O2 (aq) + H2O(l) + CO2(g)

Determine the concentration of left-over acetic acid in Trial #1.

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Trial #

Mass of NaHCO3

Volume of 0.833 M HC2H3O2

1 3.30 g 150.0 mL2 5.70 g 150.0 mL3 10.5 g 150.0 mL4 21.0 g 150.0 mL5 31.8 g 150.0 mL