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1. There are 3 people A, B, C having a total share of Rs 3,000. As share is 2/3rd of the sum of

B and Cs shares. Cs share is of the sum of A and Bs shares. What is the value of Cs

share?

Ans: 1000

Explanation: A + B +C = 3000 .(1)

(A+B)+A+B=3000

3A +3B = 6000

A+B=2000 .(2)

Now, substituting the value of equation (2) in equation (1)

A + B + C = 3000

2000 + C =3000

C =1000

2. The total income of Amit in 2003, 2004, 2005 is 364000. Every year there is an increase in

his salary by 20%. What is the salary in 2005?

Ans. 144000

Explanation: Let Amit salary in 2003 is x.

Therefore, salary in 2004 was 120/100 x and salary in 2005 is 120/100(120/100)x.

x+ 120/100x + 120/100(120/100)x= 364000

x + 120/100 x + 144/100 x = 364000

(364/100)x = 364000

x= 1,00,000

Therefore, Salary in 2005 is (364000-120000-100000) = 144000

3. In how many ways a team of 11 members can be formed from 5 men and 11 women such

that the team have at most 3 men?

Ans. 2256

Explanation: 1st Case: The team has no men member =11

C11= 1

2nd Case: The team has 1 men member = 11C10*5C1=11 * 5 = 55

3rd Case: The team has 2 men members = 11C9*5C2= 55 *10 = 550

4th Case: The team has 3 men members= 11C8*5C3= 165 * 10 = 1650

Therefore, Total no of ways = 1+55+550+1650= 2256

4. In a set of 30 numbers, average of 1st 10 numbers is equal to the average of last 20

numbers .Find the sum of last 20 numbers?

Ans. Twice the sum of firs t 10 numbers

Explanation: Average = (Total sum of Numbers/ No. of numbers )

(Sum of first 10 numbers/10) = ( sum of last 20 numbers /20)

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Therefore, Sum of last 20 numbers = 2 * sum of first 10 numbers .

5. In a class, there are 9 students in which there are 5 boys and 4 girls. In a row, there will

always a boy between any two girls. Find out how many such arrangement possible?

Ans. 43200

Explanation: 5 boys can be arranged in 5! ways.

There are six place for girls. The girls can choose any 4 out of 6 .Therefore6C4.

Now 4 girls will have 4! ways of arrangement between themselves.

Total no. of such arrangement = 120 * 15 * 24 = 43200

6. What no. should be added to 5678 so that the remainder is 35 when divided by 460?

Ans. 337

Explanation: 5678%460=158(460-158)+35=337

7. In 2003 there are 28 days in February and 365 days in that year, in 2004 there are 29

days in February and 366 days in that year. If the date 11 march 2003 is Tuesday, then

which would be the date for 11 march 2004?

Ans. Thursday

Explanation: Its given that 11 march 2003 is Tuesday. We have to find which day is 11

march 2004

So, there is difference of 366 days between the two dates.Therefore, no of odd days = (366%7)= 2. So, it will be Thursday.

1. The cost of 3 mangoes and 4 apples is Rs.85, 5 apples and 6 peaches costs 122 and that of 6

mangoes and 2 peaches costs Rs.114. What is the cost of 1 apple, 1 peach, and 1 mango?

Ans.37

Explanation: Let denote mangoes with letter m, apple with letter a and peaches with letter p.

Now, its given that

3m + 4a = 85 ..(1)

5a + 6p = 122 ..(2)

6m + 2p = 114 ..(3)

Now , we have to find the value of m,a and p.

Multiply equation (1) with 5, we get 15m + 20a = 425 .......4

Multiply equation (2) with 4, we get 20a+24p = 488 .......5

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By solving equation (4) and (5), we get 15m-24p =-63 ......6

Multiply equation (3) with 5, we get 30m+10p= 570 .....7

Multiply equation (6) with 2, we get 30m 48p = -126 ......8

Solving equation (7) and (8) we get , p =12

Now, substitute the value of p in equation (7), we get m=15

Now, substitute the value of m in equation (4),we get a=10

Therefore , a+m+ p =10+15+12=37

2. An article manufactured by a company consists of two parts X and Y. In the process of

manufacturing of

part X, 9 out 100 parts may be defective. Similarly, 5 out of 100 are likely to be defective

in the manufacturer of Y. Calculate the probability that the assembled product will not be defective?

Ans. 0.8645

Explanation: The assembled product is non defective if both parts are non defective.Probability that X is not defective = 1 - 9/100 = 91/100

Probability that X is not defective = 1 - 5/100 =95/100

Therefore, required probability that the product is not defective = 91/100 * 95/100 = .8645

3. A merchant buys 20kg of wheat at Rs.30.00 per kg and 40kg wheat at Rs.25.00 per kg. He mixes

them and sell one third of the mixture at Rs.26.00 per kg. The price at which the merchant should

sell the remaining mixture so that he may earn a profit of 25% on his whole outlay?

Ans Rs 37

Explanation: Total CP = 20 * 30 + 40 * 25= 1600

SP = 125/100 * 1600= 2000 ( 25% profit )

SP for 20 kg mix = 26 * 20 =520

Remaining total SP should be = 2000-520 = 1480

The SP for 40 kg = 1480/40 = 37

4. 1!+2!+3!...+50! when divided by 5!, the remainder is?

Ans 33

Explanation: 5! is 120 and all numbers from 5! to 50! are divisible by 5!. We have to check for the

first 4 numbers i.e, from 1! to 4!. The addition is 1+2+6+24 = 33. Therefore, the remainder is 33.

5. 1-2+3-4+5.-98+99 = ?

Ans 50

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Explanation: 1-2 =-1,3-4=-1, so, we will have 49 such series ,therefore the total is -49 and the last

term is 99. Therefore, 99-49=50

6. A child was looking for his father. He went 90 metres in the East before turning to his

right. He went 20 metres before turning to his right again to look for his father at his

uncles place 30 metres from this point. His father was not there. From here he went 100 metres to

the North before meeting his father in a street. How far did the son meet hisfather from the starting

point?

Ans 100

7. A chocolates manufacturer makes 6 different flavors of chocolates. The chocolates are sold in

boxes of 10. How many different boxes of chocolates can be made?

Ans. 3003

Explanation: Use the formulan+r1

C r1

Here n =10 and r=6

Therefore,10+6-1

C6-1= 3003

1. How many seven digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6, 7 and 8 , if

repetition of digits is not allowed and the second last digit is even?

Ans. 8640

Explanation: Total no of digits =8 (1,2,3,4,5,6.7,8)No. of even number = 4 (2,4,6,8)

As we have to find the seven digit even numbers. So the numbers must end with even digit. No of

ways this can be done is 4.

Now, the second last digit should also be even.This can be done in 3 ways.

Now we can fill the remaining digit in the numbers with any of the remaining digits from the digit list.

No of remaining digit = 6.

Therfore,

Place 1 2 3 4 5 6 7

No. of ways 2 3 4 5 6 3 4

Therefore, total no of 7 digit even number possible = 2*3*4*5*6*3*4=8460

2. What is the probability that a particular selected leap year has 53 sundays?

Ans. 2/7

Explanation:No. of days in a leap year = 366 Days.

366 Days = 52 Weeks and 2 Days

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Thus, a Leap Year has 52 Sundays.

The Remaining 2 Days can be :

1. Sunday & Monday

2. Monday & Tuesday

3. Tuesday & Wednesday

4. Wednesday & Thursday5. Thursday & Friday

6. Friday & Saturday

7. Saturday & Sunday.

Therefore, no of event =7

Favourable Outcomes = 2

Required Probability = 2/7.

3. Which of the following value of n is the number 274+ 22058+ 22nis a perfect square?

Ans. 2020

Explanation:274+22058+22n= (237)2+ (2n)2+ 22058

It is in the formula as (a+b)2=a2+b2+2*a*b

Therefore, 2*(237)*(2n)=2(38+n)=22058

38+n=2058

n=2020

4. In a 3 x 3 grid, comprising 9 tiles can be painted in red or blue. When tile is rotated by 180

degrees, there is no difference which can be spotted. How many such possibilities are there?

Ans. 32

Explanation: Let assign number to grids,

1 2 3

4 5 6

7 8 9

We can fill position 5 in 2 ways.

We can fill position 1 in 2 ways, so position 9 should be fill 1ways

We can fill position 2 in 2 ways,so position 8 should be fill 1ways

Similarly, we can fill position 3 in 2 ways,so position 7 should be fill 1 ways

We can fill position 4 in 2 ways, so position 6 should be fill 1 ways.

Total no. of possibility = 25

=32

7. A tree of height 36 m at the edge of a road broke at certain height and it fell in such a way that its

top touched the other edge of the road.If the breadth of the road is 12m, then find the height at which

tree broke?

Ans. 16 m

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Explanation: By applying Pythagoras theorem

(36-x)2= 12

2+ x

2

1296 + x2- 72x = 144 + x

2

72x = 1152

x = 1152/72

x = 16

7. 1(1!)+2(2!)+.............+2012(2012!)=?

Ans. 2013!-1

Explanation: 1(1!) = (2-1)*1!= 2!-1!

2(2)! = (3-1)(2!)=3!-2!

Therefore, the equation = 2!-1!+3!-2!+4!-3!........2013!-2012! = 2013!-1

1. Two dice are thrown. What is the probability of getting a sum of 5 before a sum of 7 appears?

Ans. 0.4

Explanation:No. of events results in sum of 5 : (1,4),(2,3),(3,2),(4,1) = 4

No. of events results in sum of 7 : (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) =6

Total possibilities = 10

Probability of getting a sum of 5 before 7 appears is 4/10 = 0.4

2. Sachin can do a piece of work in 16 days, Amit can do the same work in 12 days while Ram can

do it in 32 days. All of them started to work together but Sachin leaves after 4 days. Amit leaves the

job 3 days before the completion of the work. How long the work last?

Ans. 9 days.

Explanation: Let, the work will be complete in x days.

Sachin worked for 4 days.

Amit worked for (x-3) days

Ran worked for x days.

Therefore, 4/16+(x-3)/12+x/32=1

By solving we get,

11x=96

x= 96/11 days (9 days approx..) Only Option 9 days is given

3. If A speaks the truth 60% of the times, B speaks the truth 50% of the times. What is the probability

that at least one will tell the truth, narrating the same incident?

Ans. 0.8

Explanation. Probability of A speaks truth 6/10.

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Therefore, Probability of A speaks false =(1- 6/10)=4/10.

Probability of B speaks truth =5/10

Probability of B speaks false =(1-5/10)=5/10

Therefore, Probability that neither of them tell truth = 4/10*5/10=2/10

Therfore, Probability that at least one will tell the truth=(1- 2/10)=8/10=0.8

4. If three dies are thrown simultaneously probability of getting sum as 10?

Ans.27/216

5. How many words with or without meaning, can be formed by using all the letters of the word,

'DELHI',using each letter exactly once?

Ans. 120

Explanation:No. of permutation possible taking all at a time.

Therefore, 5P5=5!=120

6. In how many ways can we distribute 10 pencils to 4 children so that each child gets atleast one

pencil?

Ans. 84

Explanation: No, of way to distribute 10 pencils to 4 children.

By formula , we know

Number of ways of distributing n identical objects to r distinct objects so that each get atleastone

(n1)C(r1).Therefore, we the solution is

(101)C(41)=

9C3= 84

7. How many number plate with 1,2,3,4,5 digits can be created, if repetition of numbers is not

allowed?

Ans. 325

Explanation: No. of no. plate possible with 1 digit = 5

No. of no. plate possible with 2 digits = 5 * 4 =20

No. of no. plate possible with 3 digits = 5*4*3 = 60

No. of no. plate possible with 4 digits = 5*4*3*2=120No. of no. plate possible with 5 digits = 5*4*3*2*1=120

Total no. of number plate possible =120+120+60+20+5=325

8. 70, 54, 45, 41,?

Ans: 40

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Explanation:70 - 54 = 16 = 42

54 - 45 = 9 = 32

45 - 41 = 4 = 22

Therefore, now difference should be 12. So, 41-1 = 40.

1. 1, 4, 2, 8, 6, 24, 22, 88, ?

Ans 86

Explanation: 1 x 4 = 4

4 - 2 = 2

4 x 2 = 8

8 - 2 = 6

8 x 4 = 24

24 - 2 = 22

22 x 4 = 8888 - 2 = 86

2. In how many ways can 21 books on English and 19 books on Hindi be placed in a row on a shelf

so that two books on Hindi may not be together?

Ans- 1540

3. From a deck of 52 cards, 3 cards drawn randomly. What is the probability of getting 1 spade, 1

red queen and 1 black king?

Ans. 0.00235

Explanation:13C1*2C1*2C1/52C3 = 0.00235

4. A man can row 9 1/3 kmph in still water and finds that it takes him thrice as much time to row up

than as to row down the same distance in the river. The speed of the current ?

Ans. 4 2/3 km/hr.

Explanation: Let the speed be x kmph. Then downstream speed= 3x kmph

Speed in still water= (3x + x) kmph = 2x kmph.

2x=28/3 = 14/3.Speed upstream= 14/3 kmph and Speed downstream= 14 kmph.

Therefore, speed of the current = (14-14/3) km/hr = 4 2/3 km/hr.

5. Two dice are tossed. The probability that the total score is a prime number?

Ans. 5/12.

6. Find the value of "n" where 348

+ 31996

+33943

+33n

.

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Ans1963

Explanation: It is in the format as

a3+3a2b+3ab2+b3

i.e (3

16

)

3

+3.3

32

.3

n

+3.3

16

.3

2n

=3

48

+3

1996

+3

3942

+3

3n

Therefore we can say 3

33+n= 3

1996

33+n=1996

n=1963

7. One man can fill a truck in 9 min, how many trucks can be filled in one and half hours when 16

men work together ?

Ans.160

Explanation: 1 man in 9 min can fill 1 truck

16 man in 9min can fill 1*16=16 trucks16 man in 90 min can fill 16 x (90/9)=160 trucks

8. One card is drawn from a pack of 52 cards. What is the probability that the card drawn is either a

red card or a king ?

Ans.7/13

Explanation: There are 26 red card (including 2 kings) and there are 2 more kings.

Total no. of favorable cards for this event = 28

Therefore, the required probability = 28/52 = 7/13.

1. There are 3 trucks A,B and C. A loads at the rate of 10kg/min and B loads at the rate of 13 1/3

kg/min. C unloads at the rate of 5kg/min. If all the 3 trucks are acting simultaneously, find the time

taken to load 2.4 tonnes.

Ans. 130.91 min

2. The price of a book in four different shops and the successive discounts offered for the books is

given below. Select the option in which the price of the book is the least.

(a) 10%, 5%, and 5% discount on Rs.195

(c) 12.5% and 12.5% discounts on Rs.205

(b) 25%, discount on Rs.200(d) 10%, and 15% discounts on a marked price of Rs.190

Ans. D

3. When all possible six-letter arrangements of the letters of the word MASTER are sorted in

alphabetical order, what will be the 49 th word?

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Ans.AREMST

Explanation: First by arranging the given word in alphabetical order we

get A,E,M,R,S,T

There are 24 words starts with AE

There are 24 words starts with AMSo the 49th word will be AREMST

4. A workman starts his work on Monday works for 8 days and takes every 9 th day as his holiday.

His 12 th holiday will fall on?

Ans. Wednesday

5. Initial price of the scooter is 40000 and it reduces to 3/4th of the previous price every year. What

will be the price after 3 years?

Ans. 16875

Explanation: Therefore price of scooter in 3 years = 40000*(3/4)*(3/4)*(3/4) =16875

6. A starts riding his bike at 10am with a speed of 20kmph and B also starts at 10am with a speed of

40 kmph from the same point in the same direction. A turns south at 12 oclock and B turns north at

11 am. What will be the distance between A and B at 2 pm?

Ans 160 kmph

7. If there are six periods in each working day of a school. In how many ways can one set up the

time table for a day such that each subject is allowed at least one period?

Ans. 3600

Explanation: The five subjects can be done in 5! ways. The remaining 1 period can be any of the 5

subjects and it can come in at any of the 6 different periods. So 5 * 6 = 30 ways.

The total ways is 5! * 30 = 3600 ways.

8. 1!+2!+3!...+50! when divided by 5!, the remainder is?

Ans. 33

Explanation: 5! is 120 and all numbers from 5! to 50! are divisible by 5!. We have to check for the

first 4 numbers i.e, from 1! to 4!. The addition is 1+2+6+24 = 33. Therefore, the remainder is 33.

9. In month of 31 days, there are exactly 4 Thursdays and 4 Sundays. What is the day of the week

on the first of that month?

Ans. Monday

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Explanation: If Thursdays and Sundays occur 4 times, then the days between them Friday and

Saturday also will occur 4 times. The remaining days Mon, Tue and Wed will occur 5 times.

Hence the month starts on Monday.

10. My name is PREET. But my son accidentally types the by interchanging a pair of letters in myname. What is the probability that despite this interchange, the name remains unchanged?

Ans. 10%

Explanation: Using 5 letters one can form 10 combinations and the only way that the name remains

unchanged is when both Es are getting interchanged. That is one of 10, which is 10%.

1. If m is an odd integer and n an even integer, which of the following is definitely odd?

Ans. m+n

Explanation: You just remember the following odd odd = even; even even = even; even odd =odd. Also odd x odd = odd; even x even = even; even x odd = even.

2. If 3y + x > 2 and x + 2y 3, What can be said about the value of y?

Ans. y>-1

Explanation: Multiply the second equation with -1 then it will become - x - 2y >= - 3. Add theequations. Youwill get y > -1.

3. There are 20 balls which are red, blue or green. If 7 balls are green and the sum of red balls andgreen balls is less than 13, at most how many red balls are there?

Ans. 5

Explanation: Given R + B + G = 20; G = 7; and R + G < 13. Substituting G = 7 in the last equation,We get R < 6. So maximum value of R = 5.

4. All faces of a cube with an eight - meter edge are painted red. If the cube is cut into smallercubes with a two - meter edge, how many of the two meter cubes have paint on exactly one face?

Ans: 48

Explanation: If there are n cubes lie on an edge, then total number of cubes with one side painting

is given by 6 X (n-2)2

edge. Hence answer = 24.

5. Two cyclists begin training on an oval racecourse at the same time.The professional cyclist

completes each lap in 4 minutes; the novice takes 6 minutes to complete each lap. How many

minutes after the start will both cyclists pass at exactly in the 15 the lap,at the same spot where they

began to cycle?

Ans. 165

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Explanation: L.C.M for 4 & 6 is 12 so first meet is 12.and 15 th lap is 15 * 12 =165

6. Arun, Akash, Amir and Aswanth go for a picnic. When Arun stands on a weighing machine,

Akash also climbs on, and the weight shown was 132 kg. When Akash stands, Amir also

climbs on, and the machine shows 130 kg. Similarly the weight of Amir and Aswanth is found as102 kg and that of Akash and Aswanth is 116 kg. What is Aswanths weight?

Ans. 44 kg

Explanation: Given A + B = 132; B + C = 130; C + D = 102, B + D = 116Eliminate B from 2nd and 4th equation and solving this equation and 3rd we get D value as 44.

7. Roy is now 4 years older than Erik and half of that amount older than Iris. If in 2 years, roy will betwice as old as Erik, then in 2 years what would be Roy's age multiplied by Iris's age?

Ans. 48

Explanation: R =4+ ER =2 + IR+2 = 2(E+2 )Solving all the above equations we getR= 6,E= 2,I =4 so after 2 yrs it is R=8 and I =6,which is 48.

8.The telephone company wants to add an area code composed of 2 letters to every phone number.

In

order to do so, the company chose a special sign language containing 124 different signs. I

f the company used 122 of the signs fully and two remained unused, how many additional area

codes can be created if the company uses all 124 signs?

Ans: 492

Explanation: The phone company already created 122*122 area codes, now it can create 124*124.1242-1222 =(124+122)(124-122) = 246*2 = 492 additional codes.

9. A bakery opened yesterday with its daily supply of 40 dozen rolls. Half of the rolls were sold by

noon and 80 % of the remaining rolls were sold between noon and closing time. How many dozen

rolls had not been sold when the bakery closed yesterday?

Ans. 4

Explanation: 4 rolls were not sold.Because half of them were sold by noon.So 20 rolls remain, andthen 20% were not sold. So 20% of the 20 rolls is 4.

10. A necklace is made by stringing N individual beads together in the repeating pattern red bead,

green bead, white bead, blue bead and yellow bead. If the necklace begins with a red bead and

ends with a white bead, then N could be:

Ans: 68

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Explanation: R G W B Y is the bead pattern and it repeats.

Bead want to end with White.

So, the 3rd, 8th, 13th, 18th... beads will be W.

this can be expressed as 5n+3,where n is an integer.(counting no of white bead)

Test each of the answer choices to determine which is multiple of 5 plus a value of 3.Of the options,only 68=5(13)+3 can be written in the form 5n+3.

So,the answer is 68.

1. What are the total number of divisors of 600(including 1 and 600)?

a. 24

b. 40

c. 16

d. 20

Ans. a

2. What is the sum of the squares of the first 20 natural numbers (1 to 20)?

a. 2870

b. 2000

c. 5650

d. 44100

Ans. a

3. What is 28

K2(28

KC) where28

KCis the number of ways of choosing k items from 28 items?

a. 406 * 227

b. 306 * 226

c. 28 * 227

d. 56 * 227

Ans. a

4. What is 28

3k(28

KC) where28

KC is the number of ways of choosing k items from 28 items?

a. 256

b. 3* 227

c. 329

d. 3* 427

Ans. a

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5. A call center agent has a list of 305 phone numbers of people in alphabetic order of names (but

she does not have any of the names). She needs to quickly contact Deepak Sharma to convey a

message to him. If each call takes 2 minutes to complete, and every call is answered, what is the

minimum amount of time in which she can guarantee to deliver the message to Mr Sharma.

a. 18 minutes

b. 610 minutes

c. 206 minutes

d. 34 minutes

Ans. a

6. The times taken by a phone operator to complete a call are 2,9,3,1,5 minutes respectively. What

is the average time per call?

a. 4 minutesb. 7 minutes

c. 1 minutes

d. 5 minutes

Ans. a

7. The times taken by a phone operator to complete a call are 2,9,3,1,5 minutes respectively. What

is the median time per call?

a. 5 minutesb. 7 minutes

c. 1 minutes

d. 4 minutes

Ans. a

8. Eric throws two dice, and his score is the sum of the values shown. Sandra throws one die, and

her score is the square of the value shown. What is the probability that Sandras score will be strictly

higher than Erics score?

a. 137/216b. 17/36c. 173/216d. 5/6

Ans. a

9. What is the largest integer that divides all three numbers 23400,272304,205248 without leaving

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a remainder?

a. 48b. 24c. 96d. 72

Ans. b

10. Of the 38 people in my office, 10 like to drink chocolate, 15 are cricket fans, and 20 neither likechocolate nor like cricket. How many people like both cricket and chocolate?

a. 7b. 10c. 15d. 18

Ans. a

11. If f(x) = 2x+2 what is f(f(3))?

a. 18b. 8c. 64d. 16

Ans. a

12. If f(x) = 7 x +12, what is f-1(x) (the inverse function)?

a. (x-12)/7

b. 7x+12c. 1/(7x+12)d. No inverse exists

Ans a

13. A permutation is often represented by the cycles it has. For example, if we permute the numbers

in the natural order to 2 3 1 5 4, this is represented as (1 3 2) (5 4). In this the (132) says that the

first number has gone to the position 3, the third number has gone to the position 2, and the second

number has gone to position 1, and (5 4) means that the fifth number has gone to position 4 and

the fourth number has gone to position 5. The numbers with brackets are to be read cyclically. If a

number has not changed position, it is kept as a single cycle. Thus 5 2 1 3 4 is represented as

(1345)(2). We may apply permutations on itself If we apply the permutation (132)(54) once, we get 2

3 1 5 4. If we apply it again, we get 3 1 2 4 5 , or (1 2 3)(4) (5) If we consider the permutation of 7

numbers (1457)(263), what is its order (how many times must it be applied before the numbers

appear in their original order)?

a. 12b. 7

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c. 7! (factorial of 7)d. 14

Ans a

14. What is the maximum value of x3y3 + 3 x*y when x+y = 8?

a. 4144b. 256c. 8192d. 102

Ans a

15. Two circles of radii 5 cm and 3 cm touch each other at A and also touch a line at B and C. Thedistance BC in cms is?

a. SQRT (60)

b. SQRT (62)c. SQRT (68)d. SQRT(64)

Ans a

16. In Goa beach, there are three small picnic tables. Tables 1 and 2 each seat three people. Table3 seats only one person, since two of its seats are broken. Akash, Babu, Chitra, David, Eesha,Farooq, and Govind all sit at seats at these picnic tables. Who sits with whom and at which table aredetermined by the following constraints:

a. Chitra does not sit at the same table as Govind.

b. Eesha does not sit at the same table as David.c. Farooq does not sit at the same table as Chitra.d. Akash does not sit at the same table as Babu.e. Govind does not sit at the same table as Farooq.

Ans a

17. Which of the following is a list of people who could sit together at table 2?

a. Govind, Eesha, Akashb. Babu, Farooq, Chitrac. Chitra, Govind, David.d. Farooq, David, Eesha.

Ans a.

18. There are a number of chocolates in a bag. If they were to be equally divided among 14

children, there are 10 chocolates left. If they were to be equally divided among 15 children, there

are 8 chocolates left. Obviously, this can be satisfied if any multiple of 210 chocolates are added to

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the bag. What is the remainder when the minimum feasible number of chocolates in the bag is

divided by 9?

a. 2b. 5c. 4d. 6

Ans b

19. Let f(m,n) =45*m + 36*n, where m and n are integers (positive or negative). What is the minimum

positive value for f(m,n) for all values of m,n (this may be achieved for various values of m and n)?

a. 9b. 6c. 5d. 18

Ans a

20. What is the largest number that will divide 90207, 232585 and 127986 without leaving aremainder?

a. 257b. 905c. 351d. 498

Ans a

20. We have an equal arms two pan balance and need to weigh objects with integral weights in the

range 1 to 40 kilo grams. We have a set of standard weights and can place the weights in any pan. .

(i.e) some weights can be in a pan with objects and some weights can be in the other pan. The

minimum number of standard weights required is:

a. 4b. 10c. 5d. 6

Ans a

21. A white cube(with six faces) is painted red on two different faces. How many different ways canthis be done (two paintings are considered same if on a suitable rotation of the cube one paintingcan be carried to the other)?

a. 2b. 15c. 4

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d. 30

Ans a

22. How many divisors (including 1, but excluding 1000) are there for the number 1000?

a. 15b. 16c. 31d. 10

Ans a

23. In the polynomial f(x) =2*x^4 - 49*x^2 +54, what is the product of the roots, and what is the sumof the roots (Note that x^n denotes the x raised to the power n, or x multiplied by itself n times)?

a. 27,0b. 54,2c. 49/2,54

d. 49,27

Ans a

24. In the polynomial f(x) = x^5 + a*x^3 + b*x^4 +c*x + d, all coefficients a, b, c, d are integers. If 3 +

sqrt(7) is a root, which of the following must be also a root?(Note that x^n denotes the x raised to the

power n, or x multiplied by itself n times. Also sqrt(u) denotes the square root of u, or the number

which when multiplied by itself, gives the number u)?

a. 3-sqrt(7)

b. 3+sqrt(21)c. 5

d. sqrt(7) + sqrt(3)

Ans a

1. In the equation A + B + C + D + E = FG where FG is the two digit number whose value is 10F + G

and letters A, B , C , D , E, F and G each represent different digits. If FG is as small as possible.

What is the value of G?

Ans. 0

Explanation: The minimum values substituted here are 4+5+6+7=8=30 ,

Hence G=0.

2. At 12.00 hours Ravi starts to walk from his house at 8 kms an hour. At 13.30 hours, Shankar

follows him from Ravis house on his bicycle at 12 kms per hour. When will Ravi be 6 kms

behind Paul?

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Ans. 18:00 hrs

Explanation: The distances travelled by Shankar and Ravi.

Time Ravi Shankar

1.00 8 0

2.00 16 6

3.00 24 18

4.00 32 30

5.00 40 42

6.00 48 54

So at 6pm the distance between them is 6km.

3. Seven varsity basket ball players (A, B, C, D, E, F and G) are to be honoured at a special

luncheon. The players will be seated on the dias in a row. A and G have to leave the luncheon early

and so must be seated at the extreme right .B will receive the most valuable players trophy and somust be in the centre to facilitate presentation .C and D are bitter rivals and, therefore must be

seated as far apart as possible.

Which of the following pair cannot occupy the seats on either side of B?

Ans. E and G

Explanation: The pair E and G cant occupy it as G will have to be at the end since he is leaving

early.

4. An organization has 4 committees. Only 3 persons are members of all four committees, butevery pair of committees has 4 members in common. What is the LEAST possible number of the

members on any one committee?

Ans. 6

Explanation: The least number will be 6.

If it is 5 then The arrangements would be

ABCDE

ABCDF

ABCEF,but in the last arrangement it cant be possible to have 4 people common as it has to beABC D/E/F and some other person X.

So with 6 the arrangement would do better.

5. Aravind can do a work in 24 days. Mani can dig the same well in 36 days. Aravind, Mani and

Hari can do a work together in 8 days. Hari alone can do the work in

Ans. 18 days

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6. A farmer has a rose garden. Every day he either plucks 7 or 6 or 24 or 23 roses. The roseplants

are intelligent and when the farmer plucks these numbers of roses, the next day 37 or 36 or 9 or 18

new roses bloom in the garden respectively. On Monday, he counts 189 roses in the garden.

He plucks the roses as per his plan on consecutive days and the new roses

bloom as per intelligence of the plants mentioned above. After some days which of the

following can be the number of roses in the garden?

Ans. 249

Explnation: If he plucks 7, increase is of 30 flowers.

If he plucks 6. Increase is of 30 flowers.

If again he plucks 24, decrease of 15 flowers.

And in case of 23, decrease of 5 flowers.

And option B definitely satisfies the criteria.

7. A can complete a piece of work in 8 hours, B can complete in 10 hours and C in 12 hours. If

A,B, C start the work together but A laves after 2 hours. Find the time taken by B and C to

complete the remaining work.

Ans.2(1/11) hrs

Explanation: Total unit of the work is 120units

In 1 hour A can complete 15units

In 1 hour B can complete 12units

In 1 hour C can complete 10unitsIn 1 hour A+B+C can complete 37units

Therefore in 2 hours A+B+C would have completed 74units

Remaining work to be completed is 12-74=46

In 1 hour B+C can complete 22units

Therefore time taken to complete the remaining job =46/22=23/11=2(1/11)

8. A number is divided by 5,2 and 3 successively in order to get remainders of 0,1, and 2

respectively. What will be the remainders when the same number is divided by 2,3 and 5

respectively?

Ans. 1,0,4

Explanation: Let the number be X and the quotient when X is divided by 5 is Q1 and leaves the

remainder 0

And quotient when Q1 is divided by 2 is Q2 and leaves the remainder 1

And quotient when Q2 is divided by 3 is Q3 and leaves the remainder 2

Assuming any value of Q3 and solving in reverse order we will get the solution.

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Let us assume here the value of Q3 as 0

Therefore Q2= 2 since the remainder is 2

And Q1= 5 since the remainder is 1

Then the value of X is 25.

When 25 is successively divided by 2,3,5 leaves the remainders 1,0,4 with the quotients 12,4,0.

9.Three dice are rolled. What is the probability that you will get the sum of the numbers as 10?

Ans 27/216

Explanation: Three dice that shows the sum as 10 are as follows

(1,3,6), (1,4,5), (1,5,4), (1,6,3)

(2,2,6), (2,3,5), (2,4,4), (2,5,3), (2,6,2)

(3,1,6), (3,2,5), (3,3,4), (3,4,3), (3,5,2), (3,6,1)

(4,1,5), (4,2,4), (4,3,3), (4,4,2), (4,5,1)

(5,1,4), (5,2,3), (5,3,2), (5,4,1)(6,1,3), (6,2,2), (6,3,1)

Therefore the probability of getting the sum of the numbers as 10 is given by 27/216

10. There are 6 people from different countries namely Germany, Italy, Britain, Spain, Poland and

France. They are sitting around a table. Polish sits next to British. German sits next to Italian,or

British or both. Italian does not sit next to the Frenchman. Spanish sits immediately after British.

Who sits on the either side of the German?

Ans. Italian and French

1. 3 dies are thrown. What is the probability that sum ten appears?

Ans. 27/216

Explanation: When 3 dice are thrown, total number of possibilities are n(s) = 6^3 = 216

Sum is 10 : (1,3,6),(1,4,5),(1,5,4),(1,6,3)

(2,2,6),(2,3,5),(2,4,4),(2,5,3),(2,6,2)

(3,1,6),(3,2,5),(3,3,4),(3,4,3),(3,5,2),(3,1,6)

(4,1,5),(4,2,4),(4,3,3),(4,4,2),(4,5,1)

(5,1,4),(5,2,3),(5,3,2),(5,4,1)

(6,1,3),(6,2,2),(6,3,1)

Probability of getting a sum of ten is 27/216 = 1/8

2. In an examination 80% of student passed in mathematics, 55% in English, 29% failed in both

subject. Find the percent of student passed in both subject ?

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Ans.64%

Explanation: Passed in math = 80%

Passed in English = 55

Failed in both = 29%

Total percent of student passed in atleast one subject =100 -29 = 71%

Total no pass student in both Subject = 80+55-71 = 64%

3. What is the next number of the following sequence.

18,24,5,21,27,8,24,30,...

Ans 11

Explanation: There are there series

18,21,24 ------------ +3

24,27,20 -------------+35,8,.... -------------+3

8+3=11.

4. A man spends 1/3rd of his salary on food, 1/4th on rent and 1/5th on cloths. If he is left with 1800,

then who much salary does he earn.

Ans. 3692

Explanation: Let total Salary = x

1/3 x+ 1/4 x+ 1/5 x =47 /60 x.

Remaining salary = x- 47/60 x= 13/60 x

13/60 x = 1800

x=3692 (approx)

5. For a car there are 5 tires including one spare tire. All tires are equally used. If the total distance

travelled by the car is 40000 km then what is the average distance travelled by the each tire?

Ans. 32000

Explanation: Total distance travelled by the car=4000 0km

Total distance travelled by 4 wheels=4*40000=160000

as all tires are equally used

So distance travelled by the each tire=160000/5=32000

6. If A speaks the truth 60% of the times, B speaks the truth 50% of the times. What is the probability

that at least one will tell the truth ?

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Ans. 8/10

Explanation: The prob. that both of them telling the lie = (40/100* 50/100)=2/10

Therefore prob. that atleast one will tell the truth = 1- 2/10 = 8/10= .8

7. If the letters in the word ACTORS are permuted in all possible ways and arranged in alphabetical

order.Find the 40th word in permuted alphabetical order.

Ans.AOSRTC

Explanation: Arranging in alphabetical order as ACORST.

No of words forming with A=5!=120

No of words forming with AC=4!=24

No of words forming with AOC=3!=6

No of words forming with AOR=3!=6(36 words).AOSCRT = 37th word

AOSCTR =38th word

AOSRCT =39th word

AOSRTC =40th word

8. What is the probability that a particular selected leap year has 53 Sundays?

Ans. 2/7

Explanation: A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days.

The remaining 2 days may be any of the following :

Sunday and Monday

Monday and Tuesday

Tuesday and Wednesday

Wednesday and Thursday

Thursday and Friday

Friday and Saturday

Saturday and Sunday

For getting 53 Sundays in a year, one of the remaining 2 days must be a Sunday.

n(S) = 7

n(E) = 2

P(E) = n(E) / n(S) = 2 / 7

9. How many number plates with 1,2,3,4,5 digits as numbers without repetition.

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Ans. 325

Explanation: No of number plates with 1 digit = 5

No of number plates with 2 digit=5*4=20

No of number plates with 3 digit=5*4*3=60

No of number plates with 4 digit=5*4*3*2=120

No of number plates with 5 digit=5*4*3*2*1=120

Therefore total no of plate=120+120+60+20+5=325

10. What is the sum of 1-2+3-4+5.......-98+99 ?

Ans. 50

Explanation: 1-2+3-4+5.......-98+99

=(1-2)+(3-4)+(5-6)+....+(97-98)+99=(-1-1-1....49 times)+99

=-49+99

=50

1. Hanuman can complete a bridge in 10 days and Ravanan can complete the same bridge in 20

days. Now they are working together and they are completing the bridge in 20 days. What is the

contribution of Ravanan in constructing the bridge?

Ans. Destructing the bridge

Explanation: If they are both doing a positive work then they would have completed the work in less

than 10 days, but still they are consuming 20 days together. This is possible only when one of them

is

doing a negative work. If Hanuman is doing the negative work then the bridge wont get co

mpleted. So the only other person to do the negative work should be Ravanan.Thus

Ravanans contribution in constructing the bridge is Destructing it.

2. 5 coffee and 4 tea costs Rs.96, 5 badam milk and 6 coffee costs Rs. 32 and 7 tea and 6 badam

milk costs Rs.37. What is the combined price of 1tea, 1 coffee and 1 badam milk?

Ans. 15

Explanation: 5C+4T=96; 5B+6C=32; 7T+6B=37;Therefore 5C+4T+5B+6C+7T+6B =96+32+37i.e., 11C+11T+11B=165then 1C+1T+1B=15.

3. Jake is faster than Paul. Jake and Paul each walk 40 km. The sum of their speeds is 13 km/h and

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the sum of time taken by them is 13 hours. Then Jakes speed is equal to ?

Ans. 8 Kmph

Explanation: Given that speed of Jake is greater than Paul.Distance = 40 km

Sum of their speed is 13 km/h = J+PSo possible speed ratio between J & P isGo by Option12:1, 11:2, 10:3, Not in option8:5= (40/8)+(40/5) = 13 HoursSo Jakes speed is 8km/h.

4. A Samsung duo and a Galaxy are bought for Rs.40000. The Duo is sold at a profit of 33.33% and

the Galaxy is sold at a loss of 20%. There was no loss or gain. Find the cost price of the Samsung

duo ?

Ans.Rs.15,000

Explanation: x+y= 400001.33x+ 0.8y= 40000By solving these two equations:The price of Samsung Duo, ie, x=15094 ~15000

5. If a Strawberry and a Butterscotch together cost Rs. 18.00, a Vanilla and a Strawberry cost Rs.9.00 and a Butterscotch cost Rs.9.00 more than a Vanilla or a Strawberry then which of the followingcan be the price of a Butterscotch?

Ans. Rs. 13.5

Explanation: Butterscotch costs 9 more than a strawberry or Vanilla means Strwberry= Vanilla.Since Vanilla +Strawberry=9Vanilla= 4.5 and Strawberry = 4.5Then we know that Butterscotch + Strawberry= 18So Butterscotch= 18-4.5=13.5.

6. My next door neighbour lies a lot. In fact, he only tells the truth on one day a week! One dayhe told me, I lie on Mondays and on Tuesdays.The next day he said, Today is eitherThursday, Saturday or Sunday.The next day he said, I lie on Wednesdays and Fridays. On whichday of the week does my neighbour tell the truth?

Ans. Monday

Explanation: The first statement is made on Thurs, he lies.Second on Friday, Again he lies saying its Thurs, Sat or Sun.On sat again he has to lie , he says wed and Fri he lies, on fri he lies is true , So the falsestatement is that he lies on Wednesdays.

7. At the end of 1994 Rohit was 1/4 th as old as his grandmother. The sum of the years in which theywere born is 3843. How old Rohit was at the end of 2001?

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Ans. 36

Explanation: End of 1994 Rohit = Grandmother/4R+G= 38431999 Rohit age = ?[1994-(G/4)]+[1994-G] = 3843

5G/4 = 145G = 29*4

8. Raj writes a number. He sees that the number of two digits is 9 less than 3 times the number. Ifthe number is increased by 45, the result is the same as the number formed by reversing the digit.Find the number.

Ans. 27

Explanation: Going by the options, 27 = 3(27) 927+45=72(number reversed).

9. There are 5 sweets Milk peda, Ice cream, Rasagulla Paper sweet and Rasamalai that Iwish to eat on 5 consecutive days

Monday through Friday, one sweet a day, based on the following self imposed constraints:1) Paper sweet is not eaten on Monday2) If Milk peda is eaten on Monday, then Paper sweet must be eaten on Friday 3) If Paper sweet is eaten on Tuesday, Ice cream should be eaten on Monday4) Rasagulla should be eaten on the day preceding to the day of eating Milk peda.Based on the above, Rasagulla can be eaten on any day except?

Ans. Friday

Explanation: Rasagulla should be eaten on the day preceding to the day on which uh eat milk peda.Friday is the last day and hence cannot be preceded by any other day.

10. Daniel can do some work in 12 hours, Roy can do the same work in 10 hours while Hillari can

do the same work in 15 hours. All the three of them start working at 9 a.m while Daniel stops works

at 11 a.m and remaining two complete the work. Approximately at what time will the work be

finished?

Ans. 2:00 PM

Explanation: Let the total work be 60 .

That means Daniel will do 5 parts , Hillary 4 parts and oy 6 parts.

Total work they do together in an hour is 15 parts. So from 9am to 11am in two hours theycomplete 30 parts.

Next Daniel leaves Hillary+Roy do 4+6=10 parts/hour.

Hence next 30 parts will be completed in 3 hours.

Hence the work will be over by 2pm.

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1. P is thirty percentage of Q, Q is twenty percentage of N. M is fifty percentage of N, Find the

value of P/N ?

Ans. .06

Explanation: P = .3Q

Q = .2N

M = .5N

P = (.3*.2)N

P/N = .06

2. If twenty four men and sixteen women work on a day, the total wages to be paid is 11,600. If

twelve men and thirty seven women work on a day, the total wages to be paid remains the same.

What is the wages paid to a man for a days work?

Ans. 350

Explanation: Since the wages paid are equal, total work done by both the groups should also be

equal.

Equating the total work done in terms of men days and women days.

24m+16w=12m+37w - (1)

12m=21w (or) 4m=7w

Substituting w=4m/7 in eqn 1 we get

24m + 16w = 24w + 16(4m/7)

= (168m+64m)/7

= The total amount paid for 232m/7 = 11600For each men = (11600*7)/232=350.

3. A takes 2 hours to make a publication. B takes 10 hours to make a publication. Find the time

taken by them to make two publications, working independently?

Ans. 10

Explanation: A can complete a publication in 2 hours and B in 10 hours and so the maximum time

taken by both working independently to complete 2 publications will be 10 hours.

4. If all the numbers between 11 and 100 are written on a piece of paper. How many times will

the number 4 be used?

Ans. 19

Explanation: 14,24,34,44,54,64,74,84,94,40,41,42,43,44,45,46,47,48,49

Therefor there are 19 times the number 4 can be used between 11-100.

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5. In a school , sixty percent of the students are girls and thirty five percent of the girl s are poor. If a

student is randomly selected, what is the probability of selecting a poor girl student?

Ans. 21%

Explanation: Let the number of the students be X.

Therefore poor girl students = .35*.65*X

The probability of selecting poor girl is given by

= (.35*.65)*X

(100/100)*X =21%

6. Two beakers are on the table. The capacity of the first beaker is x litres and that of the second

beaker is 2x litres. Two thirds of the first beaker and one fourth of the second beaker is filled

with wine. The remaining space is filled with water. If the content in both the beakers are

mixed in a large beaker of volume 3x litres, what is the proportion of wine in the beaker?

Ans. 7/6

7.Three non negative numbers, X, Y and Z are such that the mean is M and the median is 5. If M is

10 more than the smallest number and 15 less than the biggest number, find the va lue of X+Y+Z.

Ans. 30

Explanation: (X+Y+Z)3 = M (or) X +Y +Z +3M

Let Y be the middle value, then Y=5X+Z=3M-5

X=M-10;

Z=M+15;

M-10+M+15=3M-5

M=10

X=0; Y=5; Z=25

8. From 5 men and 11 women, in how many ways can a panel of 11 be formed such

that the number of men is not more than 3?

Ans: 2266

Explanation: (5C3*11C8)+(5C2*11C9)+(5C1*11C10)+(11C11) = 2266

9. After 6 years Rajus father will be twice that of his age and two years ago, his mothers age was

twice of that of Rajus age. What is the sum of Rajus parents age?

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Ans. 4 more than four times Rajus age

Explanation: F+6=2(R+6)

F= 2R+6

M-2=2(R-2)

M= 2R-2

Therefore the sum of Rajus Parents age is

F+M=2R+6+2R-2

F+M=4R+4

4 more than four times Rajus age

10. The cost price of a cow and a horse is Rs 3 lakhs. The cow is sold at 20% profit and the horse is

sold at 10% loss. Overall gain is Rs 4200. What is the cost price of the cow?

Ans. 240000

Explanation: C+H=300000 -----eqution 1

1.20C+.90H=304200 --------equation 2

On equating 1 and 2 we get

C= Rs. 240000 and H= Rs.60000

1. J, K, L, M and N collected stamps. They collected a total of 100 stamps. None of them collected

less than 10.

No two among them collected the same number.(i) 3 collected the same number as K and M together.

(ii) L collected 3 more than the cube of an integer

(iii) The no.collected by J was the cube of an integer.

(iv) Total no.collected by K was either the square or cube of an integer.

The number of stamps collected by N was:

Ans. 12

Explanation: L can take only one value which is 11 (2^3+3) (30 is not possible because only there is

only 20 for the remaining two and one of them will have less than 10 and that is not possible)

J also can take only one value which is 27.

J + L + N = 50.

Therefore, N = 50 L J = 50 11 27 = 12.

2.The present ratio of students to teachers at a certain school is 30 to 1.If the student enrollment

were to

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increase by 50 students and the number of teachers were to increase by 5, the ratio

of the teachers would then be 25 to 1 What is the present number of teachers?

Ans. 15

Explanation: Current student to teacher ratio = 30/1 = s/t

Future student to teacher ratio = s+50/t+5 = 25/1

Solving the first equation first equation for s gives s = 30t.

Substitute this value of s into the second equation, and solve for t.

s+50/t+5 = 25/1

30t + 50 = 25t + 125

5t = 75, t = 15

3. A turtle is crossing a field. What is the total distance (in meters) passed by turtle? Consider the

following two statements

(X) The average speed of the turtle is 2 meters per minute(Y) Had the turtle walked 1 meter per minute faster than his average speed it would have finished 40

minutes earlier

(a) Statement X alone is enough to get the answer

(b) Both statements X and Y are needed to get the answer

(c) Statement Y alone is enough to get the answer

(d) Data inadequate

Ans. b

Explanation: v = 2 m/minInitially, x = v * t

When the speed increases by 1 km/hr,

x = (2+1) * (t 2/3)

The information in both statements together is sufficient to find the total distance passed by turtle.

4. A father purchases dress for his three daughters. The dresses are of same color but of different

size. The dress is kept in dark room .What is the probability that all the three will not choose their

own dress.

Ans.1/3

Explanation: At least one of them to choose correct dresses: A B C, A C B, C B A, B A C

For none of them to choose correct dresses: B C A, C A B

Probability is 2/6 = 1/3

5. Messrs. Siva Constructions, leading agents in Chennai prepared models of their lands in the

shape of a rectangle and triangle. They made models having same area. The length and width of

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rectangle model are 24 inches and 8 inches respectively. The base of the triangle model is 16

inches. What is the altitude of triangle model from the base to the top?

Ans. 24 inches

Explanation: If h is the height of triangle model, then 24*8 = 16*h/2 h= 24 inches.

6. In a stream running at 2 kmph, a motorboat goes 6 km upstream and back again to the starting

point in 33 minutes. Find the speed of the motorboat in still water?

Ans. 22 km/hr

Explanation: Let the speed of the motorboat in still water be v, then Solving for v, we get v = 22

km/h.

7. There are 4 boxes colored red, yellow, green and blue. If 2 boxes are selected, how manycombinations are there for at least one green box or one red box to be selected?

Ans. 5

Explanation: Out of 4 boxes 2 can be picked in 4C2 ways, i.e, 6 ways. Out of these 6 ways, only

one will have yellow- blue combination. All other remaining combinations will have green or red or

both. The answer is 5.

8. A merchant buys 20kg of wheat at Rs.30.00 per kg and 40kg wheat at Rs.25.00 per kg. He mixes

them and sell one third of the mixture at Rs.26.00 per kg. The price at which the merchant shouldsell the remaining mixture so that he may earn a profit of 25% on his whole outlay is

Ans. 37

Explanation: Total CP = 20 * 30 + 40*25= 1600

SP = 125/100 * 1600= 2000

SP for 20 kg mix = 26*20 =520

Rem SP = 2000-520 = 1480

The SP for 40 kg = 1480/40 = Rs37

9. My name is PREET. But my son accidentally types the by interchanging a pair of letters in my

name. What is the probability that despite this interchange, the name remains unchanged?

Ans.10%

Explanation: Using 5 letters one can form 10 combinations and the only way that the name remains

unchanged is when both Es are getting interchanged. That is one of 10, which is 10%.

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10. In month of 31 days, there are exactly 4 Thursdays and 4 Sundays. What is the day of the week

on the first of that month?

Ans. Monday

Explanation: If Thursdays and Sundays occur 4 times, then the days between them Friday and

Saturday also will occur 4 times. The remaining days Mon, Tue and Wed will occur 5 times. Hence

the month starts on Monday.

1. Ahmed, Babu, Chitra, David and Eesha each choose a large different number. Ahmed

says, My number is not the largest and not the smallest. Babu says, My number is not the largest

and not the smallest. Chitra says, My number is the largest. David says, My number is the

smallest. Eesha says, My number is not the smallest.

Exactly one of the five children is lying. The others are telling the truth. Who has thelargest number?

Ans. Eesha

Explanation: Ahmed and Babu cannot lie because each of them say two facts (not the largest,Not

the smallest) and there is no chance for both the facts to be wrong. David says My number is

smallest. If David lies, one of the remaining four should lie. But exactly

one person lies in this problem. So David says the truth.If Davids statement is true, Eeshas

statement is also true. The one who lies is Chitra and Eesha has the largest number.

2. A cow and a horse are bought for Rs.200000. The cow is sold at a profit of 20% and the horse is

sold at a loss of 10%. The overall gain is Rs.4000. The cost price of the cow is

Ans. 80,000

Explanation: Let the cost price of cow and horse is C and H Respectively

C + H = 200000 - (1)

1.2C + .8H = 204000 - (2)

Solving euation (1) & (2)

C = 80000.

3. If X^Y denotes X raised to the power Y, Find the last two digits of ( 1941 ^ 3843 ) + ( 1961^4181).

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Ans. 82

Explanation: 19412 ends in 81. 1941 3 ends in 21, 19414 ends in 61, 19415 ends in 01 and 19416

ends in 41 and this cycle keeps repeating. Similarly the cycle for 1961 powers is 61, 21, 81, 41, 01

and the cycle repeats. After adding up the final two digits of these numbers for their respective

powers, we find that the sum is 82.

4. George can do some work in 8 hours, Paul can do the same work in 10 hours while Hari can do

the same work in 12 hours. All the three of them start working at 9 a.m while George stops

work at 11 a.m and remaining two complete the work. Approximately at what time will the work be

finished?

Ans. 1 pm

Explanation:Total number of work to be done= 120 Units (LCM of 8,10,12)

Georges one hour work = 120/8 = 14 Units

Pauls one hour work = 120/10 = 12 Units

Haris one hour work = 120/12 = 10 Units

Units of work finished at 11 AM = (14+12+10)*2 = 74

Remaining work to be done = 120-74 = 46 units

One hour Paul + Hari work = 22 units

Approximately they will take two hours to finish the work

So the work will get finished at 1 PM

5. If M is 30% of Q, Q is 20% of P and N is 50% of P then M/N =

Ans. 3/25

Explanation: M is 30% of Q

Q is 20% of P

Nis 50 % of P

Then M/N = ?

Let P= 100

N = 50

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Q = 20

M = 6

M/N = 6/ 50 =3/25.

6. In a office, at various times during the day the boss gives the secretary a letter to type, each time

putting the letter on the top of the pile in the secretarys inbox. When there is time, the secretary

takes the top letter off the pile and types it. If there are five letter inall , and the boss delivers in the

order of 1 2 3 4 5, which of the following could NOT be the order in which secretary types them.

Ans. 4 5 2 3 1

Explanation: Going by the options and checking logically which order is possible.

7. There are 5 sweets Jumun, Kulfi, Peda, Laddu and Jilabi that I wish to eat on 5

consecutive days Monday through Friday, one sweet a day, based on the following self imposed

constraints:

1) Laddu is not eaten on Monday

2) If Jamun is eaten on Monday, then Laddu must be eaten on Friday

3) If Laddu is eaten on Tuesday, Kulfi should be eaten on Monday

4) Peda is eaten the day following the day of eating Jilabi

Based on the above, peda can be eaten on any day except?

Ans.Monday

Explanation: Peda can be had only after having Jilabi. So Peda can never be had on the

starting day, which is Monday.

8. At 12.00 hours Jake starts to walk from his house at 6 kms an hour. At 13.30 hours, Paul follows

him from Jakes house on his bicycle at 8 kms per hour. When will Jake be 3 kms behind Paul?

Ans. 19:30 hours

Explanation: Jake starts at 12.00 and covers 6 km/h.

Paul starts at 1.30 and covers 8 km/h.

Relative speed between Jake & paul is 2 kmph, where Paul stating Jake is 9 km ahead of

Paul. From 13.30 hours paul takes 4.30 hrs to meet Jake. Again he needs 1.30 hrs to lea

d Jake by 3 km Relative speed. Totally he takes 6 hrs. so 13.30+6 = 19.30 hrs.

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9. Jake can dig a well in 16 days. Paul can dig the same well in 24 days. Jake, Paul and Hari

together dig the well in 8 days. Hari alone can dig the well in ?

Ans.48 days.

Explanation: Given that speed of Jake is greater than Paul.

Distance = 24 km

Sum of their speed is 7 km/h = J+P

So possible speed ratio between J & P is

Go by Option

6:1 Not in option

5:2 = (24/5)+(24/2) 14 Hours

4:3 = (24/4)+(24/3) = 14 Hours

So Jakes speed is 4 km/h.

10. If a lemon and an apple together cost Rs. 12.00, a tomato and a lemon cost Rs. 4.00 and an

apple cost Rs.8.00 more than a tomato or a lemon then which of the following can be Page 2/4 the

price of a lemon?

Ans.2

Explanation: Let cost of a Lemon is L

Let cost of a Apple is A

Let cost of a Tomato is T

L+A = 12 (1)T+L = 4 - (2)

A = 8+L - (3)

A = 8+T - (4)

Sub (3) in (1)

L+8+L = 12

L = 2, A = 10, T = 2.