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Time variation. Combining electrostatics and magnetostatics: (1) . E = r / e o where r = r f + r b (2) . B = 0“no magnetic monopoles” (3) x E = 0 “conservative” (4) x B = m o j where j = j f + j M Under time-variation: (1) and (2) are unchanged, - PowerPoint PPT Presentation
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Time variationCombining electrostatics and magnetostatics:
(1) .E = /o where = f + b
(2) .B = 0 “no magnetic monopoles”
(3) x E = 0 “conservative”
(4) x B = oj where j = jf + jM
Under time-variation: (1) and (2) are unchanged, (3) becomes Faraday’s Law(4) acquires an extra term, plus 3rd component of j
Faraday’s Law of Inductionemf induced in a circuit equals the rate of change of magneticflux through the circuit
t
t
t
t
BE
SB
SE
SBE
ESB
Theorem Stokes'dd
.d.d
.d .d
..
EE
E E
by simply blerepresenti longer no so x
whichfor fieldstic electrosta for 0only general, in .d
0
0C
dS
B
dℓ
Displacement currentAmpere’s Law
currentssteady -non for t
1
1
0.
0..
j
Bj
BjjB
o
oo
Problem!
Steady current implies constant charge density so Ampere’s law consistent with the Continuity equation for steady currents
Ampere’s law inconsistent with the continuity equation (conservation of charge) when charge density time dependent
Continuity equation
Extending Ampere’s Lawadd term to LHS such that taking Div makes LHS also identically equal to zero:
The extra term is in the bracket
extended Ampere’s Law
0..
0..
jj
?j
B?j
or
1
o
jE
E
EE
...
..
ttt oo
oo
t
t
ooo
oo
EjB
BE
j
1
IˆI
I
SS
SV V
SnSj
EE
Ej
Sjj
D
D
DD
.dA
.d
At
Q
A
1
tt
A
Q density charge ousinstantane
t
.ddvt
dv .
oo
o
Illustration of displacement current
C
I
R
S
- +
oE
- +
o E/t
Discharging capacitor
Displacement current magnitude
Suppose E varies harmonically in time
EE
EE
t
kx)tsin(o
197
12o
oo
17
1.47.106.10
8.854.10
tyconductivi is here σ NBΩm6.10 Cu
EE
Ej
t
~ 10.19 rads-1 for oE/t to be comparable to E
Types of current j
• Polarisation current density from oscillation of charges inelectric dipoles• Magnetisation current density variation in magnitude ofmagnetic dipoles in space/time
PMf jjjj
tP
jP
tooo E
jB
M = sin(ay) k
k
i
j
jM = curl M = a cos(ay) i
Total current
MjM x
1st form of Maxwell’s Equations
all field terms on LHS and all source terms on RHSThe sources ( and j) are multiple (free, bound, mag, pol)special status of free source suggests 2nd Form
)(
0.
)( .
PMf
bf
t(4)
0t
(3)
(2)
(1)
jjjjjE
B
BE
B
E
ooo
o
Extending Ampere’s Law to H
D/t is displacement current postulated by Maxwell (1862)to exist in the gap of a capacitor being charged
In vacuum D = oE and displacement current exists throughoutspace
tt
tt
t
1t
ff
f
PMf
DjHPEjM
B
EPMj
EjjjB
EjB
oo
o
oo
ooo
2nd form of Maxwell’s EquationsApplies only to well behaved LIH media
Focus on sources means equations (2) and (3) unchanged!Recall Gauss’ Law for D
In this version of (1), f and o Recall H version of (4)
In this version of (4), j jf , also o and o
HHBEED oror and
f
ff EED ...
ff
ff
jE
BjD
H
jD
HD
jH
tt
tt
2nd and 3rd forms
LHS: 2nd form, free sources only, other sources hidden inpermittivity and permeability constantsRHS: 3rd form (Minkowsky) free sources only, mixed fields, noconstants
ff
ff
tt(4)
tt(3)
(2)
(1)
jD
HjE
B
BE
BE
BB
DE
0 0
0. 0.
. .
Electromagnetic Wave Equation
jE
BB
E
BE
ooo
o
t(4)
t(3)
(2)(1)
0
0. .
tt(1)
ttidentity
tt(4)
t(3)
jEE
EjEE
EjE
BE
oo
oo
ooo
ooo
2
22
2 0.
0
0
Firstform
Electromagnetic Waves in Vacuum
wavetransverse implies chosen form for z
0. then z If 0. then z|| If
ck
vk
kt
expexpt
expkexpz
exp
vector constant a isexpRe
o
oo
p2
22
2
22
2
22
22
oo
kztikzti
kztikztikzti
kzti
E
EEEE
EEE
E
EEE
oo
oo
oooo
1
00
2
22
speed of lightin vacuum
= ck = 2c/
k
Dispersion relation
Relationship between E and B
j j B
j B
E
iE
ˆˆ
ˆ
ˆ
kztikzti
kzti
kzti
expc
E expE
k
expE ikt
-x
expERe
oo
o
o
E || i
B || j
k || k
Plane waves in a nutshell
2
k i.e.
r 2r k
r k
expexp )i(i(kz)
k.r
0k.r)rk.(rk.r ||
k.r
rr
r||
k
Consecutive wave fronts
EM Waves in insulating LIH medium
Less than speed of light in vacuum complex in general, real (as has been assumed) if h<<Eg
rr
rr
o
tt
pp
22
2
2
2
ff
ff
v
cnindex Refractive
c
kv
k
k
t
exp
form (2nd
kzti
1
0
0
0
)0
2
2
2
22
EE
EE
EE
j
jEE
= ck/n = 2c/n
k
Dispersion relation
Slope=±c/n
Bound Charges
2222o
2222o
22oo
o2o
t)sin(t)cos(
m
eE-x
t)cos(eExmxmxm
1 2 3 4 5 6
-1
-0.5
0.5
1
xB
vB
t
o
-/2
-
+/2
0xB
vB
Phase relative to driving field vs frequency
Bound charge displacement xB
Or velocity vB versus time
Free Charges
tyconductivi Drude m
ec.f.
m
e
Et)cos(Em
et)cos(
m
Eexj
t)cos(
m
eE-)(x
t)sin(
m
eE-)x(
t)cos(eExmxm
22
o
2o
2
o
o
o
NN
NN
0
0
For a free charge, spring constant and o tend to zero
Dielectric susceptibility
litysusceptibi Dielectric V
ex-
moment Dipole-ex Ep
onPolarisati V
pEP
oE
o
Eo
2222o
2222o
22o
o
2
E
t)sin(t)cos(
mV
e
EM waves in conducting LIH medium
0
0
2
2
2
complex iskk
exp
t
t
and 0
form) (2nd tt
2
o
2
2
f
ff
ff2
2
kzti
i
t
t
EE
EEE
Ej
conduction Ohmic Ej
jEE
EM waves in conducting LIH medium
50Hz at Cu in 1cm2
depth skin 2
exp expexp
i)(12
1ik k
t
ztizkztioo
2
EEE
EE
EEE
i
t
ti
0
0
2
2
EM wave is attenuated within ~ skin depth in conducting mediaNB Insulating materials become ‘conducting’ when radiation frequency tuned above Eg
Energy in Electromagnetic Waves
Energy density in matter for static fields
2
1kz)t(cos
4
1
dv
Ud
kz)t(cos2
12
1
dv
dU
expexp
1 vacuum In2
1
dv
dU
2oooo
2oooo
kz)ti(o
kz)ti(o
.HH.EE
.HH.EE
H.HE.E
HH EE
HB ED
B.HD.E
oo
oo
oo
rroo
Average obtained over one cycle of light wave
Energy in Electromagnetic Waves
Average energy over one cycle of light wave
oooo4
1
dv
Ud.HH.EE oo
Distance travelled by light over one cycle = 2c/= cAverage energy in volume ab c
a
b
c
Energy in Electromagnetic Waves
)( timeperiodic per (ab) area unit crossingEnergy HE2
1
ab
U
HE2c
1
2
1
2
1HE
2
1
abc
U
B
cB
H
E
E
H
2
1
H
E
2
1HE
2
1
abc
U
c
EB c
BH
abc4
1U
oo
oooo
o
o
o
o
o
o
o
ooo
oo
oo
oooo
oo
oo
o
o
o
o
oo
oo
oo
ooo
oo
1
.HH.EE
Poynting Vector
N = E x H is the Poynting vector
Equal to the instantaneous energy flow associated with an EM wave
In vacuum N || wave vector k
Example If the E amplitude of a plane wave is 0.1 Vm-1
Energy crossing unit area per second is
25
o
o2ooo Wm1.3.10E
2
1HE
2
1