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Thermodynamics Principles
Specific internal energy
It is the energy stored in the substance due to molecular motion as well as intermolecular forces.
The SI unit is kJ/kg.
Specific enthalpy (h)
It is the sum of the specific internal energy and the product of pressure P versus specific volume,
v. The SI unit is kJ/kg.
Thermal power (Q)
It is the form of energy rate transferred to or from the machine due to a difference of
temperatures between the machine and the surroundings, the higher temperature to the lower
one.
Specific heat at constant pressure (Cp)
Cp = dhdT
Specific heat at constant volume (CV)
CV= du/dT
For an ideal gas, there is a very useful relationship between these two specific heats given by
CpCV = R
First Law of Thermodynamics Analysis for Control Volumes
Thermal machines convert chemical energy in shaft work by burning fuel (heat) in a combustion
chamber. In doing so, mass fluxes of air and fuel enter the machine and combustion products exit
it. In a working machine, energy in its several forms is presented in the conversion process, such
as heat, shaft work, enthalpy, and chemical energy. Even though energy is transformed from one
form into another, the overall amount of energy must be conserved as stated by the First Law of
Thermodynamics. In order to establish the First Law consider the schematics in Fig. 2 showing a
control volume around a thermal machine
Energy balance for the control volume in Fig. 2 results in
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(dE )CV = mi [ hi+ V2+ Zi]- m0[ ho + V
2 + Zo] + QW
dt 2 2
Second Law of Thermodynamics Analysis for Control Volumes
The rate of entropy generated in a control volume (Fig. 2) can be written according to Eq. 17
(dS )CV misi- M0s0+ QCV/ T
dt
Where, S is the total instantaneous entropy of the control volume, Siand so are the specific
entropy associated with the inlet and outlet mass fluxes, T is the control volume surface
temperature where heat is exchanged with the surrounding environment at a given rate, Q cv
RANKINE CURVE
Process 1-2: The working fluid is pumped from low to high pressure, as the fluid is a liquid at
this stage the pump requires little input energy.
Process 2-3: The high pressure liquid enters a boiler where it is heated at constant pressure by an
external heat source to become a dry saturated vapor.
Process 3-4: The dry saturated vapor expands through aturbine,generating power. This
decreases the temperature and pressure of the vapor
Process 4-1: The wet vapor then enters acondenserwhere it is condensed at a constant
temperature to become asaturated liquid.
http://en.wikipedia.org/wiki/Turbinehttp://en.wikipedia.org/wiki/Turbinehttp://en.wikipedia.org/wiki/Turbinehttp://en.wikipedia.org/wiki/Surface_condenserhttp://en.wikipedia.org/wiki/Surface_condenserhttp://en.wikipedia.org/wiki/Surface_condenserhttp://en.wikipedia.org/wiki/Boiling_pointhttp://en.wikipedia.org/wiki/Boiling_pointhttp://en.wikipedia.org/wiki/Boiling_pointhttp://en.wikipedia.org/wiki/Boiling_pointhttp://en.wikipedia.org/wiki/Surface_condenserhttp://en.wikipedia.org/wiki/Turbine8/13/2019 Thermodynamics Principles
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Thermal Efficiency of Rankine Cycle:
Heat Input = Q23 = H3H2
Heat Rejected = Q41 = H4H1
Work Output = W34 = H3H4
Work done by Pump = W12 = H2H1
Work outputPump work W34W12 Heat Input Q23
1.1 FUEL POWER F.P.)Fuel power is the thermal power released by burning fuel inside the engine.
F.P. = mass of fuel burned per second x calorific value of the fuel.
F.P. = mf x C.V.All engines burn fuel to produce heat that is then partially converted into mechanical
power. The chemistry of combustion is not dealt with here. The things you need to
learn at this stage follow.
1.1.1 AIR FUEL RATIOThis is the ratio of the mass of air used to the mass of fuel burned.
Air Fuel Ratio = ma/mf
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CALORIFIC VALUEThis is the heat released by burning 1 kg of fuel. There is a higher and lower value for
fuels containing hydrogen. The lower value is normally used because water vapour
formed during combustion passes out of the system and takes with it the latent energy.
We can now define the fuel power.
FUEL POWER = Mass of fuel/s x Calorific Value
COMBINED-CYCLE THERMODYNAMICS
A gas turbine cycle is depicted symbolically in Fig. 1. By definition, the efficiency of the gas
turbine is given by
gt = Wgt / QH
where _Qh is the energy input rate from the high-temperature source at temperature Th, and
_Wgt is the power output delivered to an electric generator. By energy conservation, the rate of
energy transfer to the lower-temperature reservoir at the exhaust temperature Tex is
QEX= Qh - Wgt
The gas-turbine cycle is based upon the reversible JouleBrayton cycle . The JouleBrayton
cycle models not only gas turbine power plants but also the familiar gas turbines of jet
engines.19Because they can burn relatively clean fuel, have relatively low capital costs, and can
be started and stopped quickly, gas turbines have become popular for electricity peaking and
emergency power generation, as well as for base load operations (providing minimum power
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requirements).16 Stationary gas turbines have the flexibility to burn not only methane but also
distillate oil, which though less clean than natural gas, is often preferable to coal for power
plants. The basic operation in Fig. 2 entails compression of air (12), providing the high pressure
needed to drive the turbine Then combustion of a fuel, typically methane (23), increases the
temperature and energy of the gas stream. Segment 34 represents the combustion gases
expanding as they drive the rotating turbine, and 41 cools and exhausts the hot gases at constant
atmospheric pressure, thereby dumping wasted energy to the environment. Advances in
metallurgy and cooling technology during recent years have enabled ever higher combustion and
exhaust temperatures. Modern gas turbines with ultra-high combustion temperatures have
efficiencies of about 0.4, roughly the same as the most advanced coal-burning plants. However,
they not only have the advantage of much higher inlet temperatures than steam turbines but also
characteristically have the disadvantage of much higher exhaust temperatures, T4 _ Tex in Fig.
2. Thus, a gas turbine cycle can dump substantial amounts of wasted energy to the environment,
which limits its efficiency. For high-efficiency operation, one generally wants a high inlet
(maximum) temperature, which gas turbines have, but also a low exhaust temperature, near that
of the environment, which gas turbines lack. Bejan cites various sources of irreversibility that
plague gas turbines and explains how clever engineering designs, entailing regenerative heat
exchangers, reheaters, and intercoolers, can bring higher efficiencies.20 However, even greater
efficiency gains are possible for electricity generation by using the high-temperature exhaust of
the gas turbine to power a steam cycle, which inherently has a much lower exhaust temperature.
For example, a gas turbine with inlet and exhaust temperatures 1673K and 873K, respectively,
might use the exhaust gases to heat a steam turbine that has exit temperature 350K, achieving the
overall temperature range, 1673 K ! 350 K. A single gas turbine cycle cannot match this. In this
regard, Bejan writes,gas-turbine cycles are better suited for efficient operation at high
temperatures than steam-turbine cycles. On the other hand, the steam-turbine cycle is more
attractive from the point of view of minimizing the temperature gap between the cold end of the
cycle and the low-temperature reservoir The engineering challenge that remains is to mesh
optimally the two cycles along that seam of intermediate temperatures where the upper (warmer)
cycle must act as a heat source for the lower one. The bottom line is that existing combined
cycles are more efficient than any currently achievable single cycle. In the simplest combined-
cycle design, the gas turbine drives one electric generator and the steam turbine runs another, as
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illustrated in Figs. 3 and 4. Ignoring losses in the heat exchanger, the inlet temperature to the
steam turbine is Tex. Combining Eqs. (3) and (4), the waste energy rate,
QEX= Qh - gt QH
In the exhaust gases becomes the input power for the steamturbine cycle, whose efficiency we
call
st =Wst / Qex
Thus,the power output delivered by the steam turbine is
Wst = st Qex = st (QH - gt Qh
Combining Eqs. (3) & (6), the total power delivered by the bgas and steam turbine combination
is
Wtot = Wgt + Wst = gt + st (1- gt) Qhand the combined-cycle efficiency is,
cc = Wtot / Qh = gt + stgtst
Simple Brayton Cycle
In an actual gas turbine, the working fluid changes from atmospheric air to combustion products thatexhaust back to the atmosphere, as illustrated in Fig. 5a. However, in order to evaluate the machine fromthe thermodynamic point-of-view, some assumptions are needed. Firstly, the working fluid is assumed tobe plain air, without any chemical transformation due to the combustion. In doing so, the airfuelcombustion process is replaced by a heat addition process at a constant pressure. Secondly, the exhaustand admission processes are replaced by a heat transfer process to the environment, which makes the
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air to flow continuously in a closed loop as indicated in Fig. 5b. In the closed cycle, air at environment pressureand temperature is first compressed, next it receives heat QH and it is followed by an expansion process in the
turbine section to, finally, reject heat QL at constant pressure. This is the Air-Standard Brayton Cycle. Having the
cycle of Fig. 5b in mind along with the ideal gas behavior and constant thermodynamic properties one may obtain
the working equations from an energy balance (Eq. 16) for each cycle component:
Heat addition:qH = h3 - h2 = CP(T3 - T2 )
Heat rejection:qL = h4 - h1 = CP(T4_ T1)
Compression work:wcomp = h2 - h1 = CP(T2_ T1 )
Turbine work:Wtur = h3 - h4 = CP(T3 - T4)
The thermal efficiency, gth; of a cycle is defined as the ratio between the cycle net work and heat added, as given byEq. 35. By applying the First Law for the whole cycle, one easy can show that w = qH- qL. Therefore, one obtains:
th = 1qL / qH
By examining the temperature-entropy diagram in Fig. 6a, one can easily notice that T3 is the maximum cycle
temperature, also known as the firing temperature, while T 1 is the minimum one (usually the environmenttemperature).
By using isentropic ideal gas relationships between pressure and temperature Eq. 34), it is straightforward to show
that
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