Thermodynamics Principles

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    Thermodynamics Principles

    Specific internal energy

    It is the energy stored in the substance due to molecular motion as well as intermolecular forces.

    The SI unit is kJ/kg.

    Specific enthalpy (h)

    It is the sum of the specific internal energy and the product of pressure P versus specific volume,

    v. The SI unit is kJ/kg.

    Thermal power (Q)

    It is the form of energy rate transferred to or from the machine due to a difference of

    temperatures between the machine and the surroundings, the higher temperature to the lower

    one.

    Specific heat at constant pressure (Cp)

    Cp = dhdT

    Specific heat at constant volume (CV)

    CV= du/dT

    For an ideal gas, there is a very useful relationship between these two specific heats given by

    CpCV = R

    First Law of Thermodynamics Analysis for Control Volumes

    Thermal machines convert chemical energy in shaft work by burning fuel (heat) in a combustion

    chamber. In doing so, mass fluxes of air and fuel enter the machine and combustion products exit

    it. In a working machine, energy in its several forms is presented in the conversion process, such

    as heat, shaft work, enthalpy, and chemical energy. Even though energy is transformed from one

    form into another, the overall amount of energy must be conserved as stated by the First Law of

    Thermodynamics. In order to establish the First Law consider the schematics in Fig. 2 showing a

    control volume around a thermal machine

    Energy balance for the control volume in Fig. 2 results in

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    (dE )CV = mi [ hi+ V2+ Zi]- m0[ ho + V

    2 + Zo] + QW

    dt 2 2

    Second Law of Thermodynamics Analysis for Control Volumes

    The rate of entropy generated in a control volume (Fig. 2) can be written according to Eq. 17

    (dS )CV misi- M0s0+ QCV/ T

    dt

    Where, S is the total instantaneous entropy of the control volume, Siand so are the specific

    entropy associated with the inlet and outlet mass fluxes, T is the control volume surface

    temperature where heat is exchanged with the surrounding environment at a given rate, Q cv

    RANKINE CURVE

    Process 1-2: The working fluid is pumped from low to high pressure, as the fluid is a liquid at

    this stage the pump requires little input energy.

    Process 2-3: The high pressure liquid enters a boiler where it is heated at constant pressure by an

    external heat source to become a dry saturated vapor.

    Process 3-4: The dry saturated vapor expands through aturbine,generating power. This

    decreases the temperature and pressure of the vapor

    Process 4-1: The wet vapor then enters acondenserwhere it is condensed at a constant

    temperature to become asaturated liquid.

    http://en.wikipedia.org/wiki/Turbinehttp://en.wikipedia.org/wiki/Turbinehttp://en.wikipedia.org/wiki/Turbinehttp://en.wikipedia.org/wiki/Surface_condenserhttp://en.wikipedia.org/wiki/Surface_condenserhttp://en.wikipedia.org/wiki/Surface_condenserhttp://en.wikipedia.org/wiki/Boiling_pointhttp://en.wikipedia.org/wiki/Boiling_pointhttp://en.wikipedia.org/wiki/Boiling_pointhttp://en.wikipedia.org/wiki/Boiling_pointhttp://en.wikipedia.org/wiki/Surface_condenserhttp://en.wikipedia.org/wiki/Turbine
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    Thermal Efficiency of Rankine Cycle:

    Heat Input = Q23 = H3H2

    Heat Rejected = Q41 = H4H1

    Work Output = W34 = H3H4

    Work done by Pump = W12 = H2H1

    Work outputPump work W34W12 Heat Input Q23

    1.1 FUEL POWER F.P.)Fuel power is the thermal power released by burning fuel inside the engine.

    F.P. = mass of fuel burned per second x calorific value of the fuel.

    F.P. = mf x C.V.All engines burn fuel to produce heat that is then partially converted into mechanical

    power. The chemistry of combustion is not dealt with here. The things you need to

    learn at this stage follow.

    1.1.1 AIR FUEL RATIOThis is the ratio of the mass of air used to the mass of fuel burned.

    Air Fuel Ratio = ma/mf

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    CALORIFIC VALUEThis is the heat released by burning 1 kg of fuel. There is a higher and lower value for

    fuels containing hydrogen. The lower value is normally used because water vapour

    formed during combustion passes out of the system and takes with it the latent energy.

    We can now define the fuel power.

    FUEL POWER = Mass of fuel/s x Calorific Value

    COMBINED-CYCLE THERMODYNAMICS

    A gas turbine cycle is depicted symbolically in Fig. 1. By definition, the efficiency of the gas

    turbine is given by

    gt = Wgt / QH

    where _Qh is the energy input rate from the high-temperature source at temperature Th, and

    _Wgt is the power output delivered to an electric generator. By energy conservation, the rate of

    energy transfer to the lower-temperature reservoir at the exhaust temperature Tex is

    QEX= Qh - Wgt

    The gas-turbine cycle is based upon the reversible JouleBrayton cycle . The JouleBrayton

    cycle models not only gas turbine power plants but also the familiar gas turbines of jet

    engines.19Because they can burn relatively clean fuel, have relatively low capital costs, and can

    be started and stopped quickly, gas turbines have become popular for electricity peaking and

    emergency power generation, as well as for base load operations (providing minimum power

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    requirements).16 Stationary gas turbines have the flexibility to burn not only methane but also

    distillate oil, which though less clean than natural gas, is often preferable to coal for power

    plants. The basic operation in Fig. 2 entails compression of air (12), providing the high pressure

    needed to drive the turbine Then combustion of a fuel, typically methane (23), increases the

    temperature and energy of the gas stream. Segment 34 represents the combustion gases

    expanding as they drive the rotating turbine, and 41 cools and exhausts the hot gases at constant

    atmospheric pressure, thereby dumping wasted energy to the environment. Advances in

    metallurgy and cooling technology during recent years have enabled ever higher combustion and

    exhaust temperatures. Modern gas turbines with ultra-high combustion temperatures have

    efficiencies of about 0.4, roughly the same as the most advanced coal-burning plants. However,

    they not only have the advantage of much higher inlet temperatures than steam turbines but also

    characteristically have the disadvantage of much higher exhaust temperatures, T4 _ Tex in Fig.

    2. Thus, a gas turbine cycle can dump substantial amounts of wasted energy to the environment,

    which limits its efficiency. For high-efficiency operation, one generally wants a high inlet

    (maximum) temperature, which gas turbines have, but also a low exhaust temperature, near that

    of the environment, which gas turbines lack. Bejan cites various sources of irreversibility that

    plague gas turbines and explains how clever engineering designs, entailing regenerative heat

    exchangers, reheaters, and intercoolers, can bring higher efficiencies.20 However, even greater

    efficiency gains are possible for electricity generation by using the high-temperature exhaust of

    the gas turbine to power a steam cycle, which inherently has a much lower exhaust temperature.

    For example, a gas turbine with inlet and exhaust temperatures 1673K and 873K, respectively,

    might use the exhaust gases to heat a steam turbine that has exit temperature 350K, achieving the

    overall temperature range, 1673 K ! 350 K. A single gas turbine cycle cannot match this. In this

    regard, Bejan writes,gas-turbine cycles are better suited for efficient operation at high

    temperatures than steam-turbine cycles. On the other hand, the steam-turbine cycle is more

    attractive from the point of view of minimizing the temperature gap between the cold end of the

    cycle and the low-temperature reservoir The engineering challenge that remains is to mesh

    optimally the two cycles along that seam of intermediate temperatures where the upper (warmer)

    cycle must act as a heat source for the lower one. The bottom line is that existing combined

    cycles are more efficient than any currently achievable single cycle. In the simplest combined-

    cycle design, the gas turbine drives one electric generator and the steam turbine runs another, as

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    illustrated in Figs. 3 and 4. Ignoring losses in the heat exchanger, the inlet temperature to the

    steam turbine is Tex. Combining Eqs. (3) and (4), the waste energy rate,

    QEX= Qh - gt QH

    In the exhaust gases becomes the input power for the steamturbine cycle, whose efficiency we

    call

    st =Wst / Qex

    Thus,the power output delivered by the steam turbine is

    Wst = st Qex = st (QH - gt Qh

    Combining Eqs. (3) & (6), the total power delivered by the bgas and steam turbine combination

    is

    Wtot = Wgt + Wst = gt + st (1- gt) Qhand the combined-cycle efficiency is,

    cc = Wtot / Qh = gt + stgtst

    Simple Brayton Cycle

    In an actual gas turbine, the working fluid changes from atmospheric air to combustion products thatexhaust back to the atmosphere, as illustrated in Fig. 5a. However, in order to evaluate the machine fromthe thermodynamic point-of-view, some assumptions are needed. Firstly, the working fluid is assumed tobe plain air, without any chemical transformation due to the combustion. In doing so, the airfuelcombustion process is replaced by a heat addition process at a constant pressure. Secondly, the exhaustand admission processes are replaced by a heat transfer process to the environment, which makes the

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    air to flow continuously in a closed loop as indicated in Fig. 5b. In the closed cycle, air at environment pressureand temperature is first compressed, next it receives heat QH and it is followed by an expansion process in the

    turbine section to, finally, reject heat QL at constant pressure. This is the Air-Standard Brayton Cycle. Having the

    cycle of Fig. 5b in mind along with the ideal gas behavior and constant thermodynamic properties one may obtain

    the working equations from an energy balance (Eq. 16) for each cycle component:

    Heat addition:qH = h3 - h2 = CP(T3 - T2 )

    Heat rejection:qL = h4 - h1 = CP(T4_ T1)

    Compression work:wcomp = h2 - h1 = CP(T2_ T1 )

    Turbine work:Wtur = h3 - h4 = CP(T3 - T4)

    The thermal efficiency, gth; of a cycle is defined as the ratio between the cycle net work and heat added, as given byEq. 35. By applying the First Law for the whole cycle, one easy can show that w = qH- qL. Therefore, one obtains:

    th = 1qL / qH

    By examining the temperature-entropy diagram in Fig. 6a, one can easily notice that T3 is the maximum cycle

    temperature, also known as the firing temperature, while T 1 is the minimum one (usually the environmenttemperature).

    By using isentropic ideal gas relationships between pressure and temperature Eq. 34), it is straightforward to show

    that

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