90
Calculate the volume of gas released at 227 o C under 83.1 kPa pressure when 16 kg of NH 4 NO 3 is exploded forming N 2 , O 2 , & H 2 O:

Thermo-chemistry

Embed Size (px)

DESCRIPTION

Calculate the volume of gas released at 227 o C under 83.1 kPa pressure when 16 kg of NH 4 NO 3 is exploded forming N 2 , O 2 , & H 2 O:. Thermo-chemistry. Thermochemistry. The study of heat transfer in chemical reactions. Thermochemistry. Heat change Calorimetry TCE. - PowerPoint PPT Presentation

Citation preview

Page 1: Thermo-chemistry

Calculate the volume of gas released at 227oC

under 83.1 kPa pressure when 16 kg of NH4NO3 is exploded forming N2,

O2, & H2O:

Page 2: Thermo-chemistry

Thermo-chemistry

Page 3: Thermo-chemistry

Thermochemistry

•The study of heat transfer in

chemical reactions

Page 4: Thermo-chemistry

Thermochemistry•Heat change

•Calorimetry

•TCE

Page 5: Thermo-chemistry

Thermo-chemical

Terms

Page 6: Thermo-chemistry

System

•That part of nature upon which

attention is focused

Page 7: Thermo-chemistry

Surroundings•That part of nature

around the part upon which we are

focused

Page 8: Thermo-chemistry

Reaction Coordinate

•A graph of energy change versus time in a chemical reaction

Page 9: Thermo-chemistry

Time

Ene

rgy

RP

Page 10: Thermo-chemistry

Exothermic Rxn•Chemical reactions

that release, give off heat, or lose

heat

Page 11: Thermo-chemistry

Endothermic Rxn

•Chemical reactions that absorb, take in heat, or gain heat

Page 12: Thermo-chemistry

Heat Change

Page 13: Thermo-chemistry

Specific Heat•The heat required to raise one gram of a substance 1oC

•C: (J/goC, J/kgoK)

Page 14: Thermo-chemistry

Sp. Heat

H = mCT

Page 15: Thermo-chemistry

Heat of Fusion•The heat required to melt one gram of a substance at its normal MP

•Hf: (J/g or J/kg)

Page 16: Thermo-chemistry

Heat of Fusion

H = mHf

Page 17: Thermo-chemistry

Heat of Vaporization

•The heat required to boil one gram of a substance at its normal BP

•Hv: (J/g or J/kg)

Page 18: Thermo-chemistry

Heat of Vap.

H = mHv

Page 19: Thermo-chemistry

Calculate the heat change when 10.0 g H2O goes from –100.0oC to 200oC.MP = 0oC BP = 100oCHf = 334 J/g HV = 2260 J/g

Cice = 2.06 J/gKCwater = 4.18 J/gK Csteam = 2.02 J/gK

Page 20: Thermo-chemistry

Drill: Calculate the heat required to change 25 g

of water from 140.0oC to 60.0oC

MP = 0oC BP = 100oCHf = 334 J/g HV = 2260 J/g

Cice = 2.06 J/gKCwater = 4.18 J/gK Csteam = 2.02 J/gK

Page 21: Thermo-chemistry

Calorimetry•Experimental measure of heat transfer

Page 22: Thermo-chemistry

Calorimeter•Device used to measure heat transfer

•A calorimeter is an adiabatic system

•Experimental yield

Page 23: Thermo-chemistry

Adiabatic System•A system that exchanges zero heat with its surroundings

Hsystem = 0

Page 24: Thermo-chemistry

H (J)H = q = the heat or enthalpy change in a system

Hsys = mCTsys parts

Page 25: Thermo-chemistry

CalorimetryHsystem = 0

Hsys = Hcal + Hrxn

Hrxn = -Hcal

Hrxn = -mCTcal

Page 26: Thermo-chemistry

When Q reacts in a 1.5 kg calorimeter containing 2.5

kg water ch. from 22.5oC to 26.5oC. Calculate Hrxn.

Cwater = 4.18 J/gK Ccal = 2.00 J/gK

Page 27: Thermo-chemistry

When X reacts in a 2.0 kg calorimeter containing 1.5 kg water went from 22.5oC to 30.5oC. Calculate Hrxn.

Cwater = 4.18 J/gK Ccal = 1.50 J/gK

Page 28: Thermo-chemistry

Homework•Problems 7 & 8

•On page 234

Page 29: Thermo-chemistry

Thermo-chemical Equation

Terms

Page 30: Thermo-chemistry

Typical Reaction

•HCl + NaOH NaCl + HOH

Page 31: Thermo-chemistry

Heat of Reaction•The heat or enthalpy change of a chemical reaction

Hrxn

Page 32: Thermo-chemistry

Typical Ionization

HCl

H+(aq) + Cl-

(aq)

Page 33: Thermo-chemistry

Heat of Solution

•The heat or enthalpy change when a substance is dissolved

Hsoln

Page 34: Thermo-chemistry

Combustion Reaction

•CxHy + O2

CO2 + HOH

Page 35: Thermo-chemistry

Heat of Combustion•The heat or enthalpy change when a substance is burned

Hcombustion

Page 36: Thermo-chemistry

Rxn Making Cpds from ele

H2 + ½ O2 H2O

Page 37: Thermo-chemistry

Heat of Formation•The heat required to form one mole of a compound from pure elements

Hfo (kJ/mole)

Page 38: Thermo-chemistry

The Degree Symbol•Indicates standard conditions & molar

quantities by itself or from a balanced

equation.

Page 39: Thermo-chemistry

Enthalpy•Heat flow in a

system

H

Page 40: Thermo-chemistry

Gibb’s Free Energy•Energy of a system that can be converted to work

•Determines spontaneity

G

Page 41: Thermo-chemistry

Energy of Formation•The energy required to form one mole of a compound from pure elements

Gfo (kJ/mole)

Page 42: Thermo-chemistry

Exergonic Reaction•A reaction in which free energy is given off

G < 0

Page 43: Thermo-chemistry

Endergonic Reaction

•A reaction in which free energy is absorbed

G > 0

Page 44: Thermo-chemistry

Exergonic Reaction•A reaction which can be spontaneous

G < 0

Page 45: Thermo-chemistry

Endergonic Reaction

•A reaction which cannot be spontaneous

G > 0

Page 46: Thermo-chemistry

Reaction at Equilibrium

G = 0

Page 47: Thermo-chemistry

Interrelation Term (G)

G interrelates thermochemistry,

chemical equilibria, & electrochemistry

Page 48: Thermo-chemistry

Entropy•A measure of disorder

So

Page 49: Thermo-chemistry

Entropy of Formation•The entropy of one mole of a substance

•Sfo (J/moleoK)

Page 50: Thermo-chemistry

Drill: Define:• Heat of reaction

• Heat of solution

• Heat of formation

• Energy of formation

• Entropy of formation

Page 51: Thermo-chemistry

Thermochemical Equation

•An equation that shows changes in heat, energy, etc

Page 52: Thermo-chemistry

Drill: Identify type of rxn when:

G > 0G < 0G = 0

Page 53: Thermo-chemistry

Thermochemical Equation

Ho

rxn Hf

o

productsHf

o

reactants

Page 54: Thermo-chemistry

Thermochemical Equation

Go

rxn Gf

o

productsGf

o

reactants

Page 55: Thermo-chemistry

Thermochemical Equation

So

rxnSf

o

products

Sfo

reactants

Page 56: Thermo-chemistry

Thermochemical Equation

•Stoichiometry of heat change

•Solves theoretical yield

Page 57: Thermo-chemistry

Interrelating Equation

GH

S

Page 58: Thermo-chemistry

Calculate H, G, & S when 19.7 kg of BaCO3 is decomposed into BaO + CO2

Cmpd BaCO3 CO2 . BaO

Hf

o -1216.3 -393.5 -553.5

Gf

o -1137.6 -394.4 -525.1

Sf

o 112.1 213.6 70.4

Page 59: Thermo-chemistry

Calculate H, G, & S when 13.6 g of CaSO4 is changed

into CaO + SO2 + O2 at 27oC

Cmpd CaSO4 SO2 CaO

Hf

o -1434.1 -296.8 -635.1

Gf

o -1321.8 -300.2 -604.0

Page 60: Thermo-chemistry

Calculate the potential H, G, & S for the reaction & Sf

o for

O2 when burning 8.8 kg of C3H8 Cpd C3H8 CO2 H2O

Hf

o-103.8 -393.5 -241.8

Gf

o- 23.5 -394.4 -228.6

Sf

o269.9 213.6 188.7

Page 61: Thermo-chemistry

Calculate Ho, Go, & S when P + QR PR2 + Qat -23oC & Teq

Compd QR PR2

Hfo(kJ/mole) -250 -450

Gfo(kJ/mole) -225 -425

Page 62: Thermo-chemistry

Heat Change•Calculate the heat change when the temperature of 1.0 kg H2O is changed from –100.0oC to 200.0oC.

Page 63: Thermo-chemistry

Lab Results: Cup H2O NaOH Thermo

5.0 g 50.0 g 4.0 g 15.0 g Ti = 22.0

oC Tf = 27.0

oC

Cmpd NaOH Na+ OH-

Hf

o -425.6 -240.1 -230.0

Determine: theoretical and experimental heat changes

Page 64: Thermo-chemistry

When 2.00 g NaOH dissolves in a 1.0 L water in a 2.5 kg calorimeter, the temp. went

from 22.5oC to 26.5oC. Calculate: Ho

soln Cwater = 4.18 J/gK Ccal = 2.00 J/gK

Page 65: Thermo-chemistry

Bond Energy•The energy change

when one mole of bonds are broken

Ho

bond

Page 66: Thermo-chemistry

Bond Equation

Hbondo

rxnHbond

o

products

Hbondo

reactants

Page 67: Thermo-chemistry

Bond Energies (kJ/mole)

C-C 347

C-H 414

O-H 464

C=O 715

Page 68: Thermo-chemistry

Drill:Calculate H, G, & S in the production of 831mL

ammonia at 227oC under

250.0 kPa pressureCompd NH3

Hfo -46.1

Gfo -16.5

Page 69: Thermo-chemistry

HOLY MACKERAL

Page 70: Thermo-chemistry

1st Law Thermodynamics

•Total energy change = heat + work

E = q + W

Page 71: Thermo-chemistry

Work•W = Fd

•P = F/A

•V = Ad

•W = PV = nRT

Page 72: Thermo-chemistry

2nd Law Thermodynamics

•Total entropy in a system always increases assuming no energy is added to the system

Page 73: Thermo-chemistry

Thermodynamic Rxns are State

Rxns

Page 74: Thermo-chemistry

State Reaction•Reactions that are independent of the

path; thus not dependent on intermediates

Page 75: Thermo-chemistry

Calculate Ho, Go, & S when A + BC AC2 + Bat -23oC & solve Teq

Compd BC AC2

Hfo(kJ/mole) -150 -250

Gfo(kJ/mole) -125 -225

Page 76: Thermo-chemistry

Hess’s LawHrxn is the same

whether it occurs in a single step or a series

of steps.

Page 77: Thermo-chemistry

Calculate Ho, Go, & S when A + BC AC + Bat -23oC & Teq

Compd BC ACHf

o(kJ/mole) -150 -250Gf

o(kJ/mole) -175 -225

Page 78: Thermo-chemistry

Write TE for the process2 A + B C + D

C + A H

D + B 2 K

H + K M + B

K + M Product

Page 79: Thermo-chemistry

Write TE for the process2 A + B C + D

C + A H

D + B 2 K

H + K M + B

K + M Product

Page 80: Thermo-chemistry

Write TE for the process2 A + 2 B C + D

C + A 2 H

D + B 2 K

H + K P + B

Page 81: Thermo-chemistry

Write TE for the process2 A + 2 B C + D

C + A 2 H

D + B 2 K

2 H + 2 K 2 P + 2 B

Page 82: Thermo-chemistry

Drill: When 5.00 g NsCO3 is decomposed to NsO & CO2 in a 500.0 g calorimeter (C = 1.50 J/gK) containing 250 g of water (C = 4.18 J/gK), the water changes from 25.00oC to 45.00oC. Calculate the heat of rxn/mole of NsCO3

Page 83: Thermo-chemistry

Substance Hof(kJ.mole)

S H S HA -100 H -150B -150 K -200C -50 P -250D -125 Q -300

Page 84: Thermo-chemistry

Write TE for the process A + B 2 C + 2 D

C + A 2 H + P

D + B 2 K + P

H + K P + Q

Page 85: Thermo-chemistry

Review

Page 86: Thermo-chemistry

Calculate Htotal, when 40.0 g of

H2O is changed from - 25oC to

125oC. FPw = 0.0oC

BPw = 100.0 oC Hv = 2260 J/gCice = 2.06 (J/g K) Hf = 334 J/gCwater = 4.18 (J/g K)Csteam = 2.02 (J/g K)

Page 87: Thermo-chemistry

Calculate Ho, G

o, & S for

AD2 + BC AC2 + BD

at (-23oC)

Cpd BC AD2 AC2 BD

Hf

o -150 -250 -300 -175

Gf

o -125 -225 -250 -150

Sf

o 75 50 80 ?

Determine Sf

o

BD

Page 88: Thermo-chemistry

Calculate Ho, Go, & So for PbO2 + CO CO2 + Pb

Cpd PbO2 CO CO2 Hf

o -277.4 -110.5 -393.5

Gfo -217.4 -137.2 -394.4

Calculate: Teq & H of 48 g PbO2

Page 89: Thermo-chemistry

Calculate Ho, Go, & So for N2O5 + H2O HNO3

Cpd N2O5 H2O HNO3 Hf

o -11.3 -285.8 -174.1

Gfo -10.4 -237.2 -151.5

Page 90: Thermo-chemistry

What does each symbol represent?

Define what is represents:

H:G:S: