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8/9/2019 Ther 1 - 110614
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Eng’r Armando C. EmataNovember 6, 2014
THERMODYNAMICS 1
BASIC PRINCIPLES,CONCEPTS AND DEFINITIONS
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TOPIC OBJECTIVES
Study the system of units as
used in Thermodynamics
no! more a"out acce#eration as de$ned"y Ne!ton
Distin%uish "et!een mass and !ei%ht
Di&erentiate amon% s'eci$c (o#ume,density and s'eci$c !ei%ht
So#(e sam'#e 'ro"#ems on a"o(e discussion
Assi%nment for ne)t meetin%
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SYSTEM OF UNITS
“The acceleration of a particular body is directly proportional to the resultant force acting on it andinversely proportional to its mass.” * Sir Isaac
Ne!ton
a = kF/m
+any systems of units ha(e "een "ased on thismomentous statement
-e de$ne a consistent system of units as one for!hich the 'ro'ortiona#ity constant k is unity. ine/uation form,
F 0 ma 1232A4
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SYSTEM OF UNITS
!here force is de$ned in terms of mass and mass interms of force
Acce#eration has the dimensions of #en%th 'er unit
time s/uared, L/t²A dimension is an attri"ute to somethin% in %enera#
terms. thus, #en%th L is a#so an attri"ute of (o#ume L
5nits are dimensiona# characteristics e)'ressed in
de$ned /uantities The #en%th of a foot is accurate#y de$ned 1in terms of
the Internationa# meter 0 2,678,96:9: !a(e#en%ths
from e#ectrica##y e)cited ry'ton ;64
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SYSTEM OF UNITS
De$ned units of time are seconds, minutes,hours, days, etc
In En%#ish units, a unit /uantity of acce#erationis most often ta, or f's>4
From E/ 232A, a unit force is one that 'roducesunit acce#eration in a "ody of unit mass On the"asis of this de$nition, one can decide u'on theunits for terms in %rou's of sym"o#s !here it issaid that units must "e consistent
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SYSTEM OF UNITS
Systems of units !here ! is unity "ut notdimension#ess?
c%s system ? 2 dyne force acce#erates 2 %mass at 2 cm=s>
m
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SYSTEM OF UNITS
< 0 33333333333 < 0 2 33333333333333333 < 0 2
333333333333
2 %m 2
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SYSTEM OF UNITS
Systems of units !here ! is not unity?
If the same !ord is used for "oth mass and
force in a %i(en system, C is neither unity nordimension#ess
2 #" force acce#erates a 2 #" mass at :@29ft=s>
2 % force acce#erates a 2 % mass at ;866cm=s>
2
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SYSTEM OF UNITS
< 0 :@29 3333333333 < 0 ;866 3333333333 < 0
;866 3333333333
2 #"m 2 %m 2 ;866 cm=s> ;866 m=s>
f m
#" 3 s>f
#" 3 ftm
% 3 s>f
% 3 cmm
f
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SYSTEM OF UNITS
Re#ation "et!een
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SYSTEM OF UNITS
Re#ation "et!een 'ound mass 1#" 4 and s#u%
< 0 2 333333333333 < 0 :@29 33333333333
Therefore, 2 33333333333 0 :@29 33333333333
2 s#u% 0 :@29 #"
m
#" 3 s>f
s#u% 3 ft
#" 3 s>f
#" 3 ftm
#" 3 s>f
s#u% 3 ft
#" 3 s>f
#" 3 ftm
m
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ACCELERATION
A unit force is one that 'roduces unitacce#eration in a "ody of unit mass
F 0 m=
m
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ACCELERATION
F 0 m=
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MASS AND WEIGHT
The mass of a "ody is the a"so#ute /uantity ofmatter in it
The /uantity of matter has to do !ith Ne!tonsuni(ersa# %ra(itation #a!, in e/uation form, is
F = " ##########
!here ? F is the force of attraction 1for theearths attraction on an earth#y system, thisthe force of %ra(ity4
gm$ m%
r²g
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MASS AND WEIGHT
"et!een the masses m$ and m% that are r distancea'art, and " is the %ra(itationa# constant
The &eight of a "ody means the force of gravity F on the "ody. it may "e determined "y a so3ca##eds'rin% sca#e
ra(ity 'roduces a force 'eld and a "ody in this
$e#d is su"ected to a body forceSince the force $e#d on the moon is much #ess than
that on the earth, the !ei%ht of a "ody is #ess there
g
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MASS AND WEIGHT
E)'ressed in e/uation
3333 0 3333 0 33333
!here ? % 0 acce#eration 'roduced "y force F
a 0 acce#eration 'roduced "y another
force FAt or near the surface of the earth,
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SAMPLE PROBLEMS
PROBLE+ 2?
-hat is the !ei%ht of a 663
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SAMPLE PROBLEMS
PROBLE+ @?
The !ei%ht of an o"ect is 78 #" -hat is its
mass at standard conditionGSo#ution?
F 0 78 #" % 0 :@29 ft=s>
m 0 33333 0 33333333333333333333333333333333333 0 78#"
% f
F%
<
H78 #" H:@29 33333333333 f #" 3 s>f#" 3 ftm
:@29 ft=s>m
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SAMPLE PROBLEMS
PROBLE+ :?
Fi(e masses in a re%ion !here the acce#erationdue to %ra(ity is :87 ft=s> are as fo##o!s? mJ 0
788 % of mass. mK !ei%hs ;88 %. m !ei%hs 27'ounda#s. mM !ei%hs : #" . m is 82 s#u% of mass-hat is the tota# mass e)'ressed 1a4 in %rams, 1"4in 'ounds, and 1c4 in s#u%sG
So#ution?
% 0 1:87 ft=s>412@ in=ft41@7 cm=in4 0 @6cm=s>
f
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SAMPLE PROBLEMS
PROBLE+ :?
So#ution cont(d?
1a4 mK 0 3333333 0 33333333333333333333333333333333333 0;:2 %
3333 0 333333 3333333333333 0 H8 #" H7:6 33333
F
%
H;88 % H;866 33333333333 f % 3 s>f
% 3 cmm
@6 cm=s>m
m
<
F%
%
27 333333333s>
#" 3 ftm
:87 3333ft
s>
%
#"
m
m
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SAMPLE PROBLEMS
PROBLE+ :?
So#ution cont(d?
3333 0 @@@@6 %
mM 0 3333333 0 33333333333333333333333333333 H7:633333
m
<m
F f
#" 3 ftm
:87 3333ft
s>
%#"
m
m
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SAMPLE PROBLEMS
PROBLE+ :?
So#ution cont(d?
mM 0 2,:7 %
33333 0 1828 s#u%s4H:@29 3333333H7:6333333
33333 0 2,72 %
m
m
< s#u%
#"m %
#"
m
m
m<
m
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SAMPLE PROBLEMS
PROBLE+ :?
So#ution cont(d?
Tota# mass 0 mJ Q mK Q m Q mM Q m0 788 Q ;:2 Q @@@@6 Q 2,:72 Q
2,72
Tota# mass 0 ,6289 %
1"4 Tota# mass 0 333333333333333333 0 ;: #"
m
,6289 %m
7:6 % =#"m mm
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SAMPLE PROBLEMS
PROBLE+ :?
So#ution cont(d?
1c4Tota# mass 0 333333333333333333333333 0 8:86 s#u%: #"m
:@29 #" =s#u%m
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SAMPLE PROBLEMS
PROBLE+ ?
Note that the %ra(ity acce#eration ate/uatoria# sea #e(e# is % 0 :@8;; f's> andthat its (ariation is * 888: f's> 'er 2888 ftascent Find the hei%ht in mi#es a"o(e this'oint for !hich 1a4 the %ra(ity acce#eration"ecomes :878 f's>, 1"4 the !ei%ht of the%i(en man is decreased "y 7, 1c4 -hat is the!ei%ht of a 2;8 #" man ato' the @,2:23ft+t E(erest in Ti"et, re#ati(e to this 'ointG
m
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SAMPLE PROBLEMS
PROBLE+ ?
So#ution?
1a4 chan%e in acce#eration 0 :878 * :@8;; 0 * 27; f's>
ei%ht, h 0 33333333333333333 0 7@;,888 ft or 288mi#es
* 27; f's>* 888: f's> 2888 ft
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SAMPLE PROBLEMS
PROBLE+ ?
So#ution contd?
1"4 F 0 87 F Let F 0 !ei%ht of the man at
sea #e(e#
33333 0 33333
3333333333 0 33333
a 0 87% 0 18741:@8;;4 0 :8; f's>
% %
F
a
F%
%
87 F%a
F%%
a
F%
% 0 :@8;; f's>
h
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SAMPLE PROBLEMS
PROBLE+ ?
So#ution contd?
h 0 33333333333333333333333333333 0 7:,698 ft or282: mi#es
1:8; * :@8;;4 f's>
* 333333333333333888: f's>
2888 ft
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SAMPLE PROBLEMS
PROBLE+ ?
So#ution contd?
1c4 % 0 :@8;; f's> m 0 2;8 #"
a 0 :@8;; f's> * H333333333333331888: f's>4
0 :@882 f's>
F 0 333333 0 33333333333333333333333333333 0 298: #"
m
@2:2 ft
2888 fta
F%
@2:2 ftma
<
12;8#" 4H:@882 ft=s>m
:@29 3333333333#" 3 s>f
#" 3 ftmf
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SPECIFIC VOLUME, DENSITY
AND SPECIFIC WEIGHT The density ) of any su"stance is its mass 1not
!ei%ht4 'er unit (o#ume In e/uatione)'ression,
) = #####
The speci'c volume v is the (o#ume of a unitmass and is the reci'roca# of density
v = ##### = #####
m*
*
m
+
)
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SPECIFIC VOLUME, DENSITY
AND SPECIFIC WEIGHT The specific &eight , of any su"stance is the force
of %ra(ity 1in the %i(en #oca#ity4 on unit (o#ume
) = , #### or , = ) ####
Since the s'eci$c !ei%ht is to the #oca# acce#erationof %ra(ity as the density is to the standard
acce#eration, ,/g = )/k , con(ersion is easi#y madeence,
) = , #### or , = ) ####
k g
gk
k
g
g
k
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SPECIFIC VOLUME, DENSITY
AND SPECIFIC WEIGHTAt or near the surface of the earth, k and g
are numerica##y e/ua#, so are ) and ,
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SAMPLE PROBLEMSPROBLE+ 7?
1a4 -hat is the s'eci$c !ei%ht of !ater atstandard conditionG
So#ution?
% 0 ;866 m=s> 0 2888
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SAMPLE PROBLEMSPROBLE+ 7?
1"4 T!o #i/uids of different densities 1J 0 2788
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SAMPLE PROBLEMSPROBLE+ 7?
So#ution contd?
mJ Q mK 0 m JVJ Q KVK 0 m
2788VJ Q 788VK 0 ;8 124
VJ Q VK 0 8288 1@4
so#(in% e/uations 124 and 1@4 simu#taneous#y,
VJ 0 88: m
VK 0 889 m
m
m
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SAMPLE PROBLEMSPROBLE+ 7?
So#ution contd?
mJ 0 JVJ 0 12788
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ASSIGNMENT – NOVEMBER 11,
2014 For ne)t meetin%, su"mit in one sheet of "ond 'a'er -rite your name,
su"ect=section, date and !rite the 'ro"#em statement P#ease !rite #e%i"#y
Non3com'#iance !i## mean non3acce'tance of your assi%nment
A mass of 828 s#u% in s'ace is su"ected to an
e)terna# (ertica# force of #" If the #oca# %ra(ityacce#eration is % 0 :87 f's> and if friction e&ects arene%#ected, determine the acce#eration of the mass ifthe e)terna# force is actin% 1a4 u'!ard, and 1"4do!n!ard
The mass of a Wuid system is 8:22 s#u%, its density is
:8 #"=ft and % is :28 f's> Find 1a4 the s'eci$c(o#ume, 1"4 the s'eci$c !ei%ht, and 1c4 the tota#(o#ume