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D DEPARTMENT OF MATHEMATICS, SCIENCE AND COMPUTER
POLYTECHNIC KOTA BHARU
BA 101 ENGINEERING MATHEMATICS 1
TEST 1
ACADEMIC SESSION :DISEMBER 2012
DURATION : 40 MINUTES
NAME : ____________________________________
REG. NO. : ____________________________________
CLASS : ____________________________________
LECTURER : ____________________________________
DATE : ____________________________________
Instruction:
* Please answerALL QUESTIONS in this paper.* This paper contains
3 printed pages including the front page.
MARKS ALLOCATION
CLO 1 CLO 2
QUESTION 1
QUESTION 2
15
TOTAL
30
15
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SOALAN 1 (QUESTION 1)-CLO2
a) Tukar n menjadi perkara rumus bagi persamaan bagi
Change the n as the subject of the formula for (5 m)
b) Selesaikan persamaan kuadratik berikut dengan menggunakan
kaedah rumuskuadratik bagi
Solved the following quadratic equation by using quadratic
formula method for
(10 m)
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SOALAN 2 (QUESTION 2)-CLO1
a) Permudahkan
Simplify
(3 m)
b) Diberi log2 3 = 1.59 dan log2 5 = 2.32, tanpa menggunakan
kalkulator, cari nilai bagilogaritma berikut:
Given that log2 3 = 1.59 and log2 5 = 2.32, without using
calculator, find the values
of the following logarithm.
i. log2
5
3
(4 m)
ii. log2
4
1(4 m)
iii. log2 452 (4 m)
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SCHEME
(QUESTION 1)
a) Change the n as the subject of the formula for
........(n)
..........(1m)
....(1m) .............(1m) ..........(1m)
....(1m)
b) Solved the following quadratic equation by using quadratic
formula method for
; a=1, b=4 & c=-1 ......(1m)
.........(1m)
.........(1m)
.........(1m)
.........(1m)
.........(1m)
.235 .........(2m)
.........(2m)
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(QUESTION 2)
a) Simplify
=
........(1m)
=
............(2m)
b) Given that log2 3 = 1.59 and log2 5 = 2.32, without using
calculator, find the valuesof the following logarithm.
a. log2
5
3
= log23- log25 .......(1m)
=1.59-2.32 ...........(1m)
=-0.73 ..................(2m)
b. log2
4
1
= log21 - log24........(1m)
= log21 - log2........(1m)= 02(1) ................(1m)
= -2 .........................(1m)
c. log2 452
= 2 log2 45...............(1m)
= 2(log2(3x3x5)) ......(1m)
= 2(log23+ log23+ log25) ....(1m)
= 2(1.59+1.59+2.32)
= 11 ...(1m)
