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THE WRONG CALL FUNDAMENTAL PARTICLES Now if a very simple problem is considered, say the structure of the fundamental particles, which as it has been previously established in our study, they adjust is the behavior. To a multispace discontinuous metric in dracks spaces, in which exist fixed force, which conform the structure of de variable isospace. Whith a action between proton is considered. ∁ρ= c x n (comformative speed) ∁ρ=6.40315364 x 10 27 cmt. Ep= ∂c=6.283118330718 x 10 31 6.40315364 x 10 27 Ep= 40.2317720098 x 10 4 1.602 x 10 12 Ep= 2.5113465674 x 10 9 ev (comformative energy of the proton) Let see the conformative energy of the proton impulsors. E 12 = 6.2831830718 x 10 31 x 3.2010042858 x 10 28 1.602 x 10 12 E 12 =12.5546171627 x 10 9 ev E 13 =4.18487238762 x 10 9 ev Protón 2 E 12 + E 13 =25.1092343254 x 10 9 +4.18487238762 x 10 9

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Page 1: The wrong call fundamental particles

THE WRONG CALL FUNDAMENTAL PARTICLES

Now if a very simple problem is considered, say the

structure of the fundamental particles, which as it has

been previously established in our study, they adjust is

the behavior. To a multispace discontinuous metric in

dracks spaces, in which exist fixed force, which conform

the structure of de variable isospace.

Whith a action between proton is considered.

∁ ρ= c

xn (comformative speed)

∁ ρ=6.40315364 x1027 cmt .

Ep=∂c=6.283118330718 x10−31∗6.40315364 x 1027

Ep= 40.2317720098 x 10−4

1.602 x10−12

Ep=2.5113465674 x10−9 ev (comformative energy of the proton)

Let see the conformative energy of the proton impulsors.

E12=6.2831830718 x10−31 x3.2010042858 x1028

1.602 x10−12

E12=12.5546171627 x 109 ev

E13=4.18487238762x 109 ev

Protón 2 E12+E13=25.1092343254 x 109+4.18487238762 x109

Ep=¿ 29.294106713x 109¿ev comformative proton energy

For the electron gives

E∆=4.693227893355x 1012eV

Page 2: The wrong call fundamental particles

For the photon the comformative energy is

EF=16.6460057076 x1014 eV

If the energy of the proton in divided between the

comformative of the E12, E13 impulsor we have

2E12+E13E p

=11.6647009589

and

E12E13

=3

The actual calculus value is 2.9999993 due to a certain

imprecision on the conformative values.

Which gives a conformative proton energy 6 times the

required to keep the electron in orbit, being these counter

balance in the hydrogen atom by the screening of the 2E12

and E13 giving moments nearly null to the axis trough the

E12, E13.axis

In the problem of the elementary particles there is not

such due that the only elementary particles is the

impulsors Oscilator E= nħxn as is seen in this early work.

Now if the electron impulsor is divided between the 2E12

proton – neutron impulsors, the maximum electron capability

in orbits is obtained.

Page 3: The wrong call fundamental particles

Cmp=I ev

2E12+2 E12= 4.693227893355 x1012 ev4 x12.5546171627 x 109 ev

Cmpmn=¿93.45621281 electrons

Say that the maximum electron in a giving element (in

nature) is Pu(plutonium)= 94 has it had been seen than the

atom is autostable.

The wrong called week energy, there is no such because

there is a great energy distribution alike a drawing,fig.1

the yuxtapotition of the E12 – E13, opposing the P-N

esqueme and the 3E6 distributed all of them in different

angles and planes with relation each other, that create a 6

resonant units, which with the increasing relation P-N and

anomalous N (neutron)creates radioactive elements on the

nature (reflected the periodic table as well), they scinde

as an electron or an α particle, according the radioactive

reaction involve, say the drack – impulse of same electron,

proton, neutron does not screen completely the neighbor

particles, being the speed of leak of the electron or α

particle depending of the arrangement of the isotope

consider.

It is to take notice that this energy distribution

originates the fractal assuagement of the matter.

Now it a proton – proton is made to interact, we can obtain

3! Particles of ultra short life and a numerous resonances.

V pp=6.177x 10−16

6.40315364 x 1027

V pp=96.468089745x 10−40 s

Page 4: The wrong call fundamental particles

CH

P

N

Forming ↑E12-E13, E12-E13↓,↑E13-E12, E13-E12↓, E13-E12↑,

↑E13-E12↑,↓E13-E12↓,and a numerous resonances that all

finished as x rays or gamma rays, according to the energy

of the impulsors, the arrow means resonance.

Now if a proton. Nucleon particle is consider, the amount

of resultant particles will be enormous say 4!5!6! etc, if

the …. Comparative energy is obtained, with which it can be

seen that a numerous hybrid particle are obtained, due to

the conforming energy and the impulsive force.

The bad call, weack, strong, electromagnetic, etc. forces

is no more that a mislead interpretation of the drank

isospace.

Fig.1

Now we can consider an elementary problem such as the

benzene atom in which the classic formulas is an hexagon

shape, that can not be because that electron distribution

is non – stable and gives moments respect to my axis a

better and more reasonable configuration maybe

CH CH

CH CH

Page 5: The wrong call fundamental particles

Fig. 2

Which a postulate in 1965, which as all the moments and

orbital equivalent to any axis.

In other occasion this formula will be consider with

several others, say that my unit of comformative energy can

be comparable to the obtained using E=mc2.

In another occasion the relation of the nucleus and proto –

nucleus energy will be consider, at the moment I am working

in a problem of nucleus constant of the nucleus and

mitochondrial cell, applicable to immunology and cell

stability