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The Nobel Prize in Physics 2008: Broken SymmetriesJohan Bijnens
Lund University
http://www.thep.lu.se/∼bijnens
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.1/44
Overview
The Royal Swedish Academy of Sciences has decided to award the Nobel Prize in Physics
for 2008 with one half to
Yoichiro Nambu, Enrico Fermi Institute, University of Chicago, IL, USA
"for the discovery of the mechanism of spontaneous brokensymmetry in subatomic physics"
and the other half jointly to
Makoto Kobayashi, High Energy Accelerator Research Organization (KEK), Tsukuba
Toshihide Maskawa,Yukawa Institute for Theoretical Physics (YITP), Kyoto University,
Japan
"for the discovery of the origin of the broken symmetrywhich predicts the existence of at least three families ofquarks in nature"
PS: Lots of information: http://nobelprize.org
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.2/44
Yoichiro Nambu
Enrico Fermi Institute,University of ChicagoChicago, IL, USAb. 1921 (in Tokyo, Japan)
D.Sc. 1952University of Tokyo, Japan
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.3/44
Makoto Kobayashi
High Energy AcceleratorResearch Organization(KEK)Tsukuba,b. 1944
Ph.D. 1972Nagoya University, Japan
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.4/44
Toshihide Maskawa
Kyoto Sangyo University;
Yukawa Institute for Theo-retical Physics (YITP)Kyoto UniversityKyoto, Japanb. 1940
Ph.D. 1967Nagoya University, Japan
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.5/44
Papers
Y. Nambu, Quasi-Particles and Gauge Invariance in the Theory ofSuperconductivity, Phys. Rev. 117 (1960) 648
Y. Nambu, Axial Vector Current Conservation in Weak Interactions, Phys. Rev.Lett. 4 (1960) 380
Y. Nambu, A ‘Superconductor’ Model of Elementary Particles and itsConsequencies, Talk given at a conference at Purdue (1960), reprinted in BrokenSymmetries, Selected Papers by Y. Nambu, ed:s T. Eguchi and K. Nishijima,World Scientific (1995).
Y. Nambu and G. Jona-Lasinio, A Dynamical Model of Elementary Particles basedon an Analogy with Superconductivity I, Phys. Rev. 122 (1961) 345
Y. Nambu and G. Jona-Lasinio, A Dynamical Model of Elementary Particles basedon an Analogy with Superconductivity II, Phys. Rev. 124 (1961) 246;
Y. Nambu and D. Lurié, Chirality Conservation and Soft Pion Production, Phys.Rev. 125 (1962) 1429
Y. Nambu and E. Shrauner, Soft Pion Emission Induced by Electromagnetic andWeak Interactions, Phys. Rev. 128 (1962) 862.
M. Kobayashi and K. Maskawa, CP Violation in the Renormalizable Theory of WeakInteractions, Progr. Theor. Phys. 49 (1973) 652.
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.6/44
Symmetry
nochangeif rotatedalongverticalaxis
InvariantunderrotationgroupU(1)
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.7/44
Symmetry
changesif rotatedalongvertical axis
But U(1) invariancegood approximation
Symmetry explicitly brokenby the picture
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.8/44
Spontaneously Broken Symmetry
Pencil balanced on end (on a table) has rotationalsymmetry about vertical axis.
Symmetry is broken when pencil falls over: lowerenergy state
Special direction is specified.
But, underlying law of gravity is still symmetrical.
Pencil could have fallen into any available direction
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.9/44
Spontaneously Broken Symmetry
http://nobelprize.org
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.10/44
Symmetry
Symmetries are very well known in physics (and definitelyin particle physics)
Heisenberg, Wigner, Eckart, Yang, Mills, Glashow,Weinberg, Salam,. . .
Nambu: Introduced the concept of spontaneouslybroken symmetries into particle physics
Kobayashi and Maskawa: Proposed the mechanism bywhich the combined charge-conjugation–parity (CP)symmetry is broken in the Standard Model
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.11/44
Spontaneous symmetry breaking
Magnets (e.g. in iron):
Symmetry: ≈ ≈
With interactions:
Low energy:
High energy:
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.12/44
Spontaneous symmetry breaking
a generic state
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.13/44
Spontaneous symmetry breaking
the ground state
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.14/44
Spontaneous symmetry breaking
No: A ground state
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.15/44
Spontaneous symmetry breaking
A ground state: choice of vacuum breaks the symmetry
Spontaneous symmetry breakingLund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.15/44
Spontaneous symmetry breaking
A very low energy excitation: spin wave
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.16/44
Spontaneous symmetry breaking
A very low energy excitation: spin waveA collective excitation: quasiparticle
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.16/44
Nambu and Superconductivity
Superconductivity: conductivity goes to zero below acritical temperature
Discovered by Kamerlingh-Onnes in 1911
Meisnner: expel magnetic fields 1933
Landau-Ginzburg-Abrikosov: Phenomenological Theory(scalar field)
Explained by Bardeen, Cooper and Schrieffer byCooper pair condensation 1957
Bogolyubov 1958, (Bogolyubov transformation)
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.17/44
Nambu and Superconductivity
Superconductivity: conductivity goes to zero below acritical temperature
Discovered by Kamerlingh-Onnes in 1911
Meisnner: expel magnetic fields 1933
Landau-Ginzburg-Abrikosov: Phenomenological Theory(scalar field)
Explained by Bardeen, Cooper and Schrieffer byCooper pair condensation 1957
Bogolyubov 1958, (Bogolyubov transformation)
Note the many other Nobel Prizes here
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.17/44
Nambu and Superconductivity
Condensed Cooper Pairs: Ground State is Charged
What about Gauge Invariance?
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.18/44
Nambu and Superconductivity
Condensed Cooper Pairs: Ground State is Charged
What about Gauge Invariance?
Electromagnetic Gauge Invariance
Wave function:ψ(x) → e−iα(x)ψ(x)
does not change |ψ(x)|2
~A(x) → ~A(x) − ~∇α(x) and V (x) → V (x) − ∂α(x)∂t
do not change ~E(x) and ~B(x)
Minimal coupling: both invariances belong together
Requiring gauge invariance determines the form ofthe interaction
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.18/44
Nambu and Superconductivity
He used the Feynman-Dyson methods forQuantumElectroDynamics (QED)
Reformulated BCS as a generalized Hartree-Fockground state
When deriving Green functions (which lead toamplitudes) you also need to introduce the loopgraphs both in the interaction vertex and in theselfenergiesWhen you do that all Ward identities are satisfiedHence everything is gauge invariant as should be
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.19/44
Nambu and Superconductivity
He used the Feynman-Dyson methods forQuantumElectroDynamics (QED)
Reformulated BCS as a generalized Hartree-Fockground state
The photon “mixes” with the available electron/holestatesLongitudinal mode of the photon couples to thecollective excitationsIn effect produces a mass for the photon ⇒Meissner effect
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.19/44
Nambu and Superconductivity
He used the Feynman-Dyson methods forQuantumElectroDynamics (QED)
Reformulated BCS as a generalized Hartree-Fockground state
The photon “mixes” with the available electron/holestatesLongitudinal mode of the photon couples to thecollective excitationsIn effect produces a mass for the photon
Brout-Englert, Higgs, Guralnik-Hagen-Kibble:generalize to Yang-MillsWeinberg, Salam apply to Glashow’s neutral currentmodel: the Standard Model
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.19/44
Nambu: SSB in the Strong Interaction
First an aside: The Weak Interaction and Parity
Parity (P ): ~x → −~x
related to mirror symmetry
Lee and Yang 1956: No experiment for P in weakinteraction and can solve τθ puzzle
Suggested 60Co and µ-decay: immediately seenLund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.20/44
Nambu: SSB in the Strong InteractionFirst an aside: The Electromagnetic and Weak Interaction
Electromagnetic coupling to electron:AµJ
µ = Aµeγµe (e ≡ ψe)
Current is conserved: ∂Jµ
∂xµ = 0 ⇒Matrix element of Jµ at q2 = 0 is ≡ 1.
Weak interaction is (leptonic µ decay)GF√
2J(µ)ρJ(e)ρ = GF√
2µγρ (1 − γ5) νµ νeγ
ρ (1 − γ5) e
Feynman-Gell-Mann, Marshak-Sudarshan: Vρ −Aρ
Vρ and Aρ conserved (CVC and CAC) for hadrons ⇒≡ 1 at q2 = 0.
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.21/44
Nambu: SSB in the Strong InteractionFirst an aside: The Electromagnetic and Weak Interaction
Electromagnetic coupling to electron:AµJ
µ = Aµeγµe (e ≡ ψe)
Current is conserved: ∂Jµ
∂xµ = 0 ⇒Matrix element of Jµ at q2 = 0 is ≡ 1.
Weak interaction is (leptonic µ decay)GF√
2J(µ)ρJ(e)ρ = GF√
2µγρ (1 − γ5) νµ νeγ
ρ (1 − γ5) e
Feynman-Gell-Mann, Marshak-Sudarshan: Vρ −Aρ
Vρ and Aρ conserved (CVC and CAC) for hadrons ⇒≡ 1 at q2 = 0.
Neutron decay:GF√
20.97 pγρ (1 − 1.27γ5)n eγ
ρ (1 − γ5) νeLund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.21/44
Nambu: SSB in the Strong Interaction
gA = 1.27 6= 1
Solved simultaneously by Gell-Mann-Levy and Nambu
PCAC: Partially Conserved Axial Current
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.22/44
Nambu: SSB in the Strong Interaction
gA = 1.27 6= 1
Solved simultaneously by Gell-Mann-Levy and Nambu
PCAC: Partially Conserved Axial Current
A CAC & gA 6= 0: p(
gAF1(q2))
(
γµγ5 − 2MN qµ
q2 γ5
)
n
But has pseudoscalar coupling and massless pole:ruled out
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.22/44
Nambu: SSB in the Strong Interaction
gA = 1.27 6= 1
Solved simultaneously by Gell-Mann-Levy and Nambu
PCAC: Partially Conserved Axial Current
A CAC & gA 6= 0: p(
gAF1(q2))
(
γµγ5 − 2MN qµ
q2 γ5
)
n
But has pseudoscalar coupling and massless pole:ruled out
p(
gAF1(q2))
(
γµγ5 − 2MN qµ
(q2+m2π)γ5
)
n
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.22/44
Nambu: SSB in the Strong InteractionConsequences:
PCAC:∂Aρ
∂xρ= im2
πFπφπ
Partially: conserved when m2π → 0
Gπ =√
2MN gA
Fπ, the pion coupling to the nucleon is
related to the pion decay constant and gAGolberger-Treiman relation
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.23/44
Nambu: SSB in the Strong InteractionConsequences:
PCAC:∂Aρ
∂xρ= im2
πFπφπ
Partially: conserved when m2π → 0
Gπ =√
2MN gA
Fπ, the pion coupling to the nucleon is
related to the pion decay constant and gAGolberger-Treiman relation
Similar suggestion also for the strangeness changinghyperon decays and the pion to Kaon
Both papers also suggested that there should be anaxial variant of isospin symmetry: exact for mπ → 0
Isospin: SU(2) symmetry from interchanging p and nWigner
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.23/44
Nambu: SSB in the Strong Interaction
Further developments
He realized that if an exact symmetry is spontaneouslybroken there must be a massless particle
Also suggested by Goldstone (Nambu-GoldstoneBosons)
Proven by Goldstone-Salam-Weinberg
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.24/44
Goldstone Modes
UNBROKEN: V (φ)
Only massive modesaround lowest energystate (=vacuum)
BROKEN: V (φ)
Need to pick a vacuum〈φ〉 6= 0: Breaks symmetryNo parity doubletsMassless mode along ridge
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.25/44
Goldstone Modes
Also here:low energy excita-tions
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.26/44
Goldstone Modes
Also here:low energy excita-tions
Overall direction isa symmetryθ(x) → θ(x) + Θ NoChangeInteractions mustvanish if θ(x) isconstantLow energy: nointeractions
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.26/44
Nambu: SSB in the Strong Interaction
Soft Pions and Current Algebra:
∂Aρ
∂xρ= im2
πFπφπ
This means that an axial symmetry rotation connectsprocesses with different numbes of pions
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.27/44
Nambu: SSB in the Strong Interaction
Soft Pions and Current Algebra:
∂Aρ
∂xρ= im2
πFπφπ
This means that an axial symmetry rotation connectsprocesses with different numbes of pions
This together with the small interactions at low energiesallows for a systematic expansion for processes onlyinvolving the low-energy excitations
Chiral Perturbation Theory is the modern way to usethis
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.27/44
How does this fit in with QCD
Chiral Symmetry
QCD: 3 light quarks: equal mass: interchange: U(3)V
But LQCD =∑
q=u,d,s
[iq̄LD/ qL + iq̄RD/ qR − mq (q̄RqL + q̄LqR)]
So if mq = 0 then U(3)L × U(3)R.
uL
dL
sL
→ UL
uL
dL
sL
and
uR
dR
sR
→ UR
uR
dR
sR
Can also see that left right independent viav < c, mq 6= 0 =⇒
v = c, mq = 0 =⇒/
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.28/44
How does this fit in with QCD
Chiral Symmetry
QCD: 3 light quarks: equal mass: interchange: U(3)V
But LQCD =∑
q=u,d,s
[iq̄LD/ qL + iq̄RD/ qR − mq (q̄RqL + q̄LqR)]
So if mq = 0 then U(3)L × U(3)R.
Hadrons do not come in parity doublets: symmetrymust be broken
A few very light hadrons: π0π+π− and also K, η
Both can be understood from spontaneous ChiralSymmetry Breaking
Anomaly: really SU(3)L × SU(3)RLund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.28/44
Kobayashi and MaskawaLet’s extend now P andGF√
20.97 pγρ (1 − 1.27γ5)n eγ
ρ (1 − γ5) νe
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.29/44
Kobayashi and MaskawaLet’s extend now P andGF√
20.97 pγρ (1 − 1.27γ5)n eγ
ρ (1 − γ5) νe
P is broken by the weak interaction
CP is not
C: Charge conjugation, replace everyone by theirantiparticle
CP conservation still allows to solve the τθ puzzle
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.29/44
Kobayashi and MaskawaLet’s extend now P andGF√
20.97 pγρ (1 − 1.27γ5)n eγ
ρ (1 − γ5) νe
P is broken by the weak interaction
CP is not
C: Charge conjugation, replace everyone by theirantiparticle
CP conservation still allows to solve the τθ puzzle
Experimentally CP is violated a little bit in KaonsCronin-Fitch 1964
K0(sd) and K0(ds) mix through the weak interaction,eigenstates KL and KS
A tiny but well measured mass difference is aconsequence
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.29/44
The 0.97
Suggestion: the weak current for hadrons really is the sameas for leptons but it mixes ∆S = 1 and ∆S = 0Gell-Mann-Levy 1960, Cabibbo 1963
Jρ = cos θCJ∆S=0ρ + sin θCJ
∆S=1ρ
∆S = 0 current: with p and n,
∆S = 1 current: with p and Λ
And the same for the coupling of pion to kaon
With sin θC ≈ 0.22 this explained the 0.97 and the by 1963
much better measured ∆S = 1 decays of Kaon and Hyper-
ons.Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.30/44
Quarks came
In quark language now weak interaction from W±
exchange and the vertex isW+µuγµ (1 − γ5) (cos θCd+ sin θCs)
A mechanism for getting the KL-KS mass difference is
K0 u
W
Wu K0
Result is way too large
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.31/44
Glashow-Iliopoulos-Maiani 1970
Add another quark
W+µuγµ (1 − γ5) (cos θCd+ sin θCs)+
W+µcγµ (1 − γ5) (− sin θCd+ cos θCs)
The mechanism is now
K0 u, c
W
Wu, c K0
Result is zero if mu = mc; the vertical lines havesin θC cos θC − cos θC sin θC (GIM mechanism)
Fits for mc ≈ 1.5GeV/c2 (Gaillard-Lee)
Charm discovered 1974 Richter-Ting
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.32/44
θC in the Standard Model
The standard model: interactions with W µ and the masses:
i, j, k, l = 1, 2, later 1, 2, 3
u1 = u, u2 = c, u3 = t, d1 = d, d2 = s, d3 = b
W Interactions: W+µ∑
i uWLiγµd
WLi + h.c.
Mass terms (v is the Higgs vacuum expectation value)
−v∑
ij dW
LiλDijd
WRj − v
∑
ij uWLiλ
Uiju
WRj+h.c.
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.33/44
θC in the Standard Model
−v∑
ij dW
LiλDijd
WRj − v
∑
ij uWLiλ
Uiju
WRj+h.c.
vλU and vΛD are complex 2 by 2 (3 by 3) matrices
Diagonalization is always possible by two complexmatrices each
V UL vλ
UVU†R = diag(mu,mc,mt)
V DL vλ
DVD†R = diag(md,ms,mb)
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.34/44
θC in the Standard Model
−v∑
ij dW
LiλDijd
WRj − v
∑
ij uWLiλ
Uiju
WRj+h.c.
vλU and vΛD are complex 2 by 2 (3 by 3) matrices
Diagonalization is always possible by two complexmatrices each
V UL vλ
UVU†R = diag(mu,mc,mt)
V DL vλ
DVD†R = diag(md,ms,mb)
Define: uWLi =∑
j VU†LijuLj and uWRi =
∑
j VU†RijuRj ,
dWLi =∑
j VD†Lij dLj , d
WRi =
∑
j VD†RijdRj
mass eigenstates
and substitute
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.34/44
θC in the Standard Model
−v∑
ijkl
dLiVDLijλ
DjkV
D†RkldRk − v
∑
ijkl
uLiVULijλ
UjkV
U†RkluRk
+h.c. = −∑
i
dLimdidRi −
∑
i
uLimuiuRi + h.c.
Phase invariance left:
dLi → eiαidLi, dRi → e−iαidRi
uLi → eiβiuLi, uRi → e−iβiuRi
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.35/44
θC in the Standard Model
−v∑
ijkl
dLiVDLijλ
DjkV
D†RkldRk − v
∑
ijkl
uLiVULijλ
UjkV
U†RkluRk
+h.c. = −∑
i
dLimdidRi −
∑
i
uLimuiuRi + h.c.
The W Interactions: W+µ∑
i uWLiγµd
WLi + h.c. become
W+µ∑
ijkl uLiγµVULijV
D†
LjkdLk + h.c.
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.35/44
θC in the Standard Model
−v∑
ijkl
dLiVDLijλ
DjkV
D†RkldRk − v
∑
ijkl
uLiVULijλ
UjkV
U†RkluRk
+h.c. = −∑
i
dLimdidRi −
∑
i
uLimuiuRi + h.c.
The W Interactions: W+µ∑
i uWLiγµd
WLi + h.c. become
W+µ∑
ijkl uLiγµVULijV
D†
LjkdLk + h.c.
VCKM = V UL V
D†
L is a unitary matrix
All other terms in the Lagrangian get V UL V
U†L = 1, . . .
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.35/44
θC in the Standard Model
The two generation case (VCKM = V )
Flavours only:(
uL cL
)
V
(
dL
sL
)
V is a general 2 by 2 unitary matrix.
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.36/44
θC in the Standard Model
The two generation case (VCKM = V )
Flavours only:(
uL cL
)
V
(
dL
sL
)
V is a general 2 by 2 unitary matrix.
Use αi and βi to make V11, V12 and V21 real :(
e−iβ1uL e−iβ2cL
)
(
V11 V12
V21 V22
)(
eiα1dL
eiα2sL
)
=
(
uL cL
)
(
ei(α1−β1)V11 ei(α2−β1)V12
ei(α1−β2)V21 ei(α2−β2)V22
)(
dL
sL
)
α2 − β2 = (α2 − β1) + (α1 − β2) − (α1 − β1)
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.36/44
θC in the Standard Model
The two generation case (VCKM = V )
Flavours only:(
uL cL
)
V
(
dL
sL
)
V is a general 2 by 2 unitary matrix.
Use αi and βi to make V11, V12 and V21 real
Unitary implies∑
i V∗ikVil = δil
V =
(
cos θC sin θC
− sin θC cos θC
)
This gives exactly what we had before
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.36/44
Kobayashi and Maskawa 1972
Bold suggestion: add a third generation (remember charmnot discovered)
Flavours only:(
uL cL tL
)
V
dL
sL
bL
V is a general 3 by 3 unitary matrix.
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.37/44
Kobayashi and Maskawa 1972
Bold suggestion: add a third generation (remember charmnot discovered)
Flavours only:(
uL cL tL
)
V
dL
sL
bL
V is a general 3 by 3 unitary matrix.
Use αi and βi to make V11, V12, V13, V21 and V31 real
Unitary implies∑
i V∗ikVil = δil
V =
c1 − s1c3 − s1s3
s1c2 c1c2c3 − s2s3eiδ c1c2s3 + s2c3e
iδ
s1s2 c1s2c3 + s2s3eiδ c1s2s3 − c2c3e
iδ
ci = cos θ1, si = sin θiLund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.37/44
Kobayashi and Maskawa 1972
This extra eiδ makes the Lagrangian intrinsicallycomplex (i.e. not removable by phase redefinitions)
This implies CP violation
can explain CP violation that was seen in kaon decays
via box diagrams K0 u, c, t
W
Wu, c, t K0
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.38/44
Kobayashi and Maskawa 1972
This extra eiδ makes the Lagrangian intrinsicallycomplex (i.e. not removable by phase redefinitions)
This implies CP violation
can explain CP violation that was seen in kaon decaysvia box diagrams
What has happened since
Third generation discovered
C. Jarlskog: easy way to see from λU and λD if CPviolation is there
Many more predictions have been seen
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The predictions: 1
There is another type of CP violation in Kaon decays:direct CP violation from Penguin diagrams:
K0
W
π+π−, π0π0γ, Z, g
1
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The predictions: 1
There is another type of CP violation in Kaon decays:direct CP violation from Penguin diagrams:
K0
W
π+π−, π0π0γ, Z, g
1Seen in 1999 byKTeV at Fermilaband NA48 at CERN(earlier at NA31CERN in 1988 notconfirmed by Fermi-lab experiment)
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The origin of penguinsTold by John Ellis:
Mary K. [Gaillard], Dimitri [Nanopoulos], and I first got interestedin what are now called penguin diagrams while we were studyingCP violation in the Standard Model in 1976. The penguin namecame in 1977, as follows.In the spring of 1977, Mike Chanowitz, Mary K. and I wrote apaper on GUTs [Grand Unified Theories] predicting the b quarkmass before it was found. When it was found a few weeks later,Mary K., Dimitri, Serge Rudaz and I immediately started workingon its phenomenology.
from symmetrymagazine
That summer, there was a student at CERN, Melissa Franklin, who is now an experimentalistat Harvard. One evening, she, I, and Serge went to a pub, and she and I started a game ofdarts. We made a bet that if I lost I had to put the word penguin into my next paper. Sheactually left the darts game before the end, and was replaced by Serge, who beat me.Nevertheless, I felt obligated to carry out the conditions of the bet.For some time, it was not clear to me how to get the word into this b quark paper that wewere writing at the time. Later, I had a sudden flash that the famous diagrams look likepenguins. So we put the name into our paper, and the rest, as they say, is history.John Ellis in Mikhail Shifman, ITEP Lectures in Particle Physics and Field Theory,hep-ph/9510397
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More predictions
In B meson decays you can have all three generationsat tree level in a process. CP violations can (and are)much larger
B0
b
d
c
cs
J/ψ = cc
KS
W
Observed at the predicted level in many processes
Lund 7/11/2008 The Nobel Prize in Physics 2008: Broken Symmetries Johan Bijnens p.41/44
More predictions
In B meson decays you can have all three generationsat tree level in a process. CP violations can (and are)much larger
B0
b
d
c
cs
J/ψ = cc
KS
W
Observed at the predicted level in many processes
Penguins also contribute and again in many places
has led to great confidence in CKM picture both for theangles and the CP violation part
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Results
Parametrization of VCKM :
Vud Vus Vub
Vcd Vcs VcbVtd Vts Vtb
The Unitarity triangle of three complex numbers
VudV∗ub + VcdV
∗cb + VtdV
∗tb = 0 (more exist)
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Results
Parametrization of VCKM :
Vud Vus Vub
Vcd Vcs VcbVtd Vts Vtb
The Unitarity triangle of three complex numbers
VudV∗ub + VcdV
∗cb + VtdV
∗tb = 0 (more exist)
|Vus| ≈ 0.2; |Vcd| ≈ 0.04 and |Vub| ∼ 0.003
Approximate Wolfenstein parametrization:
1 − λ2
2 λ Aλ3(ρ− iη)
−λ 1 − λ2
2 Aλ2
Aλ3(1 − ρ− iη) −Aλ2 1
All three side are of order λ3
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Results
γ
γ
α
α
dm∆
Kε
Kε
sm∆ & dm∆
ubV
βsin 2
(excl. at CL > 0.95) < 0βsol. w/ cos 2
excluded at CL > 0.95
α
βγ
ρ-1.0 -0.5 0.0 0.5 1.0 1.5 2.0
η
-1.5
-1.0
-0.5
0.0
0.5
1.0
1.5excluded area has CL > 0.95
ICHEP 08
CKMf i t t e r
Each num-ber is itselfan averageof severalmeasure-ments
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Conclusion
I hope I have given you a feeling for what these people have
accomplished and what the physics behind is
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