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The mitochondrial genome Nucleoid, 75kb, 10 proteins, tRNA, rRNA, „optional“ introns Relaxed codon usage Variation in the code, trp, met, thr

The mitochondrial genome Nucleoid, 75kb, 10 proteins, tRNA, rRNA, „optional“ introns Relaxed codon usage Variation in the code, trp, met, thr

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The mitochondrial genome

• Nucleoid, 75kb, 10 proteins, tRNA, rRNA, „optional“ introns• Relaxed codon usage• Variation in the code, trp, met, thr

Mitochondrial genes

• Mitochondrial function required to grow on non-fermentable carbon sources, lactate,

glycerol, ethanol

• Mutations in nuclear genes that affect mito function: PET+ -> pet-

• Mutations in mitochondrial DNA

– Wild-type, +

– Large deletions, -

– Loss of mito genome, °

– Single site mutations, , mit- (normal translation)

– Single site mutations, , syn- (deficient in translation)

• Mito mutations give 4:0 segregation

Segregation of mitochondrial

genes

Mitochondrial fusion and fission

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Non-mendelian determinants

• 2 µm plasmid, mitochondrial genes, RNA viruses, • + prions, cytoplasmatic inheritance

, , Sup35p

[URE3], [ure3], Ure2p, deficiency in ureidosuccinate utilization

Advantages of meiosis(sexual reproduction)

• Chromosome mixing, 216=65’536 possibilities• Crossing over -> indefinite number of new

combinations (45x2)• Gene conversion• Gene repair• Generation of new alleles• 2 different isolates of yeast differ every 100bp

meiosis

MATa x MATMATa/MAT(2n)synthesis (4n) -> meiotic div.

I -> meiotic div. II -> spores: MATa; MATMATa; MAT

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Classical genetics

• Monofactorial cross, ie.A (wt) x a (mut)

2:2 pattern of segregationif 4:0 -> mito

• Complementation / non-compl. (in Dipl.)• Nonallelic noncomplementation• Allelic noncomplementation• Supression

Bifactorial cross, ie.

AB x ab

If A and B are linked• PD > NPD

• The distance of the markers A B determines the number of PD:NPD:T

• cM = (100/2)[(T+6NPD)/(PD+NPD+T)]

• For map distances of up to 4 crossovers (45cM this is ok, >45cM Snow eq.)

• The number of T is proportional to the map distance

If A islinked to the centromere

Centromerlinkage of A

and B

Recombination

• General recombination = Homologous recombination

• Order of events (I meiotic div):– 1) Double strand break

– 2) Two chromatids from different chromosomes (maternal/paternal) cross over

– 3) Base pairing and strand invasion

– 4) Synthesis and gap repair

– 5) Resolution of Holiday junction

Resolution of Holiday junction

Gene conversion

Geneconversion