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The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College Mon, Oct 3, 2011 Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 1 / 45

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Page 1: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

The Lighting ModelLecture 15Section 5.3

Robb T. Koether

Hampden-Sydney College

Mon, Oct 3, 2011

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 1 / 45

Page 2: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Outline

1 The Phong Lighting ModelAmbient ReflectionDiffuse ReflectionSpecular ReflectionEmissive Light

2 Assignment

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 2 / 45

Page 3: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Outline

1 The Phong Lighting ModelAmbient ReflectionDiffuse ReflectionSpecular ReflectionEmissive Light

2 Assignment

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 3 / 45

Page 4: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Shading Calculations

Example (The Material Properties)Let the position be P = (0,5,10).Let the surface normal be n = (0.8,0.6,0.0).Let us assume that the object has the following materialproperties.

Ambient reflection is (0.6,0.4,0.2).Diffuse reflection is (0.6,0.4,0.2).Specular reflection is (1.0,1.0,1.0).Shininess is 128.That is, the object is shiny brown.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 4 / 45

Page 5: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Shading Calculations

Example (The Light Source)Let us assume that general ambient light is (0.2,0.2,0.2).Let LIGHT0 have the following properties.

Position is L = (10,10,0).Ambient light is (0.3,0.3,0.3).Diffuse light is (0.8,0.8,0.8).Specular light is (1.0,1.0,1.0).

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 5 / 45

Page 6: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Shading Calculations

Example (The Viewer)Let us assume that the viewer is located at V = (5,10,15).

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 6 / 45

Page 7: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Outline

1 The Phong Lighting ModelAmbient ReflectionDiffuse ReflectionSpecular ReflectionEmissive Light

2 Assignment

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 7 / 45

Page 8: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Computing Ambient Reflection

The ambient reflection depends onThe general ambient light inherent in the scene.

0 ≤ sa ≤ 1.

The ambient light from the light source.

0 ≤ La ≤ 1.

The ambient property of the surface.

0 ≤ ka ≤ 1.

The ambient reflection is computed as

ra = saka + Laka

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 8 / 45

Page 9: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

The Shading Calculations

Example (Calculating Ambient Reflection)We have

sa = 0.2La = 0.3ka = (0.6,0.4,0.2)

Therefore, the ambient reflection is

saka + Laka = (0.3,0.2,0.1).

Original Ambient

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 9 / 45

Page 10: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Outline

1 The Phong Lighting ModelAmbient ReflectionDiffuse ReflectionSpecular ReflectionEmissive Light

2 Assignment

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 10 / 45

Page 11: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Point and Directional Sources

At each point of a surface, the light from a light source has adirection.

Point source - direction varies with position on surface.Directional source - direction does not vary with position on surface.

With a point source, the intensity may also depend on distancefrom the source if we enable attenuation.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 11 / 45

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Diffuse Relection

Intensity of reflected diffuse lightDepends on angle of incidence.Reflects equal in all directions. Therefore, it does not depend onthe viewer’s location.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 12 / 45

Page 13: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Computing Diffuse Reflection

Let P be a point on the surface.We need to know two geometric facts.

The location of light source, as a vector l from P to the light source.The orientation of the surface, as a vector n normal to the surface.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 13 / 45

Page 14: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Diffuse Reflection

Light Source n

P Surface

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 14 / 45

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Lambert’s Law

Diffuse reflection is equal in intensity in all directions.However, the intensity depends on the angle of the incident light.Lambert’s law says that the intensity is proportional to the cosineof the angle of incidence (as measured down from the normal).

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 15 / 45

Page 16: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Lambert’s Law

nl

P Surface

θ

Small angle⇒ Large cosine⇒ Bright reflection

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 16 / 45

Page 17: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Lambert’s Law

n

l

P Surface

θ

Large angle⇒ Small cosine⇒ Dim reflection

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 16 / 45

Page 18: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Diffuse Reflection

If l and n are unit vectors, then the cosine of the angle betweenthem is

l · n = cos θ.

Two other factors are needed.Intensity of the incident light.

0 ≤ Ld ≤ 1.

Reflective property of the surface.

0 ≤ kd ≤ 1.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 17 / 45

Page 19: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Diffuse Reflection

The formula for diffuse reflection is

rd = Ldkd(l · n).

Of course, if l · n < 0, then rd = 0.Why?

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 18 / 45

Page 20: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

The Shading Calculations

Example (Diffuse Reflection)We have

L− P = (10,5,−10)

l = (10,5,−10)/√

225= (2/3,1/3,−2/3)

n = (0.8,0.6,0.0)

l · n = 0.7333Ld = (0.8,0.8,0.8)

md = (0.6,0.4,0.2)

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 19 / 45

Page 21: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

The Shading Calculations

Example (Diffuse Reflection)The diffuse reflection is

Ldkd(l · n) = (0.3520,0.2347,0.1173).

Original Diffuse

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 20 / 45

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The Shading Calculations

Example (Ambient and Diffuse Reflection)Ambient and diffuse reflection combined is

(0.6520,0.4347,0.2173).

+

Ambient Diffuse

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 21 / 45

Page 23: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Outline

1 The Phong Lighting ModelAmbient ReflectionDiffuse ReflectionSpecular ReflectionEmissive Light

2 Assignment

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 22 / 45

Page 24: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Specular Reflection

The intensity of specular reflected light varies with viewingdirection as well as the direction of the light source.The maximum intensity is in the “ideal” direction, based on theprinciple that

Angle of reflection = Angle of incidence.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 23 / 45

Page 25: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Blinn and Phong Lighting

OpenGL uses the Blinn lighting model of specular reflection.However, we will first study the Phong lighting model since itseems more natural.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 24 / 45

Page 26: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Phong Lighting

The intensity of the reflection is a function of the angle betweenthe viewer and the ideal direction r of reflection of light from thelight source off the surface.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 25 / 45

Page 27: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Phong Lighting

Light Source

Eye

n

l

P Surface

r

θθ

IdealDirection

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 26 / 45

Page 28: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Phong Lighting

To compute r, note that r + l equals twice the projection of l onto n.

n

l rθθ

r l

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 27 / 45

Page 29: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Phong Lighting

The projection of l onto n is(l · nn · n

)n = (l · n)n.

Therefore,r + l = 2(l · n)n

andr = −l + 2(l · n)n.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 28 / 45

Page 30: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Computing Specular Reflection

According to the Phong lighting model, the specular reflection isproportional to the cosine of the angle between v and r, raised tothe α power, where α is an integer between 0 and 128.This is calculated as

(cosϕ)α = (r · v)α.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 29 / 45

Page 31: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Computing Specular Reflection

Two other factors areIntensity of the incident light.

0 ≤ Ls ≤ 1.

Specular property of the surface.

0 ≤ ks ≤ 1.

Therefore, the formula for specular reflection is

rs = Lsks(r · v)α.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 30 / 45

Page 32: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Computing Specular Reflection

Of course, if l · n < 0 or if r · v < 0, then rs = 0.Why?

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 31 / 45

Page 33: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

The Shading Calculations

Example (Specular Reflection)Now we have

l = (2/3,1/3,−2/3)

n = (0.8,0.6,0.0)

V − P = (5,5,5)

v = (5,5,5)/√

75 =

(1√3,

1√3,

1√3

)r = −l + 2(l · n)n

=

(3875,4175,5075

)= (0.5067,0.5467,0.6667)

r · v = 0.9930

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 32 / 45

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The Shading Calculations

Example (Specular Reflection)And

α = 128Ls = 1.0ks = 1.0

Lsks(r · v)α = (0.4091,0.4091,0.4091)

Original Specular

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 33 / 45

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The Shading Calculations

Example (Total Reflection)Ambient, diffuse, and specular combined is

(1.0,0.8438,0.6264).

Compared to the inherent material color

(0.6,0.4,0.2).

+

Ambient Diffuse

+

Specular

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 34 / 45

Page 36: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Blinn Lighting

A slightly more efficient method is the Blinn lighting model.Let h be the halfway vector, the unit vector halfway between l andv.Then use h · n instead of r · v.

rs = Lsks(h · n)α.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 35 / 45

Page 37: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Blinn Lighting

Light Source

Eye

n

l

v

P Surface

ωω

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Page 38: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Blinn Lighting

How does h · n compare to l · v?If l, n, and v are coplanar, then the angle between h and n is halfof the angle between r and v.Why is Blinn lighting more efficient?h is computed as

h =l + v|l + v|

.

This is more efficient to compute than r.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 37 / 45

Page 39: The Lighting Model - Hampden-Sydney Collegepeople.hsc.edu/faculty-staff/robbk/Coms331/Lectures... · The Lighting Model Lecture 15 Section 5.3 Robb T. Koether Hampden-Sydney College

Outline

1 The Phong Lighting ModelAmbient ReflectionDiffuse ReflectionSpecular ReflectionEmissive Light

2 Assignment

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 38 / 45

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Emissive Lighting

Emissive “lighting” is light that emitted by the surface itself.It is used for objects that are meant to glow.It is independent of all light sources and directions.Let me be the intensity of the emissive light.

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Computing the Shade of a Surface

The total reflection from a point is the sum of the ambient, diffuse,and specular reflections and the emissive light.

ke + saka + Laka + Ldkd(l · n) + Lsks(h · n)shiny .

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Lighting in OpenGL

Since the ambient, diffuse, and specular reflections depend onlight sources, there is a separate contribution for each light source.OpenGL provides up to 8 light sources.Furthermore, there is a separate color component for each type oflight (red, green, blue).

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The Lighting Model

The complete formula for the reflected shade (Ir , Ig , Ib) for 8 lightsis

Ir = ker + sar kar+

7∑i=0

(Lar kar + Ldr kdr (l · n) + Lsr ksr (h · n)shiny

)Ig = keg + sagkag+

7∑i=0

(Lagkag + Ldgkdg(l · n) + Lsgksg(h · n)shiny

)Ib = keb + sabkab+

7∑i=0

(Labkab + Ldbkdb(l · n) + Lsbksb(h · n)shiny

)

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The Lighting Model

For each color, the computed value is “clamped” to the interval[0,1].If the value exceeds 1, then it is set to 1.

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Outline

1 The Phong Lighting ModelAmbient ReflectionDiffuse ReflectionSpecular ReflectionEmissive Light

2 Assignment

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 44 / 45

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Homework

HomeworkRead Section 5.3 – the Phong lighting model.

Robb T. Koether (Hampden-Sydney College) The Lighting Model Mon, Oct 3, 2011 45 / 45