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JN Reddy Plane Elasticity : 1
The Finite Element Method
Plane Elasticity
Read: Chapter 11 CONTENTS
• Governing equations • Weak form formulation• Finite element models using
the weak form• Triangular and rectangular
elements• Shear locking • Modeling aspects and discussion
JN Reddy
displacement, stress function, temperature, velocity potentialu u u u- - - -
REVIEW OF PLANE ELASTICITY
Plane Strain Problems
e e e( , , ), ( , , ), 0
0, 0, 0xz yz zz
u u x y t v v x y t w= = = = = =
Plane Stress Problems( , , ), ( , , ),
( , , ),
0, 0, 0
xx xx yy yy
xy xy
xz yz zz
x y t x y t
x y t
s s s s
s s
s s s
= =
=
= = =
2-D Elasticity: 2
JN Reddy
GOVERNING EQUATIONS
Strain-displacement relations
Cauchy’s formula
x xx x xy y
y xy x yy y
t n n
t n n
s s
s s
= +
= +
Stress-strain relations(orthotropic)
2-D Elasticity: 3
Stress equations of motion
2
2
2
2
xyxx xx
xy yy yy
ufx y t
uf
x y t
σσ ρ
σ σρ
∂∂ ∂+ + =
∂ ∂ ∂
∂ ∂ ∂+ + =
∂ ∂ ∂
11 12
12 22
66
00
0 0 2
xx xx
yy yy
xy xy
C CC C
C
=
σ εσ εσ ε
2xx yy xyu v u vx y y x, ,ε ε ε∂ ∂ ∂ ∂= = = +
∂ ∂ ∂ ∂x
z
y
xzσzzσ
yzσ
yyσ
zyσ
xyσxxσ
zxσ
yxσ
JN Reddy
GOVERNING EQUATIONS (continued)
Plane-strain constitutive relations
Plane-stress constitutive relations
2-D Elasticity: 4
1 12 21 2 12 2111 22
12 12 12 21 12 12 12 21
12 212 66 12 12 2 21 1
12 12 21
1 11 1 2 1 1 2
1 2
ν ν ν νν ν ν ν ν ν ν ν
ν ν νν ν ν
( ) ( ),( )( ) ( )( )
, ,( )
E EC C
EC C G E E
− −= =
+ − − + − −
= = =− −
1 2 12 211 22 12
12 21 12 21 12 21
66 12 12 2 21 1
1 1 1ν
ν ν ν ν ν ν
ν ν
= = =− − −
= =
, ,( ) ( ) ( )
,
E E EC C C
C G E E
JN Reddy
DOMAIN DISCRETIZATION (MESH)
2-D Elasticity: 5
x
y
Γ
Γ
Ω e
e
nα
Ω
iuiv
iDisplacement degrees of
freedom at a typical node i
JN Reddy
Weak Forms of the Equations
2-D Elasticity: 6
11 12
12 22
66
xx
yy
xy
u vc cx yu vc cx yu vcy x
s
s
s
¶ ¶= +
¶ ¶¶ ¶
= +¶ ¶æ ö¶ ¶ ÷ç= + ÷ç ÷ç ÷¶ ¶è ø
0 = heΩew1 ρu− ∂σxx
∂x− ∂σxy
∂y− fx dA
= heΩe
ρw1u+∂w1∂x
σxx +∂w1∂y
σxy − w1fx dA
− heSew1tx dS
0 = heΩew2 ρv − ∂σxy
∂x− ∂σyy
∂y− fy dA
= heΩe
ρw2v +∂w2∂x
σxy +∂w2∂y
σyy − w2fy dA
− heSew2ty dS
tx = he (σxxnx + σxyny) , ty = he (σxynx + σyyny)
w1 ∼ δu, w2 ∼ δv
JN Reddy
FINITE ELEMENT MODEL using weak form
2-D Elasticity: 7
Finite element approximation
Finite element model
u ≈n
j=1
uej(t)ψej (x, y), v ≈
n
j=1
vej (t)ψej (x, y)
[M11] [0][0] [M22]
uv +
[K11] [K12][K21] [K22]
uv =
F 1F 2
K11ij = he
Ωec11
∂ψi∂x
∂ψj∂x
+ c66∂ψi∂y
∂ψj∂y
dA
K12ij = K
21ji = he
Ωec12
∂ψi∂x
∂ψj∂y
+ c66∂ψi∂y
∂ψj∂x
dA
K22ij = he
Ωec66
∂ψi∂x
∂ψj∂x
+ c22∂ψi∂y
∂ψj∂y
dA
F 1i = heΩe
ψifx dA+ heSe
ψitx dS
F 2i = heΩe
ψifydx dy + heSe
ψity dS
[ ] [ ] M K FΔ Δ+ =
JN Reddy
FINITE ELEMENTS
2-D Elasticity: 8
1
2
3
2u
1u
1v
3v
3u
2v
1
2
3
4
5
6
2
67
82
3
4
1
5
2
3
4
1
1v
1u
4v
4u
3v
3u2v
2u
JN Reddy
K11ij = he
Ωec11
∂ψi∂x
∂ψj∂x
+ c66∂ψi∂y
∂ψj∂y
dA
Numerical Values of Typical Element Matrices
[Ke] =a116a
⎡⎢⎣2b −2b −b b−2b 2b b −b−b b 2b −2bb −b −2b 2b
⎤⎥⎦+ a226b
⎡⎢⎣2a −2a −a a−2a 2a a −a−a a 2a −2aa −a −2a 2a
⎤⎥⎦11[ ]K 66c h11c h
K22ij = he
Ωec66
∂ψi∂x
∂ψj∂x
+ c22∂ψi∂y
∂ψj∂y
dA
[Ke] =a116a
⎡⎢⎣2b −2b −b b−2b 2b b −b−b b 2b −2bb −b −2b 2b
⎤⎥⎦+ a226b
⎡⎢⎣2a −2a −a a−2a 2a a −a−a a 2a −2aa −a −2a 2a
⎤⎥⎦22[ ]K 22c h66c h
2-D Elasticity: 9
JN Reddy Plane Elasticity: 10
Eigenvalue Problems
D DM K F + =
Assume periodic solution
0wD D i te=
( ) 20 0 ,l l wDM K Qe e e e− + = =
( ) 20 0 ,l l wM K U Q− + = =
Assembled equations
JN Reddy Plane Elasticity: 11
TIME APPROXIMATIONS
D DM K Fe e e e e+ =
( ) g
a a
d d
d a a
D D D D
D D D D D D
21 ,12
1 , , 1, (1 )
s s s s
s s s s s s
t t
t
+
+ +
= + += + = - +
Semidiscrete FE model
Newmark scheme (second-order equations)
Fully discretized model
( )D
D D D
K F K K M
F F M
1 1 1 1 1 13
1 1 13 4 5
ˆ ˆ ˆ,
ˆ
s s s s s s
s s s s s s
a
a a a
+ + + + + +
+ + +
= = +
= + + +
JN Reddy 2-D Elasticity: 12
Static Condensation Procedure
( )( )
11 2
12 2
23
11
1
( )( )( )
y x xy x xy x x
= -= += -
1 1 2 2 3( ) ( ) ( ) ( )u x u uy x y x ay x= + +
1 1 2 2
1 2 2 1
2 2
( ) ( )x x x
x x x x
y x y x
x
= +
+ -= + 21
1( )y x 2( )y x
x
3( )y x
1x x= 2x x=
2
11 1 2 2
11 12 13 1 1 1
21 22 23 2 2 2
31 32 33 3
0
0
( ) ( )x
x
d u duEA f u dx u x P u x Pdx dx
K K K u f PK K K u f PK K K f
dd d d
a
æ ö÷ç= - - -÷ç ÷çè ø
é ù ì ü ì ü ì üï ï ï ï ï ïï ï ï ï ï ïê ú ï ï ï ï ï ïï ï ï ï ï ïê ú = +í ý í ý í ýê ú ï ï ï ï ï ïï ï ï ï ï ïê ú ï ï ï ï ï ïï ï ï ï ï ïë û î þ î þ î þ
ò
JN Reddy 2-D Elasticity: 13
Static Condensation Procedure
( ) ( )
11 12 13 1 1 1
21 22 23 2 2 2
31 32 33 3
133 3 31 1 32 2 33 3 31 1 32 2
0
K K K u f PK K K u f PK K K f
K f K u K u K f K u K u
a
a a-
é ù ì ü ì ü ì üï ï ï ï ï ïï ï ï ï ï ïê ú ï ï ï ï ï ïï ï ï ï ï ïê ú = +í ý í ý í ýê ú ï ï ï ï ï ïï ï ï ï ï ïê ú ï ï ï ï ï ïï ï ï ï ï ïë û î þ î þ î þ
= - - = - -
( ) ( )
( ) ( )
( ) ( )
13
3
13
1 13
,
ˆ ˆor
uu u uu
u
uu u u uu u u u
uu u u u u uu u
K fK f
K f
K K f
aaa a
a aa
a a aa a
a aa a a aa
aa
a
-
-
- -
é ù ì üì ü ï ïï ïï ï ï ïê ú = = -í ý í ýê ú ï ï ï ïï ïî þ ï ïë û î þ
+ = + - =
é ù- = - =ê úë û
K K Fu K uK
K u K F K u K K u F
K K K u F K K u F
JN Reddy
BEHAVIOR OF THE LINEAR PLANE ELASTICITY ELEMENT
εxx
2-D Elasticity: 14
Pure bending deformation
Linear elementDeformation(incorrect)
JN Reddy
Elimination of Shear Locking in Linear Elements
Basic idea: Start with the standard expansion in terms ofbilinear shape functions for a typical linear quadrilateralelement, quadratic modes are added as follows:
( ) ( ) ( )4 6
1 5
, , ,x h y x h y x he eh j j i i
j i= =
= + u αD
where are the standard bilinear interpolationfunctions and
( 1,2,3,4)i iy =
( ) ( )2 25 6, 1 , , 1y x h x y x h h= − = −
are the incompatible modes; are generalized displacements (node-less variables).
( 5,6)=ei iα
The generalized displacements associated with the incompatiblemodes are unique to each element and must be eliminated via“static condensation”.
2-D Elasticity: 15
JN Reddy
Elimination of Shear Locking in Linear Elements (continued)
=
FK K0K K
α
α αα α
ΔΔ Δ
Δ
Δ0K K F, K Kα α ααα αΔΔ Δ ΔΔ Δ+ = + =or
ed
Ω= TK B CB x
We begin with the standard definition of the stiffness matrix:
where [ ]1 2 3 4 5 6B = B B B B | B B and 5
6
α
α=α
Static condensation: Solving the second equation for , weobtain ( ) 1
K Kαα αα-
-= DD
α
Substituting into the first equation, we arrive at
1ˆ ( )K K K K Kα αα αΔΔ Δ − Δ−=K FD= where2-D Elasticity: 16
JN Reddy
•
•
• • • x
y
θ
312 4
6
1 2 3
7
0p••75
6
8
14
•
0 32
3p hL
23
32L
0 32
6p hL
••
0ps
2332L
•
• •
0 32 0 328 15
0 32 0 328 16
0 32 0 326 11
0 32 0 326 12
cos cos6 6
sin sin6 6
cos cos3 3
sin sin3 3
x
y
x
y
p hL p hLF F
p hL p hLF F
p hL p hLF F
p hL p hLF F
θ θ
θ θ
θ θ
θ θ
=- =-
=- =-
=- =-
=- =-
MODELING ASPECTS:Load Calculation
•
•
• x
y
1
56
1 2 3
4
7 •
••7
56
8
1
0 32
6p hL
0 32
3p hL
0 32 cos3
p hL θ
0 32 cos6
p hL θ
0 32 sin6
p hL θ
2 4
3
11
1
1 1
2-D Elasticity: 17
JN Reddy
1 2 1 211 55 33 12 56 34
1 113 51 15 23 61
1 2 2 5 619 53 35 88 22 66 44
2 5 6 2 5 677 11 55 33 8 2 6 4
,
, 0,
,
,
K K K K K K
K K K K K
K K K K K K K
K K K K F F F F
= + = +
= = =
= + = + +
= + + = + +
MODELING ASPECTS:Assembly of Element coefficients
•
•
• x
y
1
56
1 2 3
4
7 •
••75
6
8
1
0 32
6p hL
0 32
3p hL
0 32 cos3
p hL θ
0 32 cos6
p hL θ
0 32 sin6
p hL θ
2 4
3
11
1
1 1
11
2
3
•
••(5,6) (1,2)
(3,4)
1
2
5•
••(1,2) (3,4)
(9,10)
1
Global Element2-D Elasticity: 18
JN Reddy
MODELING ASPECTS:Bending of a cantilever beam
030msi, 0.25, 10 in., 2 in., 150psiν τ= = = = =E a b
0τ
y
a
8×2 mesh 16×4 mesh
0 0N/m at yt h xτ= − =2-D Elasticity: 19
h
bx
y
a
0τ2N/m x
2-D Meshes
Beam versus elasticity model
JN Reddy Plane Elasticity: 20
DISCUSSION PROBLEMS
1 2 69 GPa, 0.333, 26 GPa, 0.01 mn= = = = =E E G hPlane stress
One quadrant of the domain is used in the finite element analysis (isotropic plate of thickness h)
x
p0 (N/m2)
2b
a
y
• •
1 2 3 4 5 611
1615141312
8 1091 23
•h
t0 = 0.3 N/m2
7 43
002. m
004. m 004. m 004. m
••
•
••
•
• •
•
•
•
• •
• •(1, 2) (5, 6)(13, 14)
(31,32)
(15, 16)
(27, 28)
JN Reddy
SUMMARY
In this lecture we have covered the following topics:
• Review of plane stress and plane strain• Governing equations of plane elasticity• Finite element models using the weak form• Static condensation• Incompatible elements and shear locking • Discussion problems
2-D Elasticity: 21