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The Control Chart for Attributes. Topic The Control charts for attributes The p and np charts Variable sample size Sensitivity of the p chart. Types of Data. Variable data Product characteristic that can be measured Length, size, weight, height, time, velocity Attribute data - PowerPoint PPT Presentation
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1
The Control Chart for Attributes
Topic• The Control charts for attributes• The p and np charts• Variable sample size• Sensitivity of the p chart
2
Types of Data
• Variable data• Product characteristic that can be measured
• Length, size, weight, height, time, velocity
• Attribute data• Product characteristic evaluated with a discrete
choice• Good/bad, yes/no
3
The Control Chart for Attributes
• In a control chart for variables, quality characteristic is expressed in numbers. Many quality characteristics (e.g., clarity of glass) can be observed only as attributes, i.e., by classifying into defectives and non-defectives.
• If many quality characteristics are measured, a separate control chart for variable will be needed for each quality characteristic. A control chart for attribute is a cheaper alternative. It records an item defective if any specification is not met and non-defective if all the specifications are met.
4
The Control Chart for Attributes
• The cost of collecting data for attributes is less than that for the variables
• There are various types of control charts for attributes:– The p chart for the fraction rejected– The np chart for the total number rejected– The c chart for the number of defects– The u chart for the number of defects per unit
5
The Control Chart for Attributes
• Poisson Approximation:– Occurrence of defectives may be approximated by
Poisson distribution– Let n = number of items and p = proportion of
defectives. Then, the expected number of defectives,
– Once the expected number of defectives is known, the probability of c defectives as well as the probability of c or fewer defectives can be obtained from Appendix 4
npnp
6
Steps
1. Gather data
2. Calculate p, the proportion of defectives
3. Plot the proportion of defectives on the control chart
4. Calculate the centerline and the control limits (trial)
5. Draw the centerline and control limits on the chart
6. Interpret the chart
7. Revise the chart
The Control Chart for Fraction Rejected The p Chart: Constant Sample Size
7
The Control Chart for Fraction Rejected The p Chart: Constant Sample Size
• Step 4: Calculating trial centerline and control limits for the p chart
n
pppLCL
n
pppUCL
n
npp
p
p
)1(3
)1(3
8
• Step 6: Interpretation of the p chart – The interpretation is similar to that of a variable
control chart. there should be no patterns in the data such as trends, runs, cycles, or sudden shifts in level. All of the points should fall between the upper and lower control limits.
– One difference is that for the p chart it is desirable that the points lie near the lower control limit
– The process capability is the centerline of the p chart
,p
The Control Chart for Fraction Rejected The p Chart: Constant Sample Size
9
• Step 7: Revised centerline and control limits for the p chart
n
pppLCL
n
pppUCL
nn
npnpp
p
p
d
d
)1(3
)1(3
newnewnew
newnewnew
new
The Control Chart for Fraction Rejected The p Chart: Constant Sample Size
10
The Control Chart for Fraction Rejected The np Chart
)1(3
)1(3
ppnpnLCL
ppnpnUCL
mm
nppn
np
np
subgroups of number where,
Centerline
• The np chart construction steps are similar to those of the p chart. The trial centerline and control limits are as follows:
11
Variable Sample SizeChoice Between the p and np Charts
• If the sample size varies, p chart is more appropriate• If the sample size is constant, np chart may be used
12
Sensitivity of the p Chart
• Smaller samples are – less sensitive to the changes in the quality levels
and – less satisfactory as an indicator of the assignable
causes of variation• Smaller samples may not be useful at all e.g., if only
0.1% of the product is rejected• If a control chart is required for a single measurable
characteristic, chart will give useful results with a much smaller sample.
X
13
Example 1: A manufacturer purchases small bolts in cartons that usually contain several thousand bolts. Each shipment consists of a number of cartons. As part of the acceptance procedure for these bolts, 400 bolts are selected at random from each carton and are subjected to visual inspection for certain non-conformities. In a shipment of 10 cartons, the respective percentages of rejected bolts in the samples from each carton are 0, 0, 0.5, 0.75, 0,2.0, 0.25, 0, 0.25, and 1.25. Does this shipment of bolts appear to exhibit statistical control with respect to the quality characteristics examined in this inspection?
14
Example 2: An item is made in lots of 200 each. The lots are given 100% inspection. The record sheet for the first 25 lots inspected showed that a total of 75 items did not conform to specifications.
a. Determine the trial limits for an np chart.
b. Assume that all points fall within the control limits. What is your estimate of the process average fraction nonconforming ?
c. If this remains unchanged, what is the probability that the 26th lot will contain exactly 7 nonconforming units? That it will contain 7 or more nonconforming units? (Hint: use Poisson approximation and Appendix 4)
p
p
15
Example 3: A manufacturer wishes to maintain a process average of 0.5% nonconforming product or less. 1,500 units are produced per day, and 2 days’ runs are combined to form a shipping lot. It is decided to sample 250 units each day and use an np chart to control production.
(a) Find the 3-sigma control limits for this process.
(b) Assume that the process shifts from 0.5 to 4% nonconforming product. Appendix 4 to find the probability that the shift will be detected as the result of the first day’s sampling after the shift occurs.
(c) What is the probability that the shift described in (b) will be caught within the first 3 days after it occurs?
16
The Control Chart for Attributes
Topic• The p chart for the variable sample size
• Calculating p chart limits using nave
• Percent nonconforming chart• The c chart• The u chart with constant sample size• The u chart with variable sample size
17
• When the number of items sampled varies, the p chart can be easily adapted to varying sample sizes
• If the sample size varies– the control limits must be calculated for each
different sample size, changing the n in the control-limit formulas each time a different sample size is taken.
– calculating the centerline and interpreting the chart will be the same
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
18
Steps
1. Gather data
2. Calculate p, the proportion of defectives
3. Plot the proportion of defectives on the control chart
4. Calculate the centerline. For each sample calculate a separate pair of control limits.
5. Draw the centerline and control limits on the chart
6. Interpret the chart
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
19
• Step 4: Calculate the centerline. For each sample calculate a separate pair of control limits.
Let m = number of samples.
sample th the for
sample th the for
samples) all for centerline (one
in
pppLCL
in
pppUCL
n
pnp
i
p
i
p
m
ii
m
iii
)1(3
)1(3
1
1
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
20
• Step 6: Interpretation of the p chart – The interpretation is similar to that of a variable
control chart. there should be no patterns in the data such as trends, runs, cycles, or sudden shifts in level. All of the points should fall between the upper and lower control limits.
– One difference is that for the p chart it is desirable that the points lie near the lower control limit
– The process capability is the centerline of the p chart
,p
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
21
• The calculation of control limits for the p chart with variable sample size can be simplified with the use of nave
• The value nave can be found by summing up the individual sample sizes and dividing by the total number of times samples were taken:
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
Calculation of Control Limits Using nave
samples of number where,
mm
nn
m
ii
ave1
22
• The value nave can be used whenever the individual sample sizes vary no more than 25% from the calculated nave
• The advantage of using is that there will be a single pair of upper and lower control limits
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
Calculation of Control Limits Using nave
ave
p
ave
p
n
pppLCL
n
pppUCL
)1(3
)1(3
23
• However, if the control limits are computed using the nave the points inside and outside the control limits must be interpreted with caution:– See the control limit formula - for a larger sample,
the control limits are narrower and for a smaller sample, the control limits are wider
– So, if a larger sample produces a point inside the upper control limit computed using nave, the point may actually be outside the upper control limit when the upper control limit is computed using the individual sample size
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
Calculation of Control Limits Using nave
24
– Similarly, if a smaller sample produces a point outside the upper control limit computed using nave, the point may actually be inside the upper control limit when the upper control limit is computed using the individual sample size
• If a larger sample produces a point inside the upper control limit, the individual control limit should be calculated to see if the process is out-of-control
• If a smaller sample produces a point outside the upper control limit, the individual control limit should be calculated to see if the process is in control
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
Calculation of Control Limits Using nave
25
• The previous discussion leads to the following four cases:
• Case I: The point falls inside the UCLp and nind < nave
– No need to check the individual limit
• Case II: The point falls inside the UCLp and nind > nave
– The individual limits should be calculated
• Case III: The point falls outside the UCLp and nind > nave
– No need to check the individual limit
• Case IV: The point falls outside the UCLp and nind < nave
– The individual limits should be calculated• Check points: All the points near UCL. Check only the points
which are near UCL.
The Control Chart for Fraction Rejected The p Chart: Variable Sample Size
Calculation of Control Limits Using nave
26
• The centerline and control limits for the percent nonconforming chart
n
pppLCL
n
pppUCL
n
npp
p
p
)1(3100
)1(3100
100100
100
100
Centerline
The Control Chart for Fraction Rejected The Percent Nonconforming Chart
Constant Sample Size
27
The Control Chart for NonconformitiesThe c and u charts
• Defective and defect – A defective article is the one that fails to conform
to some specification.– Each instance of the article’s lack of conformity to
specifications is a defect– A defective article may have one or more defects
28
The Control Chart for NonconformitiesThe c and u charts
• The np and c charts– Both the charts apply to total counts– The np chart applies to the total number of defectives in
samples of constant size– The c chart applies to the total number of defects in
samples of constant size• The p and u charts
– The p chart applies to the proportion of defectives – The u chart applies to the number of defects per unit– If the sample size varies, the p and u charts may be used
29
• The number of nonconformities, or c, chart is used to track the count of nonconformities observed in a single unit of product of constant size.
• Steps
1. Gather the data
2. Count and plot c, the count of nonconformities, on the control chart.
3. Calculate the centerline and the control limits (trial)
4. Draw the centerline and control limits on the chart
5. Interpret the chart
6. Revise the chart
The Control Chart for Counts of Nonconformities
The c Chart: Constant Sample Size
30
The Control Chart for Counts of Nonconformities
The c Chart: Constant Sample Size
• Step 3: Calculate the centerline and the control limits (trial)
samples of number Where,
Centerline
m
ccLCL
ccUCL
m
cc
c
c
3
3
31
• Step 5: Interpretation of the c chart – The interpretation is similar to that of a variable
control chart. there should be no patterns in the data such as trends, runs, cycles, or sudden shifts in level. All of the points should fall between the upper and lower control limits.
– One difference is that for the c chart it is desirable that the points lie near the lower control limit
– The process capability is the centerline of the c chart
,c
The Control Chart for Counts of Nonconformities
The c Chart: Constant Sample Size
32
• Step 6: Revised centerline and control limits for the c chart
enwc
enwc
d
d
ccLCL
ccUCL
mm
ccc
new
new
3
3
new
new
new Centerline
The Control Chart for Counts of Nonconformities
The c Chart: Constant Sample Size
33
• The number of nonconformities per unit, or u chart is used to track the number of nonconformities in a unit.
• Steps
1. Gather the data
2. Count and plot u, the number of nonconformities per unit, on the control chart.
3. Calculate the centerline and the control limits (trial)
4. Draw the centerline and control limits on the chart
5. Interpret the chart
6. Revise the chart
Number of Nonconformities Per Unit The u Chart: Constant Sample Size
34
• Step 2: Count and plot u, the number of nonconformities per unit, on the control chart.
n
cu
c
n
sample a in itiesnonconform of number
sample a in items inspected of number
Let
Number of Nonconformities Per Unit The u Chart: Constant Sample Size
35
• Step 3: Calculate the centerline and the control limits (trial)
n
uuLCL
n
uuUCL
n
cu
u
u
3
3
Centerline
Number of Nonconformities Per Unit The u Chart: Constant Sample Size
36
• Step 6: Revise the chart
n
uuLCL
n
uuUCL
nn
ccu
newnewu
newnewu
d
d
new
new
3
3
Centerline
Number of Nonconformities Per Unit The u Chart: Constant Sample Size
37
• When the sample size varies, compute– either the individual control limits
– or a control limit using nave
• When using nave no individual sample size may vary more than 25% from nave
Number of Nonconformities Per Unit The u Chart: Variable Sample Size
samples of number where,
(revised) or (trial)
m
mm
nnn
m
nn
d
m
idi
ave
m
ii
ave11
38
• As the Poisson distribution is not symmetrical, the upper and lower 3-sigma limits do not correspond to equal probabilities of a point on the control chart falling outside limits. To avoid the problem with asymmetry, the use of 0.995 and 0.005 limits has been favored
• If the distribution does not follow Poisson law, actual standard deviation may be greater than and, therefore, 3-sigma limit may actually be greater than limit obtained from the formula
The Control Chart for NonconformitiesThe c and u charts
cc3
39
Example 4: The following are data on 5-gal containers of paint. If the color mixture of the paint does not match the control color, then the entire container is considered nonconforming and is disposed of. Since the amount produced during each production run varies, use nave to calculate the centerline and control limits for this set of data. Carry calculations to four decimal places. Remember to Round nave to a whole number; you can’t sample part of a 5-gal pail.
Production run 1 2 3 4 5 6
Number inspected 2,524 2,056 2,750 3,069 3,365 3,763
Number defective 30 84 76 108 54 29
Production run 7 8 9 10 11 12
Number inspected 2,675 2,255 2,060 2,835 2,620 2,250
Nunmber defective 20 25 48 10 86 25
40
Production Number Number Proportion CheckRun Inspected Defective Defective Point?
n np p1 2,524 30 0.01192 2,056 84 0.04093 2,750 76 0.02764 3,069 108 0.03525 3,365 54 0.01606 3,763 29 0.00777 2,675 20 0.00758 2,255 25 0.01119 2,060 48 0.0233
10 2,835 10 0.003511 2,620 86 0.032812 2,250 25 0.0111
41
Example 5: A c chart is used to monitor the number of surface imperfections on sheets of photographic film. The chart presently is set up based on of 2.6.
(a) Find the 3-sigma control limits for this process.
(b) Use Appendix 4 to determine the probability that a point will fall outside these control limits while the process is actually operating at a c of 2.6.
(c) If the process average shifts to 4.8, what is the probability of not detecting the shift on the first sample taken after the shift occurs?
c
42
Example 6: A shop uses a control chart on maintenance workers based on maintenance errors per standard worker-hour. For each worker, a random sample of 5 items is taken daily and the statistic c/n is plotted on the worker’s control chart where c is the count of errors found in 5 assemblies and n is the total worker-hours required for the 5 assemblies.
(a) After the first 4 weeks, the record for one worker is c=22 and n=54. Determine the central line and the 3-sigma control limits.
(b) On a certain day during the 4-week period, the worker makes 2 errors in 4,3 standard worker-hour. Determine if the point for this day falls within control limits.
43
Reading and Exercises
• Chapter 9: – Reading pp. 404-447 (2nd ed.)
– Problems 5, 10 (solve with and without nave), 11, 13, 14, 19, 20, 23, 25 (2nd ed.)–Reading pp. 414-453 (3rd ed.)
– Problems 5, 10 (solve with and without nave), 11, 13, 14, 19, 20, 23, 25 (2nd ed.)
44
Acceptance Sampling
Outline
• Sampling• Some sampling plans• A single sampling plan• Some definitions• Operating characteristic curve
45
Necessity of Sampling
• In most cases 100% inspection is too costly.• In some cases 100% inspection may be impossible.• If only the defective items are returned, repair or
replacement may be cheaper than improving quality. But, if the entire lot is returned on the basis of sample quality, then the producer has a much greater motivation to improve quality.
46
Some Sampling Plans
• Single sampling plans: – Most popular and easiest to use– Two numbers n and c– If there are more than c defectives in a sample of
size n the lot is rejected; otherwise it is accepted• Double sampling plans:
– A sample of size n1 is selected. – If the number of defectives is less than or equal to
c1 than the lot is accepted. – Else, another sample of size n2 is drawn. – If the cumulative number of defectives in both
samples is more than c2 the lot is rejected; otherwise it is accepted.
47
– A double sampling plan is associated with four numbers:
– The interpretation of the numbers is shown by an
example:
1. Inspect a sample of size 20
2. If the sample contains 3 or less defectives, accept the lot
3. If the sample contains more than 5 defectives, reject the lot.
2121 ccnn and ,,
531020 2121 ccnn ,,, Let
Some Sampling Plans
48
4. If the sample contains more than 3 and less than or equal to 5 defectives (i.e., 4 or 5 defectives), then inspect a second sample of size 10
5. If the cumulative number of defectives in the combined sample of 30 is not more than 5, then accept the lot.
6. Reject the lot if there are more than 5 defectives in the combined lot of 30
• Double sampling plans may be extended to triple sampling plans, which may also be extended to higher order plans. The logical conclusion of this process is the multiple or sequential sampling plan.
Some Sampling Plans
49
• Multiple sampling plans
– The decisions (regarding accept/reject/continue) are made after each lot is sampled.
– A finite number of samples (at least 3) are taken• Sequential sampling plans
– Items are sampled one at a time and the cumulative number of defectives is recorded at each stage of the process.
– Based on the value of the cumulative number of defectives there are three possible decisions at each stage:
• Reject the lot• Accept the lot• Continue sampling
Some Sampling Plans
50
Some Sampling Plans
• Multiple sampling and sequential sampling are very similar. Usually, in a multiple sampling plan the decisions (regarding accept/reject/continue) are made after each lot is sampled. On the other hand, in a sequential sampling plan, the decisions are made after each item is sampled. In a multiple sampling, a finite number of samples (at least 3) are taken. A sequential sampling may not have any limit on the number of items inspected.
51
Some Definitions
• Acceptable quality level (AQL)
Acceptable fraction defective in a lot• Lot tolerance percent defective (LTPD)
Maximum fraction defective accepted in a lot• Producer’s risk,
Type I error = P(reject a lot|probability(defective)=AQL) • Consumer’s risk,
Type II error = P(accept a lot| probability(defective)=LTPD)
52
A Single Sampling Plan
Consider a single sampling plan with n = 10 and c = 2• Compute the probability that a lot will be accepted
with a proportion of defectives, p = 0.10
• If a producer wants a lot with p = 0.10 to be accepted, the sampling plan has a risk of _______________
• This is producer’s risk, and AQL = 0.10
53
A Single Sampling Plan
• Compute the probability that a lot will be accepted with a proportion of defectives, p = 0.30
• If a consumer wants to reject a lot with p = 0.30, the sampling plan has a risk of _____________
• This is consumer’s risk, and LTPD = 0.30
54
Approximation to Binomial Distribution
Under some circumstances, it may be desirable to obtain and by an approximation of binomial distribution
• Poisson distribution: When p is small and n is moderately large (n>25 and np<5)
• Normal distribution: When n is very large, np(1-p)>5
55
Example: Samples of size 50 are drawn from lots 200 items and the lots are rejected if the number of defectives in the sample exceeds 4. If the true proportion of defectives in the lot is 10 percent, determine the probability that a lot is accepted using
a. The Poisson approximation to the binomial
b. The normal approximation to the binomial
56
Example: Samples of size 50 are drawn from lots 200 items and the lots are rejected if the number of defectives in the sample exceeds 4. If the true proportion of defectives in the lot is 10 percent, determine the probability that a lot is accepted using
a. The Poisson approximation to the binomial
b. The normal approximation to the binomial
0.4405 3)- A(Table .}|{
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57
Operating Characteristic Curve
AQL LTPD
= 0.10
= 0.05
Pro
babi
lity
of a
cce
pta
nce
, Pa
{
0.60
0.40
0.20
0.02 0.04 0.06 0.08 0.10 0.12 0.14 0.16 0.18 0.20
0.80
{
Percent defective
1.00
OC curve for n and c
58
Operating Characteristic Curve
OC Curve by Poisson Approximation
n 100 c 4 0.052653017
AQL 0.02 LTPD 0.08 0.0996324
ProbabilityProportion of c or less Defective Defects
(p) np (Pa)0.005 0.5 0.9998278840.01 1 0.996340153
0.015 1.5 0.9814240640.02 2 0.947346983
0.025 2.5 0.8911780190.03 3 0.815263245
59
Operating Characteristics Curve
0
0.2
0.4
0.6
0.8
1
1.2
0.00
50.
025
0.04
50.
065
0.08
50.
105
0.12
50.
145
0.16
50.
185
Proportion of Defectives
Pro
bab
ility
of
acce
pta
nce
60
OC Curve of an Ideal Sampling Plan
• Suppose that 2% is the maximum tolerable proportion defective in a lot
• So, an ideal sampling scheme would reject all lots that were worse than 2% defective and accepted all lots 2% defective better
• The OC Curve of such an ideal scheme would be vertical at p=0.02
• However, no sampling plan can give such an ideal OC curve
61
Effect of Changing the Sampling Plan
• The larger the sample size, the steeper the slope of the OC Curve– Note that this statement is true if both n and c are
increased proportionately.
• If only n increases, every Pa decreases and the curve shifts downward - so, producer’s risk increases and consumer’s risk decreases
• If only c increases, every Pa increases and the curve shifts upward - so, producer’s risk decreases and consumer’s risk increases
62
Reading
• Acceptance Sampling – Reading: Nahmias, S. “Productions and Operations Analysis,” 4th Edition, McGraw-Hill, pp. 668-675
63
Average Outgoing Quality
Outline• Average Outgoing Quality (AOQ)• Average Outgoing Quality Limit (AOQL)
64
Average Outgoing Quality
• After a sample is inspected, the items which are found defective, may be – Case 1: returned to the producer or – Case 2: repaired or replaced by the producer.
• We assume Case (2).• If a lot is rejected, it may be subjected to a 100%
inspection. Such action is referred to as screening inspection, or detailing. This is sometimes described as an acceptance/rectification scheme.
65
Average Outgoing Quality
• If a lot is rejected, there may again be two assumptions regarding the defective items. The defective items may be – Case 1: returned to the producer or – Case 2: repaired or replaced by the producer.
• We assume Case 2. • So, if a lot is rejected, it will contain no defective item
at all. The consumer will get N good items. However, if a lot is accepted, it may contain some defective items because many of the (N-n items in a single sampling plan) items not inspected may be defective.
66
Average Outgoing Quality
• Thus, if there is an average of 2% defective items, the accepted lots will contain little less than 2% defective items and rejected lots will contain no defective item at all. On average, the consumer will receive less than 2% defective items.
• Given a proportion of defective, p the Average Outgoing Quality (AOQ) is the proportion of defectives items in the outgoing lots. More precise definition is given in the next slide.
67
Average Outgoing Quality
items} ofnumber {Outgoing
}defectives ofnumber {OutgoingAOQ
E
E
sample in the items ofNumber
lot in the items ofNumber
} defectives of proportion|accepted is{lot
Let
n
N
pPPa
68
Average Outgoing Quality
)1(1
,
))(1(
)(
a
a
a
a
Pp
pP
nN
nNPpnpN
pnNP
AOQ
than larger much is If
AOQ
replaced not are items Defective 1: Case
Case 1 is not discussed in class
69
Average Outgoing Quality
pP
nNN
pnNP
a
a
AOQ
than larger much is If
AOQ
replaced are items Defective :2 Case
,
)(
70
Average Outgoing Quality
• Given a proportion of defective, we can compute the Average Outgoing Quality (AOQ)
• As p increases from 0.0, the AOQ values increases up to a limit called Average Outgoing Quality Limit (AOQL), after which the AOQ values descend continuously to 0.0. This is shown in the next slide.
71
AOQ Curve
0.015
0.010
0.005
0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10
AOQL
AverageOutgoingQuality
(Incoming) Percent Defective
AQL LTPD
72
Example: Suppose that Noise King is using rectified inspection for its single sampling plan. Calculate the average outgoing quality limit for a plan with n=110, c=3, and N=1000. (Assume that the defective items are replaced)
73
n 110 AOQLc 3 0.01564264N 1000
ProbabilityProportion of c or less Defective Defects
(p) np (Pa) AOQ0.005 0.55 0.997534202 0.0044390.01 1.1 0.974258183 0.008671
0.015 1.65 0.914145562 0.0122040.02 2.2 0.819352422 0.014584
0.025 2.75 0.703039994 0.0156430.03 3.3 0.580338197 0.015495
0.035 3.85 0.463309958 0.0144320.04 4.4 0.359447773 0.012796
74
Average Outgoing Quality
0
0.002
0.004
0.006
0.008
0.01
0.012
0.0140.016
0.018
0.00
50.
015
0.02
50.
035
0.04
50.
055
0.06
50.
075
0.08
50.
095
Proportion of Defectives
Ave
rag
e O
utg
oin
g Q
ual
ity
75
Reading
• Average Outgoing Quality – Reading: Nahmias, S. “Productions and Operations Analysis,” 4th Edition, McGraw-Hill, pp. 682-685