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technical data Systems Introduction

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technical data

Systems

Introduction

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• Systems • Introduction

1

• Introduction

I IntroductionTable of contents

1 Survey of different VRV systems...............................................................................2

2 Indoor units using R-407C..............................................................................................3

3 Outdoor units using R-407C.........................................................................................3

Indoor unit capacity index.............................................................................................................................3

4 Nomenclature.........................................................................................................................4

Indoor units .............................................................................................................................................................4

Outdoor units ........................................................................................................................................................5

5 Explanation of different Systems ..............................................................................6

features..................................................................................................................................................6

I

nverter cooling only / heat pump systems.................................................................10

I

nverter heat recovery systems............................................................................................18

I

nverter heat pump / heat recovery systems .............................................................23

6 Selection procedure ........................................................................................................ 27

Selection procedure standard System based on cooling load........................27

Capacity correction ratio..........................................................................................................29

Selection procedure

System based on cooling load .....................................37

Capacity correction ratio.................................................................................................40

Refnet pipe system..........................................................................................................................................46

Refrigerant pipe selection...........................................................................................................................49

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• Introduction

1

2

1 Survey of different VRV systems

VRV INVERTER COOLING ONLY / HEAT PUMP SERIES

• For EITHER cooling OR heating operation from one system

• Up to 16 indoor units can be operated from a single outdoor unit without the need for an additional adapter PCB. A line-up of 5,8,10 HP models precisely supports applications in small facilities and minor expansions and renovations.

VRV PLUS SERIES

• This line-up from 16HP to 30HP consists of 2 outdoor components, main and sub unit. Up to 32 indoor units can be connected to 1 single refrigerant circuit.

• Available in both heat recovery and heat pump format.

VRV HEAT RECOVERY SERIES

• For SIMULTANEOUS cooling AND heating operation from one system

• Heat recovery is achieved by diverting exhaust heat from indoor units in cooling mode to areas requiring heating.

• The BS unit switches the system between cooling and heating modes.

• Up to 16 indoor units can be operated from a single outdoor unit in heat recovery format.

• Systems • Introduction

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2

• Introduction

2 Indoor units using R-407C

3 Outdoor units using R-407C

3-1 Indoor unit capacity index

NOTE

1 e.g. Selected indoor units: FXYCP25 + FXYCP100 + FXYMP200 + FXYSP40Connection ratio: 25 + 100 + 200 + 40 = 365→ Possible outdoor unit: RSXYP24KJ

Description Indoor unitSize

20 25 32 40 50 63 71 80 100 125 200 250

2-way blow ceiling mounted cassette FXYCP-K7V19 x x x x x x x x

4-way blow ceiling mounted cassette FXYFP-KB7V19 x x x x x x x x x

Ceiling mounted corner cassette FXK-LVE x x x x

Concealed ceiling unit FXYSP-KA7V19 x x x x x x x x x

Concealed ceiling unit (small) FXYBP-KC7V19 x x

Concealed ceiling unit (large) FXM-LVE x x x x x x x x

4-way blow ceiling suspended unit FUYP-BV17 x x x

Ceiling suspended unit FXH-LVE x x x

Wall mounted unitFXA-LVE x x x

FXYAP-KV19 x x x

Floor standing unit FXL-LVE x x x x x x

Concealed floor standing unit FXN-LVE x x x x x x

Description Outdoor unitMaximum number of connectable indoor units Total capacity index

rangeCapacity steps8 13 16 20 32

Inverter cooling only RSXP5L7 x 62.5 - 162.5 20

RSXP8L7 x 100 - 260 31

RSXP10L7 x 125 - 325 31

Inverter cooling only RSXP5K7 x 62.5 - 162.5 13

RSXP8K7 x 100 - 260 20

RSXP10K7 x 125 - 325 20

Inverter heat pump RSXYP5L7 x 62.5 - 162.5 20

RSXYP8L7 x 100 - 260 31

RSXYP10L7 x 125 - 325 31

Inverter heat pump RSXYP5K7 x 62.5 - 162.5 13

RSXYP8K7 x 100 - 260 20

RSXYP10K7 x 125 - 325 20

Inverter heat pump RSXYP16KJ x 200 - 520 26

RSXYP18KJ x 225 - 585 26

RSXYP20KJ x 250 - 650 26

RSXYP24KJ x 300 - 780 29

RSXYP26KJ x 325 - 845 29

RSXYP28KJ x 350 - 910 29

RSXYP30KJ x 375 - 975 29

Heat recovery RSEYP8K7 x 100 - 260 20

RSEYP10K7 x 125 - 325 20

Heat recovery RSEYP16KJ x 200 - 520 26

RSEYP18KJ x 225 - 585 26

RSEYP20KJ x 250 - 650 26

RSEYP24KJ x 300 - 780 29

RSEYP26KJ x 325 - 845 29

RSEYP28KJ x 350 - 910 29

RSEYP30KJ x 375 - 975 29

Model 20 25 32 40 50 63 71 80 100 125 200 250

Capacity index 20 25 31.25 40 50 62.5 71 80 100 125 200 250

• Systems • Introduction 3

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• Introduction

4

4

4 Nomenclature4-1 Indoor units

V1KA740S P 9FXY

Power supply symbolV1: 1~, 230V, 50HzVE: 1~, 230V, 50Hz

Indoor units can be connected to bothR-22 and R-407C outdoor units

K: Indicates major design categoryA: Indicates minor design categoryK7: Indicates DENV productionKJ: Indicates non-DENV production

Capacity IndicationConversion to horsepower:

20: 0.8HP

25: 1HP

32: 1.25HP

40: 1.6HP

50: 2.0HP

63: 2.5HP

80: 3.2HP

100: 4HP

125: 5HP

200: 8HP

250: 10HP

Model name

C: 2-way blow ceiling mounted cassette

F: 4-way blow ceiling mounted cassette

K: Ceiling mounted corner cassette

S: Concealed ceiling unit

B: Concealed ceiling unit (small)

M: Concealed ceiling unit (large)

H: Ceiling suspended unit

A: Wall mounted unit

L: Floor standing unit

LM: Concealed floor standing unit

Indicates that this is an INVERTER HEAT PUMP/COOLING ONLY or a HEAT RECOVERY indoor unit

• Systems • Introduction

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4

• Introduction

4 Nomenclature4-2 Outdoor units

• VRV Inverter heat pump series

• VRV Plus inverter heat pump series using R-407C

• BS unit

RSX Y P 8 K7 W1Power supply symbol:W1: 3N~, 400V, 50Hz

K7, KL, KJ: indicates major design category (internal company symbol)

5: 5HP8: 8HP

10: 10HP

Indicates the use of ozone friendly refrigerant R-407C

Indicates heat pump (year around)

RSX: indicates that this is an INVERTER outdoor unitRSEY: indicates that this is a HEAT RECOVERY outdoor unit

RSX Y P 16 KJ Y1Power supply symbol:Y1: 3~, 400V, 50Hz

Major design category

16: 16HP18: 18HP20: 20HP24: 24HP26: 26HP28: 28HP30: 30HP

Indicates the use of ozone friendly refrigerant R-407C

Indicates heat pump (year around)

RSX: indicates that this is an INVERTER outdoor unitRSEY: indicates that this is a HEAT RECOVERY outdoor unit

BSV P 100 K V1Power supply symbol:V1: 1~, 230V, 50Hz

Major design category

Capacity indication (Connectable total indoor unit capacity)100: Total indoor unit capacity less than 100160: Total indoor unit capacity 100 or more but less than 160250: Total indoor unit capacity 160 or more but less than 250

Indicates the use of ozone friendly refrigerant R-407C

Indicates that this is a BS unit

• Systems • Introduction 5

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• Introduction

5

6

5 Explanation of different Systems5-1 features

• To indicate clearly that we introduce a next generation of VRV, Daikin decided to link a new name and logo the high COP VRV, i.e.

• The logo is linked in 4 ways to the major features of the high COP VRV:

1. π is equal to 3.14, the new high COP level.

2. π (PI) where

– P stands for Performance: linked to the highest COP level available based on the latest and newest VRV technology

– I stands for Intelligence: the most advanced intelligent technology is used

3. π is a technical symbol linked to the highest technical VRV unit in the market

4. π is a perfect, universal and never ending number. This is linked with the continuous improvements of Daikin.

• The above arguments explain the name πVRV. It is an easy name to remember and it includes all the new features of the next generation of VRV.

Energy Saving

• Highest COP in both Cooling and Heating operation• High partial load performance

NOTES

1 Average cooling-heating COP is obtained by adding the COP of cooling to the COP of heating and then dividing the sum by 2.

2 COP's figures are reference value

3 COP – comparison with the current K Series

Average cooling-heating COP*1

Value represents that to be achieved by a single outdoor unit.

Environmental Friendly

• Ozone friendly refrigerant : R-407C• Dramatic reduction in refrigerant charge compared to the current range

• Refrigerant recovery function :this service mode enables all expansion valves of the VRV system to be opened. In this way the refrigrerant can be drained from the VRV piping system and stored in a separate recovery tank.

Control Systems

Flexible Design

• Increased installation flexibilityDesign flexibility on a veranda is improved.Outdoor units can be installed far back from former location.

2.64 3.103.10

2.562.62 3.10

1

0

2

35HP 8HP 10HP

*3 *2

+18%

+15%

+15.5%

Current New

No. 1 COP

RSXYP-L7W1 5 8 10

Reduction of 11 % 10.5 % 14 %

DuctDuct

*Actual piping length

Height difference

* Equivalent piping length 140m

• External Static Pressure(as standard by field setting)

• Max. actual pipinglength 120m

Total length=

No special restrictions

• Systems • Introduction

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5

• Introduction

5 Features5-1 features

Extremely quiet in operation• Night quiet function

Starting time and ending time can be put in

NOTES

1 This function is available in setting at site.

2 The relationship of outdoor temperature (load) and time shown in the graph is just an example.

• Hybrid aerofoil fanThe newly developed fan ensures low sound level performance at the thick part of the aerofoil and power saving at the thin part of the foil (wide inlet fan)

• High flared bell mouthImproves low sound level characteristics by applying air flow analyses techniques developed by NASA to create smooth air flow at the edge of foil.

• Super aero grilleThe spiral shaped ribs are aligned with the direction of discharge flow in order to minimise turbulence and reduce noise.

50

8:00 12:00 16:00 20:00 0:00 4:00 8:00

50

100

580

max. -8dB (10HP)

Opera

tion s

ound

dBLo

ad %

Capa

bility

%

Night mode starts Night mode Ends

Night mode

external signal input to outdoor PCB

Hybrid aerofoil fan

Thick Thin

Bending wing of rear end Hybrid aerofoil fan

dindin

Front endVortex Flow of peripheral edge

Hub

Bell mouth

GrilleRear end

It reduces Vortex Flow of peripheral edge,power input and noise.

Peripheraledge

• Systems • Introduction 7

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• Introduction

5

8

5 Features5-1 features

An energy efficiency increase of approximately 20% achieved by the adoption of diverse new technologies :

� Reluctance DC Compressor

The reluctance DC motor provides significant increases in efficiency compared to conventional AC inverter motors, simultaneously using 2 different forms of torque to produce extra power from small electric currents.

The scroll compressor is driven by the newly developed motor enabling better performance, higher energy efficiency resulting in high energy cost savings:

• Using 4 neodymium magnets. These magnets are more powerful than the widely used ferrite types.

• The new rotor structure allows the highest reluctance torque

Energy Saving UP 11%

Reductance DC motor

Scrolling

Ferrite magnet Neodymium magnet

Powerful magnets:Secret to raising energy-efficiency!

Siliconsteel plate

Aluminium Siliconsteel plate

Contains 4 neodymium magnets

Guidance torque Reluctance torque

• Systems • Introduction

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5

• Introduction

5 Features5-1 features

� Sine Wave DC inverter

Optimizing the sine wave curve, results in smoother motor rotation and improved motor efficiency.

DC fan motor

The use of a DC fan motor offers substantial improvements in operating efficiency compared to conventional AC motors, especially during low speed rotation.

Super aero grill & powerful fan

Improved aerodynamic shape of the grille in combination with a newly developed fan results in a 10 % increase in air flow rate.

� e-Bridge circuit

Prevents accumulation of liquid refrigerant in the condenser. This results in more efficient use of the condenser surface under any circumstance and leads in turn to better energy efficiency.

� e-Pass heat exchanger

Optimization of the path layout of the heat exchanger prevents heat transferring from the overheated gas section towards the sub cooled liquid section - a more efficient use of the heat exchanger.Also heat exchange capability is improved by the use of U type wide form and waffle fins, resulting in an improved COP.

i-demand function

The newly introduced current sensor minimizes the difference between the actual power consumption and the predefined power consumption.

Rectangular wave Sine wave PWM*

* Pulse Width Modulation

Energy Saving UP 2%

200 300 400 500 600 700 800 900 10000

20

40

60

80

DC motor

DC motor efficiency(comparison with a conventional AC motor)

Efficie

ncy (%

)

Motor speed (rpm)

AC motor

Firstin the Industry

DC fan motor structure

magnet

Energy Saving UP 4%

Energy Saving UP 1%

Energy Saving UP 2%

HD Type

Waffle fin

Old fin

Current Model

U type wide form

Energy Saving UP 2%

8:00

Powe

rco

nsump

tion (

KVV)

Time12:00 16:00 20:00

• Systems • Introduction 9

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• Introduction

5

10

5 Features5-2 Inverter cooling only / heat pump systems

• Survey

• Outdoor units

• INTRODUCTION

A high-grade, high-quality, advanced individual air conditioning system is able to cover more sophisticated building environment needs.

Making buildings more “intelligent” and improving office environment have to be pursued vigorously, in order to create a space referred to as the “new office”. Therefore, there is a demand for further upgrading air conditioning systems.

Comfort on the individual level as well as work efficiency and creativity are linked to the performance of air conditioning.

Description Outdoor unitMaximum number of connectable indoor units

Total capacity index range Capacity steps8 13 16

Inverter cooling only RSXP5L7 x 62.5 - 162.5 20

RSXP8L7 x 100 - 260 31

RSXP10L7 x 125 - 325 31

Inverter cooling only RSXP5K7 x 62.5 - 162.5 13

RSXP8K7 x 100 - 260 20

RSXP10K7 x 125 - 325 20

Inverter heat pump RSXYP5L7 x 62.5 - 162.5 20

RSXYP8L7 x 100 - 260 31

RSXYP10L7 x 125 - 325 31

Inverter heat pump RSXYP5K7 x 62.5 - 162.5 13

RSXYP8K7 x 100 - 260 20

RSXYP10K7 x 125 - 325 20

RSXP5L7 RSXP8L7 RSXP10L7

RSXP5K7 RSXP8K7 RSXP10K7

• Systems • Introduction

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5

• Introduction

5 Explanation of different Systems5-2 Inverter cooling only / heat pump systems

The VRV system of advanced individual air conditioning is a sophisticated, flexible expansion system proper to handle diverse expanding needs.

• EXAMPLES OF DIFFERENT ASSEMBLY PATTERNS

A single refrigerant pipe system can be connected up to max. 16 indoor units each with a different capacity (0.8 to 5 HP) and of different types with an outdoor unit capacity ratio of up to 130%.

Outdoor unit• Outdoor units can be grouped together in a row• 3 types: 5HP, 8HP, 10HP: cooling only or heat

pump

Indoor unit• Up to 16 units can be connected in one system• Minimum capacity: 0.8HP

REFNET pipe system• Actual length of refrigerant piping 100m• Level difference of 50m makes this system

suitable for buildings up to 15 to 16 stories

RSX(Y)P5K: maximum 8 indoor units can be connected

RSX(Y)P8K: maximum 13 indoor units can be connected

Remote control

Remote control

• Systems • Introduction 11

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• Introduction

5

12

5 Explanation of different Systems5-2 Inverter cooling only / heat pump systems

zw

• MAIN FEATURES

HIDECS Circuit with Inverter Control and Original Electronic Control

1 New Linear VRV System with Inverter controlAbbreviates inverter control frequency steps and expands capacity control range.

2 Outdoor Unit Heat Exchanger Capacity ControlIncludes capacity control of outdoor unit heat exchangers for multi-variable PI control for executing optimal load control.

3 Oil Control SystemControls volume of refrigerant oil to prevent oil from rising or refrigerant liquid back in lengthy pipes.

4 Refrigerant Flow Stabilization MechanismPrevents refrigerant drift in lengthy pipes.

5 PID control with Automatic Capacity Balancing CircuitControls refrigerant flow through addition of techniques (3) and (4).

• INVERTER TECHNOLOGY

Daikin VRV air conditioning offers end users substantial savings in energy costs, the application of innovative inverter technology ensures efficient performance throughout the system’s operating cycle.

• INVERTER DRIVEN CAPACITY CONTROL

RSX(Y)P10K: maximum 16 indoor units can be connected

Remote control

Inverter Control

Load

100%

Large Small

116Hz~30Hz13 steps

CompressorCapacityControl

• Capacity control of 5HP Outdoor Unit

• Capacity control of 8HP Outdoor Unit

26%

Nr. 1CompressorInverter Control

Nr. 2Compressor100% Operation Nr. 1

CompressorInverter Control

Load

100%

Large Small

116Hz~30Hz+Nr. 2 Compressor20 steps

CompressorCapacityControl

8HP 10HP50Hz 18% 15%

Refnet joint Attached insulators for Refnet joint

• Systems • Introduction

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5

• Introduction

5 Explanation of different Systems5-2 Inverter cooling only / heat pump systems

• SMART CONTROL BRINGS COMFORT

An electronic expansion valve, using PID control, continuously adjusts the refrigerant volume in respond to load variations of the indoor units. The VRV system thus maintains comfortable room temperatures at a virtually constant level, without the temperature variations typical of conventional ON/OFF control systems.The thermostat can control stable room temperature at ± 0.5°C from set point.

• INVERTER CONTROLLED LINEAR VRV SYSTEM

The “Linear system” makes use of a multi-variable PI (Proportional Integral) control system which uses refrigerant pressure sensors to give added control over inverter and ON/OFF control compressors in order to abbreviate control steps into smaller units to provide precise control in both small and larger areas.This in turn enables individual control of up to 16 indoor units of different capacity and type at a ratio of 50~130% in comparison with outdoor unit capacity. (5HP outdoor units use inverter control compressors only.)

z

Daikin’s original new multi-variable PI control system automatically controls operation using various sensors that detect refrigerant pressure and room temperature in a certain sequence.The system is further enhanced by the addition of a capacity control function for outdoor unit heat exchangers, and is able to execute individual control of indoor units ranging from a minimum of 0.8HP to a maximum of 10HP. Because it is able to operate within a wide range of outdoor temperatures including a minimum steady temperature of -5 °C (cooling), it is also able to handle tough air-conditioning conditions throughout the year.

VRV SERIES (DAIKIN PID Controls)ON/OFF controlled air conditioner (2.5HP)

Cooling

Time

Suctio

n air t

empe

rature

NOTE

1 The graph shows the data, measured in a test room assuming actual heating load.

REFNET Joint Indoor unit

NOTE

1 If you plan to do cooling operation in outdoor temperatures of 15°C or less, be sure to carry out thermal insulation of the refrigerant liquid and gas piping

• Systems • Introduction 13

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• Introduction

5

14

5 Explanation of different Systems5-2 Inverter cooling only / heat pump systems

• PID CONTROL

Proportional Integral Derivative control with an automatic capacity balancing circuit:

– enables the use of lengthy piping up to 100 meters (actual length)

– consists of two control systems:

1 Oil control system that controls the refrigerant oil volume to prevent it from raising or backing up in the pipes

2 Refrigerant flow stabilization mechanism: prevents refrigerant drift, caused by level difference of indoor units in the same system.

• OPERATION CONTROL OF SMALL CAPACITY INDOOR UNITS

If the operating frequency is minimal, the refrigerant pressure and outdoor temperature are detected, the number of control steps are calculated, and capacity of outdoor unit heat exchanger (refrigerant accumulates in coils) and air flow of outdoor unit fans (controls pole change of the two fans) are controlled.If operating a small-capacity indoor unit, the bypass valve is controlled (ON/OFF), with capacity control being executed at a minimum of 14% for a 5HP outdoor unit (when operating one 20-class indoor unit), or a minimum of 8% for 8 and 10HP outdoor units (when operating one 20-class indoor unit.

• CONTROL FLOW

Minimum Frequency(5HP Outdoor Unit: 30Hz)

(8/10HP Outdoor Unit: 30Hz)

NoAre you operating asmall-capacity indoor unit?

Yes

Detection of Refrigerant Pressure and Outdoor Temperature

Step Control Calculation

Bypass Valve On/Off Control

Capacity Control of Outdoor UnitHeat Exchangers

Air Flow Control of OutdoorUnit Fans

Deviation (difference between sensed pressure and desired value)

No Yes

Frequency Alteration of Inverter CompressorOn/Off of ON/OFF Compressor

Outdoor Coil Capacity Control Air Volume Control by Outdoor Unit Fan

Step Control Calculation

Detection of Refrigerant Pressure and Outdoor Temperature

Sampling Timer Count

Operating Pressure Detection by Pressure Sensors

Calculation of Constant for Integral Control

Total capacity Decision by Multi-Variable P-Control

Optimal Load Decision

Minimum Frequency

Every T Seconds

• Systems • Introduction

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5

• Introduction

5 Explanation of different Systems5-2 Inverter cooling only / heat pump systems

• LOW OPERATION SOUND LEVEL

Continuous research by Daikin into reducing operation sound levels has resulted in the development of a purpose designed inverter scroll compressor and fan.

• OPERATION RANGE

Standard operation down to -15°C outdoor ambient temperature

Advanced PI control of the outdoor unit enables VRV (Plus) heat recovery and Inverter series to operate at outdoor ambients down to -5°C in cooling mode and down to -15°C in heating mode.

• POSSIBILITY TO ADD EXTRA INDOOR UNITS

VRV systems are easily adaptable to changes in room layout: extra indoor units can be added to a VRV outdoor unit up to a capacity level of 130%.

50

40

30

20

10

-5

-10

-15

50

40

30

20

10

-5

-10

-15

Coolingg43°CDB

(Plus) Inverter series (Plus) heat recorvery series

-5°CDB

-15°CWB

Heating15.5°CWB

Coolingg43°CDB

-5°CDB

-15°CWB

Heating15.5°CWB

-5°CWB

Cooling & Heating15.5°CWB

Pinched pipe

Pinched pipe

Additional units must always be added below the REFNET header.

• Systems • Introduction 15

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• Introduction

5

16

5 Explanation of different Systems5-2 Inverter cooling only / heat pump systems

• EXTENDED REFRIGERANT PIPING

The ability to sustain refrigerant piping in lengths up to 100m (120m equivalent) for K series, 120m for L series, allows systems to be designed with level differences of 50m between indoor and outdoor units and 15m between individual indoor units. Thus, even with installations in 15 storey buildings, all outdoor units can be located at rooftop level.

• MODULAR & LIGHTWEIGHT

Modular design enables units to be joined together in rows with an outstanding degree of uniformity.

The design of the outdoor units (from 5HP to 10HP) is sufficiently compact to allow them to be taken up to the top of a building in a commercial elevator, overcoming site transportation problem, particularly when outdoor units need to be installed on each floor.

• UNIFIED REFNET PIPING

The unified Daikin REFNET piping system is especially designed for simple installation and for use with both R-407C and R-22 refrigerants. Only 2 or 3 main refrigerant pipes are necessary per system and unlike conventional water based schemes, VRV systems do not require strainers, stop valves, 2 and 3 way valves, oil traps, anti freeze treatment or air purging. The use of REFNET piping in combination with electronic expansion valves, results in a dramatic reduction in imbalance in refrigerant flowing between indoor units, despite the small diameter of the piping. REFNET joints and headers (both accessories) can cut down on installation work and increase system reliability.

Actual pipinglength

*1*2

(Plus) Inverter Series

Level difference

and outdoor units

between iunits

Actual pipinglength

*1

(Plus) heat recovery Series

Level differencebetween indoorand outdoor units

Level dbetweeunits

Actual pipinglength

Height difference

*4

*5

NOTES

1 This value is based on the case where the outdoor unit is located above the indoor unit. If the outdoor unit is located underneath the indoor unit the level difference is a maximum of 40m.

2 The maximum actual piping length between the indoor unit and the first branch is 40m.

3 The BS unit can be located anywhere between the indoor unit and outdoor unit, if installing after the first branch (REFNET JOINT or HEADER), the piping limit is less than 40m. This value is based on the case where the outdoor unit is located above the indoor unit.

4 Equivalent piping length 140m

5 Total length = no special restrictions

Refnet header Attached insulators for Refnet header

• Systems • Introduction

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5

• Introduction

5 Explanation of different Systems5-2 Inverter cooling only / heat pump systems

• SEQUENTIAL START

Facilitates electrical work because up to 3 outdoor units can be hooked up to the power supply simultaneously. If using a combination of 8 and 10HP units and start-up must be executed in sequence, please purchase an optional adapter for sequential start separately.

• OPERATION MODE POSSIBILITIES

You can simultaneouly switch several outdoor units using Cool/Heat selector.

• SIMPLIFIED WIRING

A simple 2-wire multiplex transmission system links each outdoor unit to mulyiple indoor units using one 2-core wire, thus simplifying the wiring operation.

• AUTO ADDRESS SETTING FUNCTION

Allows wiring between indoor and outdoor units, as well as group control wiring of multiple indoor units, to be performed without the bothersome task of manually setting each address.

• AUTO CHECK FUNCTION

The auto check facility available on the VRV (Plus) inverter and heat recovery series is the first of its type in the industry to warn operatives of connection errors in interunit wiring and piping. This function identifies and alerts system errors by means of on/off LEDs on the outdoor unit’s PC boards.

• OUTDOOR UNIT COMBINATIONS

By using a combination of 5, 8 and 10HP units, you can easily develop a system that can handle even smaller areas.You can use up to three outdoor units of 10HP or less in any combination. For units of more than 10HP, you develop a system of the exact desired capacity, graduating in units as small as approx. 1HP each. (For power supply cabling, run cable in sequence starting from the larger outdoor unit in terms of horsepower.)

3-Phase, Power Supply

NOTE

1 Not operative unless power is turned on for all outdoor units.

Cool/Heat selector (Simultaneous, individual unit switching using outdoor unit PC board switch)

Power supply

Power supply 2 Cab

les

2 Cab

les

2 Cab

les

2 Cab

les

2 Cab

les

2 Cab

les

2 Cab

les

2 Cables

2 Cables2 Cables2 Cables2 Cables2 Cables2 Cables2 Cables2 Cables

Remote control

Remote control

Remote control

Remote control

Remote control

Remote control

Remote control

Remote control

Total HP Total Nr. of Units System Structure RSX(Y)5 1 58 1 8

10 1 102 5+5

13 2 5+8

15 2 5+103 5+5+5

16 2 8+8

18 2 8+103 5+5+8

20 2 10+103 5+5+10

21 3 5+8+823 3 5+8+1024 3 8+8+825 3 5+10+1026 3 8+8+1028 3 8+10+1030 3 10+10+10

• Systems • Introduction 17

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• Introduction

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5 Explanation of different Systems5-3 Inverter heat recovery systems

• SURVEY

• OUTDOOR UNITS

• INTRODUCTION

Total room layout flexibility

VRV systems are easily adaptable to changes in room layout: extra indoor units can be added to a VRV outdoor unit up to a capacity level of 130%.Also, since VRV heat recovery systems offer simultaneous cooling and heating, existing indoor and outdoor units can continue to provide year round air conditioning from their existing locations, even if office layouts are altered or extended.

Year round cooling and/or heating

Designed to provide simultaneous year round cooling and/or heating, VRV heat recovery systems are modular in concept and are therefore, ideal for use in rooms or zones that generate varying thermal loads according to building orientation or local hot or cold spots.It is possible for the same meeting room to give rise to differing thermal loads depending on the time of day, number of occupants present, location and usage pattern of lighting and electronic office equipment. Until the advent of the VRV, a complex 4-pipe fan coil was needed to meet this requirement. The VRV however, is easier to design and install and in its heat recovery format, can conserve energy in two or more rooms at the same time.

Description Outdoor unit Maximum number of connectable indoor units Total capacity index range

Heat recovery RSEYP8K7 13 100 - 260

RSEYP10K7 16 125 - 325

RSEYP8 RSEYP10 BSV(P)100,160

➨M i Meeting room INDOOR UNIT

• Systems • Introduction

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5 Explanation of different Systems5-3 Inverter heat recovery systems

Simultaneous cooling and heating operation with 1 system

• EXAMPLES OF DIFFERENT ASSEMBLY PATTERN

RSEYP8K: maximum 13 indoor units can be connected

RSEYP10K: maximum 16 indoor units can be connected

Outdoor unit• Outdoor units can be grouped together in a row• 2 types: 8HP, 10HP

Indoor unit• Up to 16 units can be connected to provide an

operating capacity of between 50% and 130%• Minimum capacity: 0.8HP

REFNET pipe system• Actual length of refrigerant piping 100m• Level difference of 50m makes this system

suitable for buildings up to 15 to 16 stories

BS unit

Accessory

BS unit

Remote control

BS unit

Remote control

• Systems • Introduction 19

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5 Explanation of different Systems5-3 Inverter heat recovery systems

• LOAD DISTRIBUTION

A totally individual energy saving air conditioning system that uses a highly efficient load heating and cooling free heat recovery method making use of differences in the load.A highly energy efficient, wholly modular air conditioning system has been achieved through the use of a heating and cooling free heat recovery method whereby efficiency is enhanced by selective load distribution.

The use of “R-HIDECS circuit” inverter (*2) control together with independent multi-variable PI control (*1) for the precise monitoring of status and more effective control of each part of the system, enables the highly particularized use of the system’s capacity to meet the varying air conditioning load requirements (heating and cooling requirements and load size) of different rooms.This is nothing less than a completely revolutionary modular air conditioning system which offers the user an entirely free choice of cooling or heating mode for each and every indoor unit in the system.

NOTES

*1: Proportional integrated control.

*2: Recovery-Hi-Inverter Drive and Electronic Control System.

• EFFECTIVE SIMULTANEOUS COOLING AND HEATING FROM 1 SYSTEM

Effective simultaneous cooling and heating from 1 outdoor unit is achieved by the addition of a gas suction pipe to the existing liquid and gas discharge piping of the refrigerant system. The availability of both cooling and heating functions is then achieved through the selection of either the gas discharge or the gas suction pipe in accordance with the ambient temperature and temperature settings.At this point the “R-HIDECS circuit” is used for capacity control of the indoor unit heat exchanger and the outdoor unit compressor and heat exchanger in order to achieve perfect performance through the collection and delivery of the precise amount of refrigerant required.Moreover, perfect control of the thermal balance is achieved by the use of inverter and fan speed adjustment control which in turn permits stable and efficient control in response to independent selection of cooling or heating mode for each indoor unit.

• SYSTEM OUTLINE

• ENERGY SAVING SYSTEM USING HEAT RECOVERY

This complete heat recovery system operates by selecting the mode with the smaller load during the course of simultaneous heating and cooling operations and then using the refrigerant to transmit heat from the mode which is bearing the lower load to the mode which is bearing the higher load.In this way it is possible in winter, for example, to use the waste heat from the OA room cooling operation to heat the remaining office space … a highly effective use of energy is thus achieved.

� Twin heat exchangers� Twin compressor (inverter + unloader) Fan Gas discharge pipe

� Gas suction pipe� Liquid pipe Gas pipe� REFNET joint

Outdoor unitIndoor unit

BS unit

simultanous operation mode control(up to a maximum of 12 units)

Year-round cooling

• Systems • Introduction

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5 Explanation of different Systems5-3 Inverter heat recovery systems

• COOLING AND HEATING DEVIATION

cooling

� Heat radiation mode (all cooling operation)

� Heat radiation tendency heat recovery operation (mainly cooling, partly heating operation

Heat recovery operation (cooling � heating operation)

Heat absorption tendency heat recovery operation (mainly heating, partly cooling operation)

� Heat absorption operation (all heating operation)

Heat

radiat

ionHe

at rad

iation

Heat

absor

ption

Heat

absor

ption

cooling cooling cooling

cooling cooling cooling heating

cooling cooling heating heating

cooling heating heating heating

heating heating heating heating

• Systems • Introduction 21

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5 Explanation of different Systems5-3 Inverter heat recovery systems

• FREER DESIGN AND EASIER OPERATION VIA A SINGLE HEAT RECOVERY SYSTEM

Compared to other outdoor units that have a separate heating and cooling system and a separate year-round cooling outdoor unit, this single heat recovery system saves on installation space, makes refrigerant piping simpler and increases the overall simplicity of the system.

- Fewer outdoor units, hence less installation space is needed

- Installation can be simplified and greater reliability is achieved

- Greater savings on facilities and installation costs and time

- Simple refrigerant piping system and small pipe shaft space

- Wiring has been made even easier with a power outlet now fitted to the front of the unit to add to the one on the side

- It is not necessary to take designs for room usage, conditions and air conditioning loads into account

- New refrigerant control technology has enabled an actual refrigerant piping length of 100m and a level difference of 15-16 floors

- Heat recovery operation allows you to save approx. 15-20% of annual demand compared with conventional individual air-conditioning systems (Trial by this company)

- Lets you reduce total outdoor unit capacity by approx. 15-20% (Trial by this company)

• SIMPLE OPERATION CONTROL

- Easy control because operation mode selection for outdoor units is unnecessary.

- Equipped with an automatic operation function that can automatically changeover cool/heat according to temperature setting and room temperature.

Extension between outdoor unit and furthest indoor unit: 100mExtension between first branch and furthest indoor unit: 40m

Outdoor unit

Coolingoperation

Discharge pipe Liquid pipeSuction pipe

Indoor unit

BS unit BS unitREFNET jointREFNET joint

REFNET headerLevel difference between outdoor and indoor unit: 50m

• Systems • Introduction

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5

• Systems • Introduction

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• Introduction

5 Explanation of different Systems

5-4 Inverter heat pump / heat recovery systems

• SURVEY

Conditions of heat pump system connection:

Conditions of heat pump system connection:

Conditions of BS unit connection:

• OUTDOOR UNITS + BS BOXES

VRV Plus heat pump / heat recovery systems

Main units

Sub units BS unit

Model name Horsepower Total capacity index Max. nr. of connectable indoor units Capacity steps Outdoor unit combinations

RSXYP16KJY1 16 HP 200~520 20 26 RXYP8KJ + RXEP8K7

RSXYP18KJY1 18 HP 225~585 20 26 RXYP10KJ + RXEP8K7

RSXYP20KJY1 20 HP 250~650 20 26 RXYP10KJ + RXEP10K7

RSXYP24KJY1 24 HP 300~780 32 29 RXYP16KJ + RXEP8K7

RSXYP26KJY1 26 HP 325~845 32 29 RXYP16KJ + RXEP10K7

RSXYP28KJY1 28 HP 350~910 32 29 RXYP20KJ + RXEP8K7

RSXYP30KJY1 30 HP 375~975 32 29 RXYP20KJ + RXEP10K7

Model name Horsepower Total capacity index Max. nr. of connectable indoor units Capacity steps Outdoor unit combinations

RSEYP16KJY1 16 HP 200~520 20 26 REYP8KJ + RXEP8K7

RSEYP18KJY1 18 HP 225~585 20 26 REYP10KJ + RXEP8K7

RSEYP20KJY1 20 HP 250~650 20 26 REYP10KJ + RXEP10K7

RSEYP24KJY1 24 HP 300~780 32 29 REYP16KJ + RXEP8K7

RSEYP26KJY1 26 HP 325~845 32 29 REYP16KJ + RXEP10K7

RSEYP28KJY1 28 HP 350~910 32 29 REYP20KJ + RXEP8K7

RSEYP30KJY1 30 HP 375~975 32 29 REYP20KJ + RXEP10K7

Model name Horsepower Connectable ratio Max. nr. of connectable indoor units

BSVP100K 4 HP less than 11.2 kW 5

BSVP160K 6 HP 11.2 kW~less than 18.0 kW 8

BSVP250K 10 HP 18.0 kW~less than 28.0 kW 12

RSXYP/RSEYP16,18KJY1 RSXYP/RSEYP20KJY1 RSXYP/RSEYP24,28KJY1 RSXYP/RSEYP26,30KJY1

RXYP/REYP8KJY1 RXYP/REYP10KJY1 RXYP/REYP16KJY1 RXYP/REYP20KJY1

RXEP8KJY1 RXEP10KJY1

BSVP-K

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5 Explanation of different Systems5-4 Inverter heat pump / heat recovery systems

• INTRODUCTION

VRV Plus series using R-407C are designed for outdoor installation and used for cooling and heat pump applications. The RSXYP units are available in 7 standard sizes with nominal cooling capacities ranging from 43.8 to 82.1 kW and nominal heating capacities ranging from 43.8 to 82.1 kW.

• COMPRESSOR CAPACITY CONTROL

• REDUCTION IN INSTALLATION SPACE

R-407C VRV Plus units - without function unit - consist out of 2 components only, namely main unit & sub unit, whereby the common piping system is integrated in the main unit. This significantly reduces the necessary installation space. A reduction of 13.7% for the 20HP unit and a reduction of 11.6% for the 30HP unit.

• SIMPLIFIED PIPING SYSTEM

30HP Outdoor Unit

Large Load Small

100%

11%

No. 1CompressorInverter Control

No. 1CompressorInverter Control

No. 1CompressorInverter Control

Inverter Control79~29Hz 18 steps

No. 3Compressor

100% Operation

No. 2Compressor

100% Operation

No. 2Compressor

100% Operation

79Hz~29Hz + No. 2 + No.3

Compressor 29 Steps

Comp

ressor

Capa

city Co

ntrol

30HP

Reduction by 13.7%

NEW

20HP

VRV Plus

VRV Plus

R-22

R-407C

Reductionby 11.6%

11 Pipes20 Connections

4 Pipes6 Connections

Simplified PipingE.g. 30 HP

R-22

R-407C

• Systems • Introduction

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5 Explanation of different Systems5-4 Inverter heat pump / heat recovery systems

• SUPER WIRING SYSTEM

A Super wiring system is used to enable the shared use of the wiring between the indoor and outdoor units and the centralised remote control. A high-level central control system can be achieved via a relatively simple wiring operation. Even when retrofitting with a central control system, you only need to connect the centralised remote control to the outdoor units.

• BACK-UP FUNCTION

Conventional VAV systems or water systems require expensive, bulky standby systems to prevent air conditioning from being shut down when a problem has occurred. The VRV system conditions the air in each room individually, allowing any possible problems to affect only the immediate system and not the complete VRV system. If one compressor in the outdoor units of the Plus series should malfunction, the back-up function by means of remote control will allow emergency operation of another compressor

• REDUCTION IN REFRIGERANT VOLUME COMPARED TO VRV PLUS R-22 UNITS

• REFRIGERANT PIPES with diameter 25.4 mm are changed to diameter 28.6 mm to match European standards.

• FIELD PIPING CONNECTION has been simplified: 6 spots for piping connection instead of 14 for 20HP outdoor unit and 26 for 30HP outdoor unit.

Unit Horsepower Reduction (kg) Reduction (%)

RSXYP16KJ 16 HP 4.6 kg 77%

RSXYP18KJ 18 HP 5.5 kg 75%

RSXYP20KJ 20 HP 6.7 kg 72%

RSXYP24KJ 24 HP 5.2 kg 82%

RSXYP26KJ 26 HP 6.6 kg 78%

RSXYP28KJ 28 HP 7.2 kg 78%

RSXYP30KJ 30 HP 8.8 kg 74%

Outdoor unit

Remote controlCentralised remote control

Indoor unit

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5 Explanation of different Systems5-4 Inverter heat pump / heat recovery systems

• FIELD PIPING CONNECTION

� High-efficiency scroll compressor

Conventional compressors were designed to cool a motor with all incoming refrigerant gas and send it to the compression process. Daikin’s new scroll compressor separates incoming refrigerant: a gas which is fed to compressing process through motor in order to cool the motor and a gas which is fed to compressing process directly. This minimizes loss in motor section

The refrigerant gas inlet to the compression process is located near the suction inlet to minimize loss.

� New intelligent defrost control

Detection of frosting conditions of a multiple number of heat exchangers to achieve timely activation of defrost operation.

Newly developed inverter unit

Detailed capacity control in accordance with high-efficiency scroll compressor operation.

New-type oil separator

Ensures high reliability even with extended piping.

� New oil-return operation control

Daikin’s original sensor technology for accurate return of lubrication oil to compressors.

� Twin/triple compressor control

Optimum capacity control of two or three compressors in accordance with load.

(16~20 HP: twin, 24~30 HP: triple)

Superheat optimization control (indoor unit)

In an indoor unit, liquid refrigerant is heated by a heat exchanger, and it boils and evaporates, thus changing to a gas state. The refrigerant temperature is controlled by an electronic expansion valve and thermistor so the temperature difference between the inlet and outlet stays 5°C. R-22, a single-component refrigerant remains at a constant temperature until it changes completely to a gas; therefore, the gas must be superheated to increase the temperature by 5°C. By contrast, R-407C, a mixture of three different refrigerants, increases in temperature before it becomes 7a gas, thus requiring the superheating process to bring up the temperature by only 2°C. This means more efficient operation of the heat exchanger.

��

��

��

Suction gasSuction gas

Motor coolingMotor cooling

To the suction port (directly)

Suction gas Suction gas

Orbiting scroll

Fixed scroll

R-407CR-22 L G

L

G

L: liquid refrigerant, G: gas refrigerant

R-22 refrigerant

R-407C refrigerant

Liquid-side thermistorExample: 2∞2 C

Liquid-side thermistorExample: 2∞2 C

Gas-sidethermistorExample: 7∞7 C

Gas-sidethermistorExample: 7∞7 C

Indoor unit heat exchanger

Indoor unit heat exchanger

Electronic expansion valve

Electronic expansion valve

Superheat = 5∞5 C

Superheat = 2∞2 C

• Systems • Introduction

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• Introduction

6 Selection procedure6-1 Selection procedure standard System based on cooling load

6-1-1 Indoor unit selection

Enter indoor unit capacity tables at given indoor and outdoor temperature.

Select the unit that the capacity is the nearest to and higher than the given load.

NOTE

1 Individual indoor unit capacity is subject to change by the combination. Actual capacity has to be calculated according to the combination by using outdoor units capacity table.

6-1-2 Outdoor unit selection

Allowable combinations are indicated in indoor unit combination total capacity index table.

In general, oudoor units can be selected as follows though the location of the unit, zoning and usage of the rooms should be considered.

The indoor and outdoor unit combination is determined that the sum of indoor unit capacity index is nearest to and smaller than the capacity index at 100 % combination ratio of each outdoor unit. Up to 16 indoor units can be connected to one outdoor unit. It is recommended to choose a larger outdoor unit if the installation space is large enough.

If the combination ratio is higher than 100 %, the indoor unit selection will have to be reviewed by using actual capacity of each indoor unit.

Indoor unit combination total capacity index table

Indoor unit capacity index

6-1-3 Actual performance data

Use outdoor unit capacity tables

Determine the correct table according to the outdoor unit model and combination ratio.

Enter the table at given indoor and outdoor temperature and find the outdoor capacity and power input. The individual indoor unit capacity (power input) can be calculated as follows :

ICA = OCA x INXTNX

ICA : Individual indoor unit capacity (power input)OCA : Outdoor unit capacity (power input)INX : Individual indoor unit capacity indexTNX : Total capacity index

Then, correct the indoor unit capacity according to the piping length.If the corrected capacity is smaller than the load, the size of indoor unit has to be increased. Repeat the same selection procedure.

Outdoor unit Indoor unit combination ratio130 % 120 % 110 % 100 % 90 % 80 % 70% 60 % 50 %

RSX(Y)P5K/L 162.5 150 137.5 125 112.5 100 87.5 75 62.5RSX(Y)P8K/L / RSEYP8K 260 240 220 200 180 160 140 120 100RSX(Y)10K/L RSEY10K 325 300 275 250 225 200 175 150 125

Model 20 25 32 40 50 63 71 80 100 125 200 250Capacity index 20 25 31.25 40 50 62.5 71 80 100 125 200 250

• Systems • Introduction 27

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28

6 Selection procedure6-1 Selection procedure standard System based on cooling load

6-1-4 Selection example based on cooling load

1 Given

• Design conditionCooling : indoor 20°CWB, outdoor 33°CDB

• Cooling load

• Power supply : 3-phase 380V/50Hz

2 Indoor unit selection

Enter indoor unit capacity table at:20°CWB indoor temperature33°CDB outdoor air temperature.

Selection results are as follows:

3 Outdoor unit selection

• Assume that the indoor and outdoor unit combination is as follows.Outdoor unit : RSEYP10KIndoor unit : FXYCP25K7 x 3 , FXYCP40K7 x 5

• Indoor unit combination total capacity index25 x 3 + 40 x 5 = 275 (110 %)

4 Actual performance data (50Hz)

• Outdoor unit cooling capacity : 31.7kW (RSEYP10K, 110 %)

• Individual capacityCapacity of FXYCP25K = 31.7 x 25 = 2.88kW

275

Capacity of FXYCP40K7 = 31.7 x 40 = 4.61 kW275

Actual combination capacity

The unit size for room A has to be increased from 25 to 32 because the capacity is less than the load. For new combination, actual capacity is calculated as follows.

• Indoor unit combination total capacity index25 x 2 +31.25 + 40 x5 = 281.25 (112.5 %)

• Outdoor unit cooling capacity:27,610 kcal/h (direct interpolation between 110 % and 120 % in the table)

• Individual capacityCapacity of FXYCP25K = 31.9 x 25 = 2.84kW

281.25

Capacity of FXYCP32K = 31.9 x 32 = 3.63kW281.25

Capacity of FXYCP40K = 31.9 x 40 = 4.54kW281.25

Actual capacity of new combination

Then, the capacities have to be corrected for actual piping length according to the location of indoor and outdoor units and the distance between them.

Room A B C D E F G HLoad (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2

Room A B C D E F G HLoad (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2Unit size 25 25 25 40 40 40 40 40Capacity 3.0 3.0 3.0 4.8 4.8 4.8 4.8 4.8

Room A B C D E F G HLoad (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2Unit size 25 25 25 40 40 40 40 40Capacity 2.88 2.88 2.88 4.61 4.61 4.61 4.61 4.61

Room A B C D E F G HLoad (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2Unit size 32 25 25 40 40 40 40 40Capacity 3.63 2.84 2.84 4.54 4.54 4.54 4.54 4.54

• Systems • Introduction

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6 Selection procedure6-2 VRV Capacity correction ratio

6-2-1 RSX(Y)P5L7W1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is: cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

4 When overall equivalent pipe length is 90m or more the size of the main gas pipes must be increased (outdoor unit-branch sections).[Increase in gas pipe diameters (main pipes)]RSX(Y)P5~ø 22.2

5 When the main sections of the interunit gas pipe sizes are increased the overall equivalent length should be calculated as follows.Overall equivalent length = Equivalent length to main pipe x 0.5 + Equivalent length after branching

Example:

In the above case (Cooling)Overall equivalent length = 80m x 0.5 + 40m = 80mThe correction factor in capacity when HP = 0m is thus approximately 0.75.

EXPLANATION OF SYMBOLS

HP : level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM : level difference (m) between indoor and outdoor units with indoor unit in superior position

L : Equivalent pipe length (m)

α : Capacity correction factor

Diameters of gas pipe

RSX(Y)P5~ø 19.1

3TW24772-3A

Equivalent lengthEquivalent length

Size increaseOutdoor unit Branch

Indoor unit

• Systems • Introduction 29

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6 Selection procedure6-2 VRV Capacity correction ratio

6-2-2 RSX(Y)P8L7W1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is: cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

4 When overall equivalent pipe length is 90m or more the size of the main gas pipes must be increased (outdoor unit-branch sections).[Increase in gas pipe diameters (main pipes)]RSX(Y)P8~ø 28.6

5 When the main sections of the interunit gas pipe sizes are increased the overall equivalent length should be calculated as follows.Overall equivalent length = Equivalent length to main pipe x 0.5 + Equivalent length after branching

Example:

In the above case (Cooling)Overall equivalent length = 80m x 0.5 + 40m = 80mThe correction factor in capacity when HP = 0m is thus approximately 0.87.

EXPLANATION OF SYMBOLS

HP : level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM : level difference (m) between indoor and outdoor units with indoor unit in superior position

L : Equivalent pipe length (m)

α : Capacity correction factor

Diameters of gas pipe

RSX(Y)P8~ø 25.4

3TW24782-3

Equivalent lengthEquivalent length

Size increaseOutdoor unit Branch

Indoor unit

• Systems • Introduction

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• Introduction

6 Selection procedure6-2 VRV Capacity correction ratio

6-2-3 RSX(Y)P10L7W1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is: cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

4 When overall equivalent pipe length is 90m or more the size of the main gas pipes must be increased (outdoor unit-branch sections).[Increase in gas pipe diameters (main pipes)]RSX(Y)P10~ø 31.8

5 When the main sections of the interunit gas pipe sizes are increased the overall equivalent length should be calculated as follows.Overall equivalent length = Equivalent length to main pipe x 0.5 + Equivalent length after branching

Example:

In the above case (Cooling)Overall equivalent length = 80m x 0.5 + 40m = 80mThe correction factor in capacity when HP = 0m is thus approximately 0.84.

EXPLANATION OF SYMBOLS

HP : level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM : level difference (m) between indoor and outdoor units with indoor unit in superior position

L : Equivalent pipe length (m)

α : Capacity correction factor

Diameters of gas pipe

RSX(Y)P10~ø 28.6

3TW24792-3

Equivalent lengthEquivalent length

Size increaseOutdoor unit Branch

Indoor unit

• Systems • Introduction 31

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• Introduction

6

32

6 Selection procedure6-2 VRV Capacity correction ratio

6-2-4 RSX(Y)P5K7W1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

4 When overall equivalent pipe length is 90 m or more the size of the main gas pipes must be increased (outdoor unit-branch sections).[Increase in gas pipe diameters (main pipes)]RSXYP5~ø 22.2

5 When the main sections of the interunit gas pipe sizes are increased the overall equivalent length should be calculated as followsOverall equivalent length = equivalent length to main pipe x 0.5 + Equivalent length after branching

Example

In the above case (Cooling)Overall equivalent length = 80m x 0.5 + 40m = 80mThe correction factor in capacity when Hp = 0m is thus approximately 0.75.

EXPLANATION OF SYMBOLS

HP level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM level difference (m) between indoor and outdoor units with indoor unit in superior position

L Equivalent pipe length (m)

α Capacity correction factor

[Diameters of gas pipe]

RSXYP5~ø19.1

3D006065

Equivalent length Equivalent length

Size increaseOutdoor unit Branch

Indoor unit

• Systems • Introduction

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6

• Introduction

6 Selection procedure6-2 VRV Capacity correction ratio

6-2-5 RSX(Y)P8K7W1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

4 When overall equivalent pipe length is 90 m or more the size of the main gas pipes must be increased (outdoor unit-branch sections).[Increase in gas pipe diameters (main pipes)]RSXYP8~ø 28.6

5 When the main sections of the interunit gas pipe sizes are increased the overall equivalent length should be calculated as followsOverall equivalent length = equivalent length to main pipe x 0.5 + Equivalent length after branchingExample

In the above case (Cooling)Overall equivalent length = 80m x 0.5 + 40m = 80mThe correction factor in capacity when Hp = 0m is thus approximately 0.87.

EXPLANATION OF SYMBOLS

HP level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM level difference (m) between indoor and outdoor units with indoor unit in superior position

L Equivalent pipe length (m)

α Capacity correction factor

[Diameters of gas pipe]

RSXYP8~ø 25.4

3D006063

Equivalent length Equivalent length

Size increaseOutdoor unit Branch

Indoor unit

• Systems • Introduction 33

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• Introduction

6

34

6 Selection procedure6-2 VRV Capacity correction ratio

6-2-6 RSX(Y)P10K7W1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

4 When overall equivalent pipe length is 90 m or more the size of the main gas pipes must be increased (outdoor unit-branch sections).[Increase in gas pipe diameters (main pipes)]RSXYP10~ø 31.8

5 When the main sections of the interunit gas pipe sizes are increased the overall equivalent length should be calculated as followsOverall equivalent length = equivalent length to main pipe x 0.5 + Equivalent length after branchingExample

In the above case (Cooling)Overall equivalent length = 80m x 0.5 + 40m = 80mThe correction factor in capacity when Hp = 0m is thus approximately 0.84.

EXPLANATION OF SYMBOLS

HP level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM level difference (m) between indoor and outdoor units with indoor unit in superior position

L Equivalent pipe length (m)

α Capacity correction factor

[Diameters of gas pipe]

RSXYP10~ø 28.6

3D006064

Equivalent length Equivalent length

Size increaseOutdoor unit Branch

Indoor unit

• Systems • Introduction

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6

• Introduction

6 Selection procedure6-2 VRV Capacity correction ratio

6-2-7 RSEYP8K

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

4 In the combination which does not include cooling indoor unit. Calculate the equivalent length pipe by the following when you calculate cooling capacity.Overall equivalent length = equivalent length to main pipe x 0.5 + Equivalent length after branching

(Example)

In the above case (Cooling)Overall equivalent length = 80m x 0.5 + 40m = 80mThe correction factor in capacity when Hp = 0m is thus approximately 0.87.

EXPLANATION OF SYMBOLS

HP level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM level difference (m) between indoor and outdoor units with indoor unit in superior position

L Equivalent pipe length (m)

α Capacity correction factor

[Diameters of suction gas pipe]

RSEYP8~ø25.4

3D018350

Equivalent length Equivalent length

Outdoor unit Size increase Branch BS unit

Indoor unit

• Systems • Introduction 35

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• Introduction

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36

6 Selection procedure6-2 VRV Capacity correction ratio

6-2-8 RSEYP10K

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

4 In the combination which does not include cooling indoor unit. Calculate the equivalent length pipe by the following when you calculate cooling capacity.Overall equivalent length = equivalent length to main pipe x 0.5 + Equivalent length after branching(Example)

In the above case (Cooling)Overall equivalent length = 80m x 0.5 + 40m = 80mThe correction factor in capacity when Hp = 0m is thus approximately 0.84.

EXPLANATION OF SYMBOLS

HP level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM level difference (m) between indoor and outdoor units with indoor unit in superior position

L Equivalent pipe length (m)

α Capacity correction factor

[Diameters of suction gas pipe]

RSEYP10~ø 28.6

3D0118351

Equivalent length Equivalent length

Outdoor unit Size increase Branch BS unit

Indoor unit

• Systems • Introduction

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6

• Introduction

6 Selection procedure6-3 Selection procedure System based on cooling load

6-3-1 Indoor unit selection

Enter indoor unit capacity tables at given indoor and outdoor temperature.Select the unit that the capacity is the nearest to and higher than the given load.

NOTE

1 Individual indoor unit capacity is subject to change by the combination. Actual capacity has to be calculated according to the combination by using outdoor units capacity table.

6-3-2 Outdoor unit selection

Allowable combinations are indicated in indoor unit combination total capacity index table. In general, oudoor units can be selected as follows though the location of the unit, zoning and usage of the rooms should be considered.The indoor and outdoor unit combination is determined that the sum of indoor unit capacity index is nearest to and smaller than the capacity index at 100 % combination ratio of each outdoor unit. Up to 32 indoor units can be connected to one outdoor system. It is recommended to choose a larger outdoor unit if the installation space is large enough.If the combination ratio is higher than 100 %, the indoor unit selection will have to be reviewed by using actual capacity of each indoor unit.

Indoor unit combination total capacity index table

Indoor unit capacity index

6-3-3 Actual performance data

Use outdoor unit capacity tablesDetermine the correct table according to the outdoor unit model and combination ratio.Enter the table at given indoor and outdoor temperature and find the outdoor capacity and power input. The individual indoor unit capacity (power input) can be calculated as follows :

ICA = OCA x INXTNX

ICA : Individual indoor unit capacity (power input)OCA : Outdoor unit capacity (power input)INX : Individual indoor unit capacity indexTNX : Total capacity index

Then, correct the indoor unit capacity according to the piping length.If the corrected capacity is smaller than the load, the size of indoor unit has to be increased. Repeat the same selection procedure.

Outdoor unit Indoor unit combination ratio130 % 120 % 110 % 100 % 90 % 80 % 70% 60 % 50 %

RSXYP/RSEYP16K 520 480 440 400 360 320 280 240 200RSXYP/RSEYP18K 585 540 495 450 405 360 315 270 225RSXYP/RSEYP20K 650 600 550 500 450 400 350 300 250RSXYP/RSEYP24K 780 720 660 600 540 480 420 360 300RSXYP/RSEYP26K 845 780 715 650 585 520 455 390 325RSXYP/RSEYP28K 910 840 770 700 630 560 490 420 350RSXYP/RSEYP30K 975 900 825 750 675 600 525 450 375

Model 20 25 32 40 50 63 71 80 100 125 200 250Capacity index 20 25 31.25 40 50 62.5 71 80 100 125 200 250

• Systems • Introduction 37

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• Introduction

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38

6 Selection procedure6-3 Selection procedure System based on cooling load

6-3-4 Selection example based on cooling load

1 Given

• Design conditionCooling : indoor 20°CWB, outdoor 33°CDB

• Cooling load

• Power supply : 3-phase 380V/50Hz

2 Indoor unit selection

Enter indoor unit capacity table at:20°CWB indoor temperature33°CDB outdoor air temperature.

Selection results are as follows:

3 Outdoor unit selection

• Assume that the indoor and outdoor unit combination is as follows.Outdoor unit : RSXYP26KIndoor unit : FXYCP25K x 3 , FXYCP40K x 5, FXYSP50K x 2, FXYFP80K x 1, FXYMP100K x 2

• Indoor unit combination total capacity index25 x 3 + 40 x 5 + 50 x 2 + 80 x 1 + 100 x 2 = 655 (100.77 %)

4 Actual performance data (50Hz)

• Outdoor unit cooling capacity : 75.78kW (RSXYP26K, 100.77 %)→direct interpolation between 100 and 110 %

• Individual capacityCapacity of FXYCP25K = 75.78 x 25 = 2.89kW

655

Capacity of FXYCP40K7 = 75.78 x 40 = 4.63kW655

Capacity of FXYSP50K = 75.78 x 50 = 5.78kW655

Capacity of FXYFP80K = 75.78 x 80 = 9.25kW655

Capacity of FXYMP100K = 75.78 x 100 = 11.57kW655

Actual combination capacity

Room A B C D E F G HLoad (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2

Room A B C D E F G H I J K L MLoad (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2 5.4 5.8 8.7 10.9 10.8Unit size 25 25 25 40 40 40 40 40 50 50 80 100 100Capacity 3.0 3.0 3.0 4.8 4.8 4.8 4.8 4.8 5.9 5.9 9.5 11.9 11.9

Room A B C D E F G H I J K L MLoad (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2 5.4 5.8 8.7 10.9 10.8Unit size 25 25 25 40 40 40 40 40 50 50 80 100 100Capacity 2.89 2.89 2.89 4.63 4.63 4.63 4.63 4.63 5.78 5.78 9.25 11.57 11.57

• Systems • Introduction

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6

• Introduction

6 Selection procedure6-3 Selection procedure System based on cooling load

6-3-4 Selection example based on cooling load

The unit size for room A has to be increased from 25 to 32 because the capacity is less than the load. For new combination, actual capacity is calculated as follows.

• Indoor unit combination total capacity index25x2 + 31.25 + 40x5 + 50 + 62.5 + 80 + 100x2 = 673.75 (103.65 %)

• Outdoor unit cooling capacity:76.44kW (direct interpolation between 100 % and 110 % in the table)

• Individual capacityCapacity of FXYCP25K = 76.44 x 25 = 2.84kW

673.75

Capacity of FXYCP32K = 76.44 x 32 = 3.63kW673.75

Capacity of FXYCP40K = 76.44 x 40 = 4.54kW673.75

Capacity of FXYSP50K = 76.44 x 50 = 5.67kW673.75

Capacity of FXYSP63K = 76.44 x 63 = 7.15kW673.75

Capacity of FXYMP80K = 76.44 x 80 = 9.08kW673.75

Capacity of FXYFP100K = 76.44 x 100 = 11.35kW673.75

Actual capacity of new combination

Then, the capacities have to be corrected for actual piping length according to the location of indoor and outdoor units and the distance between them.

NOTE

Select the optimum size of units and take care no to select the oversized units.

Room A B C D E F G H I J K L MLoad (Kw) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2 5.4 5.8 8.7 10.9 10.8Unit size 32 25 25 40 40 40 40 40 50 63 80 100 100Capacity 3.63 2.84 2.84 4.54 4.54 4.54 4.54 4.54 5.67 7.15 9.08 11.35 11.35

• Systems • Introduction 39

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• Introduction

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40

6 Selection procedure6-4 VRV Plus Capacity correction ratio

6-4-1 RSXYP16,18,26KJY1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

EXPLANATION OF SYMBOLS

Hp : level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM : level difference (m) between indoor and outdoor units with indoor unit in superior position

L : Equivalent pipe length (m)

α : Capacity correction factor

Diameters of suction gas pipe

RSXYP26KJY1~ø 41.3

RSXYP16, 18 KJY1~ø 34.9

3D027997

• Systems • Introduction

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• Introduction

6 Selection procedure6-4 VRV Plus Capacity correction ratio

6-4-2 RSXYP24KJY1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

EXPLANATION OF SYMBOLS

Hp : level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM : level difference (m) between indoor and outdoor units with indoor unit in superior position

L : Equivalent pipe length (m)

α : Capacity correction factor

Diameters of suction gas pipeRSXYP24KJY1~ø 41.3

3D027995

• Systems • Introduction 41

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• Introduction

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42

6 Selection procedure6-4 VRV Plus Capacity correction ratio

6-4-3 RSXYP20,28,30KJY1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

EXPLANATION OF SYMBOLS

Hp : level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM : level difference (m) between indoor and outdoor units with indoor unit in superior position

L : Equivalent pipe length (m)

α : Capacity correction factor

Diameters of suction gas pipeRSXYP28,30KJY1~ø 41.3RSXYP20KJY1~ø 34.9

3D027998

• Systems • Introduction

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6

• Introduction

6 Selection procedure6-4 VRV Plus Capacity correction ratio

6-4-4 RSEYP16,18,26KJY1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

EXPLANATION OF SYMBOLS

HP level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM level difference (m) between indoor and outdoor units with indoor unit in superior position

L Equivalent pipe length (m)

α Capacity correction factor

Diameters of suction gas pipe

RSEYP26KJY1~ ø 41.3

RSEYP16,18KJY1~ ø 34.9

3D031932

• Systems • Introduction 43

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• Introduction

6

44

6 Selection procedure6-4 VRV Plus Capacity correction ratio

6-4-5 RSEYP24KJY1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

EXPLANATION OF SYMBOLS

HP level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM level difference (m) between indoor and outdoor units with indoor unit in superior position

L Equivalent pipe length (m)

α Capacity correction factor

Diameters of suction gas pipe

RSEYP24KJY1~ ø 41.3

3D031934

• Systems • Introduction

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6

• Introduction

6 Selection procedure6-4 VRV Plus Capacity correction ratio

6-4-6 RSEYP20,28,30KJY1

• Rate of change in cooling capacity • Rate of change in heating capacity

NOTES

1 These figures illustrate the rate of change in capacity of a standard indoor unit system at maximum load (with the thermostat set to maximum) under standard conditions.Moreover, under partial load conditions there is only a minor deviation from the rate of change in capacity shown in the above figures.

2 With this outdoor unit, evaporating pressure constant control when cooling, and condensing pressure constant control when heating is carried out.

3 Method of calculating cooling / heating capacity (max. capacity for combination with standard indoor unit)cooling / heating capacity = cooling / heating capacity obtained from performance characteristics table x each capacity rate of changeWhen piping length differs depending on the indoor unit, maximum capacity of each unit during simultaneous operation is:cooling / heating capacity = cooling / heating capacity of each unit x capacity rate of change for each piping length

EXPLANATION OF SYMBOLS

HP level difference (m) between indoor and outdoor units with indoor unit in inferior position

HM level difference (m) between indoor and outdoor units with indoor unit in superior position

L Equivalent pipe length (m)

α Capacity correction factor

Diameters of suction gas pipe

RSEYP28,30KJY1~ ø 41.3

RSEYP20KJY1~ ø 34.9

3D031933

• Systems • Introduction 45

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• Introduction

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46

6 Selection procedure6-5 Refnet pipe system

6-5-1 Unified Refnet joints

Liquid side junction Discharge gas side junction Suction gas side junction Others

KHRP

26K1

1T

– Insulator– Installation manual

KHRP

26K1

8T

– Insulator– Installation manual

KHRP

26K3

7T

– Insulator– Pipe reducer (suction)

ø25.4-ø19.1ø28.6-ø25.4

– Installation manual

KHRP

26K4

0T

– Insulator– Pipe reducer (suction)

ø15.9-ø12.7– Pipe reducer (liquid)

ø9.5-ø6.4– Installation manual

KHRP

26K7

5T

– Insulator– Pipe reducers (suction)

ø25.4-ø19.1-ø15.9ø31.8-ø34.9 (3x)ø38.1-ø41.3ø31.8-ø34.9-ø41.3

– Pipe reducers (liquid)ø19.1-ø15.9-ø12.7ø12.7-ø9.5-ø6.4

– Installation manual

KHRP

25K1

8T

– Insulator– Installation manual

KHRP

25K2

0T

– Insulator– Pipe reducers (suction)

ø25.4-ø19.1– Pipe reducers (discharge)

ø12.7-ø9.5ø19.1-ø15.9

– Installation manual

KHRP

25K4

0T

– Insulator– Pipe reducers (suction)

ø15.9-ø12.7ø41.3-ø34.9-ø31.8ø34.9-ø31.8

– Pipe reducers (discharge)ø12.7-ø9.5

– Pipe reducers (liquid)ø9.5-ø6.4

– Installation manual

KHRP

25K7

5T

– Insulator– Pipe reducers (suction)

ø15.9-ø12.7ø25.4-ø19.1-ø15.9-ø12.7ø31.8-ø34.9 (3x)ø38.1-ø41.3ø31.8-ø34.9-ø41.3

– Pipe reducers (discharge)ø12.7-ø9.5ø19.1-ø15.9ø31.8-ø25.4

– Pipe reducers (liqid)ø19.1-ø15.9-ø12.7ø12.7-ø9.5-ø6.4

– Installation manual

1TW21559-11C

Inlet Outlet

Outlet

Inlet Outlet

Outlet

Inlet Outlet

Outlet

Inlet Outlet

Outlet

Inlet

Outlet

OutletInlet Outlet

Outlet

Inlet Outlet

Outlet

Inlet Outlet

Outlet

Inlet Outlet

Outlet

Inlet

Outlet

Outlet

Inlet Outlet

Outlet

Inlet Outlet

Outlet

Inlet Outlet

Outlet

InletOutlet

Outlet

Inlet

Outlet

Outlet

Inlet Outlet

Outlet

Outlet

Outlet

Inlet Outlet

Outlet

Inlet Outlet

Outlet

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Outlet

Inlet

Outlet

Outlet

InletOutlet

Outlet

• Systems • Introduction

Page 48: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

6

• Introduction

6 Selection procedure6-5 Refnet pipe system

6-5-2 Unified Refnet headers

Liquid side header Discharge gas side header Suction gas side header Others

KHRP

26K1

1H4 b

ranche

s – Insulator– Pinched pipes– Installation manual

KHRP

26K1

8H8 b

ranche

s – Insulator– Pinched pipes– Installation manual

KHRP

26K3

7H8 b

ranche

s – Insulator– Pinched pipes– Installation manual

KHRP

26K4

0H8 b

ranche

s

– Insulator– Pinched pipes– Installation manual– Pipe reducer (suction)

ø31.8-ø34.9-ø41.3

KHRP

25K1

8H6 b

ranche

s – Insulator– Pinched pipes– Installation manual

KHRP

25K3

7H8 b

ranche

s – Insulator– Pinched pipes– Installation manual

KHRP

25K4

0H8 b

ranche

s

– Insulator– Pinched pipes– Installation manual– Pipe reducers (suction)

ø15.9-ø12.7ø31.8-ø34.9-ø41.3ø25.4-ø19.1-ø15.9-ø12.7

– Pipe reducers (liquid)ø19.1-ø15.9-ø12.7ø12.7-ø9.5-ø6.4

– Pipe reducers (discharge)ø12.7-ø9.5ø19.1-ø15.9ø31.8-ø25.4

1TW21559-11C

Inlet Outlet

Inlet

Inlet

Outlet

Inlet

Inlet OutletInlet

Inlet Outlet

Inlet

InletOutlet Inlet

Inlet OutletInlet

Inlet Outlet

Inlet

• Systems • Introduction 47

Page 49: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

• Introduction

6

48

6 Selection procedure6-5 Refnet pipe system

6-5-3 Example of Refnet piping layouts

Type of fitting Sample systems

Distrib

ution

by RE

FNET

joints

Distrib

ution

by RE

FNET

head

erDis

tributi

on by

REFN

ET join

ts an

d hea

ders

Outdoor unit Outdoor unit Outdoor unit Outdoor unit

REFNET joint REFNET joint REFNET jointREFNET jointSimultaneous control of cooling/heating

Simultaneous control of cooling/heating

Indoor unitIndoor unit

Indoor unit Indoor unit

Cooling only

Cooling only

Cooling only

Cooling only

Cooling only

Outdoor unit Outdoor unit

REFNET header (6 branch fitting)

REFNET header (8 branch fitting)

REFNET header (6 branch fitting)

Indoor unit

Indoor unit

Indoor unit

Simultaneous control of

cooling/heating

Can be added Cooling only Can be added

Cooling only

Can be added

Outdoor unit

REFNET joint

Indoor unit

REFNET header (6 branch fitting)

Simultaneous control of cooling/heatingCan be added

Outdoor unit

Simultaneous control of cooling/heating

Indoor unitREFNET header (6 branch fitting)

Can be added

Cooling only

• Systems • Introduction

Page 50: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

6

• Introduction

6 Selection procedure6-6 Refrigerant pipe selection

6-6-1 RSX(Y)P5-10L

Conn

ectio

n ex

ampl

eUs

e ex

clusiv

e re

frige

rant

bra

nch

kits

for R

-407

C.Co

nnec

tion

of 8

indo

or u

nits

Indoo

r unit

Refne

t joint

Refne

t hea

der

Bran

ch w

ith re

fnet

join

tBr

anch

with

refn

et jo

int a

nd re

fnet

hea

der

Bran

ch w

ith re

fnet

hea

der

Max

imum

allo

wab

le le

ngth

bet

wee

n ou

tdoo

r and

indo

or u

nits

Actua

l pipe

leng

thPip

e len

gth be

twee

n outd

oor a

nd in

door

units

≤ 12

0m

[Exam

ple] u

nit 8:

a+b+

c+d+

e+f+

g+p ≤

120m

[Exam

ple] u

nit 1:

a+b+

h ≤ 10

0m, ∆

: a+

i+j ≤

120m

[Exam

ple] u

nit 8:

a+i ≤

120m

Equiv

alent

length

Equiv

alent

pipe l

ength

betw

een o

utdoo

r and

indo

or un

its ≤

140m

(Assu

me eq

uivale

nt pip

e len

gth of

refne

t joint

to be

0.5m

and o

f the

refne

t hea

der t

o be 1

.0m (F

or cal

culati

on pu

rposes

))

Allo

wab

le h

eigh

t bet

wee

n ou

tdoo

r and

in

door

uni

tsDif

feren

ce in

heigh

t

Differ

ence

in he

ight b

etwee

n outd

oor a

nd in

door

units

(H1) ≤

50m

( ≤ 40

m if o

utdoo

r unit

is loc

ated i

n a lo

wer p

ositio

n)

Allo

wab

le h

eigh

t bet

wee

n ad

jace

nt in

door

un

itsDif

feren

ce in

heigh

t betw

een a

djacen

t indo

or un

its (H2

) ≤ 15

m

Allo

wab

le le

ngth

afte

r the

bra

nch

Actua

l pipe

leng

thPip

e len

gth fro

m firs

t refr

igeran

t bran

ch kit

(eith

er ref

net jo

int or

refne

t hea

der) t

o ind

oor u

nits ≤

40m

Examp

le un

it 8: b

+c+d

+e+f

+g+p

≤ 40

mExa

mple

unit 6

: b+h

≤ 40

m, un

it 7: i+

k ≤ 40

mExa

mple

unit 8

: i ≤

40m

Refri

gera

nt b

ranc

h ki

t sel

ectio

nHo

w to

sele

ct th

e re

fnet

join

t•

When

using

a ref

net jo

int at

the f

irst br

anch

coun

ted fro

m the

outdo

or un

it side

, use

KHRP

26K1

7T (R

SXYP

5L) o

r KHR

P26K

37T (

RSXY

P8/10

L). [Ex

ample

: refne

t joint

A]•

For re

fnet jo

ints o

ther th

an th

e first

bran

ch, se

lect t

he pr

oper

branch

kits

based

on th

e tota

l cap

acity

index

of ind

oor u

nits in

stalled

after

the f

irst br

anch,

using

the

follow

ing ta

ble.

How

to se

lect

the

refn

et h

eade

r•

Selec

t the

prop

er bra

nch ki

t base

d on t

he to

tal ca

pacity

inde

x of in

door

units

instal

led af

ter th

e hea

der, u

sing t

he fo

llowing

table

.•

Branch

ing is

impo

ssible

betw

een r

efnet

head

er an

d ind

oor u

nit

Examp

le of

down

strea

m ind

oor u

nits

[Exam

ple]

In cas

e of re

fnet jo

int C:

indo

or un

its 3+

4+5+

6+7+

8[Ex

ample

]In

case o

f refne

t joint

B: in

door

units

7+8

In cas

e of re

fnet h

eade

r: ind

oor u

nits 1

+2+3

+4+5

+6[Ex

ample

]In

case o

f refne

t hea

der: i

ndoo

r unit

s 1+2

+3+4

+5+6

+7+8

Pipe

size

sele

ctio

nPip

e size

= ou

ter di

amete

r x m

inimum

wall

thickn

ess(un

it: mm

)

Betw

een

the

outd

oor u

nit a

nd th

e up

perm

ost s

tream

refri

gera

nt b

ranc

h ki

t•

Matc

h the

pipe

size t

o the

pipe

size o

f the

outdo

or un

itBe

twee

n tw

o im

med

iate

ly ad

jace

nt re

frige

rant

bra

nch

kits

•Se

lect th

e prop

er pip

e size

based

on th

e tota

l capa

city in

dex o

f indo

or un

its co

nnect

ed do

wnstr

eam,

using

the

follow

ing ta

ble.

Betw

een

refri

gera

nt b

ranc

h ki

t and

indo

or u

nit

•Se

lect th

e prop

er pip

e size

based

on th

e tota

l capa

city in

dex o

f indo

or un

its co

nnect

ed do

wnstr

eam,

using

the

follow

ing ta

ble.

(Pipe

size f

or dir

ect co

nnect

ion to

indo

or un

it must

be th

e sam

e as t

he co

nnect

ion siz

e of th

e ind

oor u

nit.)

Addi

tiona

l ref

riger

ant t

o be

cha

rged

Calcu

lation

of ad

dition

al ref

rigera

nt to

be ch

arged

R (kg

) is in

funct

ion of

total

leng

th of

liquid

lines

L and

as fo

llows:

RSXY

P5L

R=[(L

ø9.5)

x 0.0

6] +

[(L ø6

.4) x

0.023

]RS

XYP8

/10L

R=[(L

ø12.7

) x 0.

12] +

[(L ø9

.5) x

0.06]

+ [(L

ø6.4)

x 0.0

23]

NO

TES

•Ro

und o

ff R to

1 de

cimal

place.

•If R

is ≤

0, kee

p the

unit i

n ope

ration

Examp

le RS

XYP5

L

R = [5

5 x 0.

66] +

[40 x

0.02

3] =

4.22 →

R =

4.2kg

Examp

le RS

XYP8

/10L

R = [4

0 x 0.

12] +

[30 x

0.06

] + [6

9 x 0.

023]

= 8.1

87→

R =

8.2kg

Examp

le RS

XYP8

/10L

R = [4

0 x 0.

12] +

[30 x

0.06

] + [1

23 x

0.023

] = 9.

429→

R =

9.4kg

(V289

1)

� �A

Total

capa

city in

dex o

f indo

or un

its......

..........

..........

..........

..........

..........

..........

..........

...Bran

ch kit

RSXY

P5L

< 10

0.......

..........

..........

..........

..........

..........

KHRP

26K1

1T

≥ 10

0.......

..........

..........

..........

..........

..........

KHRP

26K1

8T

RSXY

P8/10

L<

160..

..........

..........

..........

..........

..........

.....KH

RP26

K18T

≥ 16

0.......

..........

..........

..........

..........

..........

KHRP

26K3

7T

Total

capa

city in

dex o

f indo

or un

its......

..........

..........

..........

..........

..........

..........

..........

...Bran

ch kit

RSXY

P5L

< 10

0.......

..........

..........

..........

..........

..........

KHRP

26K1

1H (u

p to 4

bran

ches)

≥ 10

0.......

..........

..........

..........

..........

..........

KHRP

26K1

8H (u

p to 8

bran

ches)

RSXY

P8/10

L<

160..

..........

..........

..........

..........

..........

.....KH

RP26

K18H

(up t

o 6 br

anche

s)

≥ 16

0.......

..........

..........

..........

..........

..........

KHRP

26K3

7H (u

p to 8

bran

ches)

Pipe

size

con

nect

ed to

out

door

uni

t

Gas

Liquid

RSXY

P5L

ø 19.1

x 1.0

ø 9.5

x 0.8

RSXY

P8L

ø 28.6

x 1.2

ø 12.7

x 0.8

RSXY

P10L

ø 28.6

x 1.2

ø 12.7

x 0.8

Total

capa

city in

dex

Gas

Liquid

< 10

0ø 1

5.9 x

1.0ø 9

.5 x 0

.8

100-

160

ø 19.1

x 1.0

ø 9.5

x 0.8

≥ 16

0ø 2

5.4 x

1.2ø 1

2.7 x

0.8

Conn

ectio

n pi

pe si

ze o

f ind

oor u

nit

Indoo

r unit

capa

city in

dex

Gas

Liquid

20 25

32 40

ø 12.7

x 0.8

ø 6.4

x 0.8

50 63

80ø 1

5.9 x

1.0ø 9

.5 x 0

.8

100 1

25ø 1

9.1 x

1.0ø 9

.5 x 0

.8

a : ø9

.5 x 3

0me :

ø9.5

x 3m

i : ø6

.4 x 5

mm

: ø6.4

x 5m

b : ø9

.5 x 5

mf :

ø9.5

x 2m

j : ø6

.4 x 5

mn :

ø6.4

x 5m

c : ø9

.5 x 5

mg :

ø9.5

x 5m

k : ø6

.4 x 5

mp :

ø6.4

x 5m

d : ø9

.5 x 5

mh :

ø6.4

x 5m

l : ø6

.4 x 5

m

a : ø1

2.7 x

30m

d : ø6

.4 x 1

0mg :

ø6.4

x 10m

m : ø

9.5 x

10m

b : ø1

2.7 x

10m

e : ø6

.4 x 1

0mh :

ø6.4

x 20m

k : ø6

.4 x 9

m

c : ø9

.5 x 1

0mf :

ø6.4

x 10m

i : ø9

.5 x 1

0m

a : ø1

2.7 x

40m

d : ø6

.4 x 1

0mg :

ø6.4

x 20m

b : ø9

.5 x 2

0me :

ø6.4

x 20m

h : ø6

.4 x 2

0m

c : ø9

.5 x 1

0mf :

ø6.4

x 23m

i : ø6

.4 x 3

0m

• Systems • Introduction 49

Page 51: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

• Introduction

6

50

6 Selection procedure6-6 Refrigerant pipe selection

6-6-2 RSX(Y)P5-10K

Conn

ectio

n ex

ampl

eUs

e ex

clusiv

e re

frige

rant

bra

nch

kits

for R

-407

C.Co

nnec

tion

of 8

indo

or u

nits

Indoo

r unit

Refne

t joint

Refne

t hea

der

Bran

ch w

ith re

fnet

join

tBr

anch

with

refn

et jo

int a

nd re

fnet

hea

der

Bran

ch w

ith re

fnet

hea

der

Max

imum

allo

wab

le le

ngth

bet

wee

n ou

tdoo

r and

indo

or u

nits

Actua

l pipe

leng

thPip

e len

gth be

twee

n outd

oor a

nd in

door

units

≤ 10

0m

[Exam

ple] u

nit 8:

a+b+

c+d+

e+f+

g+p ≤

100m

[Exam

ple] u

nit 1:

a+b+

h ≤ 10

0m, ∆

: a+

i+j ≤

100m

[Exam

ple] u

nit 8:

a+i ≤

100m

Equiv

alent

length

Equiv

alent

pipe l

ength

betw

een o

utdoo

r and

indo

or un

its ≤

125m

(Assu

me eq

uivale

nt pip

e len

gth of

refne

t joint

to be

0.5m

and o

f the

refne

t hea

der t

o be 1

.0m (F

or cal

culati

on pu

rposes

))

Allo

wab

le h

eigh

t bet

wee

n ou

tdoo

r and

in

door

uni

tsDif

feren

ce in

heigh

t

Differ

ence

in he

ight b

etwee

n outd

oor a

nd in

door

units

(H1) ≤

50m

( ≤ 40

m if o

utdoo

r unit

is loc

ated i

n a lo

wer p

ositio

n)

Allo

wab

le h

eigh

t bet

wee

n ad

jace

nt in

door

un

itsDif

feren

ce in

heigh

t betw

een a

djacen

t indo

or un

its (H2

) ≤ 15

m

Allo

wab

le le

ngth

afte

r the

bra

nch

Actua

l pipe

leng

thPip

e len

gth fro

m firs

t refr

igeran

t bran

ch kit

(eith

er ref

net jo

int or

refne

t hea

der) t

o ind

oor u

nits ≤

40m

Examp

le un

it 8: b

+c+d

+e+f

+g+p

≤ 40

mExa

mple

unit 6

: b+h

≤ 40

m, un

it 7: i+

k ≤ 40

mExa

mple

unit 8

: i ≤

40m

Refri

gera

nt b

ranc

h ki

t sel

ectio

nHo

w to

sele

ct th

e re

fnet

join

t•

When

using

a ref

net jo

int at

the f

irst br

anch

counte

d from

the o

utdoo

r unit

side,

use KH

RP26

K17T

(RSX

(Y)P5

) or K

HRP2

6K37

T (RS

X(Y)P8

/10). [

Examp

le: ref

net jo

int A

]•

For re

fnet jo

ints o

ther th

an th

e first

bran

ch, se

lect t

he pr

oper

branch

kits

based

on th

e tota

l cap

acity

index

of ind

oor u

nits in

stalled

after

the f

irst br

anch,

using

the

follow

ing ta

ble.

How

to se

lect

the

refn

et h

eade

r•

Selec

t the

prop

er bra

nch ki

t base

d on t

he to

tal ca

pacity

inde

x of in

door

units

instal

led af

ter th

e hea

der, u

sing t

he fo

llowing

table

.•

Branch

ing is

impo

ssible

betw

een r

efnet

head

er an

d ind

oor u

nit

Examp

le of

down

strea

m ind

oor u

nits

[Exam

ple]

In cas

e of re

fnet jo

int C:

indo

or un

its 3+

4+5+

6+7+

8[Ex

ample

]In

case o

f refne

t joint

B: in

door

units

7+8

In cas

e of re

fnet h

eade

r: ind

oor u

nits 1

+2+3

+4+5

+6[Ex

ample

]In

case o

f refne

t hea

der: i

ndoo

r unit

s 1+2

+3+4

+5+6

+7+8

Pipe

size

sele

ctio

nPip

e size

= ou

ter di

amete

r x m

inimum

wall

thickn

ess(un

it: mm

)

Betw

een

the

outd

oor u

nit a

nd th

e up

perm

ost s

tream

refri

gera

nt b

ranc

h ki

t•

Matc

h the

pipe

size t

o the

pipe

size o

f the

outdo

or un

itBe

twee

n tw

o im

med

iate

ly ad

jace

nt re

frige

rant

bra

nch

kits

•Se

lect th

e prop

er pip

e size

based

on th

e tota

l capa

city in

dex o

f indo

or un

its co

nnect

ed do

wnstr

eam,

using

the

follow

ing ta

ble.

Betw

een

refri

gera

nt b

ranc

h ki

t and

indo

or u

nit

•Se

lect th

e prop

er pip

e size

based

on th

e tota

l capa

city in

dex o

f indo

or un

its co

nnect

ed do

wnstr

eam,

using

the

follow

ing ta

ble.

(Pipe

size f

or dir

ect co

nnect

ion to

indo

or un

it must

be th

e sam

e as t

he co

nnect

ion siz

e of th

e ind

oor u

nit.)

Addi

tiona

l ref

riger

ant t

o be

cha

rged

Calcu

lation

of ad

dition

al ref

rigera

nt to

be ch

arged

R (kg

) is in

funct

ion of

total

leng

th of

liquid

lines

L and

as fo

llows:

RSX(

Y)P5

R=[(L

ø9.5)

x 0.0

6] +

[(Lø6

.4) x

0.023

]RS

X(Y)

P8/1

0R=

[(Lø1

2.7) x

0.12

] + [(L

ø9.5)

x 0.0

6] +

[(L ø6

.4) x

0.023

]

NO

TES

•Ro

und o

ff R to

1 de

cimal

place.

•If R

is ≤

0, kee

p the

unit i

n ope

ration

Examp

le RS

X(Y)

P5

R = [5

5 x 0.

66] +

[40 x

0.02

3] =

4.22 →

R =

4.2kg

Examp

le RS

X(Y)

P8/1

0

R = [4

0 x 0.

12] +

[30 x

0.06

] + [6

9 x 0.

023]

= 8.1

87→

R =

8.2kg

Examp

le RS

X(Y)

P8/1

0

R = [4

0 x 0.

12] +

[30 x

0.06

] + [1

23 x

0.023

] = 9.

429→

R =

9.4kg

(V289

1)

� �A

Total

capa

city in

dex o

f indo

or un

its......

..........

..........

..........

..........

..........

..........

..........

...Bran

ch kit

RSX(Y

)P5<

100..

..........

..........

..........

..........

..........

.....KH

RP26

K11T

≥ 10

0.......

..........

..........

..........

..........

..........

KHRP

26K1

8T

RSX(Y

)P8/10

< 16

0.......

..........

..........

..........

..........

..........

KHRP

26K1

8T

≥ 16

0.......

..........

..........

..........

..........

..........

KHRP

26K3

7T

Total

capa

city in

dex o

f indo

or un

its......

..........

..........

..........

..........

..........

..........

..........

...Bran

ch kit

RSX(Y

)P5<

100..

..........

..........

..........

..........

..........

.....KH

RP26

K11H

(up t

o 4 br

anche

s)

≥ 10

0.......

..........

..........

..........

..........

..........

KHRP

26K1

8H (u

p to 8

bran

ches)

RSX(Y

)P8/10

< 16

0.......

..........

..........

..........

..........

..........

KHRP

26K1

8H (u

p to 8

bran

ches)

≥ 16

0.......

..........

..........

..........

..........

..........

KHRP

26K3

7H (u

p to 8

bran

ches)

Pipe

size

con

nect

ed to

out

door

uni

t

Gas

Liquid

RSX(Y

)P5ø 1

9.1ø 9

.5

RSX(Y

)P8ø 2

5.4ø 1

2.7

RSX(Y

)P10

ø 28.6

ø 12.7

Total

capa

city in

dex

Gas

Liquid

< 10

0ø 1

5.9ø 9

.5

100-

160

ø 19.1

ø 9.5

≥ 16

0 (RS

X(Y)P8

/10 on

ly)ø 2

5.4ø 1

2.7

Conn

ectio

n pi

pe si

ze o

f ind

oor u

nit

Indoo

r unit

capa

city in

dex

Gas

Liquid

20 25

32 40

ø 12.7

ø 6.4

50 63

80ø 1

5.9ø 9

.5

100 1

25ø 1

9.1ø 9

.5

a : ø9

.5 x 3

0me :

ø9.5

x 3m

i : ø6

.4 x 5

mm

: ø6.4

x 5m

b : ø9

.5 x 5

mf :

ø9.5

x 2m

j : ø6

.4 x 5

mn :

ø6.4

x 5m

c : ø9

.5 x 5

mg :

ø9.5

x 5m

k : ø6

.4 x 5

mp :

ø6.4

x 5m

d : ø9

.5 x 5

mh :

ø6.4

x 5m

l : ø6

.4 x 5

m

a : ø1

2.7 x

30m

d : ø6

.4 x 1

0mg :

ø6.4

x 10m

m : ø

9.5 x

10m

b : ø1

2.7 x

10m

e : ø6

.4 x 1

0mh :

ø6.4

x 20m

k : ø6

.4 x 9

m

c : ø9

.5 x 1

0mf :

ø6.4

x 10m

i : ø9

.5 x 1

0m

a : ø1

2.7 x

40m

d : ø6

.4 x 1

0mg :

ø6.4

x 20m

b : ø9

.5 x 2

0me :

ø6.4

x 20m

h : ø6

.4 x 2

0m

c : ø9

.5 x 1

0mf :

ø6.4

x 23m

i : ø6

.4 x 3

0m

• Systems • Introduction

Page 52: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

6

• Introduction

6 Selection procedure6-6 Refrigerant pipe selection

6-6-3 RSXYP16-30K

Conn

ectio

n ex

ampl

eHe

at p

ump

syst

emCo

nnec

tion

of 8

indo

or u

nits

Indoo

r unit

Refne

t joint

Refne

t hea

der

Bran

ch w

ith re

fnet

join

tBr

anch

with

refn

et jo

int a

nd re

fnet

hea

der

Bran

ch w

ith re

fnet

hea

der

Max

imum

al

low

able

le

ngth

Betw

een o

utdoo

r and

indo

or un

itsAc

tual p

ipe le

ngth

Pipe l

ength

betw

een o

utdoo

r and

indo

or un

its ≤

100m

[Exam

ple] u

nit 8:

a+b+

c+d+

e+f+

g+p ≤

100m

[Exam

ple] u

nit 6:

a+b+

h ≤ 10

0m, u

nit 8:

a+i+

k ≤ 10

0m[Ex

ample

] unit

8: i ≤

40m

Equiv

alent

length

Equiv

alent

pipe l

ength

betw

een o

utdoo

r and

indo

or un

its ≤

125m

(Assu

me eq

uivale

nt pip

e len

gth of

refne

t joint

to be

0.5m

and o

f the

refne

t hea

der t

o be 1

.0m (F

or cal

culati

on pu

rposes

))

Betw

een o

utdoo

r unit

(main

) and

outdo

or un

it (sub

)Ac

tual p

ipe le

ngth

Pipe l

ength

betw

een o

utdoo

r unit

(main

) and

outdo

or un

it (sub

) (Q) ≤

5m

Allo

wab

le

heig

ht

leng

th

Betw

een o

utdoo

r and

indo

or un

itsDif

feren

ce in

heigh

tDif

feren

ce in

heigh

t betw

een o

utdoo

r and

indo

or un

its (H1

) ≤ 50

m ( ≤

40m

if outd

oor u

nit is

locate

d in a

lowe

r posi

tion)

Betw

een a

djacen

t indo

or un

itsDif

feren

ce in

heigh

tDif

feren

ce in

heigh

t betw

een a

djacen

t indo

or un

its (H2

) ≤ 15

m

Betw

een o

utdoo

r unit

(main

) and

outdo

or un

it (sub

)Dif

feren

ce in

heigh

tDif

feren

ce in

heigh

t betw

een o

utdoo

r unit

(main

) and

outdo

or un

it (sub

) (H3)

≤ 5m

Allo

wab

le le

ngth

afte

r the

bra

nch

Actua

l pipe

leng

thPip

e len

gth fro

m firs

t refr

igeran

t bran

ch kit

(eith

er ref

net jo

int or

refne

t hea

der) t

o ind

oor u

nits ≤

40m

Examp

le un

it 8: b

+c+d

+e+f

+g+p

≤ 40

mExa

mple

unit 6

: b+h

≤ 40

m, un

it 8: i+

k ≤ 40

mExa

mple

unit 8

: i ≤

40m

Refri

gera

nt b

ranc

h ki

t sel

ectio

nHo

w to

sele

ct th

e re

fnet

join

t•

When

using

refne

t joint

s at t

he fir

st bra

nch co

unted

from

the ou

tdoor

unit s

ide. If

the s

ystem

capa

city is

<500

, use

KHRP

26K4

0T +

pipe

size r

educe

r. If t

he sy

stem

capaci

ty is ≥

500,

use KH

RP26

K75T

+ pi

pe siz

e red

ucer.

•Fo

r refne

t joint

s othe

r than

the f

irst br

anch,

selec

t the

prop

er bra

nch ki

ts ba

sed on

the t

otal c

apaci

ty ind

ex of

indoo

r unit

s insta

lled af

ter th

e first

bran

ch, us

ing th

e fol

lowing

table

:

How

to se

lect

the

refn

et h

eade

r•

Selec

t the

prop

er bra

nch ki

t base

d on t

he to

tal ca

pacity

inde

x of in

door

units

instal

led af

ter th

e hea

der, u

sing t

he fo

llowing

table

.•

Branch

ing is

impo

ssible

betw

een r

efnet

head

er an

d ind

oor u

nit•

For s

ystem

s with

a tot

al cap

acity

is ≥64

0, co

nnect

a ref

net jo

int br

anch.

Examp

le of

down

strea

m ind

oor u

nits

[Exam

ple]

In cas

e of re

fnet jo

int C:

indo

or un

its 3+

4+5+

6+7+

8[Ex

ample

]In

case o

f refne

t joint

B: in

door

units

7+8

In cas

e of re

fnet h

eade

r: ind

oor u

nits 1

+2+3

+4+5

+6[Ex

ample

]In

case o

f refne

t hea

der: i

ndoo

r unit

s 1+2

+3+4

+5+6

+7+8

Pipe

size

sele

ctio

nPip

e size

= ou

ter di

amete

r x m

inimum

wall

thickn

ess(un

it: mm

)Us

e the

inclu

ded r

educi

ng jo

int w

hich m

atche

s the

pipe

size

Betw

een

the

outd

oor u

nit a

nd th

e up

perm

ost s

tream

refri

gera

nt b

ranc

h ki

t•

Selec

t pipe

size a

ccordi

ng to

outdo

or sys

tem na

meBe

twee

n tw

o im

med

iate

ly ad

jace

nt re

frige

rant

bra

nch

kits

•Se

lect th

e prop

er pip

e size

based

on th

e tota

l capa

city in

dex o

f indo

or un

its co

nnect

ed do

wnstr

eam,

using

the

follow

ing ta

ble.

•Se

lect c

onne

ction p

ipe siz

e acco

rding

to th

e outd

oor u

nit. D

o not

select

a lar

ger p

ipe siz

e

Betw

een

refri

gera

nt b

ranc

h ki

t and

indo

or u

nit

•Pip

e size

for d

irect

conn

ection

to in

door

unit m

ust be

the s

ame a

s the

conn

ection

size o

f the

indo

or un

it.

Addi

tiona

l ref

riger

ant t

o be

cha

rged

Calcu

lation

of ad

dition

al ref

rigera

nt to

be ch

arged

R (kg

) is in

funct

ion of

total

length

of liq

uid lin

es L

NO

TES

•Ro

und o

ff R to

1 de

cimal

place.

R = [(L

ø22.2

) x 0.

39] +

[(Lø1

9.1) x

0.28

] + [(L

ø15.9

) x 0.

19] +

[(Lø1

2.7) x

0.12

] + [(L

ø9.5)

x 0.0

6] +

[(ø6.4

) x 0.

023]

+ 0

: RSX

YP16

,18,24

,28+

0.4: R

SXYP

30+

0.6: R

SXYP

26+

0.8: R

SXYP

20

R = [3

0 x 0.

39] +

[10 x

0.19

] + [1

0 x 0.

12] +

[40 x

0.06

] + [4

9 x 0.

023]

+ [0]

= 18

.32

� �AOu

tdoor

unit

REFN

ET join

t (A-

G)

Indoo

r unit

s (1-8

)

Outdo

or un

itRE

FNET

joint (

A-B)

Refne

t hea

der

Indoo

r unit

s (1-8

)

Outdo

or un

itRE

FNET

head

er

Indoo

r unit

s (1-8

)

Indoo

r cap

acity

index

..........

..........

..........

..........

.Bran

ch kit

< 10

0.......

..........

..........

..........

..........

..........

..........

.....KH

RP26

K11T

100≤

x <1

60.....

..........

..........

..........

..........

.........K

HRP2

6K18

T

160≤

x <3

30.....

..........

..........

..........

..........

.........K

HRP2

6K37

T

330≤

x <6

40.....

..........

..........

..........

..........

.........K

HRP2

6K40

T

> 64

0.......

..........

..........

..........

..........

..........

..........

.....KH

RP26

K75T

Indoo

r cap

acity

index

..........

..........

..........

..........

.Bran

ch kit

< 10

0.......

..........

..........

..........

..........

..........

..........

.....KHR

P26K

11H

100≤

x <1

60.....

..........

..........

..........

..........

..........K

HRP2

6K18

H

160≤

x <3

30.....

..........

..........

..........

..........

..........K

HRP2

6K37

H

330≤

x <6

40.....

..........

..........

..........

..........

..........K

HRP2

6K40

H

Pipe

size

con

nect

ed to

out

door

uni

t

Gas

Liquid

RXYP

16K

ø 19.1

x t1.

0ø 3

4.9 x

t1.3

RXYP

18-2

0Kø 1

9.1 x

t1.0

ø 34.9

x t1.

3

RXYP

24K

ø 19.1

x t1.

0ø 4

1.3 x

t1.7

RXYP

26-3

0Kø 2

2.2 x

t1.2

ø 41.3

x t1.

7

Total

capa

city in

dex

Liquid

Gas

< 10

0ø 9

.5 x t

0.8ø 1

5.9 x

1.010

0≤ x

<160

ø 9.5

x .t08

ø 19.1

x 1.0

160≤

x <3

30ø 1

2.7 x

t0.8

ø 25.4

x 1.2

330≤

x <4

80ø 1

5.9 x

t1.0

ø 34.9

x 1.3

480≤

x <6

40ø 1

9.1 x

t1.0

ø 34.9

x 1.3

≥ 64

0ø 1

9.1 x

t1.0

ø 41.3

x 1.7

Conn

ectio

n pi

pe si

ze o

f ind

oor u

nit

Total

capa

city in

dex

Gas

Liquid

20, 2

5, 32

, 40

ø 6.4

x t0.8

ø 12.7

x t0.

8

50, 6

3, 80

ø 9.5

x t0.8

ø 15.9

x t1.

0

100,

125

ø 9.5

x t0.8

ø 19.1

x t1.

0

200

ø 12.7

x t0.

8ø 2

5.4 x

t1.2

250

ø 12.7

x t0.

8ø 2

8.6 x

t1.2

Examp

le for

refrig

erant

branch

using

refne

t joint

and r

efnet

head

er for

RSXY

P28

a : ø2

2.2 x

30m

d : ø9

.5 x 1

0mg :

ø6.4

x 10m

j : ø6

.4 x 1

0m

b : ø1

5.9 x

10m

e : ø9

.5 x 1

0mh :

ø6.4

x 20m

k : ø6

.4 x 9

m

c : ø9

.5 x 1

0mf :

ø9.5

x 10m

i : ø1

2.7 x

10m

a↑b↑

i↑c+

d+e+

f↑

g+h+

j+k

↑⇓

18.3k

g

• Systems • Introduction 51

Page 53: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

• Introduction

6

52

6 Selection procedure6-6 Refrigerant pipe selection

6-6-4 RSEYP8-10K

Conn

ectio

n ex

ampl

eCo

nnec

tion

of 8

indo

or u

nits

Indoo

r unit

Refne

t joint

Refne

t hea

der

Three

lines

Two l

ines

Conn

ecting

-line l

ength

Bran

ch w

ith re

fnet

join

tBr

anch

with

refn

et jo

int a

nd re

fnet

hea

der

Bran

ch w

ith re

fnet

hea

der

Max

imum

allo

wab

le le

ngth

bet

wee

n ou

tdoo

r and

indo

or u

nits

Actua

l pipe

leng

thPip

e len

gth be

twee

n outd

oor a

nd in

door

units

≤ 10

0m

[Exam

ple] u

nit 8:

a+b+

c+d+

e+t ≤

100m

[Exam

ple] u

nit 1:

a+f+

g+h ≤

100m

, unit

7: a+

b+c+

d ≤ 10

0m[Ex

ample

] unit

8: a+

p ≤ 10

0m

Equiv

alent

length

Equiv

alent

pipe l

ength

betw

een o

utdoo

r and

indo

or un

its ≤

125m

(Assu

me eq

uivale

nt pip

e len

gth of

refne

t joint

to be

0.5m

and o

f the

refne

t hea

der t

o be 1

.0m (F

or cal

culati

on pu

rposes

))

Allo

wab

le h

eigh

t bet

wee

n ou

tdoo

r and

in

door

uni

tsDif

feren

ce in

heigh

t

Differ

ence

in he

ight b

etwee

n outd

oor a

nd in

door

units

(H1) ≤

50m

( ≤ 40

m if o

utdoo

r unit

is loc

ated i

n a lo

wer p

ositio

n)

Allo

wab

le h

eigh

t bet

wee

n ad

jace

nt in

door

un

itsDif

feren

ce in

heigh

t betw

een a

djacen

t indo

or un

its (H2

) ≤ 15

m

Allo

wab

le le

ngth

afte

r the

bra

nch

Actua

l pipe

leng

thPip

e len

gth fro

m firs

t refr

igeran

t bran

ch kit

(eith

er ref

net jo

int or

refne

t hea

der) t

o ind

oor u

nits ≤

40m

[Exam

ple] u

nit 8:

b+c+

d+e+

t ≤ 40

m[Ex

ample

] unit

1: f+

g+h ≤

40m,

unit 7

: b+c

+d ≤

40m

[Exam

ple] u

nit 8:

p ≤

40m

Conn

ectin

g lin

ePi

ping

bet

wee

n ou

tdoo

r and

BS

units

•Co

nnect

three

conn

ecting

lines:

suctio

n gas

line, d

ischa

rge ga

s line

and l

iquid

line (T

hick l

ines a

bove)

•Sel

ect re

frigera

nt bra

nch ki

t from

KHRP

25K2

0T, 1

8T, 3

7H an

d 18H

(For

how

to sel

ect, re

fer to

the i

tem be

low)

Pipi

ng b

etw

een

BS u

nit a

nd in

door

uni

t and

bet

wee

n re

frige

rant

bra

nch

kit a

nd c

ool-o

nly

indo

or u

nit

•Co

nnect

two c

onne

cting l

ines: g

as line

(suct

ion ga

s line

in th

e case

of co

ol-on

ly ind

oor u

nit) a

nd liq

uid lin

e (Thi

n line

s abo

ve)•

Select

refrig

erant

branch

kit fr

om KH

RP26

K18T

, and

18H (

For ho

w to

select

, refer

to th

e item

below

)

Refri

gera

nt b

ranc

h ki

t sel

ectio

nHo

w to

sele

ct th

e re

fnet

join

t•

When

using

a ref

net jo

int at

the f

irst br

anch

coun

ted fro

m the

outdo

or un

it side

, use

KHRP

25K2

0T. [E

xample

: refne

t joint

A]

•Fo

r refne

t joint

s othe

r than

the f

irst br

anch,

selec

t the

prop

er bra

nch ki

ts ba

sed on

the t

otal c

apaci

ty ind

ex of

indoo

r unit

s insta

lled af

ter th

e first

bran

ch, us

ing th

e fol

lowing

table

.

How

to se

lect

the

refn

et h

eade

r•

Selec

t the

prop

er bra

nch ki

t base

d on t

he to

tal ca

pacity

inde

x of in

door

units

instal

led af

ter th

e hea

der, u

sing t

he fo

llowing

table

.•

Branch

ing is

impo

ssible

betw

een r

efnet

head

er an

d ind

oor u

nit.

Examp

le of

down

strea

m ind

oor u

nits

[Exam

ple]

In cas

e of re

fnet jo

int C:

indo

or un

its 5+

6+7+

8[Ex

ample

]In

case o

f refne

t joint

B: in

door

units

7+8

In cas

e of re

fnet h

eade

r: ind

oor u

nits 1

+2+3

+4+5

+6[Ex

ample

]In

case o

f refne

t hea

der: i

ndoo

r unit

s 1+2

+3+4

+5+6

+7+8

Pipe

size

sele

ctio

nPip

e size

= ou

ter di

amete

r x m

inimum

wall

thickn

ess(un

it: mm

)

Betw

een

the

outd

oor u

nit a

nd th

e up

perm

ost s

tream

refri

gera

nt b

ranc

h ki

t•

Matc

h the

pipe

size t

o the

pipe

size o

f the

outdo

or un

it

•Wh

en on

ly on

e BS u

nit is

conn

ected

per re

frigera

nt line

of th

e outd

oor u

nit, d

ischa

rge ga

s line

does

not

branch

. In th

is case

, use

ø15.9

disch

arge g

as line

in or

der t

o prev

ent c

onfus

ion w

ith su

ction g

as line

.

Betw

een

two

imm

edia

tely

adja

cent

refri

gera

nt b

ranc

h ki

ts a

nd B

S un

it•

Selec

t the p

roper

pipe s

ize ba

sed on

the t

otal ca

pacity

inde

x of in

door

units

conn

ected

down

strea

m, us

ing

the fo

llowing

table

.

•Wh

en tw

o line

s are

conn

ected

betw

een t

wo ad

jacen

t refrig

erant

branch

kits,

select

the p

roper

gas li

ne siz

e ba

sed on

data

menti

oned

unde

r “Su

ction g

as line

” colu

mn in

the t

able

abov

e.

Betw

een

BS u

nit (

refri

gera

nt b

ranc

h ki

t) an

d in

door

uni

t•

Selec

t the p

roper

pipe s

ize ba

sed on

the t

otal ca

pacity

inde

x of in

door

units

conn

ected

down

strea

m, us

ing

the fo

llowing

table

.(Pi

pe siz

e for

direct

conn

ection

to in

door

unit m

ust be

the s

ame a

s the

conn

ection

size o

f the i

ndoo

r unit

.)

•Wh

en th

e tota

l capa

city su

m is i

n the

rang

e mark

er *, t

he co

nnect

ion siz

e of th

e BS u

nit (B

SVP1

00KV

1) is

differ

ent fr

om co

nnect

ing lin

e size

, redu

ce the

conn

ecting

line s

ize by

using

tape

red pi

pe at

tache

d to t

he BS

unit.

Addi

tiona

l ref

riger

ant t

o be

cha

rged

Calcu

lation

of ad

dition

al ref

rigera

nt to

be ch

arged

R (kg

) is in

funct

ion of

total

leng

th of

liquid

lines

L and

as fo

llows:

R=[(L

ø12.7

) x 0.

12] +

[(Lø9

.5) x

0.06]

+ [(L

ø6.4)

x 0.0

23]

NO

TES

•Ro

und o

ff R to

1 de

cimal

place.

•If R

is ≤

0, kee

p the

unit i

n ope

ration

Examp

le

R = [4

5 x 0.

12] +

[44 x

0.06

] + [2

8 x 0.

023]

= 8.6

→ R

= 8.6

kg

Examp

le

R = [4

0 x 0.

12] +

[30 x

0.06

] + [6

9 x 0.

023]

= 8.1

8 → R

= 8.1

8kg

Examp

le

R = [4

0 x 0.

12] +

[70 x

0.06

] + [6

8 x 0.

023]

= 10

.56 →

R =

10.56

kg

(V289

1)

� �A a~t

12

34

56

78

B1

B2

H2

H1

B3

B4

ab

cd

e

f

gh

k

in

qs

t

mp

r

AB

CD

E

FG

1 ~ 6

Eithe

r coo

l or h

eat m

ode c

an be

selec

ted7 +

8 Co

oling o

nly

12

34

56

7

8H2

H1B

5

B1

B2

B3

B4

a hj

ln

gi

k m

pq

f

ce

d

b

A

B

1 ~ 4,

7 +

8 Eith

er co

ol or

heat

mode

can b

e sele

cted

5 + 6

Coolin

g only

12

34

56

78

H2

H1

B1

B2

B3

B4

B5

B6

a

fd

bh

jl

n

ge

ci

km

p

1 ~ 6

Eithe

r coo

l or h

eat m

ode c

an be

selec

ted7 +

8 Co

oling o

nly

BS UNIT

Discha

rge ga

s line

Suctio

n gas

lineLiq

uid lin

e

Gas li

ne

Liquid

line

Total

capa

city in

dex o

f indo

or un

its......

..........

..........

..........

..........

..........

..........

..........

...Bran

ch kit

≥ 16

0.....

..........

..........

..........

..........

..........

..........

.......K

HRP2

5K20

T

< 16

03 l

ines...

..........

..........

..........

..........

..........

.....KH

RP25

K18T

2 line

s........

..........

..........

..........

..........

..........

KHRP

26K1

8T

Total

capa

city in

dex o

f indo

or un

its......

..........

..........

..........

..........

..........

..........

..........

...Bran

ch kit

≥ 16

0.....

..........

..........

..........

..........

..........

..........

.......K

HRP2

5K37

H (up

to 8

branch

es)

< 16

03 l

ines...

..........

..........

..........

..........

..........

.....KH

RP25

K18H

(up t

o 6 br

anche

s)

2 line

s........

..........

..........

..........

..........

..........

KHRP

26K1

8H (u

p to 8

bran

ches)

Pipe

size

con

nect

ed to

out

door

uni

t

Suctio

n gas

lineDis

charge

gas li

neLiq

uid lin

e

RSEY

P8ø 2

5.4 x

1.2ø 1

9.1 x

1.0ø 1

2.7 x

0.8

RSEY

P10

ø 28.6

x 1.2

ø 19.1

x 1.0

ø 12.7

x 0.8

Total

capa

city in

dex

Suctio

n gas

lineDis

charge

gas li

neLiq

uid lin

e

* < 50

ø 12.7

x 0.8

ø 9.5

x 0.8

ø 6.4

x 0.8

≥ 50

~≤1

00ø 1

5.9 x

1.0ø 1

2.7 x

0.8ø 9

.5 x 0

.8

> 10

0~≤1

60ø 1

9.1 x

1.0ø 1

5.9 x

1.0ø 9

.5 x 0

.8

> 16

0ø 2

5.4 x

1.2ø 1

9.1 x

1.0ø 1

2.7 x

0.8

Conn

ectio

n pi

pe si

ze o

f ind

oor u

nit

Total

capa

city in

dex

Gas p

ipeLiq

uid pi

pe

* < 50

ø 12.7

x 0.8

ø 6.4

x 0.8

≥ 50

~≤1

00ø 1

5.9 x

1.0ø 9

.5 x 0

.8

> 10

0~≤1

60ø 1

9.1 x

1.0ø 9

.5 x 0

.8

a : ø1

2.7 x

30m

f : ø9

.5 x 5

mk :

ø6.4

x 5m

p : ø6

.4 x 5

m

b : ø1

2.7 x

10m

g : ø9

.5 x 5

ml :

ø9.5

x 5m

r : ø6

.4 x 3

m

c : ø1

2.7 x

5mh :

ø9.5

x 5m

m : ø

9.5 x

2ms :

ø6.4

x 5m

d : ø9

.5 x 5

mi :

ø9.5

x 5m

n : ø9

.5 x 5

mt :

ø6.4

x 5m

e : ø9

.5 x 5

mj :

ø6.4

x 5m

o : ø9

.5 x 2

m

a : ø1

2.7 x

40m

e : ø9

.5 x 5

mi :

ø6.4

x 5m

m : ø

6.4 x

10m

b : ø9

.5 x 1

0mf :

ø9.5

x 10m

j : ø6

.4 x 2

mn :

ø6.4

x 4m

c : ø9

.5 x 5

mg :

ø6.4

x 5m

k : ø6

.4 x 1

0mo :

ø6.4

x 10m

d : ø9

.5 x 5

mh :

ø6.4

x 2m

l : ø6

.4 x 2

mp :

ø6.4

x 10m

a : ø1

2.7 x

40m

e : ø9

.5 x 5

mi :

ø6.4

x 2m

m : ø

6.4 x

2m

b : ø9

.5 x 1

0mf :

ø6.4

x 10m

j : ø6

.4 x 2

0mn :

ø6.4

x 10m

c : ø9

.5 x 5

mg :

ø6.4

x 2m

k : ø6

.4 x 2

mp :

ø6.4

x 30m

d : ø9

.5 x 2

0mh :

ø6.4

x 10m

l : ø6

.4 x 1

0m

• Systems • Introduction

Page 54: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

6

• Introduction

6 Selection procedure6-6 Refrigerant pipe selection

6-6-5 RSEYP16-30K

Bran

ch w

ith re

fnet

join

tBr

anch

with

refn

et jo

int a

nd re

fnet

hea

der

Bran

ch w

ith re

fnet

hea

der

Max

imum

al

low

able

le

ngth

Betw

een o

utdoo

r and

ind

oor u

nitAc

tual p

ipe len

gth

Actua

l pipe

length

Actua

l pipe

length

Examp

le of

down

strea

m ind

oor u

nits

Pipe l

ength

betw

een o

utdoo

r and

indo

or un

its ≤

100m

Examp

le un

it 8 :

a +

b + c

+ d +

e +

s ≤ 10

0m

Examp

le un

it 8 :

b +

c + d

+ e +

s ≤

40m

Examp

le in

case o

f refne

t joint

C: in

door

units

5 + 6

+ 7 +

8

Betw

een

outd

oor u

nit a

nd th

e up

perm

ost s

tream

refri

gera

nt b

ranc

h ki

t•

Selec

t pipe

size a

ccordi

ng to

outdo

or sys

tem.

Betw

een

two

imm

edia

tely

adja

cent

refri

gera

nt b

ranc

h ki

ts a

nd B

S un

it•

Selec

t the

prop

er pip

e size

based

on th

e tota

l cap

acity

index

of ind

oor u

nits c

onne

cted d

ownst

ream,

using

the

follow

ing ta

ble.

• Se

lect c

onne

ction p

ipe siz

e acco

rding

to th

e outd

oor u

nit (t

able

on th

e bott

om le

ft). D

o not

select

a lar

ger

pipe s

ize.

Betw

een

BS u

nit a

nd in

door

uni

tl

Pipe s

ize fo

r direc

t con

nectio

n to i

ndoo

r unit

must

be th

e sam

e as t

he co

nnect

ion siz

e of in

door

unit.

Examp

le for

refrig

erant

branch

using

refne

t joint

and h

eade

r (RS

EYP3

0K)

Examp

le in

case o

f refne

t joint

B: in

door

units

7+8

Examp

le in

case o

f refne

t hea

der: i

ndoo

r unit

s 1+

2+3+

4+5+

6Exa

mple

in cas

e of re

fnet h

eade

r: ind

oor u

nits 1

+2+

3+4+

5+6+

7+8

How

to se

lect

the

refn

et h

eade

r•

Selec

t the

prop

er bra

nch ki

t mod

el ba

sed on

the t

otal c

apaci

ty ind

ex of

indoo

r unit

s insta

lled af

ter

the he

ader

using

the f

ollowin

g tab

le.•

Branch

ing is

impo

ssible

betw

een r

efnet

head

er an

d ind

oor u

nit.

• For

syste

ms w

ith a

total

capaci

ty of

640 a

nd ov

er,

conn

ect a

refne

t joint

bran

ch.

• In

case o

f 2 pi

pes,

please

selec

t KHR

P26K

-H se

ries.

Examp

le un

it 6 :

b +

l ≤ 4

0m, E

xample

unit 8

:m

+ n +

p ≤

40m

Examp

le un

it 8 :

o ≤

40m

Examp

le un

it 6 :

a +

b + l ≤

100m

Examp

le un

it 8 :

a +

o ≤ 10

0m

Equiv

alent

pipe l

ength

betw

een o

utdoo

r and

indo

or un

its ≤

125m

(assu

me eq

uivale

nt pip

e len

gth of

refne

t joint

to be

0.5m

, that

of ref

net h

eade

r to b

e 1m,

that

of BS

unit t

o be 4

m, ca

lculat

ion pu

rposes

)

Pipe l

ength

betw

een o

utdoo

r unit

(main

) and

outdo

or un

it (sub

)(Q) ≤

5m

Differ

ence

in he

ight b

etwee

n ind

oor u

nits a

nd ou

tdoor

units

(H1) ≤

50m

( ≤

40m

or les

s whe

n oud

oor u

nit is

locate

d in a

lowe

r posi

tion)

Differ

ence

in he

ight b

etwee

n adja

cent in

door

units

(H2) ≤

15m

Differ

ence

in he

ight b

etwee

n outd

oor u

nit (m

ain) a

nd ou

tdoor

unit (

sub) (H

3) ≤

5m

Pipe l

ength

from

first re

frigera

nt bra

nch ki

t (eit

her re

fnet jo

int or

refne

t hea

der )

to ind

oor u

nit ≤

40m

Differe

nce in

heigh

t

Equiva

lent le

ngth

Betw

een o

utdoo

r unit

(main

) and

outdo

or un

it (su

b)

Betwe

en out

door a

nd ind

oor un

its

Betwe

en adj

acent

indoor

units

Betwe

en out

door u

nit (ma

in) and

outdo

or uni

t (sub)

Allo

wab

le

heig

ht le

ngth

Allo

wab

le le

ngth

afte

r the

bra

nch

Refri

gera

nt b

ranc

h ki

t sel

ectio

n

Pipe

size

sele

ctio

nPip

e size

= ou

ter di

amete

r x m

inimum

wall

thickn

ess(Un

it; mm

). Us

e the

inclu

ded r

educi

ng jo

int w

hich m

atche

s the

pipe

size.

Addi

tiona

l ref

riger

ant t

o be

cha

rged

Calcu

lation

of ad

dition

al ref

rigera

nt to

be ch

arged

R (kg

) is in

funct

ion of

the t

otal le

ngth

of liqu

id Iine

s L

No

te• R

ound

off R

to 1

decim

al pla

ce

indoo

r capa

city in

dex

< 16

0

160 ≤

x <

330

330 ≤

x <

640

640 ≤

x

branch

kit

KHRP

25K18

T

KHRP

25K2

0T

KHRP

25K4

0T +

KHRP

26K4

0T

KHRP

25K7

5T +

KHRP

25K7

5T

indoo

r cap

acity

index

100 ≤

x <

160

50 ≤

x <

100

160 ≤

x <

330

330 ≤

x <

480

480 ≤

x <

640

640 ≤

x <

700

x

> 70

0

x <

50

Pipe s

ize

Liquid

pipe

ø6

.4 x t

0.8ø9

.5 x t

0.8ø1

2.7 x

t0.8

ø9

.5 x t

0.8

ø9.5

x t0.8

ø12.7

x t0.

8ø1

5.9 x

t1.0ø1

9.1 x

t1.0ø1

9.1 x

t1.0ø1

9.1 x

t1.0

ø15.9

x t1.0

ø19.1

x t1.0

ø25.4

x t1.2

ø34.9

x t1.3

ø34.9

x t1.3

ø41.3

x t1.7

ø41.3

x t1.7

ø12.7

x t0.

8ø1

5.9 x

t1.0ø1

9.1 x

t1.0ø2

5.4 x

t1.2ø2

5.4 x

t1.2ø2

5.4 x

t1.2f34

.9 x t

1.3

Gas p

ipeSu

ction

Discha

rge

Outdo

or sys

tem na

me

RSEY

P24K

RSEY

P18-

20K

RSEY

P26K

RSEY

P28-

30K

RSEY

P16K

Pipe s

ize

Liquid

pipe

ø15.9

x t1.0

ø2

8.6 x

t1.2ø3

4.9 x

t1.3ø1

9.1 x

t1.0ø1

9.1 x

t1.0ø2

2.2 x

t1.2ø2

2.2 x

t1.2

ø34.9

x t1.3

ø41.3

x t1.7

ø41.3

x t1.7

ø41.3

x t1.7

ø28.6

x t1.2

ø28.6

x t1.2

ø34.9

x t1.3

ø34.9

x t1.3

Gas p

ipeSu

ction

Discha

rge

indoo

r cap

acity

index

20 ·

25 ·

32 ·

4050

· 63

· 80

100 ·

125

200

250

Pipe s

ize

ø 6.4

x t0.8

ø 9.5

x t0.8

ø 9.5

x t0.8

ø 12.7

x t0.

8ø 1

2.7 x

t0.8

ø 12.7

x t0.

8ø 1

5.9 x

t1.0ø 1

9.1 x

t1.0ø 2

5.4 x

t1.0ø 2

8.6 x

t1.2

Liquid

pipe

Gas p

ipe

a: ø 2

2.2 x

30m

d: ø 9

.5 x

5mb:

ø 19.1

x 10

mc:

ø 9.5

x 20

me:

ø 9.5

x 20m

f : ø 9

.5 x

5m

g: ø 9

.5 x 1

5mh:

ø 9.5

x 5m

i : ø 9

.5 x 1

0m

j : ø 9

.5 x

5mk:

ø 9.5

x 20m

l : ø 9

.5 x

5m

m: ø 1

2.7 x

10m

n : ø 1

2.7 x

5m

o : ø 1

2.7 x

20m

p : ø

6.4 x

9m

indoo

r capa

city in

dex

< 16

0

160 ≤

x <

330

330 ≤

x <

640

branch

kit

KHRP

25K18

H (M

ax. 6

branch

es)

KHRP

25K37

H (M

ax. 8

branch

es)

KHRP

25K4

0H (M

ax. 8

branch

es)

+ KH

RP26

K40H

P

R=

R=

30

x0.39

+

1

0x0.28

+

35x0.1

2

+

110x

0.06

+

9

x0.023

+1.0 =

31.27

ab

m+n+

op

c+d+

e+f+g

+h+i+

j+k+l

31.3

0:R

SEYP

16, 1

8, 24

, 26,

280.6

:RSEY

P20

1.0:RS

EYP3

0+

x0.39

Total le

ngth

of ø22.

2liqu

id line

+x0.2

8Tota

l lengt

hof ø

19.1liqu

id line

+x0.1

9Tota

l lengt

hof ø

15.9

liquid l

ine+

x0.12

Total le

ngth

of ø12.

7liqu

id line

+x0.0

6Tota

l lengt

hof ø

9.5liqu

id line

+x0.0

23Tota

l lengt

hof ø

6.3liqu

id line

REFN

ET join

t(

~

)

BS un

it

(

~

)

A

AG

F

B1

B1B4

Indoo

r unit

(

~

)1

8Co

ol/He

at sel

ection

possi

ble (

~

)

16

Coolin

g only

(

.

)

78

1h

fg

ik

b

m

a

l

c

G

2j

34

B

B2

on

5B3

qp

6B4

CD

r

H2

H1

s

78

E

de

H3

Q

Outdo

or uni

tRE

FNET

joint

(

.

)

BS

unit

(

~

)

A

AB

B5

B1B5

Indoo

r unit

(

~

)1

8Co

ol/He

at sel

ection

possi

ble(

~

,

.

)1

47

8

Coolin

g only

(

.

)5

6

d

c

1B1

H2

H1

H3

Q

am

b

Outdo

or uni

t

fe

2B2hg 3B3

ji

4B4k

5

lo

np

67

8B

REFN

ET hea

der

BS

unit

(

~

)

B1B6

Indoo

r unit

(

~

)1

8Co

ol/He

at sel

ection

possi

ble (

~

)

16

Coolin

g only

(

. )

78H2

H1

H3

Q

a

Outdo

or uni

t

ih 4B4

g

f 3B3

e

d 2B2

c

b 1B1

kj 5B5

m

l 6B6

n

7

o

8

REFN

ET hea

der

(Unit :

mm)

(Unit :

mm)

How

to se

lect

the

refn

et jo

int

• Wh

en us

ing re

fnet jo

ints a

t the

first

branch

coun

ted fro

m the

outdo

or un

it side

.If t

he sy

stem

capaci

ty is <

500

, use

KHRP

25K4

0T +

KHRP

26K4

0TP(P

ipe siz

e red

ucer).

If the

syste

m cap

acity

is ≥ 50

0, use

KHRP

25K7

5T +

KHRP

25K7

5TP (

Pipe s

ize re

ducer

).•

For re

fnet jo

ints o

ther t

han t

he fir

st bra

nch, se

lect t

he pr

oper

branch

kit

mode

l base

d on t

he to

tal ca

pacity

inde

x of t

he in

door

units

instal

led

after

the fir

st bra

nch us

ing th

e follo

wing t

able:

• In

case o

f 2 pi

pes,

please

selec

t KHR

P26K

-T ser

ies

1 A

Outdo

orun

itInd

oor

unit

Discha

rge ga

s pipe

(3 pip

es)(2

pipes)

Suctio

n gas

pipe

Liquid

pipe

Gas p

ipe

Liquid

pipe

BS unit

indoo

r unit

refne

t joint

refne

t hea

der

• Systems • Introduction 53

Page 55: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

• Introduction

6

54

• Systems • Introduction
Page 56: technical data - daikintech.co.uk · technical data Systems ... 20 25 32 40 50 63 71 80 100 125 200 250 ... Concealed ceiling unit FXYSP-KA7V19 xxxxxx xxx Concealed ceiling unit

2Systems

ISO14001 assures an effective environmental management system in order to help protect human health and the environment from the potential impact of our activities, products and services and to assist in maintaining and improving the quality of the environment.

Daikin Europe N.V. is approved by LRQA for its Quality Management System in accordance with the ISO9001 standard. ISO9001 pertains to quality assurance regarding design, development, manufacturing as well as to services related to the product.

Daikin units comply with the Europeanregulations that guarantee the safety ofthe product.

VRV products are not within the scope of the Eurovent certification programme.

Specifications are subject to change without prior notice

Zandvoordestraat 300B-8400 Ostend - BelgiumInternet: http://www.daikineurope.com

EED

E02-

2/2A

• 0

8/20

02Pr

epar

ed in

Bel

gium

by

Van

mel

le