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Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 1
BrazilProblem 14 – Circle of Light
Brazil
Problem 14 Circle of Light
Reporter: Felipe de Melo
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 2
BrazilProblem 14 – Circle of Light
Problem 14 Circle of Light
When a laser beam is aimed at a wire, a circle of light can be observed on a screen perpendicular to the wire. Explain this phenomenon and investigate how it depends on the relevant parameters.
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 3
BrazilProblem 14 – Circle of Light
• Reflection• Refraction• Snell’s Law• Interference
Theoretical Introduction
• Materials• Procedures• Data Analysis
Experiments
• Relevant parameters
Conclusion
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 4
BrazilProblem 14 – Circle of Light
REFLECTION
Reflection occurs on the surface of the wire
Conic formation
Incidence angleReflection angle
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 5
BrazilProblem 14 – Circle of Light
REFLECTION
Half of the wire surface All the circle, without
the wire shadow
Only because the wire is rounded the reflection
forms a circle
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 6
BrazilProblem 14 – Circle of Light
REFRACTION
Refraction occurs through the wire
Will form the front part of the circle
Higher refraction indeces will distribute the refraction along a bigger part of the circle
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 7
BrazilProblem 14 – Circle of Light
REFRACTIONVertical
projection plan
We will call this angle as beta
Both angles are equal
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 8
BrazilProblem 14 – Circle of Light
REFRACTION
Distance to wire center
Incidence angle
First angular deviation
Refraction angle
Wire radius
A laser light ray
The wire
Horizontal projection plan
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 9
BrazilProblem 14 – Circle of Light
REFRACTION
SNELL’S LAW
�⃗�1
�⃗�2
�⃗�
𝑛1∗𝑠𝑒𝑛 (𝜃1 )=𝑛2∗𝑠𝑒𝑛(𝜃2)
𝜃1𝜃2
Does not exist a plan that contains both at the
same time
Best way to quantify both angles is using
vectors
Incident light ray
Refracted light ray
Normal straight line in relation with the surface
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 10
BrazilProblem 14 – Circle of Light
𝑠2=𝑛1𝑛2
[𝑁×(−𝑁×𝑠1) ]− �̂� √1−(𝑛1𝑛2 )2
( �̂�×𝑠1 )⋅ ( �̂�×𝑠1 )
REFRACTION
VECTORIAL FORM OF SNELL’S LAW
Refracted light ray
unit vector
Wire refraction index
Air refraction index Normal unit
vector
Incident light ray unit vector
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 11
BrazilProblem 14 – Circle of Light
𝛼=tan−1(√1−𝜂2 (1−cos2 (𝛽 )cos2 (𝜃 ) )−𝜂 cos (𝜃 ) cos (𝛽) ) sin (𝜃 )
𝜂 sin2 (𝜃 ) cos (𝛽)+cos (𝜃)√1−𝜂2 [1− cos2 ( 𝛽) cos2(𝜃) ]
REFRACTION
Inclination in relation to horizontal axis 𝜂=
𝑛1𝑛2
lim𝜃→
𝜋2
𝛼=tan−1 √1−𝜂2
cos 𝛽𝜂The last refracted ray, with biggest angular deviation
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 12
BrazilProblem 14 – Circle of Light
REFRACTION
𝛼𝑚𝑎𝑥=tan−1 √1−𝜂2cos𝛽𝜂𝛼𝑚𝑎𝑥=tan
−1 √𝑛2−1cos𝛽
Assuming : wire immersed in air
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 13
BrazilProblem 14 – Circle of Light
0<cos 𝛽<1
REFRACTION
𝛼𝑚𝑎𝑥=tan−1 √𝑛2−1cos𝛽 0<𝛽<
𝜋2
On this interval, is a decresent
function
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 14
BrazilProblem 14 – Circle of Light
REFRACTION
Refraction
index
Light intensity
Inclination angle
Light intensity
Increase the area iluminated by refracted light
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 15
BrazilProblem 14 – Circle of Light
REFRACTION
Form primaly the front part of the circle
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 16
BrazilProblem 14 – Circle of Light
REFRACTION AND REFLECTION
Translucid wireAssume absorption
equals to zero
𝑇 +𝑅+𝐴=1Energy conservation
𝑇 +𝑅=1
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 17
BrazilProblem 14 – Circle of Light
REFRACTION AND REFLECTION
FRESNEL’S RELATION
http://www.ece.rice.edu/~daniel/262/pdf/lecture13.pdf
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 18
BrazilProblem 14 – Circle of Light
REFRACTION AND REFLECTION
From spherical geometry:
cos𝜃𝑖=cos𝜃 cos𝛽
𝛽 ≤𝜃𝑖<𝜋2
Higher values for beta will increase the reflected light intensity
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 20
BrazilProblem 14 – Circle of Light
CIRCLE FORMATION
𝑟 ≅htan 𝛽
Disconsidering the wire dimensions
LaserWire
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 21
BrazilProblem 14 – Circle of Light
CIRCLE FORMATION
Δ h=𝑑 (sin 𝛽−sin 𝛽 ′)
Wire diameter
Horizontal inclination
Horizontal inclination after
refraction
Much smaller than other experiment
dimensions
can be disconsidered
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 22
BrazilProblem 14 – Circle of Light
𝑤=𝑧 𝜆𝑑
INTERFERENCE
DOUBLE SLIT PATTERN OF INTERFERENCE
Wire diameterDistance
between two dark
shadows
Light wave-lengthDistance to screen
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 23
BrazilProblem 14 – Circle of Light
PREDICTION OF THE RELEVANT PARAMETERS
Incident angleThe measure of the radius
Light intensity distribution
Wire dimensionsThinner wires will turn easier
to see the interference
Refraction Index Light intensity distribution
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 24
BrazilProblem 14 – Circle of Light
EXPERIMENTS
MATERIALS
• Nylon wires (n=1.56) with different diameters (0.405mm, 0.7mm, 0.8mm)
• Copper wire of 150 • Micrometer• Laser of wave-length
532nm• Chalk powder
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 25
BrazilProblem 14 – Circle of Light
EXPERIMENTS
CONIC FORMATIONConic
formation
Height and radius
Light intensty
Intensity
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 26
BrazilProblem 14 – Circle of Light
0 5 10 15 20 250
5
10
15
20
25𝜷=45°±1°
Height [cm]
Rad
ius
[cm
]
EXPERIMENTS
RELATION BETWEEN HEIGHT AND RADIUSConic
formation
Height and radius
Light intensty
Intensity
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 27
BrazilProblem 14 – Circle of Light
EXPERIMENTS
LIGHT INTENSITY DISTRIBUTION
Point of maximun reflection
Point of maximun refraction +
𝛽=35 .0 °±0.5 Conic formation
Height and radius
Light intensty
Intensity
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 28
BrazilProblem 14 – Circle of Light
EXPERIMENTS
DIFFERENT SHAPES
It will form a circle
It will form an ellipse
It will form a parabola
It will form a hyperbole
Laser
Screen
Wire
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 29
BrazilProblem 14 – Circle of Light
EXPERIMENTS
DIFFERENT SHAPES
Circle
Ellipse
Parabole
Hyperbole
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 30
BrazilProblem 14 – Circle of Light
𝑑𝑧𝑤=𝜆
𝑑=150𝜇𝑚±5𝜇𝑚𝑧=2,79𝑚±0,05𝑚𝑤=1,00𝑐𝑚±0,05𝑐𝑚 𝜆𝑒𝑥𝑝𝑒𝑟𝑖𝑚𝑒𝑛𝑡𝑎𝑙=
150∗10− 6
2,7910− 2
𝜆𝑒𝑥𝑝𝑒𝑟𝑖𝑚𝑒𝑛𝑡𝑎𝑙=537𝑛𝑚±33𝑛𝑚
EXPERIMENTS
INTERFERENCE
Copper wire, only reflects the light
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 31
BrazilProblem 14 – Circle of Light
EXPERIMENTS
INTERFERENCE
Interference+
Reflection+
Refraction0.2 mm nylon wire
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 32
BrazilProblem 14 – Circle of Light
SUMMARY:
THEORETICAL INTRODUCTION
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 33
BrazilProblem 14 – Circle of Light
SUMMARY:
EXPERIMENTS
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 34
BrazilProblem 14 – Circle of Light
CONCLUSIONS
RELEVANT PARAMETERS
Increase reflectanceLaser inclination
Refraction Index
Define the shape of figureShape of the wire
Position of the surface
Visibility of interference Thinner wire diameter
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 35
BrazilProblem 14 – Circle of Light
BIBLIOGRAPHY
• Vector form of Snell’s Law, Available on http://www.starkeffects.com/snells-law-vector.shtml, Access on 20 April
• REFLECTIVITY; Wikipedia. Available on <http://en.wikipedia.org/wiki/Reflectivity> Access on 10 november
• FRESNEL EQUATIONS; Wikipedia. Available on <http://en.wikipedia.org/wiki/Fresnel_equations> Access on 10 november
• KONG, H. J. ; CHOI, Jin; SHIN, J. S.; YI, S. W.; JEON, B. G.; Hollow conic beam generator using a cylindrical rod and its performances.
• MV Klein & TE Furtak, Optics, 1986, John Wiley & Sons, New York; Huygens Principle
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 36
BrazilProblem 14 – Circle of Light
Thank you!Thank you!
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 37
BrazilProblem 14 – Circle of Light
REFRACTION
𝜃=arcsin (𝑥𝑟 )𝛼=𝜃−𝜃 ′
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 38
BrazilProblem 14 – Circle of Light
HEIGHT VARIATION
Δ h=𝑑 (sin 𝛽−sin 𝛽 ′)
Δ h=2𝑑∗ sin 𝛽− 𝛽′
2∗ cos 𝛽+𝛽 ′
2≤1
Δ h≤2𝑑
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 39
BrazilProblem 14 – Circle of Light
RADIUS VARIATION (I)
Δ 𝑟=Δhtan 𝛽
Δ h=𝑑 (sin 𝛽− sin 𝛽 ′ )
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 40
BrazilProblem 14 – Circle of Light
RADIUS VARIATION (II)
Before refraction light velocity on this projection:
Δ 𝑟=𝑑 cos𝛽 (1− 𝜂cos𝛼 )
sin 𝛽cos𝛼
𝑛1=sin 𝛽 ′𝑛2
Δ h=𝑑 sin 𝛽 (1− 𝜂cos𝛼 )
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 41
BrazilProblem 14 – Circle of Light
RADIUS VARIATION (III)
Δ 𝑟=𝑑 cos𝛽 (1− 𝜂cos𝛼 )
≤1 ¿1
Δ 𝑟<𝑑
|𝛼|< 𝜋2
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 42
BrazilProblem 14 – Circle of Light
LIGHT INTENSITY
FRESNEL’S EQUATIONS
𝑅1 𝑠 (𝑥 )=(𝑛𝑎𝑖𝑟 cos𝜃 cos 𝛽 –𝑛𝑤𝑖𝑟𝑒√1−( 𝑛𝑎𝑖𝑟
𝑛𝑤𝑖𝑟𝑒)2
∗ (1− cos2𝜃 cos2 𝛽 )2
𝑛𝑎𝑖𝑟 cos𝜃 cos𝛽+𝑛𝑤 𝑖𝑟𝑒√1−( 𝑛𝑎𝑖𝑟
𝑛𝑤𝑖𝑟𝑒)2
∗ (1− cos2𝜃 cos2 𝛽)2 )2
𝑅1𝑝 (𝑥)=(𝑛𝑎𝑖𝑟 √1−(( 𝑛𝑎𝑖𝑟
𝑛𝑤𝑖𝑟𝑒)2
∗ (1−cos2𝜃 cos2 𝛽 )2)2
−𝑛𝑤𝑖𝑟𝑒cos𝜃 cos 𝛽
𝑛𝑎𝑖𝑟√1−(( 𝑛𝑎𝑖𝑟
𝑛𝑤𝑖𝑟𝑒)2
∗ (1− cos2𝜃 cos2𝛽 )2)2
+𝑛𝑤𝑖𝑟𝑒 cos𝜃 cos𝛽 )2
Paralel polarized light
Perpendicular polarized light
Team of BrazilProblem ## Title
Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 43
BrazilProblem 14 – Circle of Light
LIGHT INTENSITY
FRESNEL’S EQUATIONS