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Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015 Reporter: Felipe de Melo 1 Brazil Problem 14 – Circle of Light Brazil Problem 14 Circle of Light Reporter: Felipe de Melo

Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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Page 1: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 1

BrazilProblem 14 – Circle of Light

Brazil

Problem 14 Circle of Light

Reporter: Felipe de Melo

Page 2: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 2

BrazilProblem 14 – Circle of Light

Problem 14 Circle of Light

When a laser beam is aimed at a wire, a circle of light can be observed on a screen perpendicular to the wire. Explain this phenomenon and investigate how it depends on the relevant parameters.

Page 3: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 3

BrazilProblem 14 – Circle of Light

• Reflection• Refraction• Snell’s Law• Interference

Theoretical Introduction

• Materials• Procedures• Data Analysis

Experiments

• Relevant parameters

Conclusion

Page 4: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 4

BrazilProblem 14 – Circle of Light

REFLECTION

Reflection occurs on the surface of the wire

Conic formation

Incidence angleReflection angle

Page 5: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 5

BrazilProblem 14 – Circle of Light

REFLECTION

Half of the wire surface All the circle, without

the wire shadow

Only because the wire is rounded the reflection

forms a circle

Page 6: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 6

BrazilProblem 14 – Circle of Light

REFRACTION

Refraction occurs through the wire

Will form the front part of the circle

Higher refraction indeces will distribute the refraction along a bigger part of the circle

Page 7: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 7

BrazilProblem 14 – Circle of Light

REFRACTIONVertical

projection plan

We will call this angle as beta

Both angles are equal

Page 8: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 8

BrazilProblem 14 – Circle of Light

REFRACTION

Distance to wire center

Incidence angle

First angular deviation

Refraction angle

Wire radius

A laser light ray

The wire

Horizontal projection plan

Page 9: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

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BrazilProblem 14 – Circle of Light

REFRACTION

SNELL’S LAW

�⃗�1

�⃗�2

�⃗�

𝑛1∗𝑠𝑒𝑛 (𝜃1 )=𝑛2∗𝑠𝑒𝑛(𝜃2)

𝜃1𝜃2

Does not exist a plan that contains both at the

same time

Best way to quantify both angles is using

vectors

Incident light ray

Refracted light ray

Normal straight line in relation with the surface

Page 10: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

𝑠2=𝑛1𝑛2

[𝑁×(−𝑁×𝑠1) ]− �̂� √1−(𝑛1𝑛2 )2

( �̂�×𝑠1 )⋅ ( �̂�×𝑠1 )

REFRACTION

VECTORIAL FORM OF SNELL’S LAW

Refracted light ray

unit vector

Wire refraction index

Air refraction index Normal unit

vector

Incident light ray unit vector

Page 11: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

𝛼=tan−1(√1−𝜂2 (1−cos2 (𝛽 )cos2 (𝜃 ) )−𝜂 cos (𝜃 ) cos (𝛽) ) sin (𝜃 )

𝜂 sin2 (𝜃 ) cos (𝛽)+cos (𝜃)√1−𝜂2 [1− cos2 ( 𝛽) cos2(𝜃) ]

REFRACTION

Inclination in relation to horizontal axis 𝜂=

𝑛1𝑛2

lim𝜃→

𝜋2

𝛼=tan−1 √1−𝜂2

cos 𝛽𝜂The last refracted ray, with biggest angular deviation

Page 12: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

REFRACTION

𝛼𝑚𝑎𝑥=tan−1 √1−𝜂2cos𝛽𝜂𝛼𝑚𝑎𝑥=tan

−1 √𝑛2−1cos𝛽

Assuming : wire immersed in air

Page 13: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

0<cos 𝛽<1

REFRACTION

𝛼𝑚𝑎𝑥=tan−1 √𝑛2−1cos𝛽 0<𝛽<

𝜋2

On this interval, is a decresent

function

Page 14: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

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BrazilProblem 14 – Circle of Light

REFRACTION

Refraction

index

Light intensity

Inclination angle

Light intensity

Increase the area iluminated by refracted light

Page 15: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

REFRACTION

Form primaly the front part of the circle

Page 16: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

REFRACTION AND REFLECTION

Translucid wireAssume absorption

equals to zero

𝑇 +𝑅+𝐴=1Energy conservation

𝑇 +𝑅=1

Page 17: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

REFRACTION AND REFLECTION

FRESNEL’S RELATION

http://www.ece.rice.edu/~daniel/262/pdf/lecture13.pdf

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BrazilProblem 14 – Circle of Light

REFRACTION AND REFLECTION

From spherical geometry:

cos𝜃𝑖=cos𝜃 cos𝛽

𝛽 ≤𝜃𝑖<𝜋2

Higher values for beta will increase the reflected light intensity

Page 19: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

CIRCLE FORMATION

𝑟 ≅htan 𝛽

Disconsidering the wire dimensions

LaserWire

Page 20: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

CIRCLE FORMATION

Δ h=𝑑 (sin 𝛽−sin 𝛽 ′)

Wire diameter

Horizontal inclination

Horizontal inclination after

refraction

Much smaller than other experiment

dimensions

can be disconsidered

Page 21: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

𝑤=𝑧 𝜆𝑑

INTERFERENCE

DOUBLE SLIT PATTERN OF INTERFERENCE

Wire diameterDistance

between two dark

shadows

Light wave-lengthDistance to screen

Page 22: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

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BrazilProblem 14 – Circle of Light

PREDICTION OF THE RELEVANT PARAMETERS

Incident angleThe measure of the radius

Light intensity distribution

Wire dimensionsThinner wires will turn easier

to see the interference

Refraction Index Light intensity distribution

Page 23: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

EXPERIMENTS

MATERIALS

• Nylon wires (n=1.56) with different diameters (0.405mm, 0.7mm, 0.8mm)

• Copper wire of 150 • Micrometer• Laser of wave-length

532nm• Chalk powder

Page 24: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

EXPERIMENTS

CONIC FORMATIONConic

formation

Height and radius

Light intensty

Intensity

Page 25: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

0 5 10 15 20 250

5

10

15

20

25𝜷=45°±1°

Height [cm]

Rad

ius

[cm

]

EXPERIMENTS

RELATION BETWEEN HEIGHT AND RADIUSConic

formation

Height and radius

Light intensty

Intensity

Page 26: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

EXPERIMENTS

LIGHT INTENSITY DISTRIBUTION

Point of maximun reflection

Point of maximun refraction +

𝛽=35 .0 °±0.5 Conic formation

Height and radius

Light intensty

Intensity

Page 27: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

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BrazilProblem 14 – Circle of Light

EXPERIMENTS

DIFFERENT SHAPES

It will form a circle

It will form an ellipse

It will form a parabola

It will form a hyperbole

Laser

Screen

Wire

Page 28: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

EXPERIMENTS

DIFFERENT SHAPES

Circle

Ellipse

Parabole

Hyperbole

Page 29: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

𝑑𝑧𝑤=𝜆

𝑑=150𝜇𝑚±5𝜇𝑚𝑧=2,79𝑚±0,05𝑚𝑤=1,00𝑐𝑚±0,05𝑐𝑚 𝜆𝑒𝑥𝑝𝑒𝑟𝑖𝑚𝑒𝑛𝑡𝑎𝑙=

150∗10− 6

2,7910− 2

𝜆𝑒𝑥𝑝𝑒𝑟𝑖𝑚𝑒𝑛𝑡𝑎𝑙=537𝑛𝑚±33𝑛𝑚

EXPERIMENTS

INTERFERENCE

Copper wire, only reflects the light

Page 30: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

EXPERIMENTS

INTERFERENCE

Interference+

Reflection+

Refraction0.2 mm nylon wire

Page 31: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

SUMMARY:

THEORETICAL INTRODUCTION

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BrazilProblem 14 – Circle of Light

SUMMARY:

EXPERIMENTS

Page 33: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

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BrazilProblem 14 – Circle of Light

CONCLUSIONS

RELEVANT PARAMETERS

Increase reflectanceLaser inclination

Refraction Index

Define the shape of figureShape of the wire

Position of the surface

Visibility of interference Thinner wire diameter

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BrazilProblem 14 – Circle of Light

BIBLIOGRAPHY

• Vector form of Snell’s Law, Available on http://www.starkeffects.com/snells-law-vector.shtml, Access on 20 April

• REFLECTIVITY; Wikipedia. Available on <http://en.wikipedia.org/wiki/Reflectivity> Access on 10 november

• FRESNEL EQUATIONS; Wikipedia. Available on <http://en.wikipedia.org/wiki/Fresnel_equations> Access on 10 november

• KONG, H. J. ; CHOI, Jin; SHIN, J. S.; YI, S. W.; JEON, B. G.; Hollow conic beam generator using a cylindrical rod and its performances.

• MV Klein & TE Furtak, Optics, 1986, John Wiley & Sons, New York; Huygens Principle

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BrazilProblem 14 – Circle of Light

Thank you!Thank you!

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BrazilProblem 14 – Circle of Light

REFRACTION

𝜃=arcsin (𝑥𝑟 )𝛼=𝜃−𝜃 ′

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BrazilProblem 14 – Circle of Light

HEIGHT VARIATION

Δ h=𝑑 (sin 𝛽−sin 𝛽 ′)

Δ h=2𝑑∗ sin 𝛽− 𝛽′

2∗ cos 𝛽+𝛽 ′

2≤1

Δ h≤2𝑑

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BrazilProblem 14 – Circle of Light

RADIUS VARIATION (I)

Δ 𝑟=Δhtan 𝛽

Δ h=𝑑 (sin 𝛽− sin 𝛽 ′ )

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BrazilProblem 14 – Circle of Light

RADIUS VARIATION (II)

Before refraction light velocity on this projection:

Δ 𝑟=𝑑 cos𝛽 (1− 𝜂cos𝛼 )

sin 𝛽cos𝛼

𝑛1=sin 𝛽 ′𝑛2

Δ h=𝑑 sin 𝛽 (1− 𝜂cos𝛼 )

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BrazilProblem 14 – Circle of Light

RADIUS VARIATION (III)

Δ 𝑟=𝑑 cos𝛽 (1− 𝜂cos𝛼 )

≤1 ¿1

Δ 𝑟<𝑑

|𝛼|< 𝜋2

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BrazilProblem 14 – Circle of Light

LIGHT INTENSITY

FRESNEL’S EQUATIONS

𝑅1 𝑠 (𝑥 )=(𝑛𝑎𝑖𝑟 cos𝜃 cos 𝛽 –𝑛𝑤𝑖𝑟𝑒√1−( 𝑛𝑎𝑖𝑟

𝑛𝑤𝑖𝑟𝑒)2

∗ (1− cos2𝜃 cos2 𝛽 )2

𝑛𝑎𝑖𝑟 cos𝜃 cos𝛽+𝑛𝑤 𝑖𝑟𝑒√1−( 𝑛𝑎𝑖𝑟

𝑛𝑤𝑖𝑟𝑒)2

∗ (1− cos2𝜃 cos2 𝛽)2 )2

𝑅1𝑝 (𝑥)=(𝑛𝑎𝑖𝑟 √1−(( 𝑛𝑎𝑖𝑟

𝑛𝑤𝑖𝑟𝑒)2

∗ (1−cos2𝜃 cos2 𝛽 )2)2

−𝑛𝑤𝑖𝑟𝑒cos𝜃 cos 𝛽

𝑛𝑎𝑖𝑟√1−(( 𝑛𝑎𝑖𝑟

𝑛𝑤𝑖𝑟𝑒)2

∗ (1− cos2𝜃 cos2𝛽 )2)2

+𝑛𝑤𝑖𝑟𝑒 cos𝜃 cos𝛽 )2

Paralel polarized light

Perpendicular polarized light

Page 42: Team of Brazil Problem ## Title Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago KalifeNakhon Ratchasima, 27 June – 4 July 2015

Team of BrazilProblem ## Title

Diego de Moura, Felipe de Melo, Matheus Camacho, Thiago Bergamaschi, Thiago Kalife Nakhon Ratchasima, 27 June – 4 July 2015Reporter: Felipe de Melo 43

BrazilProblem 14 – Circle of Light

LIGHT INTENSITY

FRESNEL’S EQUATIONS