TCY - Inequalities.ppt

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    1

    INEQUALITIES

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    INTRODUCTION

    If a and b are real numbers then we can compare their positionsby the relation

    Less than Less than or equal to

    Greater than or equal to

    For example: if x > 3 , it means x can be any value more than 3

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    VARIOUS TYPESOFGRAPHS

    Shadeup

    Shadedown

    Solidline

    Dashedline

    > x + 1

    1

    2

    3

    1

    2

    3

    321 1 2 3

    y > x + 1

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    y < x + 1

    1

    2

    3

    1

    2

    3

    321 1 2 3

    y < x + 1

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    x > 2

    1

    2

    3

    1

    2

    3

    321 1 2 3

    x > 2

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    1

    2

    3

    1

    2

    3

    321 1 2 3

    4

    WRITE THE EQUATION

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    1

    2

    3

    1

    2

    3

    321 1 2 3

    4

    WRITE THE EQUATION

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    PROPERTIES OF INEQUALITIES

    Ifa is greater than b

    If we add c (any real number) then which one is greater

    A + c or b + c

    Solution: (a + c) is greater than b + c

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    You know 8 is greater than 4 or 8 > 4

    Add 2 on both sides

    8 + 2 > 4 + 2

    10 > 6

    TRUE

    EXAMPLE

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    Ifa is greater than b

    If we subtract c (any real number) then which one is greater

    a c or b c

    Solution: (a c) is greater than b c

    PROPERTIES OF INEQUALITIES

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    You know 8 is greater than 4 or8 > 4

    Subtract

    2from both sides

    8 2 > 4 2

    6 > 2

    TRUE

    EXAMPLE

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    Ifa is greater than b i.e. (a > b)

    If we multiply by c (any real number) then which one is

    greater

    ac or bc ?

    Depends upon c because c can be a positive or negative real

    number

    PROPERTIES OF INEQUALITIES

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    You know 8 is greater than 4 or

    8 > 4

    Multiply by

    2both sides

    8(2) > 4(2)

    16 > 8

    TRUE

    EXAMPLE

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    You know 8 is greater than 4 or

    8 > 4

    Multiply by

    2both sides

    8( 2) > 4( 2)

    16 > 8

    FALSE

    EXAMPLE

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    Ifa is greater than b

    WHICH IS GREATER

    ac or bc

    If c is positive then ac > bc

    If c is negative then ac < bc

    REMEMBER

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    If a is greater than b

    WHICH IS GREATER

    or

    Is Greater than a

    1

    b

    1

    b

    1

    a

    1

    REMEMBER

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    Transitive: If a < b and b < c, then a < c

    Additionofinequalities: If a < b and

    c < d, then a + c < b + d.

    Addition of a constant: If a < b, then

    a + c < b + c. Multiplication by a constant:

    If a < b and c is positive real number, then: ac < bc

    and if c is negative real number, then ac > bc

    Taking Reciprocals: If a < b and a, b 0, then

    PROPERTIES OF INEQUALITIES

    b

    1

    a

    1

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    Inequalitynotation

    Real number line graph

    3x

    3x

    52 x

    3x

    3x

    INTERVAL NOTATION

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    You solve linear inequalities in the same way as you would solvelinear equations, but with one exception.

    Property :If in the process of solving an inequality, you multiplyor divide the inequality by a negative number, then , you must

    switch the direction of the inequality.

    Ifx> a, then x

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    Solve x+ 3 < 2.

    Graphically

    SOLVING LINEAR INEQUATIONS

    CASE-1

    When the equation was "x+ 3 = 2 type,

    We normally subtract 3 from both sides.

    Then the solution is: x< 1

    X + 3 < 2

    - 3 -3

    -------------------------

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    Solve 2x< 9.

    Like inequality divide by 2

    CASE-2

    5.42

    9x

    2

    9

    2

    x2

    9x2

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    What happens when the number is negative?

    27x3

    If you divide both sides by 3,

    3

    27

    3

    x3

    9x (The inequality will change if we multiply or divide with a

    negative number on both sides.)

    CASE-3

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    SOLVING QUADRATIC INEQUATIONS

    When we have an inequality with "x2" as the highest-

    degree term, it is called a "quadratic inequality".

    Solve x2 3x+ 2 > 0

    Step 1: Change the inequality to an equation. Find x- intercept

    x2 3x+ 2 = 0(x 1) (x 2) = 0

    x = 1 or 2

    Step 2: Plot the points ( x = 1, 2) on the number line

    3 2 1 0 1 2 3

    The number line is divided into the intervals (- , 1), (1, 2),

    and (2, ).

    1 2

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    x2

    3x

    + 2 > 0 or(x 1) (x 2) > 0The number line is divided into the intervals (- , 1), (1, 2),

    and (2, ).

    1 2

    Test-point method: Pick a point (any point) in each interval

    x= 3

    (x - 1) is positive(x - 1) (x - 2) is positive(x - 3) is positivePOSITIVE

    x= 1.5

    (x - 1) is negative(x - 1) (x - 2) is negative(x - 3) is positiveNEGATIVE

    x= 0

    (x - 1) is negative(x - 1) (x - 2) is positive(x - 2) is negativePOSITIVE

    (x 1) (x 2) is positive when x > 2 or x < 1

    1 2

    SOLVING QUADRATIC INEQUATIONS

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    x2 xor

    You cant say

    Lets f ind the interval

    wh ere x2is g reater than

    x

    WHICH ONE IS GREATER?

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    For what value of x ? x2 x 0 or(x) (x 1) 0

    Step 1: Change the inequality to an equation. Find value of x

    x = 0, 1

    x2x= 0

    Step 2: Plot the points

    0 1Step 3: Test point method

    0 1 At x = 2At x = 0.5At x = -1 +

    +

    0 1

    Step 4: Solution x > 1 or x < 0

    SOLUTION

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    You can solve some absolute-value equationsusing logics. For instance, you have learned

    that the equation |x| 8 has two solutions: 8and 8.

    SOLVING ABSOLUTE-VALUE EQUATIONS

    To solve absolute-value equations, you can use the fact

    that the expression inside the absolute value symbols

    can be either positive or negative.

    Because I X I = + X if X > 0- X If X < 0

    0 if X = 0

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    SOLVING AN ABSOLUTE-VALUE EQUATION

    Solve |x

    2 | 5

    x 2 IS POSITIVE|x 2 | 5

    x 7 x3

    x 2 IS NEGATIVE|x 2 | 5

    | 7 2 | | 5 | 5 | 3 2 | | 5 | 5

    The expressionx 2can be equal to5or5.

    x 2 5

    x 2 IS POSITIVE

    x 2 5

    Solve |x

    2 |

    5

    The expressionx 2 can be equal to 5 or5.SOLUTION

    x 2 5

    x 2 IS POSITIVE|x 2 | 5

    x 2 5

    x 7

    x2IS POSITIVE|x 2 | 5

    x 2 5

    x 7

    x 2 IS NEGATIVE

    x 2 5x3

    x2IS NEGATIVE|x 2 | 5

    x 2 5

    The equation has two solutions: 7 and 3.

    CHECK

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    Recall that xis the distance betweenx and 0. If x 8, thenany number between 8 and 8 is a solution of the inequality.

    8 7 6 5 4 3 2 1 0 1 2 3 4 5 6 7 8

    You can use the following properties to solve

    absolute-value inequalities and equations.

    Recall that |x | is the distance betweenx and 0. If |x | 8, thenany number between 8 and 8 is a solution of the inequality.

    Recall that | x | is the distance between xand 0. If | x | 8,then any number between 8 and 8 is a solution of theinequality.

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    SOLVING ABSOLUTE-VALUE EQUATIONS AND INEQUALITIES

    ax b c and ax b c.

    ax b

    c and ax

    b

    c.

    ax b c or ax b c.

    ax b c or ax b c.

    ax b c or ax b c.

    | ax b | c

    |ax

    b

    |

    c

    | ax b | c

    | ax b | c

    | ax b | c

    means

    means

    means

    means

    means

    means

    means

    means

    means

    means

    When an absolute value is less thana number, theinequalities are connected by and. When an absolute

    value is greater thana number, the inequalities are

    connected by or.

    SOLVING ABSOLUTE-VALUE INEQUALITIES

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    Solve |x

    4| < 3

    x 4 IS POSITIVE x 4 IS NEGATIVE|x 4| 3

    x 4 3x 7

    |x 4| 3

    x 4 3x 1

    Reverseinequality symbol.

    This can be written as 1 x 7.

    The solution is all real numbers greater than 1 andless than 7.

    EXAMPLE

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    2x 1 9

    | 2x 1 |3 6

    | 2x 1 | 9

    2x10

    2x+ 1 IS NEGATIVE

    x5

    Solve | 2x 1| 3 6 and graph the solution.

    | 2x 1 |3 6

    | 2x 1 | 9

    2x 1 +9

    2x 8

    2x+ 1 IS POSITIVE

    x 4

    SOLVING AN ABSOLUTE-VALUE INEQUALITY

    Reverse

    inequality symbol.

    | 2x 1 |3 6

    | 2x 1 | 9

    2x 1 +9

    x 4

    2x 8

    | 2x 1 |3 6

    | 2x 1 | 9

    2x 1 9

    2x10

    x5

    2x+ 1 IS POSITIVE 2x+ 1 IS NEGATIVE

    6 5 4 3 2 1 0 1 2 3 4 5 6

    The solution is all real numbers greater than or equal

    to4or

    less than or equal to5

    . This can be written asthe compound inequality x5orx 4.5 4.

    SOLVING THE INEQUALITIES WITH

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    SOLVING THE INEQUALITIES WITH

    THE HELP OF OPTIONS

    We can solve all the inequality questions by going with theoptions.

    Take an example:

    x2 7x + 10 < 0

    (1) X < 2 (2) x > 5 (3) x < 5

    (4) 2 < x < 5 (5) Both (1) and (2)

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    SOLUTION

    Since the first option is x < 2, we take x = 1 and check whether

    the given inequality is satisfying or not.

    If x = 1, 12 7(1) + 10 < 0

    4 < 0 (wrong)

    Option (1), (3) and (5) are wrong.

    Now take x = 6,

    62 7 6 + 10 < 0

    4 < 0 (wrong)

    So, option (2) is wrong.

    So, the answer is (4).

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    EXAMPLE

    If |x 3| > 2, which will be greater?Column A Column B

    |x| 2

    |x 3| > 2 means x > 5 or x < 1

    If x > 5, |x| > 2

    But if x < 1, we cant say

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