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7/28/2019 t 4 Solutions
1/2
MATH 3705B
Test 4 Solutions
March 19, 2012
Questions 1-2 are multiple choice. Circle the correct answer. Only the answer will be marked.Marks]
1. The solution of Laplaces equation urr +1
r
ur +1
r
2u = 0 inside the circle r = 2 has the form5]
u(r, ) =a0
2+
n=1
rn[an cos(n) + bn sin(n)].
The solution which satisfies the boundary condition u(2, ) = 2cos(3)+2 sin(2) is u(r, ) =
(a) 2 8r3 cos(3) + 2r2 sin(2) (b) 2 r3 cos(3) + 2r2 sin(2)
(c) 2 cos(3) + 2 sin(2) (d) 21
8r3 cos(3) +
1
2r2 sin(2) (e) None of these
Answer: (d)
2. The bounded solution of Laplaces equation urr +1
rur +
1
r2u = 0 outside the circle r = 25]
has the form
u(r, ) =a0
2+
n=1
rn[an cos(n) + bn sin(n)].
The solution which satisfies the boundary condition u(2, ) = 3 cos(2) 2 sin(3) is u(r, ) =
(a) 12r2 cos(2) 16r3 sin(3) (b) 3r2 cos(2) 2r3 sin(3)
(c) 34
r2 cos(2) 14
r3 sin(3) (d) 3 cos(2) 2 sin(3) (e) None of these
Answer: (a)
3. The solution of Laplaces equation uxx + uyy = 0, 0 < x < L, 0 < y < M, satisfying the10]boundary conditions u(x, 0) = 0, u(x, M) = 0, u(0, y) = 0, u(L, y) = f(y), has the form
u(x, y) =n=1
an sinhnx
M
sin
nyM
.
Find the solution of Laplaces equation uxx + uyy = 0 within the rectangle 0 < x < 2
0 < y < 1, which satisfies the boundary conditions u(x, 0) = 0, u(x, 1) = 0, u(0, y) = 0u(2, y) = y y2. Write down the complete solution u(x, y).
Solution:
u(x, y) =n=1
an sinh(nx)sin(ny) and u(2, y) = y y2
y y2 =n=1
an sinh(2n)sin(ny)
7/28/2019 t 4 Solutions
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2
an sinh(2n) = 2
1
0
(y y2) sin(ny)dy
= 2
n(y y2) cos(ny)
10
+2
n
1
0
(1 2y) cos(ny)dy
=2
n22(1 2y)sin(ny)
1
0
2
n22
1
0
2 sin(ny)dy
= 4
n33cos(ny)
1
0
=4
n33[1 (1)n]
u(x, y) =n=1
4[1 (1)n]
n33 sinh(2n)sinh(nx) sin(ny).
4. The solution of Laplaces equation uxx + uyy = 0, 0 < x < L, 0 < y < M, satisfying the10]boundary conditions u(x, 0) = f(x), u(x, M) = 0, u(0, y) = 0, u(L, y) = 0, has the form
u(x, y) =
n=1
an sinhn(M y)
L sin
nx
L .
Find the solution of Laplaces equation uxx + uyy = 0 within the rectangle 0 < x < 20 < y < 1, which satisfies the boundary conditions u(x, 1) = 0, u(0, y) = 0, u(2, y) = 0u(x, 0) = 3 sin(x) 2 sin(3x). Write down the complete solution u(x, y).
Solution:
u(x, y) =
n=1
an sinh
n(1 y)
2
sin
nx2
and u(x, 0) = 3 sin(x) 2 sin(3x)
3sin(x) 2 sin(3x) =n=1
an sinh
n2
sin
nx
2
a2 sinh() = 3, a6 sinh(3) = 2, an = 0 for n = 2, 6. Hence,
u(x, y) =3
sinh()sinh[(1 y)] sin(x)
2
sinh(3)sinh[3(1 y)] sin(3x).