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Smith College, EGR 325 April 3, 2018
Synchronous Generators Overview Generating 3-phase power
‘Field’ winding on rotor to energize with DC current
Equivalent circuit and phasor diagrams
Connecting to a power grid The power system as an “infinite bus”
Maximum power transfer Power system dynamics Maintaining synchronism
2
Small Synchronous Machine
Small Synchronous Machine
3
4
Synchronous Generator Operation Discuss at tables, to explain how a synchronous generator works.
Start with knowledge of inputs and outputs Input: Mechanical power, electrical DC voltage Output: 3 phase electrical power
Discuss where/how each input is connected
Output – from where?
Electromagnetics à explain
What is the ‘synchronous’ speed?
5
Conceptual Objective for Today Determine a simple representation of the maximum power that a generator can deliver (we already know this?) a) Generator Pmax limit? b) Thermal (melting point) limit of line? c) Dynamics of what the system can support in order to
maintain synchronism How much power can the generator be expected to supply before it essentially ‘stalls’ A function of the generator and the power system
N
S
Ia
Ib
Ic
φf
ωs
Armature windings – on the stator, induced current Field windings – on the rotor, energized by a DC input voltage (to get current)
6
Rotating rotor induces currents in
stator windings, of
what waveform?
N
S
Ia
Ib
Ic
φf
ωs
Time
Vaa’ Vbb’ Vcc’ X
X c
b ́a
X c ́
b
N
S
φf ωs
3 Stator Windings (“pole pairs”)
a’
7
View of a Single Phase φ f
ω s E f
N
S
I f
V f tdd
~E ff
φ
Ø If is energized by an external circuit, creates the ‘moving charges’ Ø Ef is directly proportional to the excitation current If (rotor windings) Ø The frequency of Ef is proportional to the synchronous speed ωs Ø Ef exists because the rotor is energized and is rotating…
Generator Equivalent Circuit
Ø Ef represents the rotor so we do not need to draw the rotor in the circuit model Ø Subscript f = ‘field’ with If supplied from external DC source
I a
X s
E f V t
Vt is the power system, an “Infinite Bus”
Ef is function of If Magnitude and phase of Ia are dependant variables
8
Generator Equivalent Circuit
satf XIVE +=
V t
I a X s
I a θ
E f δ I a
X s
E f V t
(Phasor for IaXs is 90° shifted from the phasor for Ia)
Two Angles (differences): • θ = θ__ – θ__ = power factor angle • δ = δ__ – δ__ = “power angle”
Power Calculations: S = VI*
θsinIVQ att 3=
θcosIVP at3=
Ia
Xs
Ef Vt
Ia
Vt
Ef
Ia Xs
θ
δ
Vt and Ef are phase quantities (see ‘side trip’ at end of slides)
f t
9
* Real Power Transfer Calculation *
δθ sinEcosXI fsa =
s
fa X
sinEcosI
δθ =
δsinXEV3
Ps
ft=
θcosIV3P at=
θ
Ia
Vt
Ef
Ia Xs
θ
δ
Observe from the phasor diagram:
New method to obtain previous equation
Power Characteristics of Generator
δsinXEV3
Ps
ft=
P
δ
Pmax
δl 90o
s
ft
XEV
P3
max =
10
Generator Connected to Power System
Pm G
Xs
Infinite bus
Vt Infinite Bus: • = The entire power system • Constant Voltage • Constant Frequency
Connection Through a Transmission Line…
Pm Xl GXs Vt Vo Ia
I a Xs
Ef Xl
Vt Vo
δsinXEV3
Ps
ft=
P
δ
Pmax
δl 90o
11
Reactive Power Calculation
tfsa VEXI −= δθ cossin
θsin3 att IVQ =
Ia
Xs
Ef Vt
Ia
Vt
Ef
Ia Xs
θ
δ
Vt and Ef are phase quantities
f t
€
Qt = 3Vt Ia sin θ =3VtXs
E f cosδ − Vt( )€
Qt = 3Vt Ia sin θ
€
Ia Xs sin θ = Ef cosδ − Vt
If Ef cos δ > Vt ; Qt is positive and Current is lagging
If Ef cos δ < Vt ; Qt is negative and Current is leading
If Ef cos δ = Vt ; Qt is zero and Current is in phase
Reactive Power: Can be Negative
1)
2) 3)
12
Example A (3-phase) synchronous generator is connected to
an infinite bus. The terminal voltage of the generator is 5 kV The equivalent field voltage is 4.8 kV. The synchronous reactance of the generator is 10 Ω.
Compute the maximum power the generator can deliver before it will be pulled out of synchronism
Solution
Ia
Xs
Ef Vt
13
Solution
P = 3Vt E f
Xs
sinδ P
P
δ
Pmax
δl 90o
Pmax = 3Vt E f
Xs
=3*5 (4.8)10
=7.2MW
Phase values Line-to-line
P
P
δ
Pmax
δl 90o
14
Maximum Power Delivery
P =Vt E f
Xs
sinδI a
X s
E f V t
P
P
δ
Pmax
δl 90o
Power Angle
satf XIVE +=
V t
I a X s
I a θ
E f δ
Two Important Angles: • θ = θ__ – θ__ = power factor angle • δ = δ__ – δ__ = “power angle”
I a
X s
E f V t
15
Mid-way Recap of Concepts From circuits, EGR 220
Power factor, power factor angle, θ
From previous slides Power angle, δ Maximum power transfer depends upon ___?
Infinite bus representing the rest of the power system The actual total mass of all rotating rotors
Real power, P vs. reactive power, Q Possible values? < 0? > 0? Interpretation of above (< or >0)
Synchronous Generators 1) Understand how mechanical power is converted
into electrical power
2) Understand maximum power transfer How the limit on power delivered to the grid is
determined.
3) Dynamics – the affect of load increase and decrease on the generator speed (and the system frequency)
16
Real Power – Frequency P and f dynamics are coupled
Demand > Supply: frequency will decrease (more energy drained from system than produced, acts like brakes on the turbines)
Supply > Demand: frequency will increase (more energy in the power system than consumed, acts like an accelerator so turbines spin faster)
Generation-based frequency regulation Generator inertia Generator governors
Real Power – Frequency
An increase/decrease in load causes the generator rotation to ____________? (increase/decrease)
The angular frequency of the generator is the frequency (or multiple) of the electricity generated.
Mechanical Turbine Electrical Power Load/Demand
17
Renewables and Power Balance
The net load variability with wind and solar variability directly affects the grid frequency, and can harm load motors
Mechanical Turbine Electrical Power Load/Demand
Power Angle à Springs Analogy First example: Springs
Twisting a stiff spring vs. a weak spring and notice the relative angular position of both ends
Restoring force returns it to its resting position If you twist too far, it cannot return à “loss of synchronism”
Second example: Hand generators Relative angular position of shaft Before and after a disturbance
A deceleration or an acceleration An imbalance of PM and PE
Power angle Angular position of the generator rotors, (Relative to a rotating synchronous position) Angular position of rotor (mechanical angle) = phase angle of voltage phasor (electrical
angle) = power angle
18
Power Angle Generators rotate with angular velocity ωm
This is the angular velocity of the ‘rotor’
δm = rotor angular position with respect to a synchronously rotating reference
δm is the power angle
This is also the phase angle of the voltage phasor
The mechanical angle is the electrical angle Coupling of the electro-mechanical system
Power Delivered Across a Line This mechanical angle is the electrical phase Ø Coupling of the electro-mechanical system
What is the role of this “power angle?” We know Z (X) is a fixed parameter. Goal of good system operations is to keep|Vi|, voltage
magnitude, nearly constant
This means that δ is what we change in order to change real power flow How does an operator change δ?
P =
V1 V2X
sinδ
19
Connection Through a Transmission Line…
Pm Xl GXs Vt Vo Ia
P =VtV0Xl
sinδ
P
P
δ
Pmax
δl 90o
Graphically: PM & PE vs. δ Assume a step change to PM changing mechanical
power from pm0 to pm1
GSO reading
20
Interpreting Dynamics In steady-state pe = pm = pm0 andδ = δ0
pe0 = pm0 = pmax sin(δ0)
A step change in pm from pm0 to pm1 occurs at time t = 0.
Due to rotor inertia, the rotor position cannot change instantaneously δ(0+) =δ(0-) = δ0
This means that electrical power output remains unchanged
pe(0+) = pe(0-)
Interpreting Dynamics But pm(0+) = pm1
Mechanical power (energy) has changed
This means that pm(0+) > pe(0+) i.e., supply > demand
So, there is a positive, momentary, acceleration of the rotor
The rotor accelerates and δ increases Recall δ is the angular difference between the rotor
positions at either end of the lines (as well as the difference in their voltage phase angles)
Until pe = pm1 at point δ= δ1
21
To Increase Power Delivery
P =VtV0Xl
sinδ
Pm Xl GXs Vt Vo Ia
Assume a sudden change to PM changing mechanical power from Pm0 to Pm1
Pm < Pe = area below curve
Pm > Pe = area above curve
22
Dynamics Steady-state, point a
Pm0 = Pe0 = Pmax sin(δ0)
Suddenly, Pm increases! Perhaps a steam valve was opened This causes the rotor speed to increase
Accelerating power, Pa = Pm1 – Pe This causes the rotor speed and rotor angle to increase, momentarily
With an increase in δ, the power delivery also increases
P =VtV0Xl
sinδ
HW Question 1 A synchronous generator is connected to an
infinite bus through a transmission line. The infinite bus voltage is 15kV and the equivalent field voltage of the machine is 14kV. The transmission line inductive reactance is 4Ω, and the synchronous reactance of the machine is 5Ω. Compute the (power) transfer capability of the system. If a 2Ω capacitor is connected in series with the
transmission line, compute the new capacity of the system.
23
HW Question 2 A 100 MVA synchronous generator is connected to a 25kV
infinite bus through two parallel transmission lines.
The synchronous reactance of the generator is 2.5Ω, and the inductive reactance of each transmission line is 2Ω.
The generator delivers 100 MVA to the infinite bus at 0.8 power factor lagging.
Suppose a lightning strike causes one of the transmission lines to open. Assume that the mechanical power and excitation of the generator are unchanged.
Can the generator still deliver the same amount of power to the infinite bus?
A disturbance can also be loss of a Tx line – changing ‘Xeq’ – changing Pmax – changing the curve itself
24
Renewables and Power Balance
The net load variability with wind and solar variability directly affects the grid frequency, and can harm load motors
Mechanical Turbine Electrical Power Load/Demand
Restarting a System New Jersey and New York remained in electrical
blackout longer than expected.
Once all the transmission lines are reconnected, what do power system engineers need to do to be able to restart the system? They cannot simply start all the generators up separately
and say they are done – why not?
What can the power transfer equation tell us?
What can knowledge of reactive power, Q, tell us?
25
Summary Synchronous generators
P and Q Expressions Graphs (esp. Pmax) Phasor diagrams
Connecting to the power grid “Infinite bus” Power delivered to load
Dynamics – energy balance and effect on system frequency
Summary Power delivery into a power system
Role of the “power angle”
Power system dynamics Spring analogy Coupling of mechanical and electrical elements via the
power angle Loss of a transmission line Adding series compensation Variability of wind and solar power – maintaining
system energy balance Restarting a system after a blackout
26
X
X c
b ́a
X c ́
b a ́
SIDE TRIP: How is Three-Phase Connected?
X
X c
b ́a
X c ́
b a ́
Y-Connection (Wye)
27
X
X c
b ́a
X c ́
b a ́
Delta (Δ) Connection: Source
v ca v bc
v ab
v cn v bn v an
Phase vs. Line-Line Voltages
Phase Voltages Line Voltages
(generator)
(ground, or neutral)
Task: Draw the phasor diagrams for the phase voltages, and for the line-line voltages.
28
Phase voltage; Wye Connected
n
€
V an = V a = V∠0°V
v an
v bn
v cn
Reference
v cn v bn v an
n
c
b
a
a
c
b
€
V cn = V c = V∠120°V
€
V bn = V b = V∠−120°V
€
V bc = V bn −V cn = V∠−120°( )− V∠120°( ) = 3 V ∠− 90°
v ca v bc
v ab
n
c
b
a
Line-to-line voltage; Delta connection
€
V ab = V an −V bn = V∠0°( )− V∠−120°( ) = 3 V ∠30°
€
V ca = V cn −V an = V∠120°( )− V∠0°( ) = 3 V ∠150°
Reference
v ab
v ca
v bc
030
v bn
b
n v an
a
v cn
c
Unless stated otherwise: All voltages are line-to-line quantities
29
Connections: “Delta” or “Wye”
Source Load Transmission Line
a
c b
Z
Z Z
I a
I b
I c
V ca
a
b c
n V ab
I a
V bc I c
I b
Iab +
-
Line current
Phase current
Ica
Ibc
Phase current
Objective of “Side Trip”
To be familiar with: Wye and delta connections “Phase” voltage versus line-line voltage To understand the factor of √3
30
Using Equations and Data Phase to ground, vs. line to line voltages:
Be careful with phase vs. line-line values Line-line given in problem Values often for a single phase
Note that the current in the transmission line is a function of the power angle, δ. Find δ Find Ia = (Ef – V0)/X Find Vt = V0 + IaXl
The line-line Vt = √3 Vt-ph