Symmetry analysis of Generalized Burger's equation

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    Symmetry Analysis of GeneralizedBurgers Equation

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    Chapter I

    Introduction

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    1.1 Introduction

    The Partial differential equations (PDEs) arising in many physical fields like the

    condense matter physics, fluid Mechanics, physics and optics, etc. which exhibit a

    rich variety of non linear phenomena. When the inhomogenetics of media and non-

    uniformity of boundaries are taken into account in various physical situations, the

    variable coefficient PDEs often can provide more powerful and realistic molds than

    their constant- coefficient counterparts in describing a large variety of real phenomena.

    It is known that to find exact solutions of the PDEs is always one of the central themes

    of Mathematics and Physics. In the last few decades, remarkable progress has been

    made in understanding the integrability and non-integrability of nonlinear partial

    differential equations.

    The motivation for the present thesis comes from the work on the GBE with

    variable viscosity

    ut + uux =(t)

    2uxx, (1.1)

    by Doyle and Englefield (1990). They arrived at (1.1) by considering an application

    of the Burgers equation

    ut + uux =

    2uxx, (1.2)

    in the formation and decay of nonplane shock waves. In (1.2) x is a coordinate moving

    with the wave at the speed of sound and u is the velocity fluctuations. The coefficient

    of uxx, which allows for viscosity, is approximated by a constant in (1.2), but is

    in reality a function of the time t (Lighthill (1956)), say, (t). Doyle and Englefield

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    (1990) by using the method for defining an optimal system of group-invariant solutions

    (Olver (1986)) showed that (t) satisfies the first order equation

    =

    c1 + c2c3t2 + (c1 c2)t + c4 , (1.3)

    and obtained the following five distinct expressions for (t) by setting certain of the

    constants ci equal to zero:

    1(t) = et, (1.4)

    2(t) = e1/t, (1.5)

    3(t) = (t + )r, (1.6)

    4(t) =

    t +

    t +

    r, = 0 = , (1.7)

    5(t) = exp2tan1(t + )

    . (1.8)

    Sachdev, Nair and Tikekar (1988) through u = (1+ t)(1n)/2

    (1+n)/2(1n)

    f(), =

    1/2(1 + t)(1n)/2x reduced another GBE

    ut + u(1n)/(1+n)ux =

    2(1 + t)nuxx, (1.9)

    to

    f 2f(1n)/(1+n)f + (n + 1)(f + f) = 0, (1.10)

    for which an exact solution in terms of an error function is obtained in a manner

    described below: Equation (1.10) is integrated once under the conditions f and f

    vanish as to give

    f (1 + n)f2/(1+n) + (1 + n)f = 0, (1.11)

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    which is once again integrated to yield the solution f = e(1+n)2/2[h()](1+n)/(1n),

    where h() = [f(0)](1n)/(1+n) 2(1 n)erf[1n2

    ]. Doyle and Engelfield (1990)

    observed that equation (1.11) being the Bernoullis equation can be converted to a

    linear equation and therefore solved in terms of an error function. The forms (1.4)-

    (1.8) included those of Scott (1981a) and Sachdev, Nair and Tikekar (1988) as special

    cases.

    Mayil Vaganan (1994) employed the direct method to derive the similarity reduc-

    tions of the Burgers equation as well as its generalizations

    ut + uux +ju

    2t= uxx, (1.12)

    ut + u2ux +

    ju

    2t= uxx, (1.13)

    ut + u2ux = uxx, (1.14)

    ut + uux + f(x, t) = g(t)uxx, (1.15)

    ut + uux + f(t)u

    = g(t)uxx. (1.16)

    The Burgers equation (1.2) is introduced by Batman (1915). Equation (1.2) is

    in fact a special case of mathematical models of turbulance (Burgers (1939, 1940)).

    A similarity solution in the form u(x, t) = t1/2S(z), z(x, t) = x/

    2t, where S(z)

    satisfies a Riccati equation is obtained by Burgers (1950). Hopf (1950) and Cole

    (1951) linearized the Burgers equation (1.2) through the Cole-Hopf transformation

    u = x/ to the heat equation t = (/2)xx.

    Now we describe some important works on the GBEs: Lardner and Arya (1980)

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    obtained matched asymptotic solutions of the Burgers equation with linear damping

    ut + uux + u =

    2

    uxx, (1.17)

    under the constraint that the shock is thin. They have also considered an extended

    form of (1.17) in which the coefficient ofux is p0u + q0u2 + r0c(t), where p0, q0 and r0

    are constants. The very presence ofu in (1.17) is due to the fact that the equation of

    motion includes a small viscous damping term proportional to the velocity (Crighton

    (1979)). The N-wave solutions for (1.17) are obtained by Sachdev and Joseph (1994).

    Asymptotic solutions to the modified Burgers equation

    ut + u2ux = uxx, (1.18)

    with two initial disturbances, namely, N-wave and sinusoid, for small values of the

    dissipation coefficient are derived by Lee-Bapty and Crighton (1987).

    Lighthill (1956) and Leibovich and Seebass (1974) derived the nonplanar Burgers

    equation

    ut + uux +ju

    2t=

    2uxx, (1.19)

    where 0 < < 1 are constants and j = 0, 1, 2 to describe the propagation of weakly

    nonlinear longitudinal waves in gases or liquids from a non planar source. Sachdev,

    Joseph and Nair (1994) have given an exact N-wave solutions for (1.19).

    The GBE describing the progressive waves with cylindrical symmetry j = 1 or

    spherical symmetry j = 2 is

    vx + vv j2x

    v = v. (1.20)

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    The existence of an exact solution of the form x1/2v(x, ) = (x/2) to (1.20) is first

    noted by Chong and Sirovich (1973) and subsequently Rudenko and Soluyan (1977)

    provided the closed form expression for . Sinai (1976) found the the profile of the

    axisymmetric body which gives rise to a similarity solution in the steady supersonic

    flow problem governed by an equation of the form (1.20).

    Grundy, Sachdev and Dawson (1994) obtained large time solutions of an initial

    value problem (IVP) for a GBE:

    ut + (u+1)x +

    ju

    2t= uxx, u(x, 1) = u1(x). (1.21)

    Sachdev and his collobarators (1986, 1987, 1988) by inserting the self-similar form

    u = tpf(), = x/

    t into the GBEs

    ut + uux + u

    =

    2uxx, (1.22)

    ut + uux +

    ju

    2t=

    2uxx, (1.23)

    ut + uux =

    2g(t)uxx, (1.24)

    obtained equations for f() in the form

    f a1fqf + a2f + a3fr = 0, (1.25)

    which is transformed through H() = fq to an equation of the form

    HH + aH2

    + f()HH + g()H2 + bH + c = 0, (1.26)

    which they called the Euler-Painleve transcendent (EPT). Here f() and g() are

    arbitrary functions and a,b,c are real constants. Equation (1.26) extends the class

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    of nonlinear ordinary differential equations (ODEs) studied by Euler and Painleve

    (Kamke (1943)) for which b = c = 0. Equation (1.26) with b = c = 0 is exactly

    linearizable to

    v + f v + (a + 1)gv = 0, (1.27)

    through H = v1

    a+1 . It has been established that for the Burgers equation and its

    generalizations b = 0 and therefore (1.26) is, in general, not linearizable.

    Recently Rao, Sachdev and Mythily Ramaswamy (2001, 2002, 2003) obtained the

    self-similar reductions of the GBEs (1.22), (1.23) and investigated them in detail

    for positive single-hump, monotonic (bounded or unbounded) solutions and also for

    solutions with a finite zero by assuming certain asymptotic conditions at .

    The following GBE

    ut + unux +

    j2t +

    u +

    + x

    un+1 = 2 uxx, (1.28)

    has been studied for N-wave solutions by Sachdev, Joseph and Mayil Vaganan (1996)

    and for similarity solutions by Mayil Vaganan and Asokan (2003).

    We now list below the GBEs which are studied in this project:

    ut + f(t)uux + l(t)u + g(t)uxx = 0, (1.29)

    ut + unux =

    (t)

    2uxx, (1.30)

    ut + unux(

    j

    2t+ )u + (+

    xun+1) =

    (t)

    2uxt, (1.31)

    where f(t), g(t) and l(t) are variable coefficients, n is a positive integer.

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    The structure of the thesis is arranged as follows. In chapter 2, the Painleve

    test is extended to equation (1.29) in order to obtain the constraints on the variable

    coefficients for it to possess the Painleve property. In chapter 3, auto-Backlund trans-

    formation is presented via the truncated Painleve expansion, also analytic solutions

    are obtained. In chapter 4 the generalized burgers equation is linearized to the heat

    equation under the generalized Cole-Hopf transformation.

    References

    1. Bianchi, L. Lezioni sulla teoria dei gruppi continui finiti di trasformazioni. Pisa:

    Spoerri, 1918.

    2. Bluman, G. W. and Cole, J. D. The general similarity solution of the heat

    equation, J. Math. Mech. 18: 1025 - 1042 (1969).

    3. Bluman, G. W. and Cole, J. D. Similarity methods for Differential Equations.

    Applied Mathematical Sciences No. 13, Springer-Verlag, New York, 1974.

    4. Bluman, G. W. and Kumei, S. Symmetries and Differential Equations. Springer-

    Verlag, New York, 1989.

    5. Bluman, G. W. and Anco, S. C. Symmetries and Integration methods for Dif-

    ferential Equations, Applied Mathematical Sciences, No. 154, Spriner-Verlag,

    New York, 2002.

    6. Burgers, J. M. Mathematical examples illustrating relations occuring in the

    9

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    theory of turbulent for motion, Trans. Roy. Neth. Acad. Sci. 17: 1 - 53

    (1939).

    7. Burgers, J. M. Application of a model system to illustrate some points of the

    statistical theory of free turbulence, Proc. Roy. Neth. Acad. Sci. 43: 2 - 12

    (1940).

    8. Burgers, J. M. The formation of vortex sheets in a simplified type of turbulent

    motion, Proc. Roy. Neth. Acad. Sci. 53: 122 - 133 (1950).

    9. Chong, T. H. and Sirovich, L. Nonlinear effects in steady supersonic dissipative

    gasdynamics - II. Three dimensional axisymmetric flow, J. Fluid Mech. 58: 53

    - 63 (1973).

    10. Chowdhury, A. R. and Naskar, M. J. Phys. A: Math. Gen. 19: 1775 - 1781

    (1986).

    11. Cole, J. D. On a quasi-linear parabolic equation occurring in aerodynamics,

    Quart. Appl. Math. 9: 225 - 236 (1951).

    12. Doyle, J. and Englefield, J. Similarity solutions of a generalized Burgers equa-

    tion, IMA J. Appl. Math. 44: 145 - 153 (1990).

    13. Grundy, R. E., Sachdev, P. L. and Dawson, C. N. Large time solution of an

    initial value problem for a generalised Burgers equation, Nonlinear Diffusion

    Phenomenon.(Eds: P. L. Sachdev and R. E. Grundy) pp.68-83. Narosa Pub-

    lishing House, New Delhi, 1994.

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    14. Gungor, F. Symmetries and invariant solutions of the two-dimensional variable

    coefficient Burgers equation, J. Phys. A: Math. Gen. 34: 4313 - 4321 (2001).

    15. Hopf, E. The partial differential equation ut + uux = uxx, Commun. Pure Appl.

    Math. 3: 201 - 230 (1950).

    16. Ibragimov, N. H. CRC Hand Book of Analysis of Differential Equations, Exact

    Solutions and Conservation Laws, CRC Press, New York, 1994.

    17. Kalyani, R. Some solutions of Burgers equation, J. Maths. Phys. Sci. 5: 109 -

    120 (1971).

    18. Kamke, E. Differential gleichungen: Losungsmethoden and Losungen, Akademis-

    che Verlagagesellschaft, Leipzig, 1943.

    19. Kuznetsov, V. P. Soviet Phys. Acoust. 16: 467 - 470 (1971).

    20. Lee-Bapty, I. P. and Crighton, D. G. Nonlinear wave motion governed by the

    modified Burgers equation, Phil. Trans. R. Soc. Lond. A 323: 173 - 209

    (1987).

    21. Lighthill, M. J. Viscosity effects in sound waves of finite amplitude. Surveys

    in Mechanics (Eds. G. K. Batchelor and R. M. Davies) Cambridge University

    Press, pp. 250 - 351 (1956). .

    22. Mayil Vaganan, B. Exact Analytic Solutions for some classes of partial differ-

    ential equations, Ph. D. Thesis, Indian Institute of Science, Banglore, India,

    1994.

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    23. Mayil Vaganan, B. and Asokan, R. Direct Similarity Analysis of Generalized

    Burgers Equations and Perturbation Solutions of Euler-Painleve Transcendents,

    Stud. Appl. Math. 111(4): 435 - 451 (2003).

    24. Olver, P. J. Symmetry groups and group invariant solutions of partial differential

    equations, J. Diff. Geom. 14: 497 - 542 (1979).

    25. Olver, P. J. Applications of Lie Groups to Differential Equations. Graduate

    Text in Mathematics No. 107, Springer-Verlag, New York, 1986.

    26. Rudenko, O. V. and Soluyan, S. I. Theoretical foundations of nonlinear acoustics

    (English translation by R. T. Beyer), New York, Consultants Bureau (Plenum),

    1977.

    27. Schwarz, F. J. Phys. A: Math. Gen. 20: 1613 - 1614 (1987).

    28. Sinai, Y. L. Similarity solution of the axisymmetric Burgers equation, Phys.

    Fluids, 19: 1059 - 1060 (1976).

    29. Srinivasa Rao, Ch., Sachdev, P. L. and Mythily Ramasamy Analysis of self

    similar solutions of a generalized Burgers equation with nonlinear damping,

    Math. Problems Eng. 7: 253 - 282 (2001).

    30. Srinivasa Rao, Ch., Sachdev, P. L. and Mythily Ramasamy Analysis of the self

    similar solutions of the non-planar Burgers equation, Nonlinear Analysis 51:

    1447 - 1472 (2002).

    12

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    31. Srinivasa Rao, Ch., Sachdev, P. L. and Mythily Ramasamy Self-similar solutions

    of a generalized Burgers equation with nonlinear damping, Nonlinear Analysis:

    Real World Applications 4: 723 - 741 (2003).

    32. Steven Nerney, Edward J. Schmahl and Musielak, Z. E. Analytic solutions of

    the vector Burgers equation, Quart. Appl. Math. 1: 63 - 71 (1996).

    33. Tajiri, M., Kawamoto, S. and Thushima, K. Reduction of Burgerrs equation to

    Riccati equation, Math. Japon. 28: 125 - 133 (1983).

    34. Taylor, G. I. The conditions necessary for discontinuous motion in gases, Proc.

    R. Soc. Lond. A 84: 371 - 377 (1910).

    35. Webb, G. M. and Zank, G. P. Painleve analysis of the two dimensional Burgers

    equation, J. Phys. A: Math. Gen. 23: 5465 - 5477 (1990).

    36. Zabolotskaya, E. A. and Kholohlov, R. V. Sov. Phys. Acoust. 15: 35 - 40

    (1969).

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    Chapter II

    Painleve Analysis of Generalized Burg-ers Equation

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    2.1 Introduction

    Nowadays, a wide class of nonlinear evolution equations (NLEEs) has been derived

    to describe a variety of nonlinear wave phenomena in different physical contests,

    including nonlinear optics, hydrodynamics, condensed matter, plasma physics and

    quantum field theory. The study of integrable models continues to attract much

    attention from many mathematicians and physicists.

    The painleve property for ordinary differential equations is defined as follows.

    The solutions of a sytem of ordinary differential equations are regarded as (analytic)

    functions of a complex (time) variable. The movable singularities of the solution

    (as a function of complex t) whose location depends on the initial conditions and

    are, hence movable. Fixed singularities occur at points where the coefficients of the

    equation are singular. The system is said to possess the Painleve property when all

    the movable singularities are single valued.

    Experience has shown that, when a system possess the Painleve property, the

    system will be Integrable. Albowitz have proven that when a partial differential

    equation is solvable by the inverse scattering transform and a system of ordinary

    differential equation is obtained from this pde by an exact similarity reduction then

    the solution associated with the Gelfand-Levitan-Marchenko equation will possess

    the Painleve property. Furthermore, they conjecture that, when all the odes obtained

    by exact similarity transforms from a given pde have the Painleve property, perhaps

    after a change of variables,then the pde will be integrable. In another context

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    Chudnovsky has observed that a certain pde which arises a compatabality condition

    in a generalization of the theory of Isomonodromy. Deformation is meromorphic [in

    (x, t)].It is somewhat remarkable that a connection between integrability and the

    Painleve property has been noted since the work of Kowalevskaya, and, as of yet, the

    precise equivalence of these concepts remains to be determined.

    In this chapter we define a Painleve property for partial differential equations

    that does not refer to that for ordinary differential equations.Indeed, we believe that

    by extending the definition of the Painleve property it is possible to treat the phe-

    nomenon of integrable behaviour in a unified manner. For the past few years, several

    inhomogeneous NPDEs (INPDEs) have been studied from the soliton point of view.

    This chapter is devoted to study the generalized Burgers equation

    ut + f(t)uux + g(t)uxxx + l(t)u = 0, (2.1)

    where f(t), g(t) and l(t) are time dependent coefficients.

    Equation (2.1) arises in various areas of Mathematical Physics and Nonlinear

    Dynamics.

    2.2 Painleve Property

    One major difference between analytic functions of one complex variable and analytic

    functions of several complex variables cannot be isolated. If f = f(z1,...,zn) is a

    meromorphic function of N complex variable (2N real variables), the singularities of

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    f occur along analytic manifolds of dimension 2N-2. These manifolds are determined

    by conditions of the form

    (z1,...,zn) = 0 (2.2)

    where is an analytic function of in a neighbourhood of the manifold. Therefore, we

    say that a pde has the Painleve property when the solutions of the pde are single-

    valued about the movable, singularity manifold. To be precise, if the singulariy

    manifold is determined by (2.1) and u = u(z1,...,zn) is a solution of the pde, then we

    assume that

    u = u(z1,...,zn) =

    j=0

    ujj (2.3)

    where

    = (z1,...,zn)

    and

    uj = uj(z1,...,zn)

    are analytic functions of (z1,...,zn) in a neighbourhood of the manifold (2.1) , and

    is an integer.Substituting (2.2) into the pde determines the possible values of and

    defines the recursion relations for uj , j = 0, 1, 2,.... The process is analogous to that

    for ordinary differential equations.

    2.3 Painleve Analysis for (2.1)

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    According to the method of Kurskal (1989), the solutions for (2.1) can be expanded

    interms of the Laurent series as follows.

    u(x, t) = (x, t)j=0

    j(x, t)uj , (2.4)

    where (x, t) = x + (t), uj(x, t) = uj(t) are analytic functions in a neighbourhood

    of (x, t) = 0, the non characteristic movable singularity manifold defined by u0 = 0

    and is a positive integer.

    Through the leading order analysis, we found that = 1 and

    u0 = 2g(t)

    f(t)x. (2.5)

    The recursion relations are found to be

    uj2,t + (j 2)uj1t + fj

    m=0

    ujm [um1,x + (m 1)xum] + g(t) [uj2,xx

    +2(j 2)uj1,xx + (j 2)xxuj1 + (j 1)(j 2)uj2

    x

    + l(t)uj2 = 0(2.6)

    Collecting terms involving uj, it is found that

    2x(j 2)(j + 1)uj = F(uj1,...,u0, t, x, xx,...)forj = 0, 1, 2,... (2.7)

    We note that the recursion relations (2.7) are not defined when j = 1, 2. These

    values of j are called the resonances of the recursion relation and correspond to

    points where arbitrary functions of (x, t) are introduced into the expansion. j = 1

    corresponds to the arbitrary singularity manifold ( = 0).On the other hand the

    resonance at j=2 introduces an arbitrary function u2 and a compatability condition

    on the functions (, u0, u1) that requires the right hand side of (2.7) vanish identically.

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    For Burgers equation,we find from (2.6)

    j = 0 u0 = 2g(t)

    f(t)

    x (2.8)

    j = 1 u1 = 1f x

    (t + gxx) (2.9)

    j = 2 u0,t + f(t)(uu0)x + g(t)u0,xx + l(t)u0 = 0 (2.10)

    Taking account of (2.8), (2.9) and (2.10)(which represents a compatibility condition

    since it involves already determined quantities) reduces to

    gft + l

    g

    f = 0 (2.11)

    from which it follows that equation (2.1) possesses the Painleve property if and only

    if

    g(t) = c1f(t)e

    l(t)dt. (2.12)

    2.4 Conclusions

    The variable-coefficient nonlinear evolution equations, although their coefficient func-

    tions often make the studies hard, are of current interests since they are able to

    describe the real situations in many fields of physical and engineering sciences. In

    this chapter we have considered a generalized Burgers equation containing arbitrary

    functions f(t), g(t) and l(t). The Painleve analysis leads to the explicit constraint

    on the variable coefficient on the variable coefficients for such a equation to pass the

    Painleve test.

    We have applied directly the PDE Painleve test to equation (2.1) and provided

    constrain (2.12) which is the necessary and sufficient condition for equation (2.1)

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    to have the Painleve property. Thus, equation (2.1) is predicted to be completely

    integrable if and only if the variable coefficients of equation (2.1) satisfy constraint

    (2.12).

    References

    1. J. Weiss, M. Tabor, G. Carnevale, The Painleve property for partial differential

    equations J. Math. Phys. 24 (1983) 522-526.

    2. J. Weiss, The Painleve property for partial differential equations, J. Math. Phys.

    24 (1983) 1405-1413.

    3. P. A. Clarkson, Painleve analysis and the complete integrability of a generalized

    variable-coefficient Kadomtsev-Petviashvili equation, IMA J. Appl. Math. 44

    (1990) 27-53

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    Chapter III

    Auto-Backlund transformation andExact Solutions of generalized Burg-ers equation

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    3.1 Introduction

    It has been shown that for the generalized Burgers equation of the form

    ut + uux + g(t)uxx. (3.1)

    which is a well established nonlinear equation for the study of acoustic and shock

    waves. Backlund transformations exist only if g(t) is constant when (3.1) reduces to

    the ordinary Burgers equation. The equation has not been solved for non-constant

    a(t). However, Doyle and Englefield(1990) have found that similarity solutions of

    (3.1) for specific g(t), (i.e). et or e1/t for which is infinitesimal invariant transfoma-

    tions exist. Later, Kington and Sophocleous(1991) have shown that in addition to the

    finite point transformation, a reciprocal point transformation as well as transforma-

    tions relating equations with different functions g(t) exist. In this work, we further

    generalize the equation (3.1)is of the form

    ut + f(t)uux + g(t)uxx + l(t)u = 0. (3.2)

    The generalized Burgers equation with the nonlinear f(t), damping term l(t) and

    dispersion term a(t) can model propagation of a long shock-wave in a two layer

    shallow liquid. Malomed and Shira(1991) have qualitatively demonstrated that for

    the special case of the GBE with g(t) = -1 a shock wave solution reverses its velocity

    and disintegrate after the passage of the critical point where f(t) changes its sign.

    However, any analytic solitary wave solutions for the GBE have not been found. In

    the following, we make use of both the truncated Painleve expansion and symbolic

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    computation method to obtain an auto-Backlund transformation and certain soliton-

    typed explicit solutions with some constraints between f(t) and g(t).

    A non-linear pde is said to possess the Painleve property when the solutions of

    the NPDE are single valued about the movable singularity manifold which is non-

    characteristic. To be more precise, if the singularity manifold is determined by

    (z1, z2,...,zn) = 0. (3.3)

    and u = u(z1, z2,...,zn) is a solution of the NPD, then it is required that

    u = j=0

    ujj (3.4)

    where u0 = 0, = (z1, z2,...,zn), uj = uj(z1, z2,...,zn) are analytic function of (zj)

    in a neighbourhood of the manifold and is a negative rational number. Substitution

    of equation(3.4) into the NPDE determines the allowed values of , and defines the

    recursion relation for uj, j=0,1,2,...When the equation (3.4) is correct, the NPDE is

    said to possess the Painleve property and is conjectured to be integrable.

    3.2 Auto-Backlund Transformation

    In order to find the solitonic solutions for equation (3.2), we truncate the Painleve

    expansion (3.4) at the constant-level term in the senses of Tian and Gao(1995) and

    Hong and Jung(1999)

    u(x, t) = j(x, t)jl=0

    ut(x, t)t(x, t). (3.5)

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    On balancing the highest-order contributions from the linear term (uxx) with the

    highest-order contributions from the nonlinear terms (uux), we get J = 1, so that

    u(x, t) =u0(x, t) + u1(x, t)(x, t)

    (x, t)(3.6)

    We will stay with the general assumption then x = 0 but will not initially impose

    any constraint on the model parameter g(t) and f(t). When substituting the above

    expression into (3.2), we let the coefficients of like powers of to vanish so as to get

    the set of Painleve- Backlund equations,

    3 : f(t)u20x + 2g(t)u02x = 0 (3.7)

    2 : f(t)u0u0,x f(t)u1u0x 2g(t)xu0, x g(t)u0xx u0t = 0. (3.8)

    1 : u0,t + b(t)u0u1,x + f(t)u1u0,x + g(t)u0,xx + lu0 = 0. (3.9)

    0 : u1,t + f(t)u1u1,x + g(t)u1,xx + iu1 = 0 (3.10)

    The set of equations (3.6)-(3.10)contitutes an auto-backlund transformation, if

    the set is solvable with respect to (x, t), u0(x, t) and u1(x, t). Equation (3.7) brings

    out two solutions:

    u0(x, t) =

    2g(t)(x)

    f(t) or u0(x, t) = 0 (3.11)

    After substituting the non trivial solution into (3.8), we obtain

    u1(x, t) = g(t)xx + txf(t)

    . (3.12)

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    Subsequently, we find the constraint equation for variable coefficients g(t) and f(t)

    from equation (3.9)

    g(t) = c1f(t)e

    l(t)dt (3.13)

    Where c1 is an arbitrary constant.Thus, we are able to find a family of exact analytic

    solutions to Eq.(3.2) as follows.

    u(x, t) = g(t)xx + txf(t)

    +

    2g(t)x

    f(t)

    (x, t)1 (3.14)

    with the constraint equation for (x, t) and g(t)

    22xg(t)txx + 2xg(t)tt 4txxg(t)2xx 2txxg(t)t

    ddt

    g(t)2xt 4g(t)3xxxxxx + 3g(t)33xx

    +4g(t)22xxt 2txg(t)2xxx

    +g(t)xx2

    t + g(t)3

    2

    xxxx + g(t)l2

    xt = 0 (3.15)

    we note that once a Backlund transformation discovered, and a set of seed solutions

    is given, one will be able to find an infinite number of solutions by the repeated

    applications of the transformation, (i.e.) to generate a heirarchy of solutions with

    increasing complexity. In the rest, we will find a family of exact analytic solutions to

    (3.2).

    Sample solution:

    (x, t) = 1 + e[A(t)x+B(t)] (3.16)

    Is subtituted into the constraint Eq.(3.15). Equating to zero the coefficients of

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    like powers of x yield

    x1 :ddt

    A(t) ddt

    a(t)

    a(t) d2

    dt2A(t) + 2

    ( ddt

    A(t))2

    A(t) lA(t) = 0 (3.17)

    x0 :ddt

    B(t) ddt

    a(t)

    a(t) d

    2

    dt2B(t) + 2

    ddt

    B(t) ddt

    A(t)

    A(t) lB (t) = 0 (3.18)

    By setting A(t) = e1t a a trial function to Eq.(3.17),we find an ordinary differ-

    ential equation for g(t) as

    d

    dta(t)1 + g(t)

    21 = 0

    g(t) = c2e

    1tel(t)dt (3.19)Finally, B(t) is obtained from Eq.(3.18) as

    B(t) = c4 +

    c5e1te

    l(t)dtdt (3.20)

    where ci are all non-zero arbitrary constants. Combining all terms, we find a family

    of the analytical solutions of Eq.(3.2) as

    u(x, t) = e1t

    c2c1

    c2e

    l(t)dt + 1xe

    2l(t)dt + c5e

    l(t)tl(t)dt

    +2

    c1e

    l(t)dt e[1t+e

    1tx+c5e1te

    l(t)dt

    dt+c4] 1(x, t) (3.21)

    References

    1. J. Doyle, M.J. Englefield, IMAJ Appl. Math. 44 (1990). 145.

    2. J.G. Kingston, C. Sophocleous, Phys. Lett. A 155 (1991). 15.

    3. N. Joshi, Phys. Lett. A 125 (1987). 456.

    4. W.P. Hong, Y.D. Jung, Phys. Lett. A 257 (1999). 149.

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    5. B.A. Malomed, V.I. Shrira, Physica D 53 (1991). 1.

    6. B. Tian, Y.T. Gao, Phys. Lett. A 209 (1995). 297.

    7. W.P. Hong, Nuovo Cimeto B 114 (1999). 845.

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    Chapter IV

    Exact Linearization of GeneralizedBurgers Equation via the General-ized Cole-Hopf Transformations

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    4.1 Introduction

    The search of exact solutions of nonlinear partial differential equations is of great

    importance, because these equations appear in complex physics phenomena, mechan-

    ics, chemistry, biology and engineering.

    In this chapter we obtain new solutions for the generalized Burgers equation

    ut + f(t)uux + g(t)uxx + l(t)u = 0, (3.22)

    Equation (3.22) is a generalization of the well-known Burgers equation(Burgers (1974))

    ut + uux = uxx. (3.23)

    Owing to the assumptions of the constant coefficients and unforced turbulence, the

    physical situations in which the classical Burgers equation arises tend to be highly

    idealized. In practice, the generalized Burgers equation (3.22) may provide us with

    more realistic models in many different physical contextslike the long-wave propaga-

    tion in an inhomogeneous two-layer shallow liquid, directed polymers in a random

    medium, pinning of vortex lines in superconductors etc.

    Harry Bateman(1915) considered a nonlinear equation whose steady solutions

    were thought to describe certain viscous flows. This equation, modeling a diffusive

    nonlinear wave, is now widely known as the Burgers equation, and is given by

    ut + uux = uxx. (3.24)

    where is a constant measuring the viscosity of the fluid. It is nonlinear parabolic

    equation, simply describing a temporal evolution where nonlinear convection and

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    linear diffusions are combined, and it can be derived as a weakly nonlinear approxi-

    mation to the equations of gas dynamics. Although nonlinear, Eq.(3) is very simple,

    and interest in it was revived in the 1940s, when Dutch physicist Jan Burgers pro-

    posed it to describe a mathematical model of turbulence in gas(Burgers(1940)). As

    a model for gas dynamics, it was then studied extensively by (Burgers(1948)), Eber-

    hard Hopf(1950), Julian Cole(1951), and others, in particular; after the discovery of a

    coodinate transformation that maps it to the heat equation. While as a model for gas

    turbulence the equation was soon rivaled by more complicated models, the linearizing

    transformation just mentioned added importance to the equation as a mathematical

    model, which has since been extensively studied. The limit 0 is an hyperbolic

    equation, called the inviscid Burgers equation.

    ut + uux = 0. (3.25)

    This limiting equation is important because it provides a simple example of a con-

    servation law, capturing the crucial phenomenon of shock formation. Indeed, it was

    oriinally introduced as a model to describe the formation of shock waves in gas dy-

    namics. A first-order partial differential equation for u(x, t) is called a conservation

    law if it can be written in the form ut+(f(u))x = 0. For equation (3.24), f(u) = u2/2.

    Such conservation laws may exhibit the formation of shocks, which are discontinuities

    appearing in the solution after a finite time and then propagating in a regular manner.

    When this phenomenon arises, an initially smooth wave becomes steeper and steeper

    as time progresses, until it forms a jumb discontinuity-the shock.

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    Nowadays, the Burgers equation is used as a simplified model of a kind of hydro-

    dynamic turbulence(Case & Chiu(1969)), called Burgers turbulence. Burers himself

    wrote a treatise on the equation now known by his name (Burgers (1974)), where

    several variants are proposed to describe this particular kind of turbulence. Equa-

    tion (3.23) was originally derived to describe the propagation of nonlinear waves in

    dissipative media, where (> 0) is the kinematic viscosity, and u(x, t) represents the

    fluid velocity field. It plays an active role in explaining two fundamental effects char-

    acteristic of any turbulence: the nonlinear redistribution of energy over the spectrum

    and the action of viscosity in small scales. Over the decades, the Burgers equation

    has been widely used to model a large calss of physical systems in which the non-

    linearity is fairly weak(quadratic) and the dispersion is negligible compared to the

    linear damping. Hopf (1950) and Cole(1951) independently discovered a transforma-

    tion that reduces the Burgers equation (3.23) to a linear diffusion equation. First, we

    write (3.23) in a form similar to a conservation law

    ut +

    x

    1

    2u2 ux

    = 0. (3.26)

    This may be regarded as the compatibility condition for a function ti exist, such

    that

    u = x, (3.27)

    ux 12

    u2 = t. (3.28)

    We substitue the value of u from (3.27) in (3.28) to obtain

    xx 12

    x2 = t. (3.29)

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    Next, we introduce = 2log so that

    u = x = 2x

    . (3.30)

    This is called the Cole-Hopf transformation which, by differentiating, gives

    xx = 2

    x

    2 2

    xxandt = 2t

    . (3.31)

    Consequently, (3.29) reduces to the linear heat equation

    t = xx. (3.32)

    The relation between the Burgers and the heat equation was already mentioned in

    an earlier book(Forsyth(1906), but the former had not been recognized as physically

    releant; hence, the importance of this connection was seemingly not noticed at the

    time. Using the transformaion of Equation (3.23), known as the Cole-Hopf trans-

    formation, it is easy to solve the initial value problem for this equation. Recently,

    a generalization of the Cole-Hopf transformation has been successfully used to lin-

    earize the boundary value problem for the Burgers equation posed on the semiline

    x > 0Calogero(1989).

    Many solutions of equation (3.32) are well-known in the literature. For a more

    complete exposition, we exhibit some of them in next sections.

    To solve equation (3.23), we simply substitute the given solution for in (3.30).

    Motivated by this idea, we intend to extend the Cole-Hopf transformaion to lin-

    earize equation (3.22). This is our aim in the Second section.

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    This chapter is organized as follows: In section 4.2 we successfully apply the

    generalized Cole-Hopf transformation to generalized Burgers equation and we reduce

    the problem of solving this equation to solve the linear heat equation. Section 4.3

    is dedicated to show some exact solutions to linear heat equation by transformation

    groups. At the end, we give some conclusions.

    4.2 Exact Linearization of Generalized Burgers Equation

    In this section we construct the generalized Cole-Hopf transformation from equa-

    tion (3.23) to the standard heat equation. In order to look for soltions to generalized

    Burgers equation (3.22), we apply the generalized Cole-Hopf transformation given by

    u(x, t) = A(x, t)G(z, ) + B(x, t), z = (t)x + (t), = (t), (3.33)

    where A(x, t) = 0, B(x, t), (t), (t) and (t) are some functions to be determinedlater. We use the above ansatz into (1) to obtain

    G[AT] + GGz[f A

    2] + Gzz [gA2] + G[At + f BAx + f ABx + lA]

    +Gz[A(x + ) + fBA + 2gAx] + [Bt + f BBx + gAxx + gBxx + lB] = 0, (3.34)

    Now we assume the following conditions

    f A2

    A= 1 (3.35)

    gA2

    A= 1 (3.36)

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    At + f BAx + f ABx + lA = 0 (3.37)

    A(x + ) + fBA + 2gAx = 0, (3.38)

    Bt + f BBx + gAxx + gBxx + lB = 0, (3.39)

    f AAx = 0 (3.40)

    In view of (14)-(18), equation (13) reduces to the Burgers equation

    G + GGz + Gzz = 0 (3.41)

    Application of x to (17)gives

    Bx =f

    (3.42)

    Equations (18) and (19) lead to

    (

    f) + f(

    f)2 l

    f = 0 (3.43)

    (

    f) + f(

    (f)2) l

    f = 0 (3.44)

    from which we find that

    (t) =c1

    c0 +

    f eldtdt

    (3.45)

    (t) =

    c2f 2e

    ldtdt (3.46)

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    Inserting (3.46) in equations (3.33) and (3.38) we have

    z = (c1

    c0 +

    f eldtdt

    )x + c2c2

    1 f e

    ldtdt

    [c0 +

    f eldtdt]2

    (3.47)

    B =e

    ldt[x c2c1]

    c0 +

    f eldtdt

    (3.48)

    Using (3.42) in (3.37) and solving for A(t), we get

    A(t) = c3e

    l(t)dt (3.49)

    Now (3.35) gives = A, and its solution is (after inserting for A, )

    = c3c21

    e

    ldtdt

    [c0

    f eldtdt]2

    + c4 (3.50)

    Substituting all the known terms into (3.33) we find that

    u = c3c1

    c0 + f eldtdte

    l(t)dtG(, z) +

    eldt[x c2c1]

    c0 + f eldtdt (3.51)

    If we replace G in (3.51) by

    G =z(, z)

    (, z)(3.52)

    We find that (3.41) and (3.51) become

    = zz (3.53)

    which is the linear heat equation and

    u =e

    ldt

    [c0 +

    f eldtdt]

    [c1c3z(, z)

    (, z)+ (x c2c1)] (3.54)

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    4.3 Exact Solutions to linear heat equation

    Suppose that = (x, t) is a solution to equation

    t = xx (3.55)

    Then = (x,t) is a solution to heat equation

    t = xx (3.56)

    Conversely, if = (x, t) is a solution to (3.56), then = (x, t/) is a solution to

    (3.55).Thus, equation (3.55) and (3.56) are the same. We shall call Equation (3.55)

    the normalized heat equation. We already obtained some solutions to equation (3.56)

    in a form of travelling wave.In thi section we give solutions to this equation by uing

    Lie group theory[12].

    Definition : Let be a system of differential equations. A symmetry group of

    the system is a local group of transformations G acting on an open subset M of

    the space of independent and dependent variables for the system with the property

    that whenever u = f(x) is a solution of, and whenever g.f is defined for g G,

    then u = g.f(x) is also a solution of the system. (By Solution we mean any smooth

    solution u = f(x) defined on any subdomain X).

    Following are Symmetry groups of the heat equation (1):

    G1 (x + ,t,u),

    G2 (x, t + , u),

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    G3 (x,t, exp(e)u),

    G4 (exp()x, exp(2)t, u),

    G5 (x + 2t), t , u exp(x 2t),

    G6

    x

    1 4t ,t

    1 4t , u

    1 4t exp x2

    1 4t

    ,

    G (x,t,u + (x, t))

    This means that if = (x, t)is a solution of the heat equation (1), so are the functions

    (1) = (x , t),

    (2) = (x, t ),

    (3) = exp()(x, t),

    (4) = (exp()x, exp(2)t) ,

    (5) = exp(x + 2t)(x 2t,t),

    (6) =1

    1 + 4texp[

    x21 + 4t

    ](x

    1 + 4t,

    t

    1 + 4t),

    (7) = (x, t) + x(x, t)

    Where is any real number and (x, t)is any other solution to the heat equation. The

    symmetry groups G3 and G thus reflect the linearity of the heat equation;we can add

    solutions and multiply them by constants. The groups G1

    and G2

    demonstrate the

    time- and space-in variance of the equation, reflecting the fact that the heat equation

    has constant coefficients.The well-known scaling symmetry turns up in G4, while G5

    represents a kind of Galilean boost to a moving coordinate frame. The last group G6

    is a genuinely local group of transformations. Its appearance is far from obvious from

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    basic physical principles, but it has the following nice consequence If we let = c be

    just a constant solution, then we immediately conclude that the function

    =c

    1 + 4texp(

    x21 + 4t

    ), (3.57)

    is also a solution. In particular, if we set c =

    / we obtain the fundamental solution

    to the heat equation at the point (x0, y0) = (0, (1/(4)))To obtain the fundamental

    solution

    =14t

    exp(x2

    4t), (3.58)

    We need to translate this solution in t using the group G2 (with replaced by (1/4))

    It can be shown that the most general solution obtainable from a given solution

    = (x, t) by group transformations is of the form

    (x, t) =1

    1 + 46texp[3 5x + 6x

    2 5t1 + 46t

    ]

    (exp(4)(x 25t)

    1 + 46 1, exp(24)t

    1 + 46t 2) + (x, t) (3.59)

    Where 1,...,6are real constants and = (x, t) an arbitrary olution to the heat

    equation.

    Previous considerations allow to obtain particular solutions to the heat equations

    t = xx.Some of them are

    w(t) = k = constant, (3.60)

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    w(x) = A(x) + B, (3.61)

    w(x, t) = A(x2 + 2t) + B, (3.62)

    w(x, t) = A(x3 + 6tx) + B, (3.63)

    w(x, t) = A(x4 + 12tx2 + 122t2) + B, (3.64)

    w(x, t) = x2n +n

    k=1

    (2n)(2n 1)...(2n 2k + 1)(t)kx2n2kk!

    (3.65)

    w(x, t) = x2n+1 +n

    k=1

    (2n + 1)(2n)...(2n 2k + 2)(t)kx2n2k+1k!

    (3.66)

    w(x, t) = Aexp(2

    t x) + B, (3.67)w(x, t) = A

    1t

    exp( x2

    4t) + B, (3.68)

    w(x, t) = A exp(2tcos(x + B), (3.69)

    w(x, t) = A exp(2tcos(x + B) + C, (3.70)

    w(X, t) = A exp(x)cos(x 22t + B) + K, (3.71)

    w(x, t) = A erf(x

    2t ) + B, (3.72)

    Where A,B,C and are arbitrary constants, n is a positive integer,

    erf(z) 2

    z0

    exp(2)d, (3.73)

    is the error function ( probability integral).

    These solutions are useful in solving generalized Burgers equation (3.22).

    4.4 Conclusions

    We successfully applied the generalized Cole-Hopf transformation to generalized Burg-

    ers equation. As a particular case, we obtained some solutions to linear heat equation.

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    We think that the application of the generalized Cole-Hopf transformation is a useful

    tool in the search of solutions to other generalized burgers equation.

    References

    1. M. Scott, Encyclopedia of Nonlinear Science, Taylor and Francis, 2005.

    2. H. Bateman, Some recent research on the motion of fluids, Monthly Weather

    Review 43 (1915) 163-170.

    3. J. Burgers, Application of a model system to illustrate some points of the sta-

    tistical theory of free turbulence, Proceedings of the Nederlandse Akademie van

    Wetenschappen 43 (1940) 2-12.

    4. J. Burgers, A mathematical model illustrating the theory of turbulence, Ad-

    vances in Applied Mechanics 1 (1948) 171-199.

    5. E. Hopf, The partial differential equation ut uux luxx, Communications in

    Pure and Applied Mathematics 3 (1950) 201-230.

    6. J. Cole, On a quasilinear parabolic equation occurring in aerodynamics, Quar-

    terly Journal of Applied Mathematics 9 (1951) 225-236.

    7. K.M. Case, S.C. Chiu, Burgers turbulence models, Physics of Fluids 12 (1969)

    1799-1808.

    8. J. Burgers, The Nonlinear Diffusion Equation: Asymptotic Solutions and Sta-

    tistical Problems, Reidel, Dordrecht and Boston, 1974.

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    9. A.R. Forsyth, Theory of Differential Equations, Cambridge University Press,

    Cambridge, 1906.

    10. F. Calogero, S. De Lillo, The Burgers equation on the semiline, Inverse Problems

    5 (1989) L37.

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    Chapter V

    SIMILARITY SOLUTIONS OF THE GENERALIZED

    BURGERS EQUATION ut + unux +

    + j

    2t

    u +

    +

    x

    un+1 =

    (t)2 uxx

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    5.1 Introduction

    The generalized Burgers equation

    ut + unux +

    +

    j

    2t

    u +

    +

    x

    un+1 =

    (t)

    2uxx, (5.1)

    where , , are non negative constants, n is a positive integer, j = 0, 1, 2 and

    (t) is the variable viscosity, has been studied recently by several authors. When

    n = 1, = = = j = 0 and (t) = , a constant, (5.1) becomes the well-known

    Burgers equation

    ut + uux =

    2uxx. (5.2)

    The Hopf-Cole transformation (Hopf (1950), Cole (1951)) changes (5.2) to the linear

    heat equation. When n = 1, = = = 0 and (t) = , a constant, (5.1) becomes

    the nonplanar Burgers equation

    ut + uux +j

    2tu =

    2uxx. (5.3)

    When n = 2, = = = j = 0 and (t) = , a constant, (5.1) becomes the

    modified Burgers equation

    ut + u2ux =

    2uxx. (5.4)

    When n = 1, = = j = 0 and (t) = , a constant, (5.1) becomes the Burgers

    equation with linear damping term:

    ut + uux + u =

    2uxx. (5.5)

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    In fact equation (5.1), with (t) = , a constant, includes as special cases the equa-

    tions

    Ur + 12a20

    U U +jU

    2r=

    2a30

    U, (5.6)

    vr + 12c20

    vv +v

    r=

    b

    2c200v, (5.7)

    ut + uux +ju

    2t=

    2uxx and ut + uux + u =

    2uxx, (5.8)

    ut + uux + u =

    2uxx, (5.9)

    vx +

    jv

    2x vv = v, (5.10)ut + uux + H(x,t,u,ux) = 0, (5.11)

    ut + uux +

    j

    2tu =

    2uxx, (5.12)

    studied respectively by Scott (1981), Enflo (1985), Sachdev, Enflo, Srinivasa Rao,

    Mayil Vaganan and Poonam Goyal (2003), Lardner and Arya (1980), Crighton and

    Scott [4], Nimmo and Crighton (1979), and Sachdev and Nair (1987). The Burgers

    equation with linear damping (5.9) is recently investigated by Mayil Vaganan and

    Senthil Kumaran (2004) for its symmetries by the Lies classical method (Lie (1967),

    Bluman and Kumei (1989)).

    When (t) = , a constant, (5.1) becomes

    ut + unux + ( +

    j

    2t)u + (+

    x)un+1 =

    2uxx. (5.13)

    Sachdev, Joseph and Mayil Vaganan (1996) studied (5.13) for exact N-wave solutions.

    Mayil Vaganan and Asokan (2003) obtained similarity solutions of (5.13) by the direct

    method of Clarkson and Kruskal (1989).

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    But the viscosity is actually a function of t (Lighthill (1956)). In this case the

    Burgers equation takes the form

    ut + uux =(t)

    2uxx. (5.14)

    Doyle and Englefield (1990) determined similarity reductions of the generalized Burg-

    ers equation (GBE) (5.14) using the method for defining an optimal system of group-

    invariant solutions (Olver (1995)). Mayil Vaganan and Senthil Kumaran (2003) ob-

    tained invariant solutions of (5.14) by the direct method. Scott (1981) obtained the

    long time asymptotics of solutions of (5.14) when (t) = t, > 0. Parker (1980)

    also derived large-time asymptotics of the generalized Burgers equation

    V

    t+ (t)V (t)V V

    x= (t)

    2V

    x2, (5.15)

    subject to the initial condition

    V(x, 0) = r(x) = A1 sin(x/l), 0 < x < l. (5.16)

    Later Sachdev, Nair and Tikekar (1988) introduced the Euler-Painleve transcendents

    in the form

    HH + aH2

    + A(z)HH + B(z)H2 + bH + c = 0, (5.17)

    as the self-similar reductions of the GBE

    ut + uux =

    2g(t)uxx, (5.18)

    when g(t) is given by either (1 + t)n or emt.

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    Mayil Vaganan and Senthil Kumaran (2004, 2005, 2005) in a series of papers

    obtained similarity solutions in terms of exponential, error and Kummer functions of

    the GBEs

    ut + unux =

    2uxx, (5.19)

    ut + unux + u =

    2uxx, (5.20)

    ut + uux + u =

    2uxx. (5.21)

    This chapter gives detailed account of group-invariant solutions of the generalized

    Burgers equation (5.1), recover previously obtained solutions and determine new so-

    lutions and this is carried out in section 2. The results and discussions of the present

    chapter are contained in section 3.

    2. Similarity solutions of (5.1)

    If (5.1) is invariant under a one parameter group of infinitesimal transformations

    x = x + X(x,t,u) + (2),

    t = t + T(x,t,u) + (2),

    u = u + U(x,t,u) +

    (2), (5.22)

    then

    u

    jT

    2t2 T

    j

    2t+

    (Uu 2Xx)

    j

    2t+

    +ut

    T

    Tt +

    2Txx + 2Xx

    + unux

    T

    + Xx

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    un+1T

    +

    x

    (Uu 2Xx)

    +

    x

    X

    x2

    +un1ux [nU] + U j2t

    + + Ut

    2Uxx

    +un

    U(n + 1)

    +

    x

    + Ux

    + ux

    Xt

    2(2Uxu Xxx)

    +uxut

    2Txu + 2Xu

    + unut[Tx] + unu2x[2Xu] + u2x

    2(Uuu 2Xxu)

    +u3x

    2Xuu

    + u2xut

    2Tuuuux

    3Xu

    j

    2t+

    + un+1ux

    3Xu

    +

    x

    +uxt[Tx] + uut

    Tu

    j

    2t+

    + un+1ut

    Tu

    +

    x

    + uxuxt[Tu] = 0.(5.23)

    We consider two cases: 1) The case Xu = Tu = Uu = 0 and 2) The general case.

    1: The case Xu = Tu = Uu = 0.

    Here (5.23) simplifies to

    u T j

    2t2

    T

    j

    2t

    + (Uu

    2Xx)

    j

    2t

    + +ut

    T

    Tt +

    2Txx + 2Xx

    + unux

    T

    + Xx

    +un+1T

    +

    x

    (Uu 2Xx)

    +

    x

    X

    x2

    +nun1uxU +

    U

    j

    2t+

    + Ut

    2Uxx

    +un

    U(n + 1)

    +

    x

    + Ux

    + ux

    Xt

    2(2Uxu Xxx)

    unutTx + uxtTx = 0. (5.24)

    Equating the coefficients of uxt, un1ux to zero in (5.24), we get Tx = U = 0. Setting

    the coefficients of u, ut, unux, u

    n+1, ux in (5.24) equal to zero, we have

    jT2t2

    +

    j

    2t+

    2Xx T

    = 0, (5.25)

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    T

    Tt + 2Xx = 0, (5.26)

    T

    + Xx = 0, (5.27)2Xx T

    +

    x

    X

    x2= 0, (5.28)

    Xt + 2

    Xxx = 0. (5.29)

    We obtain from (5.26) and (5.27) that

    Tt = Xx. (5.30)

    Using (5.27) and (5.30) in equation (5.25) we get

    jTt jt

    T = 0. (5.31)

    On inserting (5.27), equation (5.28) becomes

    +

    x

    Xx

    x2X = 0. (5.32)

    Now we consider three cases: In the foregoing analysis c0, r1, x0, t0, f0, c1, r2, c2, A0, B0, r3, r0,

    C0, D0, r4, r5, r6, r7, r8 are arbitrary constants and the relation between f and H is

    f = H1/n.

    Case 1.1: = = 0

    Equation (5.1) with = = 0 is

    ut + unux +

    j

    2tu +

    xun+1 =

    (t)

    2uxx. (5.33)

    In this case the solutions of (5.30)- (5.32) are

    T = c0t, X = c0x. (5.34)

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    The characteristic equations are

    dx

    c0x

    =dt

    c0t

    =du

    0

    . (5.35)

    Solving (5.35) we obtain

    z =x

    tand u = f(z). (5.36)

    Substituting (5.34) in (5.27) and solving for , we get

    (t) = r1t. (5.37)

    Using (5.36) and (5.37) in (5.33), we thus arrive at

    f +2

    r1zf 2

    r1fnf j

    r1f 2

    r1zfn+1 = 0. (5.38)

    Through the transformation f = H1/n equation (5.38) is changed to

    HH

    n + 1

    n

    H

    2+

    2

    r1zH H 2

    r1H +

    jn

    r1H2 +

    2n

    r1zH = 0. (5.39)

    We call (5.39) the generalized Euler-Painleve transcendent because it contains a term

    2nr1z

    H which is not present in the general form of the Euler-Painleve transcendent

    (5.17).

    Case 1.2 = = j = 0

    For this case equation (5.1) is

    ut + unux + u

    n+1 =(t)

    2uxx. (5.40)

    The infinitesimals are

    X = x0, T = t0 and U = 0. (5.41)

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    Substituting (5.41) in (5.27) and solving for , we get

    = , a constant. (5.42)

    Thus the similarity form of equation (5.40) is

    u = f(z), z = x x0t0

    t. (5.43)

    Inserting (5.43) in (5.40) and using (5.42) we find that f(z) satisfies the equation

    f 2x0t0

    f 2

    fnf 2

    fn+1 = 0. (5.44)

    A solution of equation (5.44) is

    f = f0e2x0z/t0, (5.45)

    provided = 2x0t0

    .

    Under the transform f = H1/n equation (5.44) changes again to a generalized

    Euler-Painleve transcendent(GEPT)

    HH

    n + 1

    n

    H

    2 2x0t0

    HH 2

    H +2n

    H = 0. (5.46)

    It follows from f = H1/n and the solution (5.45) of (5.44) that the corresponding

    solution of the GEPT (5.46) is

    H =1

    fn0e2nx0z/t0. (5.47)

    The reduction of (5.33) with (t) given by (5.37) to the GEPT (5.46) facilitates the

    determination of an exact closed form solution in terms of an exponential function.

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    The extra term 2n

    H in (5.46) (recall the EPT (5.17)) together with 2

    H helps

    to find an exact solution. As for (5.44) the terms f,2x0t0

    f and 2

    fnf,2

    fn+1

    separately lead to this exponential solution.

    Case 1.3 = = = 0

    In this case equation (5.1) takes the form

    ut + unux +j

    2tu =(t)

    2 uxx. (5.48)

    The infinitesimals are

    T = c0t, X = c0x + c1, U = 0. (5.49)

    Inserting (5.49) in (5.27) and solving for , we get

    (t) = r2t. (5.50)

    The similarity transformation of (5.48) is

    u = f(z), z =c0x + c1

    t. (5.51)

    Putting (5.50) and (5.51) in (5.48), the latter reduces to

    f +2

    r2c20zf 2

    r2c0fnf j

    r2c20f = 0. (5.52)

    Using the transformation f = H1/n, equation (5.52) becomes an EPT

    HH

    n + 1

    n

    H

    2+

    2

    r2c20zH H 2

    r2c0H +

    jn

    r2c20H2 = 0. (5.53)

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    2. The general case

    Now setting the coefficients of uxuxt, uxt in (5.23) equal to zero, we have

    Tu = Tx = 0. (5.54)

    Equating the coefficients of u2x, uxut in (5.23) to zero and using (5.54), we obtain

    Xu = Uuu = 0. (5.55)

    Equation (5.55) lead to

    U = A(x, t)u + B(x, t). (5.56)

    Again equating the coefficients ofux, ut and the remaining terms in (5.23) to zero, we

    have

    unT

    + Xx

    + nun1UXt

    2(2Uxu Xxx) = 0,(5.57)

    T

    Tt + 2Xx = 0,(5.58)u

    jT

    2t2 T

    j

    2t+

    (Uu 2Xx)

    j

    2t+

    + U

    j

    2t+

    +Ut 2

    Uxx + un+1

    T

    +

    x

    (Uu 2Xx)

    +

    x

    X

    x2

    +un

    U(n + 1)

    +

    x

    + Ux

    = 0.(5.59)

    Using (5.56) and (5.58) in (5.57) and setting the coefficients of un, un1 and u0 to

    zero, we get

    Tt Xx + nA = 0, (5.60)

    B = 0, (5.61)

    Xt Ax + 2

    Xxx = 0. (5.62)

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    Substituting (5.56) and (5.58) in (5.59) and equating the coefficient of un+1 and u to

    zero, we have

    T

    +

    x

    (A 2Xx)

    +

    x

    X

    x2+ A(n + 1)

    +

    x

    + Ax = 0,(5.63)

    jT2t2

    T

    j

    2t+

    + 2Xx

    j

    2t+

    + At

    2Axx = 0.(5.64)

    Inserting (5.58) in (5.63) and (5.64), we get

    Xxx + n

    +

    x

    Xx n

    x2x = 0, (5.65)

    j2t +

    T j2t2 T + At Axx = 0. (5.66)

    Integration of equation (5.60) with respect to x gives

    X = (T + nA) x + C1(t), (5.67)

    where C1(t) is the function of integration. Substituting (5.67) in (5.62) and equating

    the coefficients of x and x0 to zero, we get

    T + nAt = 0, (5.68)

    C1 + Ax = 0. (5.69)

    Solving (5.68) for A, we get

    A = T

    n+ c2. (5.70)

    Using (5.70) in (5.69), we find that

    C1(t) = c1. (5.71)

    In view of (5.70) and (5.71), (5.67) becomes

    X = nc2x + c1. (5.72)

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    On inserting (5.70), equation (5.66) becomes

    T

    nj

    2t +

    T

    +

    jn

    2t2 T = 0. (5.73)

    Equations (5.56) and (5.61) lead to

    U = Au. (5.74)

    We reduce (5.1) to ODEs under the cases (1) j = = 0, (2) = = = 0, (3)

    = = 0, (4) j = = 0, (5) = = j = 0 and (6) = j = 0. For brevity we

    suppress the details of the determination of X , T , U .

    Case 2.1 j = = 0

    For this case equation (5.1) is

    ut + unux + u + u

    n+1 = (t)2

    uxx. (5.75)

    Substituting j = 0 in (5.73) and solving for T, we get

    T = A0ent + B0. (5.76)

    On using (5.76), equation (5.70) gives

    A = A0ent + c2. (5.77)

    Putting = 0 in (5.65), we get

    Xxx + nXx = 0. (5.78)

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    Inserting (5.72) in (5.78), we get c2 = 0. Therefore (5.77) and (5.72) can be written

    as

    A = A0ent, X = c1. (5.79)

    Using (5.79) in (5.76), we get

    U = A0entu. (5.80)

    Substituting (5.76) and (5.79) in (5.58), we have

    = A0nent

    A0ent + B0. (5.81)

    The exact solution of equation (5.81) is

    (t) = r3

    A0ent + B0

    1

    (5.82)

    The characteristic differential equation dxX

    = dtT

    = duU

    takes the form

    dx

    c1=

    dt

    A0ent + B0=

    du

    A0entu, A0 = 0. (5.83)

    The case A0 = 0 is studied in case 2.1(b).

    The similarity form of (5.75) with (t) given by (5.82) namely

    ut

    + unux

    + u + un+1 =r3

    2 (A0ent + B0)uxx

    , (5.84)

    is

    u =

    A0ent + B0

    1/n

    f(z), (5.85)

    z = x c1nB0

    log

    ent

    A0ent + B0

    , B0 = 0. (5.86)

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    The case B0 = 0 is subsequently considered in Case 2.1(a).

    Substituting (5.86) in (5.84), we get the ordinary differential equation

    f +2c1r3

    f 2r3

    fnf 2r3

    fn+1 2B0r3

    f = 0. (5.87)

    A solution of equation (5.87) is

    f(z) = expc1

    r3 1

    r3

    c21 + 2B0r3

    z

    . (5.88)

    Through f = H1/n equation (5.87) is transformed again to an GEPT

    HH

    n + 1

    n

    H

    2+

    2c1r3

    HH 2r3

    H +2n

    r3H+

    2nB0r3

    H2 = 0. (5.89)

    The solution of (5.89) corresponding to (5.88) is

    H(z) = exp

    nc1r3 n

    r3

    c21 + 2B0r3

    z

    . (5.90)

    Case 2.1(a) B0 = 0

    In this case the infinitesimals are

    T = A0ent, X = c1, U = A0entu. (5.91)

    The viscosity is

    (t) = r0ent, (5.92)

    The similarity form of equation (5.75) when (t) is given by (5.92) namely

    ut + unux + u + u

    n+1 =r02

    entuxx, (5.93)

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    is

    u = etf(z), z(x, t) = x +c1

    A0nent. (5.94)

    Here f is governed by

    f 2c1r0A0

    f +2

    r0fnf 2

    r0fn+1 = 0, (5.95)

    whose solution is

    f(z) = e2c1r0A0

    z, (5.96)

    provided that = 2c1r0A0 .

    Through the transform f = H1/n equation (5.95) becomes a GEPT

    HH

    n + 1

    n

    H

    2 2c1A0r0

    HH +2

    r0H +

    2n

    r0H = 0, (5.97)

    with the solution

    H(z) = e2nc1r0A0

    z. (5.98)

    Case 2.1(b) A0 = 0

    The infinitesimals and (t) are

    T = B0, X = c1, U = 0, (t) = r1. (5.99)

    The similarity transformation is

    u = f(z), z = x c1B0

    t, (5.100)

    where f satisfies

    f 2r1

    fnf +2c1

    B0r1f 2

    r1f

    r1fn+1 = 0. (5.101)

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    A solution of equation (5.101) is

    f(z) = exp c1

    B0r1 c21

    B0r12+

    2

    r1 z , (5.102)

    provided that =

    c1

    B0r1

    c21B0r12

    + 2r1

    .

    Through the transform f = H1/n equation (5.101) becomes a GEPT

    HH

    n + 1

    n

    H

    2+

    2c1B0r1

    H +2

    r1H2 +

    2

    r1H = 0. (5.103)

    Therefore the solution of (5.103) is

    H(z) = exp

    n

    c1

    B0r1

    c21B0r12

    +2

    r1

    z

    . (5.104)

    Case 2.2 = = = 0

    Equation (5.1) reduces to

    ut + unux +

    j

    2tu =

    (t)

    2uxx. (5.105)

    The infinitesimals are

    T = C0 + D0tjn2 , X = nc2x + c1, U =

    c2 c0

    n

    D0j

    2tjn21

    u. (5.106)

    The viscosity equation is

    =

    2nc2

    C0 +jnD02

    tjn21

    C0t + D0tjn/2. (5.107)

    The general solution of equation (5.107) is

    (t) = r4t2nc2C0

    1C0 + D0t

    jn2 1

    2nc2C0[ jn2 1]

    1

    . (5.108)

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    The similarity form of the equation (5.105) with (t) is given by (5.108), viz.,

    ut + unux +

    j

    2tu =

    r4

    2t2nc2C0

    1 C0 + D0t jn2 1

    2nc2

    C0[ jn2 1]1

    uxx, (5.109)

    is

    u = tc2C0

    1n

    C0 + D0t

    jn21 c2

    C0( jn2 1)+ 1n

    f(z), (5.110)

    z = (c2x + c1)C0 + D0t

    jn21 nc2C0[ jn2 1] . (5.111)

    For this case the reduced ODE is

    f 2C0r4(n + 1)

    jn

    2 1

    zf +

    2C0r4(n + 1)

    jn

    2 1

    fnf 2C0

    r4(n + 1)

    jn

    2 1

    f = 0.

    (5.112)

    The first integral of equation (5.112) with c2 = C0n(n+1)jn2 1

    is

    f 2C0r4(n + 1)

    jn

    2 1

    zf +

    2C0r4(n + 1)2

    jn

    2 1

    fn+1 = 0. (5.113)

    The transformation f = H1/n linearizes (5.113) to

    H 2nC0r4(n + 1)

    1 jn

    2

    zH +

    2nC0r4(n + 1)2

    1 jn

    2

    = 0. (5.114)

    The general solution of equation (5.114) is

    H(z) =

    H(0)

    nC0(2jn)

    2r4(n + 1)2erf

    nC0(2jn)2r4(n + 1)

    z

    exp

    nC0(2jn)

    2r4(n + 1)z2

    .

    (5.115)

    The corresponding solution of (5.112) with c2 = C0n(n+1)jn2 1

    is

    f(z) =

    H(0)

    nC0(2jn)

    2r4(n + 1)2erf

    nC0(2jn)

    2r4(n + 1)z

    1/n

    exp

    C0(2jn)2r4(n + 1)

    z2

    .

    (5.116)

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    Thus an exact closed form solution of (5.109) is given by using (5.111); (5.116) in

    (5.110):

    u(x, t) = tc2C0

    1n

    C0 + D0t

    jn21 c2C0( jn2 1)

    + 1n

    H(0)

    nC0(2jn)

    2r4(n + 1)2

    erf

    nC0(2jn)

    2r4(n + 1)(c2x + c1)

    C0 + D0t

    jn21 nc2C0[ jn2 1]

    1/n

    exp

    C0(2jn)

    2r4(n + 1)(c2x + c1)

    2C0 + D0t

    jn2 1

    2nc2C0[ jn2 1]

    . (5.117)

    Case 2.2(a) c2 = 0

    When c2 = 0, (5.106), (5.108) reduce to

    T = C0t+D0tjn2 , X = c1 U =

    C0n

    +D0j

    2tjn21

    u, (t) = r41

    C0t + D0tjn2

    1.

    (5.118)

    The corresponding similarity transformation is

    u = t1/nC0 + D0t

    jn211/n

    f(z), (5.119)

    z = x c1C0

    jn2 1

    log tjn21

    C0 + D0tjn21

    , (5.120)

    where f(z) is any solution of

    f +2

    r4fnf +

    2c1

    r4f

    2C0

    r4j

    2 1

    n f = 0. (5.121)

    The equation (5.121) changes to an EPT

    HH

    n + 1

    n

    H

    2+

    2c1r4

    HH 2r4

    H +2C0r4

    H2 = 0, (5.122)

    through f = H1/n. The case n = 2, j = 1 is investigated in case 2.2(d).

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    Case 2.2(b) c2 = C0 = 0

    Setting c2 = C0 = 0 in (5.107) and solving we obtain

    (t) = r4tjn2 . (5.123)

    The infinitesimals are

    T = D0tjn2 , X = c1, U = D0j

    2tjn2 1u, (5.124)

    give rise to the similarity transformation

    u = tj/2f(z), z = x +c1

    D0jn2 1

    t1 jn2 . (5.125)

    The reduced ODE for this case is

    f 2r4

    fnf +2C1

    D0r4

    f = 0, (5.126)

    whose first integral is the Bernoullis equation

    f 2r4(n + 1)

    fn+1 +2C1

    D0r4f = 0, (5.127)

    where we have taken the constant of integration equal to zero. The transformation

    f = H1/n linearizes (5.127) to

    H 2nc1D0r4

    H+2n

    r4(n + 1)= 0. (5.128)

    The general solution of (5.128) is

    H(z) = H(0)e2nc1D0r4

    z D0c1(n + 1)

    . (5.129)

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    The corresponding solution of (5.126) is

    f(z) =

    H(0)e

    2nc1D0r4

    z

    D0

    c1(n + 1)1/n

    . (5.130)

    In fact (5.129) is a solution of

    HH

    n + 1

    n

    H

    2+

    2c1D0r4

    HH 2r4

    H = 0, (5.131)

    which is derived from (5.126) through f = H1/n.

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    Case 2.2(c) D0 = 0

    The infinitesimals and viscosity are

    T = C0t, X = nc2x + c1, U =

    c2 C0n

    u, (t) = r4t

    2nc2C0

    1

    . (5.132)

    The similarity transformation is

    u = tc2C0

    1n f(z), z = (nc2x + c1) t

    nc2/C0. (5.133)

    The similarity function f is governed by

    f 2nc2r4

    fnf 2nc2C0r4

    zf

    j

    n2c22r4+

    2(nc2 C0)n3C0c22r4

    f = 0. (5.134)

    A first integral of (5.134) with c2 =C0(2jn)2n(n+1)

    is the Bernoullis equation

    f 4C0r4(2jn) f

    n+1 +4(n + 1)

    C20r4(2jn)zf = 0, n = 2, j = 1. (5.135)

    Equation (5.135) is lenearized via f = H1/n to

    H 4(n + 1)nC20r4(2jn)

    zH +4n

    C0r4(2jn) = 0, (5.136)

    whose general solution is

    H(z) =

    H(0)

    2n

    r4(n + 1)(2jn)erf

    2n(n + 1)

    C20r4(2jn)z

    exp

    2n(n + 1)

    C20r4(2jn)z2

    .

    (5.137)

    Therefore the corresponding solution of (5.134) is

    f(z) =

    H(0)

    2n

    r4(n + 1)(2jn)erf

    2n(n + 1)

    C20r4(2jn)z

    1/n

    exp

    2(n + 1)

    C20r4(2jn)z2

    . (5.138)

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    Case 2.2(d) c2 = D0 = 0

    The variable viscosity and the infinitesimals are

    (t) =r4t

    , T = C0t, X = c1, U = C0n

    u. (5.139)

    The similarity form is

    u = t1/nf(z), z = x c1C0

    log t, (5.140)

    where f is satisfied by

    f 2r4

    fnf +2c1

    C0r4f +

    1

    r4

    2jn

    2

    f = 0. (5.141)

    When n = 2, j = 1 (5.141) is integrated to (after setting the constant of integration

    equal to zero)

    f 2r4(n + 1) fn+1 + 2c1C0r4

    f = 0, (5.142)

    a Bernoulli equation and therefore linearizes through f = H1/n to

    H 2nc1C0r4

    H+2n

    r4(n + 1)= 0. (5.143)

    The general solution of (5.143) is

    H(z) =

    H(0)e2nc1C0r4

    z + C0c1(n + 1)

    , (5.144)

    and the corresponding solution of equation (5.141) with n = 2, j = 1 is

    f(z) =

    H(0)e

    2nc1C0r4

    z+

    C0c1(n + 1)

    1/n

    . (5.145)

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    When n = 2, j = 1, (5.105) becomes the modified cylindrical Burgers equation with

    variable viscosity

    ut + u2ux + 1

    2tu = r

    4

    2tuxx. (5.146)

    Its closed form solution is written by using (5.140), (5.145):

    u(x, t) = t1/n

    H(0)tc1/C0e(4c1/C0r4)x +C03c1

    1/2. (5.147)

    Case 2.2(e) C0 = 0

    The infinitesimals are

    T = D0tjn2 , X = nc2x + c1, U =

    c2 D0j

    2tjn21

    . (5.148)

    The viscosity is

    (t) = r4tjn2 exp 4nc2

    D0(2jn)t1

    jn2 , n = 2, j = 1. (5.149)

    The similarity form is

    u = exp

    2c2

    D0(2jn)t1 jn2

    t

    j2 f(z), (5.150)

    z = (nc2x + c1)exp

    2nc2D0(2jn) t

    1 jn2

    . (5.151)

    The reduced ODE for this case is

    f 2nc2r4

    fnf +2

    nc2D0r4zf 2

    n2c2D0r4f = 0. (5.152)

    Through f = H1/n equation (5.152) changes to

    HH

    n + 1

    n

    H

    2+

    2

    nc2D0r4zH H 2

    nc2r4H +

    2

    n2c2r4D0H2 = 0. (5.153)

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    We note that for (5.105) we have found exact closed form solutions in terms of an

    exponential and error functions.

    Case 2.3 = = 0

    In this case equation (5.1) becomes

    ut + unux +

    j

    2tu + un+1 =

    (t)

    2uxx. (5.154)

    The infinitesimals are

    T = C0t + D0tjn2 , X = c1, U =

    C0

    n D0j

    2tjn21

    u. (5.155)

    The function (t) is governed by

    = C0 +

    jnD02

    tjn2 1

    C0t + D0tjn2

    . (5.156)

    The general solution of equation (5.156) is

    (t) =r5

    C0t + D0tjn2

    . (5.157)

    We remark that a special case of (5.154) with = 0, namely (5.105) also admits (t)

    in the form same as (5.157) (see equation (5.118) in Case 2.2(a)).

    The similarity form of solutions of (5.154) is

    u = t1/n

    C0 + D0tjn211/n

    f(z), (5.158)

    z = x c1(jn2 1)C0

    logtjn2 1

    C0 + D0tjn2 1

    , (5.159)

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    where f(z) satisfies

    f

    2

    r5 f

    n

    f

    2c1

    r5 f

    +

    2

    r5 f

    n+1

    2C0

    r5j

    2 1

    n

    f = 0. (5.160)

    A solution of (5.160) is

    f(z) = exp

    c1

    r5c21

    r25+

    2C0r5

    j

    2 1

    n

    z , (5.161)

    provided that = c1r5

    c21r25

    + 2C0r5

    j2 1

    n

    .

    Through f = H1/n equation (5.160) is transformed to a GEPT

    HH

    n + 1

    n

    H

    2 2c1r5

    HH 2r5

    H +2n

    r5H+

    2nC0r5

    j

    2 1

    n

    H2 = 0. (5.162)

    Therefore the solution of (5.162) is

    H(z) = exp

    n

    c1r5

    c21r25

    +2C0r5

    j

    2 1

    n

    z

    . (5.163)

    A special but physically interesting situation arises if we take j = n = 2. Under this

    assumption (5.154) become the modified spherical Burgers equation with nonlinear

    damping term and variable viscosity:

    ut + u2ux +

    1

    tu + u3 =

    r5t2

    uxx. (5.164)

    Case 2.3(a) C0 = 0

    In this case the infinitesimals and (t) are

    T = D0tjn2 , X = c1, U = D0j

    2tjn21u, (t) = r5t

    jn2 . (5.165)

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    The similarity transformations are

    u = t

    j/2

    f(z), z = x +

    c1

    D0jn2 1

    t

    1 jn2

    . (5.166)

    The f- equation is found to be

    f 2r5

    fnf +2c1

    D0r5f 2

    r5fn+1 = 0, (5.167)

    for which we obtain the solution

    f(z) = e2c1

    D0r51 z, (5.168)

    under the condition = 2c1D0r5

    . We assume that c1/D0 < 0 to ensure that > 0.

    Equation (5.167) is transformed via f = H1/n to GEPT

    HH

    n + 1

    n

    H

    2+

    2c1D0r5

    HH 2r5

    H +2n

    r5H = 0, (5.169)

    with the solution

    H(z) = e2c1nD0r51

    z. (5.170)

    Case 2.3(b) D0 = 0

    In this case the infinitesimal transformations are

    T = C0t, X = c1, U = C0n

    u. (5.171)

    Inserting D0 = 0 in (5.156) and solving, we obtain

    (t) =r5t

    . (5.172)

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    The similarity transformations are

    u = t1/nf(z), z = x

    c1

    C0log t. (5.173)

    Equations satisfied by f and H are

    f 2r5

    fnf +2c1

    C0r5f +

    1

    r5

    2jn

    n

    f 2

    r5fn+1 = 0.(5.174)

    HH

    n + 1

    n

    H

    2+

    2c1C0r5

    HH 2r5

    H

    2jnr5

    H2 +

    2n

    r5H = 0. (5.175)

    It is easily verify that

    f(z) = exp

    c1

    C0r5 c21

    C20r25

    +jn 2

    nr5

    z

    . (5.176)

    is a solution of (5.174) provided = c1C0r5

    c21C20r

    25

    + jn2nr5

    and therefore the solution

    of (5.175) is

    H(z) = exp

    n

    c1C0r5

    c21C20r

    25

    +jn 2

    nr5

    z

    . (5.177)

    All the 3 reductions of (5.154) given in Case 2.3, 2.3(a), 2.3(b) are GEPTs for which

    exact closed form solutions in terms of exponential function is found.

    Case 2.4 = = 0

    Putting = = 0, (5.1) takes the form

    ut + unux +

    j

    2tu +

    xun+1 =

    (t)

    2uxx. (5.178)

    The infinitesimals are

    T = C0t + D0tjn2 , X = nc2x, U =

    c2 C0

    n

    D0j

    2tjn21

    u. (5.179)

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    The viscosity equation is

    =

    2nc2 C0 + D0jn2

    tjn21

    C0t + D0t jn2 . (5.180)

    Solving equation (5.180), we get

    (t) = r6t2nc2C0

    1

    C0 + D0tjn21 2nc2

    C0(jn2 1)

    +1

    . (5.181)

    The similarity transformation is

    u = t c2C0 1n

    C0 + D0tjn21 c2

    C0( jn2 1)+1/n

    f(z), (5.182)

    z = xtnc2C0

    C0 + D0t

    jn21 nc2C0(

    jn2

    1) . (5.183)

    The f and H equations are

    f 2r6

    fnf +2nc2r6C0

    zf 2r6z

    fn+1 2r6

    c2 C0

    n+

    jC02

    f = 0,(5.184)

    HH

    n + 1n H2 +2nc2r6C0 zH H

    2

    r6 H

    +2n

    r6zH+2n

    r6

    c2 C0n +

    jC02

    H

    2

    = 0.(5.185)

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    Case 2.4(a) C0 = 0

    The infinitesimal transformations are

    T = D0tjn2 , X = nc2x, U =

    c2 D0j

    2tjn2 1

    u. (5.186)

    The general solution of (5.180) with C0 = 0 is

    (t) = r6exp

    4nc2

    D0(2jn)t1 jn2

    t

    jn2 . (5.187)

    The form of the similarity solution of (5.178) is

    u = exp

    2c2

    D0(2jn)t1 jn2

    t

    jn2 f(z),

    z = xexp

    nc2

    D0(2jn)t1

    jn2

    , (5.188)

    where f(z) satisfies

    f 2r6

    fnf +2nc2D0r6

    zf 2r6z

    fn+1 2c2D0r6

    f = 0. (5.189)

    The H equation is

    HH

    n + 1

    n

    H

    2 2nc2r6D0

    zH H 2r6

    H 2nr6z

    H+2nc2D0r6

    H2 = 0. (5.190)

    Case 2.5 = = j = 0

    Equation (5.1) with = = j = 0 is

    ut + unux +

    xun+1 =

    (t)

    2uxx. (5.191)

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    The function (t) is any solution of

    =

    2c2

    s1

    s1t + s2 . (5.192)

    Solving (5.192), we get

    (t) = r7 (s1t + s2)2c2s1

    s1 . (5.193)

    The infinitesimals are

    T = s1t + s2, X = c2x, U = c2 s1

    n u. (5.194)

    The similarity transformations are

    u = (s1t + s2)(c2s1)/(ns1) f(z), z = x (s1t + s2)

    c2/s1 , (5.195)

    where f(z) is satisfied by

    f

    2

    r7 fn

    f

    +

    2c2r7 zf

    2

    r7zfn+1

    2

    r7c2 s1s1 f = 0. (5.196)

    The H equation is a GEPT :

    HH

    n + 1

    n

    H

    2+

    2c2r7

    zH H 2r7

    H +2n

    r7zH+

    2n

    r7

    c2 s1

    s1

    H2 = 0. (5.197)

    Case 2.5(a) s1 = 0

    In this case the infinitesimals, (t) and similarity transformation are

    T = s2, X = c2x, U =c2n

    u, (t) = r7e2c2s2

    t, u = e

    c2ns2

    tf(z), z = xe

    c2s2t.

    (5.198)

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    The f and H equations are

    f

    2

    r7 f

    n

    f

    +

    2c2

    s2r7 zf

    2

    r7zf

    n+1

    2c2

    ns2r7 f = 0,(5.199)

    HH

    n + 1

    n

    H

    2+

    2c2s2r7

    zH H 2r7

    H +2

    r7zH+

    2n

    r7

    c2 s1

    s1

    H2 = 0.(5.200)

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    Case 2.6 = j = 0

    Equation (5.1) when = j = 0 is of the form

    ut + unux + u +

    xun+1 =

    (t)

    2uxx. (5.201)

    The infinitesimals are

    T = A0ent + B0, X = nc2x, U =

    A0ent + c2

    u. (5.202)

    The viscosity equation is

    =

    2nc2 A0entA0ent + B0

    , (5.203)

    which admits the following general solution

    (t) = r8e2nc2B0

    tA0e

    nt + B0

    2c2B0

    +1

    . (5.204)

    The similarity transformation is

    u = ec2B0

    tA0e

    nt + B0

    c2

    nB0+1/n

    , z = xe

    nc2B0

    tA0e

    nt + B0 c2B0 , (5.205)

    where f and H = fn satisfy

    f 2r8

    fnf +2nc2

    r8zf 2

    r8zfn+1 2

    r8(c2 + B0) f = 0.(5.206)

    HH

    n + 1

    n

    H

    2+

    2nc2r8

    zH H 2r8

    H +2n

    r8zH+

    2n

    r8(c2 + B0) H

    2 = 0.(5.207)

    Case 2.6(a) B0 = 0

    The infinitesimals are

    T = A0ent, X = nc2x, U =

    A0ent + c2

    u. (5.208)

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    The function (t) and the similarity transformation are

    (t) = r8exp

    2nc2

    A0 e

    nte

    nt

    , (5.209)

    u = etexp c2

    nA0ent

    f(z), z = x exp

    c2

    A0ent

    . (5.210)

    Here f and H are governed by

    f 2r8

    fnf +2nc2A0r8

    zf 2r8z

    fn+1 2c2r8A0

    f = 0, (5.211)

    HH

    n + 1

    nH

    2+

    2nc2

    A0r8

    zH H

    2

    r8

    H +2

    r8z

    H+2c2

    r8A0

    H2 = 0. (5.212)

    3. Result and Discussions

    We applied the Lies classical method to equation (5.1) and considered two case

    Tu = Xu = Uu = 0 and the general case separately. We list below the conditions

    imposed on the parameters appearing in the GBE

    ut + unux + ( +

    j

    2t)u + (+

    x)un+1 =

    (t)

    2uxx, (5.213)

    and all possible (t)s obtained for each such condition:

    1. = = j = 0

    1 = .

    2. j = = 0

    2 = r3

    A0ent + B0

    1

    , 3 = r0ent, 4 = r1.

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    3. = = = 0

    5

    = r4t2nc2C0

    1 C0

    + D0tjn21

    2nc2

    C0[ jn2 1]1

    , 6

    = r4C

    0t + D

    0tjn2 1 ,

    7= r

    4t

    jn2 ,

    8 = r4t2nc2C0

    1, 9 =

    r4t

    , 10 = tjn2 exp

    4nc2

    D0(2jn)t1 jn2

    , 11 = r2t.

    4. = = 0

    12 = r5

    C0t + D0tjn2

    1, 13 = r5t

    jn2 , 14 =

    r5t

    .

    5. = = 0

    15 = r6t2nc2C0

    1

    C0 + D0tjn2 1

    2nc2C0(

    jn2 1)

    1, 16 = r6t

    jn2 exp

    4nc2

    D0(2jn)t1 jn2

    ,

    18 = r1t.

    6. = = j = 0

    19 = r7 (s1t + s2)2c2s1

    s1 , 20 = r7e2c2s2

    t.

    7. = j = 0

    21 = r8e2nc2B0

    tA0e

    nt + B0

    2c2B0

    +1

    , 23 = r8exp

    2nc2

    A0ent

    et.

    An important contribution of the present work is the generalization of the Euler-

    Painleve transcendent (5.17) to a generalized EPT in the form

    HH + aH2

    + A(z)HH + B(z)H2 + bH + C(z)H+ c = 0, (5.214)

    (see for instance (5.39), (5.46),(5.89) (5.97)). Indeed the similarity reductions of

    ut + unux +

    j

    2tu +

    xun+1 =

    r1t

    2uxx,

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    ut + unux +

    j

    2tu +

    xun+1 =

    r62

    t2nc2C0

    1

    C0 + D0tjn21 2nc2

    C0(jn2 1)

    +1

    uxx,

    ut + un

    ux +j

    2tu +

    xun+1

    =r62 exp

    4nc2D0(2jn) t

    1 jn

    2

    tjn

    2 uxx,

    ut + unux +

    j

    2tu +

    xun+1 =

    r62

    t2nc2C0

    1uxx,

    ut + unux + u

    n+1 =

    2uxx,

    ut + unux + u + u

    n+1 =r32

    A0e

    nt + B01

    uxx,

    ut + unux + u + u

    n+1 =r02

    uxx,

    ut + unux + u + un+1 = r02

    entuxx,

    ut + unux +

    j

    2tu + un+1 =

    r52

    tjn/2uxx,

    ut + unux +

    j

    2tu + un+1 =

    r52t

    uxx,

    ut + unux +

    xun+1 =

    r72

    (s1 + s2)2c2s11

    uxx,

    ut + unux +

    xun+1 =

    r72

    e2c2s2

    tuxx,

    ut + unux + u +

    x

    un+1 = r8

    2e2nc2B0

    tA0e

    nt + B0

    2c2B0

    +1

    uxx,

    ut + unux + u +

    xun+1 =

    r82

    exp2nc2

    A0ent

    etuxx,

    are transformed via f = H1/n to (5.214). Equation (5.214) is more general than

    (5.17) in the sense that the former contains an extra term C(z)H. And when

    A(z), B(z), C(z) are constants then an exact solutions of (5.214) in terms of an ex-

    ponential function can be determined. It is also evident from the general form of the

    f-equation viz.,

    f + p(z)f + qf + rfnf + s(z)fn+1 = 0. (5.215)

    The condition A,B,C are constants is equivalent to p(z), s(z) are constants. And in

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    this case by splitting (5.215) into two equations f+p(z)f+qf = 0, rfnf+sfn+1 = 0

    one can easily see that f-equation admits an exponential solution. We also obtain

    solutions of f-equations and hence those of H-equations in terms of error functions

    by linearizing the f equation when p(z) is linear in z and s(z) is a constant in (5.215).

    Here we first obtain an intermediate integral of the f-equation in terms of Bernoullis

    equation and is easily linearized. The linear first order equation is shown to have

    exact solutions in terms of an error function.(see (5.116), (5.136)).

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