SURVEYING I (15CE21T) · UNIT – 2 COMPASS SURVEYING 1 Explain whole circle bearing (WCB) system with a neat sketch. 5 Nov – 2016 2 Explain the temporary adjustments of compass

SURVEYING – I (15CE21T)

Question Bank – Unit Wise Department of Civil Engineering [ Jain Polytechnic,Belagavi ] Page 1

f

UNIT – 1 INTRODUCTION & CHAIN SURVEYING

Sl. No. Questions Marks Year

1 What are the primary divisions of surveying?

Explain any one of them. 5 Apr– 2016 & 2017

2 What is ranging? Explain direct ranging with neat

sketch. 5 Apr– 2016 & 2017

3 What are the points to be considered while

selecting survey stations? 5 Apr– 2016/,NOV18

4 Explain with a neat sketch the stepping method of

chaining on sloping ground. 5 Apr– 2016 & 2017, nov 19

5 What is meant by offset? Explain clearly how the

perpendicular offset is taken using a cross staff 4 Apr– 2016

6

The length of a survey line was measured with a

20m chain and was found to be equal to 1200m. As

a check the length was measured with a 30m chain

and was found to be 1212m. On comparing 20m

chain with the test got it was found to be

1decimeter too long. Find the actual length of the

30m chain used.

6 Apr– 2016 & 2017

7 List the classification survey based on object of

survey. OR Nature of field 5 Nov – 2016/18

8 State the conditions to be satisfied by survey lines

and survey stations in chain surveying. 5 Nov – 2016

9 Define geodetic surveying. 2 Nov – 2016

10 Explain i. Cumulative error,

ii. Compensating error in chain surveying. 4 Nov – 2016

11

A 30m chain was found to be 0.15m too long after

chaining a distance of 5000m. It was found to be

0.3m too long after measuring a total distance of

10000m. At the start of survey work, a chain was

tested and was found to be exactly 30m in length.

Find out the correct length of the measured

distance.

8 Nov – 2016 & 2017

12

Plot the following field details of cross staff survey

and calculate the total area, all measurements being

taken in meters.

6 Nov – 2016 & 2017/18

13 Explain the principles of surveying 5 Apr-2018, NOV 19

14 List the errors in chain surveying. 5 Apr-2018

15 List the tallies used in metric chain 2 Apr– 2018



16

A 20m chain was found to be 0.10m too long after

chaining a distance of 1500m. It was found to be

0.18m too long after measuring a total distance of

2900m. At the start of survey work, a chain was

tested and was found to be exactly 20m in length.

Find out the correct length of the measured

distance.

8

Apr– 2018

17 What is cross staff survey? Mention applications. 5 NOV 2019

17 With neat sketch explain reciprocal ranging 4 Apr– 2018, NOV 18, NOV

19

18

Plot the following field details of cross staff survey

and calculate the total area. All dimensions taken in

m

6 Apr– 2018

19 What are the obstacles in chain surveying 5 Nov-18, Nov 19

20 Mention instruments used for setting right angle and

explain cross staff survey. 5 Nov 19

21

A 20m chain was found to be 20 cm too short after

chaining a distance of 200m. What is true length of

line?

5 Nov 19

UNIT – 2 COMPASS SURVEYING

1 Explain whole circle bearing (WCB) system with a

neat sketch. 5 Nov – 2016

2 Explain the temporary adjustments of compass. 5 Nov – 2016, nov 19

3 Define true meridian and magnetic meridian. 4 Nov – 2016

4

In a regular pentagon of side 5m, calculate interior

angles and bearings of all other sides, if the F.B. of

one of its side AB = 45 degree.

6

Nov – 2016

5

Find the true bearing of line AB if magnetic

bearing of line is 48 24’. Take declination as

i. 5 38’E

ii. 8 34’W

4

Nov – 2016

6 Explain with a neat sketch the cross section of

magnetic needle present in the prismatic compass. 6 Nov – 2016, NOV 19

7 Give the comparison between prismatic compass

and surveyor’s compass. 5 Apr– 2016 & 2017

8 Explain quadrantal bearing system with the neat

sketch. 5

Apr– 2016, Apr 2017, NOV

19

9 Differentiate between (i) F.B. & B.B.

(ii) closed & open traverse 5 NOV 19



9

Define the following with neat sketch.

i. Fore bearing

ii. Back bearing

4

Apr– 2016 & 2017

10 Convert the following Q.B. to W.C.B. and W.C.B.

to Q.B. 6

Apr– 2016 & 2017 Nov-18,

nov 19

11

Compare W.C.B. & R.B.

i. S 36 40’E

ii. S 38 10’W

iii. N 26 30’W

a. 96 20’ b. 194 40’ c. 320 20’

5 Nov 19

11

The following bearings were observed in running a

closed compass traverse.

Line FB BB

AB 150 00’ 329 45’

BC 77 30’ 256 00’

CD 41 30’ 222 45’

DE 314 15’ 134 45’

EA 220 15’ 40 15’

At what stations do you suspect local attraction?

Determine the corrected bearings.

What is Local Attraction? (2M)

Line FB BB

AB 32 30 214 30

BC 124 30 303 15

CD 181 00 1 00

DE 289 30 108 45

10

Apr– 2016 & Nov – 2017

,Nov-2018

12 Compare Prismatic compass with surveyors’

compass 5 Apr– 2018

13 Explain procedure to identify local attraction 5 Apr– 2018

14 Define Magnetic Dip and Magnetic Declination 3 Apr– 2018

15



Line FB BB

AB 45º 45’ 226º10’

BC 96º55’ 227 º5

CD ‘29 º45 ‘229 º10’

DE 324 º48’ 144 º48’



10 Apr– 2018



16



Line FB BB

AB 150º 0’ 330º0’

BC 230º30’ 48º0

CD 306º15 127 º45’

DE 298 º00’ 120 º00’

EA 49 º30’ 229 º30’



10 NOV 19

16 Find the magnetic declination at a place if the

magnetic bearing of the sun at noon is (a) 184º

(b) 350º 20’

6

Apr– 2018

17 Explain parallax and its elimination 5

Apr– 2018

18 Compare Chain Survying to compass Surveying 5 Nov-18

UNIT – 3 LEVELLING

1 List the different types of bench marks. Explain GTS bench mark.

5 Apr– 2016 & 2017

2 What is parallax? How it is eliminated. 5 Apr– 2016 & 2017 Nov-18

3 The following staff readings were observed

successively with a level, the instrument having

been moved after third, sixth and eighth readings:

2.228, 1.606, 0.988, 2.090, 2.864, 1.262, 0,602, 1.982, 1.044, 2.684m.

Enter the above readings in a page of level book

and calculate the R.L. of the points, if the first

reading was taken with a staff held on a B.M. of 432.384m

10

Apr– 2016/ Apr– 2018

4 Give the comparison between H.I. method and rise and fall method.

4/5 Apr– 2016 & Nov – 2017

Apr– 2018, NOV 19

5 Explain differential leveling with a neat sketch. 6 Apr– 2016

6 Define the following terms used in leveling:

a. Level surface

b. Level line

c. Datum

d. M S L

e. B S

f. Line Of collimation g. GTS Bench Mark

5

Apr– 2016, Nov-18, Nov 19



7 The following staff readings were taken with a

dumpy level and 4m staff on continuously sloping

ground: 1.680, 2.470, 3.550, 0.680, 1.200, 2.050, 3.800, 1.200, 1.600, 1. 850, 3.600, 1.800, 2.500,

3.500. Rule out complete page of level book and

find out R.L. of points by rise and fall method.

Apply arithmetic check. The first reading taken on a B.M. of R.L. 150.000m.

10

Apr– 2016 & Nov – 2016,

2017/Apr– 2018, nov 19

8 Explain permanent bench mark and temporary bench mark.

5 Apr– 2016 & Nov - 2016

9 Explain the temporary adjustments of dumpy level. 6 Apr– 2016 Nov-18, nov 19

10 Give the comparison between H.I. and rise and fall method.

4 Apr– 2017

11 Define the terms in leveling : (i) Datum (ii)

Elevation (iii) vertical angle (iv) MSL (v) Bench

mark

5

Apr– 2018

12 Define the terms in leveling : (i) BS (ii) IS (iii) FS (iv) CP (v) HI

5 Apr– 2018, Nov-18

13 List the errors in leveling 5 Apr– 2018 Nov-18

14 List Different types levelling Explain fly levelling 5 Nov-2018, NOV 19

15 List points to be remembered while reading & entering staff reading in level book

4 NOV19

UNIT – 4 LEVELLING – APPLICATION

1 What are the uses of longitudinal section and cross section?

5 Apr– 2016 & 2017

2 List the instrumental errors in leveling. 5 Apr– 2016 & Nov - 2017

3 In a running fly level from a bench mark of R.L.

183.125m, the following readings were obtained.

B.S.- 1.215, 2.035, 1.980, 2.625

F.S.- 0.965, 3.830, 0.980

From the last position of the instrument, 5 pegs at

20m interval are to be set out on the given gradient.

10

Apr– 2016

4 Explain briefly how the grade pints are established.

Explain the procedure for establishment of sewer

gardes

5

Apr– 2016, Nov-18

5 Explain clearly how the longitudinal setting is plotted.

5 Apr– 2016, Nov-18

6 Explain with a neat sketch profile leveling. 6

Nov – 2016/ Apr– 2018, Nov-18



7 In running fly levels from a bench mark of R.L.

360.650m, the following readings were obtained:

B.S.- 0.964, 1.632, 1.105, 0.850, 0.396 F.S.- 0.948, 1.153, 1.984, 1.125

From the last position of the instrument 7 pegs at

10m intervals are to be set out on a uniform falling

gradient of 1 in 40. The first peg is to have R.L. of

360.000m. work out staff readings required for

setting the tops of the pegs on the given gradient

and enter the results in a level book form.

10

Nov – 2016 & 2017

8 List the personal errors in leveling. 5 Nov – 2016

9 Explain fly leveling with a neat sketch. 5 Nov – 2016

List the possible personal errors in compass surveying

4 Apr– 2018

10 Following the reading are observed with dumpy

level. The instruments moved after third and sixth

reading 2.220, 1.600, 2.085, 2.865, 1.265, 0.605, 1.985,

1,045, 2.685 The first reading is taken on BM of

432.850m

10/6

Nov-18, nov 19

11 In running fly levels from a bench mark of R.L.

360.650m, the following readings were obtained:

B.S.- 0.695, 1.630, 1.105, 0.850, 0.396 F.S.- 0.948, 1.153, 1.984, 1.125

From the last position of the instrument 7 pegs at

10m intervals are to be set out on a uniform falling

gradient of 1 in 40. The first peg is to have R.L. of

360.000m. work out staff readings required for

setting the tops of the pegs on the given gradient and

enter the results in a level book form.

6 Nov 19

12 Four sight pegs are to be erected over points A,

B, C & D is 74.500m. the sewer is on a gradient

of 1 in 200 raising from D to A. The RL of pegs

on surface ground are 76.300, 75.500, 75.650

respectively from A to D. find suitable Height of

boning rod and height of sight rail above pegs at

A, B & C.

10 Nov 19

11 The RL of a floor is 64.545 A staff reading on the

floor is 0.650 and the inverted staff reading to the

bottom of a beam is 3.015. find the height of the

beam above the floor and RL of the bottom the T-Beam

4

Nov-18

A B C D



12 A contractor asked to set sewer grade form

following data. Find the height bonning Rod and

height sight at A , B and C Gradient 1 in 150 from A to D invert of 60 m. the

height of sight at d is 1.75m

7

Nov-18

UNIT – 5 CONTOURING

1 Define the terms: a. contour, b. contouring, c. contour line, d. contour interval, e. horizontal equivalent.

5 Apr– 2016 & 2017 and Nov

– 2017

2 What is contour. List the uses of contours. 5 Apr– 2016 Nov-18, nov 19

3 What is direct contouring? Explain the field procedure.

5 Apr– 2016

4 List the characteristics of contours. 5

Nov – 2016 & Apr– 2017/ Apr– 2018, Nov-18, nov 19

5 Explain the radial method of contouring with a neat sketch.

5 Nov – 2016/ Apr– 2018

6 What is meant by interpolation of contour? List the three methods.

4 Nov – 2016 & 2017/ Apr–

2018

7 List the advantages and disadvantages of direct method of contouring.

4 Nov – 2016

8 Explain block leveling with neat sketch. 6 Nov – 2016

9 Mention the methods of locating Contours. 5 Apr– 2018

10 List the uses of contour maps 5 Apr– 2018

11 Explain procedure followed for having horizontal control in direct method of contouring.

5 Apr– 2018

12 The area enclosed by contours in lake are under as follow.

6

Nov-18, nov 19 UNIT – 6 AREAS & VOLUMES

1 Write the formulae with notations to calculate the volume of earth work by

i) Trapezoidal rule ii) Prismoidal rule

4

Apr– 2016

2 The following offsets were taken from a chain line

to an irregular boundary line at an interval of 10 m

0.0, 2.50, 3.50, 4.60, 3.20, 0.0 m

Calculate the area between the chain line, the

irregular boundary line and the end offsets by i) Trapezoidal rule ii) Simpson’s rule

6

Apr– 2016/17

Nov 2017



3 A road at a constant RL of 180.000 runs north +

South. The ground east to west is level. The surface

levels along the centre line of the road are as

follows: (H in ‘m’ – 0,30,60,90,120,150,180.

Level in ‘m’- 183.50, 182.45, 182.15, 181.55,

, 182.05, 180.80. Compute the volume of earth work by

i) Trapezoidal method

ii) Prismoidal method

Adopt width of road formation as 8 m & side slope

1:5:1

10

Nov – 2016/17

4 Write the formula to calculate the cross section area of an earthen embankment with neat sketch for level section

2

Nov-18

5 A road at a constant RL of 180.000 runs north +

South. The ground east to west is level. The surface

levels along the centre line of the road are as

follows: (H in ‘m’ – 0,30,60,90,120,150,180.

RL in ‘m’- 117.50, 116.25, 115.95, 116.65, 117.20,

117.85, 115.70. Compute the volume of earth work

by

iii) Trapezoidal method

iv) Prismoidal method Adopt width of road formation as 8 m & side slope 1:5:1

10 Nov 19

6 The following perpendicular offsets were taken from chain line to an irregular boundary

8

Nov-18

Chainage Offsets in M 0 15.50

10 26.20

25 31.80

40 25.60

60 29.00

75 31.50

Engineering Drawing-II [15CE22D]

Question Bank – Unit Wise Department Civil Engineering [Jain Polytechnic, Belagavi] Page

Unit – 1 PROJECTION OF SOLIDS

S No Questions Marks Appeared in

1. A square pyramid of base edge 40mm and 60mm long has one of its shorter edges on HP. The axis of the pyramid is inclined at 30° to the HP and appears to be inclined at 45° to the VP. Draw the projections

if the apex is near to the observer.

15

April 16

2 A cylinder of 40mm diameter and axis height 60mm is resting with its ends of the base diameter on HP. The axis of the cylinder is inclined at 30° to the HP and appears to be inclined at 45° to VP. Draw the projections.

15

April 16

3 A cube of 30 mm side rests one of its edges on HP such that one of the

square faces containing that edge if inclined at 30° to HP & the edge on

which it rests being inclined at 60° to VP Draw its projection

15

April17

4

A Hexagonal prism of 25 mm side of base and axis 60mm long is placed

with one of its base edges on HP such that the axis is inclined at 450

to HP

and 450

to VP. Draw its projections.

15

April17

5 An equilateral triangular prism 20 mm side of base and 50mm long rests

with one of its shorter edge on HP such that rectangular face containing the

edge on which the prism rests is inclined at 300

to HP. The edge on which

the prism rests is inclined at 600

to VP. Draw its projections.

15

Nov 17

6 A Pentagonal pyramid 20 mm side of base and 35 mm altitude rests with one of its corners on HP such that the two base edges passing through the corner on which rests make equal inclinations with HP. The axis is inclined

at 450

to VP and 300

to HP. Draw the top and front views of the pyramid.

15

Nov 17

7 A hexagonal pyramid, base 30mmside and axis 60mm long has one of its

triangular face containing the slant edge on which it rests are equally

inclined to HP. The axis appears to be inclined at 450

to VP. Draw its

projections when its base is nearer to the observer than its apex.

15

April 18

8 Draw the projection of a pentagonal prism of base side 20 mm and axis

length 40 mm resting on a corner such that the two base edges passing

through it make equal inclination with HP and its base inclined at 60° to

HP and the axis appears to be inclined at 30° to VP in the top view.

15

April 18

9

A Hexagonal prism of 30 mm side of base and axis 60mm long is placed

with one of its base edges on HP such that the axis is inclined at 30° to HP

and axis appears to be inclined at 45° to VP. Draw its projections when the

base of the prism is nearer to observer.

15

Nov 18

10

A cone of base diameter 50mm and axis 80mm lies on HP with its axis

inclined at 45° to HP and appears to be inclined at 30° to the VP in the top

view. Draw top and front views of the cone

15

Nov 18

11 Draw the projection of a triangular prism of base side 30 mm and axis length

60 mm resting on a corner such that the two base edges passing through it

make equal inclination with HP and its base inclined at 60° to HP and the axis

appears to be inclined at 30° to VP in the top view.

15 Nov 19



12 A hexagonal pyramid, base 25mm side and height 55mm rests with one of its

triangular face on HP and axis appears to be inclined at 30º to VP in the top

view. Draw its top & front view.

15 Nov 19

Unit – 2 CONVERSION OF ISOMETRIC VIEWS INTO ORTHOGRAPHIC VIEWS

1

Draw three principal views of given Fig.

10

April 16

2


10

April 16

3


10

April 17,

nov 19



4


10

April 17

5


10

Nov 17

6


10

April 18

7


10

April 18



8

Draw three principal views of the components as shown in given Fig.

10

Nov 18

9

Draw three principal views of the components as shown in given Fig.

10

Nov 18

10 Draw three principal views of the components as shown in given Fig.

10 Nov 19



Unit – 3 ISOMETRIC VIEWS

1

Draw Isometric view of given object.

15

April 16

2

A cylindrical slab 100mm diameter and 40mm thick is supporting a cube of 50mm edge. On the top of the cube rests a square pyramid of

altitude 55mm and side of base 30mm such that the base edges of the pyramid are parallel to the edges of the top face. The axes of the solids are in the same straight line. Draw the isometric projection of the combination of the solids.

15

April 16 /

April 18

3


15

April 17

4

A Cube of side 40 mm is resting coaxially over a circular slab of diameter 80 mm and thickness 30mm.Draw the isometric view of the combination of the solid.

15

April 17

5 Draw isometric Top, front, and side view hexagon of side 30mm

15 Nov 17



6


15

Nov 17

7


15

April 18

8

Draw Isometric view of following objects whose orthographic views are given in figure.

15

Nov18



9 Draw Isometric view of following objects whose orthographic views are given in figure

15 Nov 19

10 Three cubes of sides 60mm, 40mm & 20mm are placed centrally one above the other. Draw isometric view.

15 Nov 19

Unit – 4 PERSPECTIVE PROJECTIONS

1

Draw the perspective view of a cube 25mm edge, resting on ground on

one of its faces. It has one of its vertical edges in the picture plane and all its vertical faces are equally inclined to the picture plane. The station

point is 55 mm in front of the picture plane. The station point is 55mm in front of the picture plane, 40mm above the ground and is in a central plane 9mm to the left of the centre of the cube.

15

April 16

2

15

April 17

3

A cube of 50mm side of base rests on ground such that one of the sqaure face is

inclined at 25° to the picture plane. The nearest vertical edge touches the picture plane.

The station point is 65mm infornt of the picture plane, 90mm above ground and lies

opposite to the nearest vertical edge that touches the picture plane. Draw the perspectie

view.

15

Nov 18



4 Draw perspective view of a square prism of 30mm side of base & height 40mm,

resting on ground on its base such that one of its rectangular face is inclined at 30º to

PP. The nearest vertical touches the picture plane. The station point is 45mm infront of

PP 65mm above ground & lies opposite to nearest vertical edge that touches picture

plane.

15 Nov 19

5

Draw one point parallel perspective view of the block shown below.

The station point is located at 80mm to the right of the centre of the

block and 100mm from the picture plane. The observers eyelevel is 60mm above the ground level.

15

Nov 17

6

15

April 18

Unit – 4 CROSS SECTION OF BUILDING COMPONENTS



1

Taking section through door, draw the cross setcion of wall for the

ollowing data. Adopt scale 1:50.

(a) Foundation: 1200mm wide and 1100mm deep with concrete bed

1:4:8 200mm thick and two courses of SSM in CM 1:6 450mm depth of

each course and 750mm and 600mm depth.

(b) Basement: SSM in CM 1:6, 450mm wide, 450mm depth which

includes 100mm thick plinth concret.

(c) Wall BBM in CM 1:6 of 300mm thick. Ceiling height 3.2m.

(d) Roof slab: RCC roof slab in CC 1:2:4 and 150mm thick

(e) Size of door: 1.0 x 2.1m

(f) Provide suitable parapet wall, flooring, WPC, lintel and chejja

10

April 16/

Nov 17

2 Show the conventional representation of Building materials in Section i)Brick ii) Stone iii) Concrete iv) Wood v) Glass

10 April 17/18

Nov 17

3

Draw the cross sectional details of load bearing wall for the following specifications (a) width of excavation: 900mm

Depth of excavation: 1100mm (b) Cement concrete bed: 900mm width and 250mm thick (c) Foundation consists of two steps of SSM

Size of first step – 600mmx 400mm Size of second step – 500mmx 450mm

(d) Basement course consists of SSM of 400mm width and 450mm depth. Height of plinth concrete – 150mm

(e) Burnt Brock masonry wall, 300mm thick for superstructure and 200mm thick for parapet wall

Take height of ceiling – 3m, RCC slab thickness – 120mm. Provide lintel (RCC) – 150mm thick Size of door: 1.0 x 2.1m Assume any other data required to draw section suitably. Scale: 1:50

10

Nov 18

Show details in sectional view of wall through door with chejja by following details: (a) Foundation : 1200mm wide 1100mm deep with concrete bed 1:4:8

200mm thick & two courses of SSM in CM 1:6 Depth of course 450mm, 750mm & 600mm widths

(b) Cement concrete bed: 900mm width and 250mm thick (c) Basement: course consists of SSM of 450mm width. Height

of plinth concrete – 100mm (d) WALL: Burnt Brock masonry wall, 300mm thick for

superstructure and 200mm thick for parapet wall Take height of ceiling – 3m, RCC slab thickness – 120mm. Provide lintel (RCC) – 150mm thick Size of door: 1.0 x 2.1m Assume any other data required to draw section suitably. Scale: 1:50

10 Nov 19



Unit – 4 BUILDING DRAWING (Compulsory)

1

35

April 16

2

35

April 17



3

35

Nov 17

4

35

April 18



5

The line diagram of a building is shown in figure. The detailed specifications are

Foundation: Depth 1100mm from ground level. Provide two steps of size stone

masonry.

Cement concrete bed – 900mm width and 200mm depth.

Basement: 450mm high including plinth concrete of 1500 thick

Walls: Burnt brick masonry of 300mm thick Roof: RCC slab of 120mm thick.

Chejja: RCC chejja over opening 0.6mm projection.

Take ceiling height as 3.00m and lintel level at 2.10m from floor level.

Assume any other details required suitably.

Draw to scale 1:50 (i) Plan at sill level. (ii) section along X-X, (iii) Front elevation

Provide the following openings

Door D – 1.0m x 2.1m, Door D1 – 0.9m x 2.1m, Window W – 1.8m x 1.2m,

Window W1 – 1.2m x 1.2m, Ventilator V – 0.6m x 0.45m

35

Nov18



The line diagram of a building is shown in figure. The detailed specifications are

Foundation: Depth 1100mm from ground level. Provide two steps of size stone

masonry.

Cement concrete bed – 900mm width and 200mm depth.

Basement: 450mm high including plinth concrete of 1500 thick

Walls: Burnt brick masonry of 300mm thick Roof: RCC slab of 120mm thick.

Chejja: RCC chejja over opening 0.6mm projection.

Take ceiling height as 3.20m and lintel level at 2.10m from floor level.

Assume any other details required suitably.

Provide the following openings

Door D – 1.0m x 2.1m

Window W – 1.2m x 1.2m.

Draw to scale 1:50

(i) Plan at sill level.

(ii) (ii) section along A-A,

(iii) (iii) Front elevation.

35 Nov 19

Documents

SURVEYING I (15CE21T) · UNIT – 2 COMPASS SURVEYING 1 Explain whole circle bearing (WCB) system with a neat sketch. 5 Nov – 2016 2 Explain the temporary adjustments of compass