SUN'SKAAR - Final Report on Capstone Project

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    CERTIFICATE 

    I hereby certify that the work which is being presented in the Capstone project entitled

    “SUN’SKAAR (Solar Car)” in partial fulfillment of the requirement for the award of

    degree of Bachelor of technology and submitted in Department of Mechanical Engineering,

    Lovely Professional University, Punjab is an authentic record of my own work carried out

    during period of Capstone under the supervision of Pankaj Saini, Asst. Professor,

    Department of Mechanical Engineering, Lovely Professional University, Punjab.

    The matter presented in this report has not been submitted by me anywhere for the award of

    any other degree or to any other institute.

    Date: …………..  VIKAS KUMAR, MUKESH ADLAK,

    PRATUL VISHWAKARMA, MAHESH NYATI,

    RAJEEV KURREE, SAGAR CHIKKA

    This is to certify that the above statement made by the candidate is correct to best ofmy knowledge.

    Date: ………….. PANKAJ SAINI 

    BIKASH KANT

    MANDEEP SAINI 

    Mentor 

    Department of Mechanical

    L ov e ly P rof  e s si o n a l U n i v er si t y Ja 

    Engineering 

    l a n d h a r , P unjab 

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    SUN’SKAAR (SOLAR CAR) 

    i

    ACKNOWLEDGEMENT

    I would like to place on record my deep sense of gratitude to Mr. Pankaj Saini Sir,

    Assistant Professor at Lovely Professional University, Jalandhar for his generous guidance,

    help and useful suggestions.

    I express my sincere gratitude to Mr. Bikash Kant Sir, Assistant Professor at Lovely

    Professional University, Jalandhar for his stimulating guidance, and continuous encouragement

    .

    I also wish to extend my thanks to Mr. Mandeep Saini Sir, Assistant Professor at

    Lovely Professional University, Jalandhar for his stimulating guidance, and continuous

    encouragement.

    I am extremely thankful to Mr. Gurpreet Singh Phul Sir, HOS, Lovely Professional

    University Jallandhar, for valuable suggestions and encouragement and for providing the

    opportunity to get the knowledge.

    .

    Date: ……………… VIKAS KUMAR, MUKESH ADLAK,

    PRATUL VISHWAKARMA, MAHESH NYATI,

    RAJEEV KURREE, SAGAR CHIKKA 

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    SUN’SKAAR (SOLAR CAR) 

    ii

    TABLE OF CONTENTS 

    Page No.

     Acknowledgement   i 

    Table of Contents ii-iii

     List of Tables  iv

     List of Figures  v-vi

     List of Nomenclature vii

     List of Abbreviations vii

    Chapter 1: Introduction 1

    1.1: Objectives 1

    Chapter 2: Literature Review 2-3

    Chapter 3: Future Scope of the Study 4

    Chapter 4: Research Methodology 5-12

    4.1: 200+ km mileage 5

    4.2: 1kw electricity generation by Sun 6-7

    4.3: Aerodynamic design & great look for the vehicle 8

    4.4: 40 km/h speed 9-12 

    Chapter 5: Production Plan / Gantt Chart 13-15

    Chapter 6: Research & Experimental work done 16-62

    6.1: Design & Bodyworks 16-21

    6.1.1: Chassis 16-20

    6.1.1.1: Material Selection 16

    6.1.1.2: Dimensional Specifications 16

    6.1.1.3: Chassis Loading & Simulation 17-20

    6.1.2: Bodyworks 21

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    iii

    6.2: Power Transmission 22-26

    6.2.1: Formulas 22-23

    6.2.2: Calculations 24-26

    6.3: Suspension 27-35

    6.4: Braking & Wheels 36-43

    6.4.1: Braking 36-40

    6.4.2: Wheels 40-43

    6.5: Steering 44-56

    6.5.1: Steering Dynamics 44-50

    6.5.2: Steering mechanism 51-52

    6.5.3: Ackerman Steering Geometry 52-56

    Chapter 7: Cost Report 57-62

    7.1: ECE Components 57-59

    7.2: Mechanical Components 60-62

    Chapter 8: Results & Discussion 63-66

    8.1: Detail Specifications & Features 63-66

    Chapter 9: Conclusion & Summary 67-68

    9.1: Highlights 67

    9.2: Advantages 67-68

    Chapter 10: Pictures / Images 69-72

    References

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    List of Tables

    Table Title Page

    5.1 Production plan / Gantt chart………………………………………………….13 

    6.1 Dimensions for Suspension calculation………………………...…..................27

    6.2 A-arm data…………………………………………………............................ 27

    6.3 Spring specification. ........................................................................................ 32

    6.4 Data for braking calculation ….. .....................................................................36

    6.5 Braking Specification........................................................................................39

    6.6 Dimensions of vehicle………………………………………………………...54 

    6.7 Formulaes for Steering…………………………………………….……….....54

    7.1 Cost Report for Electronics components………………………….…………..57

    7.2 Cost report for Mechanical components………………………….…………...60

    8.1 Engine & Transmission specification…………………………………………63 

    8.2 Performance data……………………………………………………………...64 

    8.3 Other specification…………………………………………………………….64 

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    v

    LIST OF FIGURES

    FIGURE CONTENT Page no.

    Fig 4.1- Solar cells 6

    Fig 4.2- CAD model of SunsKaar in Solidworks 8

    Fig 4.3- Hall sensor test circuit 10

    Fig 4.4- Hall sensor test(Pull Up) 10

    Fig 4.5- Oscilliscope image 11

    Fig 6.1- Front impact (Horizontal displacement) 17

    Fig 6.2- Static loading (vertical bending) 18

    Fig 6.3- Rear Impact (horizontal deflection) 19

    Fig 6.4- Torsion Test 20

    Fig 6.5- A Arm data 27

    Fig 6.6- Lateral weight transfer during the Left turn of vehicle 28

    Fig 6.7- Longitudnal Weight transfer During Braking 29Fig 6.8- Cornering force 30

    Fig 6.9- Camber calculation 31

    Fig 6.10-Tire axis system 31

    Fig 6.11- Spring Deflection due to load applied: 32

    Fig 6.12- King pin inclination 33

    Fig 6.13- Geometry of front suspension 34

    Fig 6.14-Geometry of front suspension(angle calculation) 34

    Fig 6.15a- Mounting of front suspenion(left) 35

    Fig 6.15b- Mounting of front suspenion(right) 35

    Fig 6.16- Geometry of Rear Suspension: (leaf spring) 35

    Fig 6.17- Tyre rating 41

    Fig 6.18- A front-wheel-steering vehicle and the Ackerman condition. 44

    Fig 6.19- A front-wheel-steering vehicle and steer angles of the inner and outer wheels 45

    Fig 6.20- Equivalent bicycle model for a front-wheel-steering vehicle. 49

    Fig 6.21- Eff ect of w/l on the Ackerman condition for front-wheel-steering vehicles 50

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    vi

    Fig 6.22- A sample parallelogram steering linkage and its components. 51

    Fig 6.23- A rack-and-pinion steering system 52

    Fig 6.24- Ackermans Angle 53

    Fig 10.1- Sunskaar at Auto expo 69Fig 10.2- Sunskaar interior 70

    Fig 10.3- Pvc modelling 71

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    vii

    NOMENCLATURE

    English Symbols

    θ  Angle

    Fd Drag Force

     ƥ  Density

    π   Constant  

     µ Friction Coefficient

    ABBREVIATIONS

    ATDC After Top Dead Center

    BDC Bottom Dead Center

    BTDC Before Top Dead Center

    CA Crank Angle

    CAD Computer Aided Design

    CCS Combined Charging System

    CFD Computational Fluid Dynamics

    CO Carbon Monoxide

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    Chapter 1

    Introduction

     ________________________________________________________

    A car made by innovative engineers of Lovely Professional University which can

    contribute its role in the daily life of a common man. Our Solar Car deserves to be among

    the highest mileage vehicle currently present in Indian market which is made with

    minimum expenditure having high efficiency.

    Our car gets energy from the ultimate power source “The SUN” and can be charged by

    home electricity. Home appliances can also run using the energy from our car.  We are also

    introducing some hi-tech features in it which can be useful for safety & security purposes.  

    1.1 Objectives: 

    1) 

    Start a new chapter in the field of renewable energy resources.

    2)  Introduce an ecofriendly option for automotive sector.

    3) 

    Produce safe and clean energy.

    4)  To provide a safer and clean environment.

    5)  Increase the life of Human being.

    6)  Create a better future for ourselves.

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    Chapter 2

    Literature Review

     ________________________________________________________

    Solar cars combine technology typically used in the aerospace, bicycle, alternative

    energy and automotive industries. The design of a solar vehicle is severely limited by the

    amount of energy input into the car. Most solar cars have been built for the purpose of solar car

    races. Since 2011 also solar-powered cars for daily use on public roads are designed List of

    solar cars (with homologation).

    Solar cars are often fitted with gauges as seen in conventional cars. To keep the car

    running smoothly, the driver must keep an eye on these gauges to spot possible problems. Cars

    without gauges almost always feature wireless telemetry, which allows the driver's team to

    monitor the car's energy consumption, solar energy capture and other parameters and free the

    driver to concentrate on driving.

    Solar cars depend on PV cells to convert sunlight into electricity. Unlike solar thermal

    energy which converts solar energy to heat for either household purposes, industrial purposes

    or to be converted to electricity, PV cells directly convert sunlight into electricity.[1] When

    sunlight (photons) strike PV cells, they excite electrons and allow them to flow, creating an

    electrical current. PV cells are made of semiconductor materials such as silicon and alloys of

    indium, gallium and nitrogen. Silicon is the most common material used and has an efficiency

    rate of 15-20%.

    During the 1990s, regulations requiring an approach to "zero emissions" from vehicles

    increased interest in new battery technology. Battery systems that offer higher energy density

     became the subject of joint research by federal and auto industry scientists. 

    Solar cars were first built by universities and manufacturers. The sun energy collector areas

     proved to be too large for consumer cars, however that is changing. Development continues

    on solar cell design and car power supply requirements such as heater or air-conditioning fans.

    http://en.wikipedia.org/wiki/Solar_car#cite_note-1http://en.wikipedia.org/wiki/Solar_car#cite_note-1http://en.wikipedia.org/wiki/Solar_car#cite_note-1http://en.wikipedia.org/wiki/Solar_car#cite_note-1

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    The Stanford Solar Car Project is America's top solar car team. The project began in

    1989 and is an entirely student-run, non- profit organization fueled by its members’ passion for

    environmentally sustainable technology. The team designs and builds solar powered cars to

    race in the 2000 mile long World Solar Challenge in the Australian Outback.

    Powered solely by the sun, this single-seat race vehicle uses the same amount of energy

    that it takes to power a hair-dryer. On a closed test course, infimum reached speeds of over 105

    mph. Building the solar car is a two year project that takes over 100 student team members and

    more than 1 million dollars.

    That's the allure of the solar car, in many ways the Holy Grail of clean energy transport.

    It came one step closer to reality this week with Ford Motor debuting its C-MAX Solar Energy

    Concept car at Consumer Electronics Show (CES) 2014 in Las Vegas. (Related Quiz: What

    You Don't Know About Cars and Fuel)

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    Chapter 3

    Future Scope of the Study

     ________________________________________________________

    Solar Electric Cars are the future of world movement. The best feature of this car is that

    it is the pollution free. Solar car can save 3 Rs. Per km in comparison of petrol cars so it can

    save the big chunk of money for middle class people.

    3.1 Utility:

    1)  It works on clean energy.

    2)  Pollution free.

    3) 

    Economic.

    4) 

    Cost Efficient.

    3.2 Uniqueness:

    1)  Works on Solar Energy.

    2)  Mileage greater than any other vehicle present in India.

    3) 

    Clean and pollution free.

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    Chapter 4

    Research Methodology

     ________________________________________________________

    Research work on Solar Car started with following targets :

    4.1 200+ km mileage.

    4.2 1kw electricity generation by Sun.

    4.3 Aerodynamic design & great look for the vehicle.

    4.4 

    40 km/h speed.

    4.1 200+ km mileage:

    Mileage of vehicle depends on battery. So our technical team began to search

     best battery with less cost, compact size, light weight & higher capacity in Ah.

    We had two options first Exide and second one is Tata batteries. And we

    obtained Tata Battery with following specifications :

    Capacity : 80 Ah

    Voltage : 12 volts

     No. of Batteries : 8 (2 sets, 4 batteries in 1 set)

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    4.2 1kw electricity generation by Sun:

    Electricity generation depends on solar cells. The working & selection of solar cells

    discussed below :

    Solar cells

    ANALYZING & CRYTICAL THINKING:The solar cells are selected bytaking the

    following things into consideration

    1)Area of the cell Fig-4.1-solar cell

    2)Power delivered by the cell

    3)Availability of the cell

    4)Cost of the cell

    5)Manufacturing nation

    Here we have two main class of cells they are :

    1.Monocrystalline cells

    2.Polycrystalline cells

    Monocrystalline cells are choosen for the following reasons:

    Solar cells made of monocrystalline silicon (mono-Si), also called single-crystalline silicon

    (single-crystal-Si), are quite easily recognizable by an external even coloring and uniform look,

    indicating high-purity silicon.

    Monocrystalline Premium Line panels have a maximum efficiency of about 15.47%,

    whereas Conergy’s polycrystalline PowerPlus modules have a maximum efficiency of 14.13%. 

    HERE ARE FEW ADVANTAGES OF USING MONICRYSTALLINE CELLS:

    LONGITIVITY:

    Monocrystalline solar panels are first generation solar technology and have been around a

    long time, providing evidence of their durability and longevity. The technology, installation,

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     performance issues are all understood. Several of the early modules installed in the 1970′s are still

     producing electricity today.

    EFFICIENCY:Monocrystalline solar panels are able to convert the highest amount solar energy into

    electricity, thus if your goal is to generate the maximum possible electricity at your area,

    monocrystalline is an obvious choice.

    Solar panels products use cadmium telluride (CdTe). Cadmium is a heavy metal that

    accumulates in plant and animal tissues. Cadmium is a ‘probable carinogen‘. While Cadmium

    doesn’t pose a threat while the solar panel is in service, disposing of the panels has to be done

     properly, which often comes at a large cost.

    “Monocrystalline cells are not harmful or hazardous to the environment.” 

    MORE ELECTRICITY:

    Monocrystalline panels produce more electricity per m/2 than other panels.

     Now by taking all the above aspects into consideration the monocrystalline cells were selected .

    SPECIFICATIONS:

    Per a single cell:

    1)DIMENSIONS:150X150mm

    2)COST:2$

    3)OUTPUT VOLTAGE:0.56V

    4)OUTPUT CURRENT:8A

    For the whole set:

    1)OUTPUT VOLTAGE:48V

    2)OUT POWER:1KW(approximately)

    3)NUMBER OF SETS:2

    4)NUMBER OF CELLS IN EACH SET:96

    5)ALLIGNMENT OF CELLS:The two sets were connected parallel to produce a voltage of 48v

    and a power of 1KW.

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    4.3 Aerodynamic design & great look for the vehicle:

    Fig 4.2 CAD model of Sun’sKaar in Solidworks 

    Final Design of Solar Car has been prepared after rejection of more than 40 designs using

    Solidworks & NX (Unigraphics) softwares.

    Following factors were considered for final selection :

    1) 

    6 m^2 area for solar cells for generating 1kw solar electricity.

    2)  Esthetics & comforts for driver & passangers.

    3)  Safety.

    4)  Easy to install solar cells.

    5)  Dynamic look.

    6) 

    Easy to manufacture.

    7) 

    Aerodynamics of vehicle.

    Etc.

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    4.4 40 km/h speed:

    Speed & load carrying capacity of the vehicle depends on motor. Selection criteria of motor &

    it’s working is discussed below : 

    WORKING OF BRUSHLESS DC MOTOR

    Problem: The Brushless DC Motor is running incorrectly, or stops running. 

    Solution:  A Brushless DC Motor having difficulty operating could indicate that the Hall

    Sensors are bad. To check, use a resistor to pull up each Hall to 5 volts, and check each Hall

    with an oscilloscope while spinning the shaft. Monitor the point between the Hall and the

    resistor as pictured below in Figure 2.

    Repeat this process for each individual Hall. When spinning the shaft manually, a low

    and high signal should appear on the scope. Keep in mind the importance of what value is used

    for the resistance; this depends on the amount of current the Hall sensors can withstand.

    If this test demonstrates that the Hall Sensors are working correctly, the next step is to

    check the phases of the Brushless DC Motor. Hook up the Brushless DC Motor to a controller.

    With an oscilloscope, check each phase to see if a switching signal is present. If the phases do

    not pose a problem, this may indicate a bearing problem, or internal shorts. If these techniques

    do not seem to explain why the Brushless DC Motor is working improperly, the purchase of a

    new Brushless DC Motor should be considered.

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    Fig 4.3-Hall sensor test circuit

    Fig 4.4-Hall sensor test(pull up)

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    Fig 4.5-Oscilliscope Image

    The Hall Effect uses three hall sensors within the Brushless DC Motor to help detect the

     position of the rotor. This method is primarily used in speed detection, positioning, current

    sensing, and proximity switching. The magnetic field changes in response to the transducer that

    varies its output voltage. Feedback is created by directly returning a voltage, because the sensor

    operates as an analogue transducer. The distance between the Hall plate and a known magnetic

    field can be determined with a group of sensors, and the relative position of the magnet can be

    deduced. A Hall sensor can act as an on/off switch in a digital mode when combined with

    circuitry.

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    Controller to Motor Connection

    Yellow 2mm

    Green 2mm Phase Wire

    Blue 2mmYellow

    Green Hall

    Blue Effect

    Red

    Controller Input

    Red Input wires

    Black 48 V

    Green ->Throtal -> input VCC

    Pink->Throtal -> Output

    Black->Throtal -> Ground

    Yellow reverse/forward

    Black

    Two white wires -> limiting the speed

    Grey -> Speedometer

    Orange -> Dynamic Brake

    Orange (Thicker wire) -> Ignition

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    Chapter 5

    Production Plan / Gantt Chart

    The plan is divided into different phases. This is a table consists of the information

    which is required in production work and the things which will be used during production.

    Table 5.1 Production Plan / Gantt Chart 

    Sl

    no.

    Work Tools

    required/machine

    Other material Cost Mem

     bersrequi

    red

    Days

    requir ed

    1) Sketching of

    chassis

    Plywood-1

    Pencil,rubber,whites

    heet,measuringsacle

    27/10/13 2 2

    2) Pvc modeling Hand hacksaw Clip,nails,wire,

    Measuring scale

    30/10/13 3 3

    3) Making of

    space frame

    Power

    cutter,handhacksaw,

    welding machine

    Rectangular

     pipes(arrange from

    inside university)

    3/11/13 6 3-4

    4) Cutting of

     pipes

    Power

    cutter,handhacksaw,

    filer

    Cutter and grinder 5/11/13 4 2

    5) Welding of

     pipes

    Welding machine Welding elctrodes 7/11/13 4 2

    6) Chassis

    finishing

    Grinder Grinding wheel 8/11/13 2 1

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    7) Making of A

    arms

    Power cutter, hand

    hacksaw, welding

    machine

    Pipe,cutter,grinder 10/11/13 2 2

    8) Hub

    mounting and

    tire assembly

    in front

    Power cutter,

    welding machine

    Hub of

    wheel,tyre,nuts and

     bolts

    12/11/13 3 2

    9) Transmission

    assembly with

    motor.

    Power cutter and

    welding machine

    Tyre and motor hub

    assembly

    14/11/13 3 2

    10) Tyre

    mounting rear

    Power cutter Hub, tyre, nuts and

     bolts, with shaft

    16/11/13 2 1-2

    11) Brake

    mounting

    Power cutter Coupler, brake and

    caliper, nuts & bolts

    17/11/13 2 1

    12) Steering

    mounting

    Power cutter and

    welding machine

    Steering assembly,

     pipes, nuts and bolts

    19/11/13 3 1-2

    13) Seat

    mounting

    Power cutter Angles, nuts and

     bolts, rubber tubes

    20/11/13 2 1

    14) Body works

    frame

    Wood cutter, filer thermacole, nails,

    fevicol, wood

    22/11/13 3-4 2

    15) Body works As required Glass fibre material 20/12/13 4-5 15

    16) fitting of body

    works with

    chassis

    Power cutter and

    grinder

     Nuts and

     bolts,rubber tubes

    22/12/13

    3-4 2

    17) Finishing of

     body works

    Power cutter and

    files

    styrofoam,rubbertub

    es,sheet metal

    23/12/13 2-3 1

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    18) Wiring and

    innovation

    As required Plastic pipes, 28/12/13 2-4 5

    19) Solar panels

    on body

    As required Solar cells /solar

    sheets,wires,

    7/1/14 3 10

    20) Controller

    circuit

     between solar

     panels and

     battery

    As required Wires,PCB board

    and electrical

    components

    12/1/14 2 5

    21) Others As required 31/1/14 2 19

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    Chapter 6

    Research & Experimental work done

     ________________________________________________________

    6.1 DESIGN & BODYWORKS:

    6.1.1 CHASSIS: 

    IT is the backbone of any vehicle. Designed to bear all types of load whether long

    duration, short duration or impact load. It contains mounting space and points for all thecomponent of the vehicle. We used ladder type of chassis with different types of pipe thickness

    and diameter in different places where it is well suited. We used ladder chassis because of its

    rigidity and manufacturing simplicity.

    6.1.1.1 MATERIAL SELECTION:

    AISI 1020 was selected for the chassis because the following stated reasons:

    1.  Machinability (70%)

    2.  Weld ability

    3. 

    Availability

    The frame or chassis can be called as skeleton of a vehicle, beside its purpose being seating

    the driver, providing safety and incorporating other sub system of the vehicle.

    6.1.1.2 Dimensional Specifications

    Round pipe of dimension:

    25.4mm O.D

    2mm & 3mm THICKNESS

    AISI 1020 seamless mild steel pipes, normalized at 810°

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    6.1.1.3 CHASSIS LOADING AND SIMULATION

    Front impact (Horizontal displacement):

    Calculation:

    F = (mv2-mv1)/t

    Here, v2=0 ; ( since, it is assumed that after impact it will come to rest)

    F = (-mv1)/t; (here negative sign indicates that direction of impact force will be approx. to the

    velocity.)

     Neglecting the negative sign, we have;

    F=mv1/t

    The time t can be written as t=2x/u + v

    Here v=0 and u=v1,

    Therefore, F=mv2/2x; (x is distance travelled before stopping)

     Now, putting values, we have;

    M = 500kg, u = 40 km/hr = 11.1m/s , x = 2m

    F=15,401.25N

    Fig 6.1- Front impact (Horizontal displacement)

    Results:

    FOS = 1.52

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    Static loading (vertical bending)

    Total mass assumed -> 500 kg

     Now, total vertical static force including gravitational

    500 x 9.87 = 4905 N

    Fig 6.2- Static loading (vertical bending)

    Results:

    FOS = 3.04

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    Rear Impact (horizontal deflection)

    Force, F = (mv2-mv1)/tLet us assume that after back impact velocity gets 1.5 times more, therefore

    V2=3/2 v1

      F =mv1/2t

    Assume that vehicle moves distance x during this change, therefore time taken to

    cover this distance x,

    t = 2x/ (u+v) =2x/ (2.5u)

     F=(5/8)×(mu

    2

    /x)

     Now putting values

    M = 500kg, u = 40 km/hr = 11.1m/s , x = 2m

    F=19,251 N

    Fig 6.3- Rear Impact (horizontal deflection

    Results:

    FOS = 1.03

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    Torsion Test

    Four outer joints of back portion are fixed and opposite forces are applied at to outer

    links of front portion. Force on each outer linkF=1000 N

    Fig 6.4- Torsion Test

    Result:

    FOS = 7.75

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    6.1.2 Bodyworks

    Area of bodyworks -161 square feet

    Material required:

    high temperature wax v207, epoxy resin,curing agent(),5.8 oz fiberglass cloth 38”. 

    Chemical and its rates:

    Chemical Rates

    Epoxy resin(diglycidyle ether of bisphenol) - 160 per kg

    Curing agent(diethylanilenetriamine) - 390 per liter

    5.8 oz fiberglass cloth 38” - 160 per kg

    high temperature wax v207 - 600 per kg

    *Ratio of epoxy resin & curing agent is 10:1 (weight by volume) and it also vary according to

    the curve surface.

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    6.2 Power Transmission 

    6.2.1 Formulas:

    Power :

    P = TW

    Where : P = Power (Watt)

    T = Torque (Nm)

    W = Angular Velocity (rad/sec)

    Torque :

    T = F.r

    Where : T = Torque (Nm)

    r = Wheel Radius (m)

    F = Forces on Vehicle (N)

    F = Rolling Friction Force + Drag Force + Force due to Inclination

    o  Rolling Friction Force (Fr) = µ.m.g

    Where : µ = Rolling Friction coefficient = 0.02

    m = Mass of Vehicle (Kg)

    g = Gravity = 9.81 m/s^2

    o  Drag Force (Fd) = (Cd.ƥ.A.V^2)/2 

    Where : Cd = Drag Coefficient (depends on design)

     ƥ = Air Density = 1.2 Kg/m^3

    A = Area (Front) (m^2)

    V = Velocity of Vehicle (m/s) = R.W

    o  Force due to Inclination = m.g.sinθ 

    Where : m = Mass (Kg)

    g = Gravity = 9.81 m/s^2

    θ = Inclination Angle 

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    Angular Velocity :

    W = (2.π.N)/60 = V/r 

    Where : π = 3.14

     N = RPM of Wheel

    Gear Ratio :

    R = N1/N2 = T2/T1

    Where : N1 = RPM of motor or engine

     N2 = RPM of wheel

    T2 = Torque to wheel = No. of teeth of gear/sprocket 2

    T1 = Torque of motor or engine = No. of teeth of gear/sprocket 1

    Acceleration :

    a = F/m

    Where : F = Net force on vehicle (N)

    m = Mass of vehicle (Kg)

    a = Acceleration of vehicle (m/s^2)

    Time taken to attain top speed :

    t = (V2 –  V1)/a

    Where : a = Acceleration of vehicle (m/s^2)

    V2 = Final velocity of vehicle (m/s)

    V1 = Initial velocity of vehicle (m/s)

    Climbing ability :

    F = T2/r = Fr + Fd + mgsinθ 

    θ = ? 

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    6.2.2 Calculations:

    Force on vehicle :

    F = Fr + Fd + mgsinθ 

    F = µmg + (CdƥAV^2)/2 + mgsinθ 

    Where : m = 500 Kg

    Cd = 0.35

    A = 1.5 m^2

    V = 11.11 m/s = 40 Km/h

    θ = 0 

    (Note : Take θ = 0 because we made this car for plane surface only.)  

    F = 0.02x500x9.81 + (0.35x1.2x1.5x11.11^2)/2 + 0

    = 98.1 + 77.76

    F = 175.86 N

    Initial Torque required :

    Ti = Fr.r

    = µmg x r

    = 0.02x500x9.81x0.25

    Ti = 24.52 Nm

    Overall Torque required :

    T = F.r

    Where : r = 0.25 m

    T = 175.86x0.25

    T = 43.965 Nm

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    RPM Required :

    W = V/r2πN/60 = 11.11/0.25 

    2x3.14xN/60 = 44.44

    N = 424.58 rpm

    Power Required for Car :

    P = T.W

    = 43.965x44.44

    = 1953.8 Watt

    P = 1.9538 Kw

    After this calculations we selected 2 kw motor for our car with following specifications :

    P = 2 Kw

    T = 7 Nm (approx.)

     N = 3000 rpm

    Differential Specifications :

    Gear Ratio I : 7:1

    So, after selecting 7:1 gear ratio Torque & RPM to the wheels are :

     N1/N2 = T2/T1 = R

    Where : N1 = 3000 rpm

    T1 = 7 Nm

     N1/N2 = R

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    3000/N2 = 7/1

    N2 = 428.57 rpm

    T2/T1 = R  

    T2/7 = 7/1T2 = 49 Nm

    Acceleration of vehicle:

    F = ma

    T2/r = 500xa

    49/0.25 = 500xa

    a = 0.392 m/s^2

    Time taken to reach the speed of 40 Km/h or 11.11 m/s :

    a = (V2 –  V1)/t

    0.392 = (11.11 –  0)/t

    t = 28.34 seconds

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    6.3 Suspension 

    Vehicle Data

    It is a system of mechanical linkages, springs and dampers used to connect wheel to chassis. In

    a normal car a suspension system is needed to isolate the passengers from the uneven road

    surface and give a smooth ride but in a high performance car, passenger comfort is sacrificed

    for better handling and road holding.

    Table 6.1 : Dimensions for Suspension calculation 

    Table 6.2 : A-arm data

    A-Arm Data:

    Fig 6.5-A Arm data

    Dimensions Front Rear

    Wheel base 2500 mm NA

    Track width 1600 mm 1600 mmCurb Weight 500 kg

    Suspension System MacPherson strut Leaf spring with Hydrolic

    Damper

    Tire Stiffness

    Tire Radius 203.2 mm 203.2 mm

    Tire pressure

    Length of Swing

    Arm(L)

    254 mm

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    Roll Centre Height:

    H / (T/2) = R/L

    Where,

    H=roll centre heightT= Track width

    R=wheel Radius

    L= Swing arm length

    H= (T/2)×(R/L)

    H= (1600/2)×(203.2/254) H=640 mm

    Weight transfer Calculation 

    Lateral weight transfer during the Left turn of vehicle

     

    Fig 6.6- Lateral weight transfer during the Left turn of vehicle

    The Weight (W) of the car is evenly distributed among the four tires, so each tire has

    W/4=1716.7 force on its contact patch.

    Weight of the Body = 9.81×500

    =4905 N-m/s2

    Accelaration (A): 9.81 m/s2 

    WR ×T = W×T/2 +W×A×H 

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    WR =(4905×1.6 /2+500×1 G ×0.450) /1.6

    WR = 2593 N

     Now WL=W-WR  

    WL=2512 NWhere

    WR = Weight on right tire

    WL=weight on Left tire

    T=Track width

    H=Center of gravity height

    Weight transfered = WR -W/2

    =3630.3 -6867/2

    = 140.5 N

    Fractional Weight Transfered(FWT) = A×h/T =1G ×0.45/1.6

    FWT= 0.281 m/s2 

    Weight transfer(%)= FWT×100 (%)

    Weight transfer on right tire =28 % of the total weight

    Longitudnal Weight transfer During Braking

    Fig 6.7- Longitudnal Weight transfer During Braking 

    Wbrake×Wb = A×W×H

    W brake= (1×4905×0.45)/2.5

    W brake=882.9 N

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    Where,

    W brake= Weight transfer due to braking

    Wb= Wheel baseDuring braking at 1G 882.9 N comes off the rear tires and onto the front tire.

    Static weight distribution on was 2452.5 N on the front

    And the same on rear. Now we have 1569.6 N equally divided between the rear tires and 3335

     N on the front two tires.

    Camber Angle Calculation:

    Cornering force: 

    Fig 6.8-Cornering force

    α= Sliping angle 

    Fycosα= Cornering force ǁ to path of motion v.

    FySinα is perpendicular to V. 

    In static condition, the Total cornering force,

    Fy = (Wtotal ×V2)/Rg

    Here,

    V=40 km/hr =11.11m/s

    R=Turning radius

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    = 4.98 m

    Fy= 150×(11.11)2/4.98×9.81

    lateral camber force,Fy= 378.98 N

     Normal load, Fz =4905 NSo from the Graph, we can get the value of camber angle(ˠ) . 

    Fig 6.9-camber calculation

    Camber angle(ˠ)= 30 

    Here is the Tire axis system,

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    Fig 4.6-Tire axis system

     

    Spring Stiffness Calculation

    Diameter of spring wire (d) 16 mm

    Mean coil diameter (D) 101.6 mm

     Number of active coil (n) 9

    Shear Modulus of rigidity G 79.3 Gpa (steel)

    Spring force 2200 N

    Table 6.3  Spring specification

    By putting this value you can directly get spring stiffness from spring stiffness calculator at

    http://www.tribology-abc.com/calculators/t14_1.htm

    Spring stiffness= 10.5 KN/m

    Spring Deflection due to load applied:

    http://www.tribology-abc.com/calculators/t14_1.htmhttp://www.tribology-abc.com/calculators/t14_1.htm

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    Fig 6.11- Spring Deflection due to load applied

    Total weight = 4905 N

    Weight on one tyre= 1226 NMoment at fixed point z is zero, so

    (241×F’) + (368×1226)=0 

    F’=-1872 N

    Fig 6.12-King pin inclination

    As the Kingpin inclination is 100 , force on spring

    F”= f’ cos (100)

    F”=-1872×cos(100)

    F”=1571 N 

    So, deformation of the spring due to applied load,

    Stiffness= Force/Deflection

    Deflection= 1571/10.5

    Deflection of spring =14.6 cm

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    Geometry of Front Suspension

    Macphersion strut

    Fig 6.13-Geometry of front suspension

     

    Fig 6.14-Geometry of front suspension(angle calculation)

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    Fig 6.15a-Mounting of front suspension(left) Fig 6.15b-Mounting of front

    suspension(right)

    Geometry of Rear Suspension: (leaf spring)

     

    Fig 6.16- Geometry of Rear Suspension: (leaf spring) 

    Sin(45o)=BC/2.75

    BC=1.94 inch

    Cos(45o)= AB/2.75

    AB=1.94 inch

    CD2= AD2 + BC2 

    CD2 = (25.46)2 + (1.94)2 

    CD = 25.53 inc

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    6.4 Braking & Wheels

    6.4.1 Braking system

    Type of brake 1)Hydraulic drum brake in

    front

    2)wired drum brake in the

    Rear

    Weight of car 500 Kg

    Wheel base 2.5m

    Track width 1.6m

    Height of centre of gravityCoefficient of friction 0.7

    Speed of the vehicle 40km/hr

    Velocity of the vehicle 11.11m/s

    Table 6.4 Data for braking calculation

    Speed of the vehicle(V) =40km/h

    Mass of the vehicle(m) =500 kg

    Net force on vehicle(F) =Fr+Fd+mgsinθ

    = μmg + (CdƥAV^2)/2 + mgsinθ 

    = 0.02x500x9.81 +

    (0.35x1.2x1.5x11.11^2)/2 + 0

    = 98.1 + 77.76

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    F = 175.86 N

    Where :

    m = 500 Kg

    Cd = 0.35

    A = 1.5 m^2

    V = 11.11 m/s^2 = 40 Km/h

    θ = 0

    (Note : Take θ = 0 because we made this car for

     plane surface only.)

    Accleration of the vehicle=

    F=m*a

    a=F/m

    a=175.86/500

    a =0.39572 m/s^2

    Kinetic energy of the vehicle=

    K.E(car)=½*mv^2

    = ½*500*(11.11)^2

    =30858.025 J

    *since V2=0(final velocity after stopping will be zero)

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    Angular velocity of wheel=

    W1=v1/r

    =11.11/0.35

    =31.742rad/s

    Since w2 will be zero due to breaking action. Vehicle is coming to

    rest

    Kinetic energy of 4 wheels:-

    KE(wheels)  =4[1/2*I(W1^2-W2^2)]

    =4[1/2*(0.5)*(31.74)^2]

    =1007.42 J

    Total energy absorbed by four brakes consists of kinetic

    energy of car[e]=

    Total K.E=¼[kinetic energy of

    car+kinetic energy of wheel]

    =1/4[3085.025+1007.42]

    =7966.36 Joule

    Brake time[t]=

    (V1-V2)/t=0.395g

    (11.11-0)/t=0.395*9.8

    11.11/3.871=t

    t=2.8700s

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    Stooping Distance

    d = (V^2) / (a*2)

    =11.11^2/(0.39572*2)

    =6.97m

    Torque capacity of brake=

    θ =(W1/2)/t 

    =(31.472/2)*2.87

    =45.162

    Mt=E/ θ 

    =7966.36/45.162

    =176.395 N-m

    Where

    E=total energy absorbed by brake

    Mt=braking torque

    θ =angle through which the brake drums rotates during the braking

     period

    After calculation:-

    Net force on vehicle(F) 175.86 N

    Accleration of the vehicle 0.39572 m/s^2

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    Kinetic energy of the vehicle 30858.025 J

    Total energy absorbed by four

    brakes

    7966.36 Joule

    Brake time[t] 2.8700s

    Stooping Distance 6.97m

    Torque capacity of brake 176.395 N-m

    Table 6.5 Braking Specification

    6.4.2 Wheels

    In modern vehicles all the primary control and

    disturbance forces, which are applied to the vehicle, with the

    exception aerodynamic forces are generated, in the tire road

    contact patch. That has been said that ‘the critical control

    forces that determine how the vehicle turns, brakes and

    accelerates are developed in four contact patches ’.a thorough

    understanding of the relationship between tires, their operating

    conditions, and the resulting forces and moments developed at

    the contact patch is an essential aspect of the dynamics of the

    total vehicle.

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    The tires serves essentially three basic functions:

    • It supports the vehicle load, while cushioning against road

    shocks.

    • It develops longitudinal forces for acceleration and

     braking

    • It develops lateral forces while cornering

    As a mechanical structure, the elastic torus of the tire is

    composed of composed of a high flexible carcass of high

    tensile strength cords fastened to steel-cable beads that firmly

    anchor the assembly to the rim. The internal pressure stresses

    the structure in such a way that any external force causingdeformation in the carcass results in a tire reaction force. The

     behavioral characteristics of the tire depend not only on the

    operating conditions, but on the type of the construction as

    well.

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    Fig 5.1-Tyre rating

    Tyre rating 

    The tires being in the present go-kart are slick tires with the

    respective tire ratings:

    • Front tire rating –  20X 4 –  5.6

    • Rear tire ratings –  20 X 4 –  5.6

    Description: 

     Front tire- 20 X 4.00 – 

     5.6  

    • 20 inch= tire overall dia.

    • 4.00 inch = width of the tire

    • 12inch = tire rim dia.

     Rear tire – 

     20 X 4.0 –  5.6

    • 20 inch= tire overall dia.

    • 4.0inch = width of the tire

    • 12 inch= tire rim dia.

    Tire stiffness calculation: 

    Maximum mass of the kart = 500kg

    Weight of the kart = 500*9.81

    = 4905N

    weight on each front tire is = (4905*0.4)/2 = 981N

    weight on each rear tire is = (4905*0.6)/2 = 1471.5N

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    let the deflection under maximum pressure

    on front tire be = 3mm let the deflection

    under maximum pressure on rear tire be =

    4mm

    stiffness of front tire = (weight on front tire) / deflection = 981 / 3

    = 327 N/mm

    stiffness of front tire = (weight on rear tire) / deflection = 1471.5 /

    4

    = 367.875N/mm

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    The distance between the steer axes of the steerable wheelsis called the track and is shown by w. The distance between the

    front and rear axles

    W  

    δ 

    δo 

     Inner  

    Oute

    r  

    Wheel  whe

    el  

    A B

    C  

    Centerof  

    l  

    a2 

    rotation   R δi 

    δo 

    D C

     R1 

    Fig 6.19. steer angles of the inner and outer wheels.

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    is called the wheelbase and is shown by l. Track w and wheelbase lare considered as kinematic width and length of the vehicle.

    The mass center of a steered vehicle will turn on a circlewith radius R,

    R²= a2  + l2 cot2 δ  (7.2)

    where δ is the cot-average of the inner and outer steer angles.

    cot δ = 

    cot δo + cot

    δi 

    . (7.3)

    2

    The angle δ is the equivalent steer angle of a  bicyclehaving the same wheelbase l and radius of rotation R.

    Proof:

    To have all wheels turning freely on a curved road, thenormal line to the center of each tire-plane must intersect at acommon point. This is the Ackerman condition.

    Figure 7.2 illustrates a vehicle turning left. So, the turningcenter O is on the left, and the inner wheels are the left wheels thatare closer to the center of rotation. The inner and outer steer anglesδi and δo may be calculated from the triangles 4OAD and 4OBC as

    follows:

    tan δi  =

    l

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    R 1 − 

    w

    tan δo  =

    l

    R 1 +

    w

    Eliminating

    R 1 

    R 1  =

    w +

    l

    2 tanδi 

    = − 

    1 l

    w +2  tan δo 

     provides the Ackerman condition (7.1), which is a directrelationship between δi and δo.

    cot δo − cot δi = (7.7)l

    To find the vehicle’s turning radius R, we define an

    equivalent bicycle model, as shown in Figure 7.3. The radius ofrotation R is perpendicular to the vehicle’s velocity vector v at the

    mass center C. Using the geometry

    We have 

    R 2  = a2 + R 2  (7.8)

    2 1

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    cot δ  =

    R 1

    l

    =

    (cot δi + cot δo) (7.9)

    and therefore,

    R²= (7.10)a22 + l2 cot2 δ. 

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    The Ackerman condition is needed when the speed of the

    vehicle is too small, and slip angles are zero. There is no lateralforce and no centrifugal force to balance each other. The Ackermansteering condition is also called the kinematic steering condition, because it is a static condition at zero velocity.

    A device that provides steering according to the Ackermancondition (7.1) is called Ackerman steering, Ackerman mechanism,or Ackerman geom-etry. There is no four-bar linkage steeringmechanism that can provide the Ackerman condition perfectly.However, we may design a multi-bar linkages to work close to thecondition and be exact at a few angles.

    Figure 7.4 illustrates the Ackerman condition for differentvalues of w/l. The inner and outer steer angles get closer to eachother by decreasing w/l.

    Fig 6.20. Equivalent bicycle model for a front-wheel-steeringvehicle.

    δ 

    C  

    l  

    Centerof    R  a2 

    otation  δ 

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     R1 

    50

    w/l=0.2  0.4 0.6  0.8 41.66 1.0 

    1.2 

    33.33 1.4 

    1.6  

    δi [deg] 25 2.0 

    16.66 w/l=3.

    8.33

    00  10 20 30

    4

    0 50 60 70 80 

    9

    δo [deg] 

    Fig 6.21 Eff ect of w/l on the Ackerman condition for front-wheel-steering vehicles.

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    6.5.2 Steering Mechanisms

    A steering system begins with the steering wheel orsteering handle. The driver’s steering input is transmitted by ashaft through a gear reduction system, usually rack-and-pinion orre-circulating ball bearings. The steering gear output goes tosteerable wheels to generate motion through a steering mechanism.The lever, which transmits the steering force from the steering gear

    to the steering linkage, is called Pitman arm.

    The direction of each wheel is controlled by one steeringarm. The steering arm is attached to the steerable wheel hub by akeyway, locking taper, and a hub. In some vehicles, it is anintegral part of a one-piece hub and steering knuckle.

    To achieve good maneuverability, a minimum steeringangle of approximately 35 deg must be provided at the frontwheels of passenger cars.

    Tie rod

    Intermediate rod

    Pitman arm Idler arm

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    Fig 6.22. A sample parallelogram steering linkage and itscomponents.

     Rack  

    δS  

    u R 

    Steering box 

     Drag link  

    Fig 6.23 A rack-and-pinion steering system.

    of the racks, and then by the drag links to the wheel steering δ i = δi (uR ), δo = δo (uR ). The drag link is also called the tie rod.

    The overall steering ratio depends on the ratio of thesteering box and on the kinematics of the steering linkage.

    6.5.3 Ackerman Steering Geometry:

    The typical steering system, in a road or race car, has tie-rod linkages and steering arms that form an approximate parallelogram, which skews to one side as the wheels turn. If thesteering arms are parallel, then both wheels are steered to the sameangle. If the steering arms are angled, as shown in Figure 1, this isknown as Ackerman geometry. The inside wheel is steered to agreater angle then the outside wheel, allowing the inside wheel tosteer a tighter radius. The steering arm angles as drawn show100%Ackerman. Different designs may use more or less

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     percentage pro-Ackerman, anti-Ackerman, or Ackerman may beadjustable. (In fact adjustable Ackerman is rare. This could be thecar designer saying to us, "Do not mess with this.”) Full Ackerman

    geometry requires steering angles, inner wheel and outer wheel, as per Figure 1. The angles are a function of turn centre radius, wheel base and track.

    .

    Figure 6.24 Ackerman angle

    In practise, the steering angles achieved are not perfectAckerman geometry. This is not of concern. We are only

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    interested in the fact that we can have some degree of increasingdynamic toe out and that it is exponentially increasing withsteering angle. consider "Ackerman" a term to describe any

     progression of dynamic toe out generated by the steeringgeometry. If it is our choice to use Ackerman, we must use a high percentage because, for small steering angles, Ackerman isminimal

    We are using rack and pinion steering system having a steeringratio of 16:1

    Dimensions of the vehicle are as follows

    Table 6.6 Dimensions of Vehicle

    Specification Dimension

    Wheel base(l) 2.40 m

    Tack Width(W) 1.55 mSteering Ratio 16:1

    Turning Radius 5 m

    Table 6.7 Formula used:

    Ackerman condition Cot δₒ - cot δᵢ = W/l

    Turning Radius R² = a² + L² cot² δ 

    δₒ is the maximum outer wheel steer angle as shown in the figure 

    δᵢ  is the maximum inner wheel steer angle as shown in the figure

    δ is the average of maximum outer and inner steer angles 

    a is the distance from axel to the CG

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    Calculations:

    1.  Ackerman Steering angles

    Cot δₒ - cot δᵢ = W/l

    = (1.55)/(2.40)

    = 0.62

    By the help of hit and trail method , we calculate δₒ and δᵢ 

    Trail 1: if δₒ = 20 and δᵢ  = 30

    Cot δₒ - cot δᵢ = 2.74-1.73

    = 1.01

    As trail 1 is not equal to 0.62 , we proceed for trail 2

    Trail 2: if δₒ = 24 and δᵢ  = 30

    Cot δₒ - cot δᵢ = 2.24-1.73

    = 0.51

    As trail 2 is not equal to 0.62, we proceed for trail 3

    Trail 3: if δₒ = 23 and δᵢ = 30

    Cot δₒ - cot δᵢ = 2.35-1.73

    = 0.62

    as trail 3 is satisfied

    Therefore δₒ = 23 and δᵢ = 30

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    2.Turning Radius

    R² = a² + L² cot² δ 

    cot δ = (Cot δₒ + cot δᵢ )/2

    = (2.35+1.73)/2

    = 2.04

    Therefore δ= 26.14 

    We have “a = 1m” 

    R² = 1²+2.4² cot²(26.14)

    R = 4.98m

    Therefore we have turning radius approximately 5 meter 

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    Chapter 7

    Cost Report

     _________________________________________________________

    7.1 ECE Components cost report

    S.No Description of Items with

    specifications

    Quantity

    USED

    Unit Price

    (Rs.)

    Cost (Rs.)

    1.

    Solar cells (monocrystalline) 300 145 43,500

    2. Batteries(cells)(li-ion batteries)

    3.7v 2.5 ah

    8 5500 44000

    3.

    Motor

    (2kw)+Controller+differential

    1 75000 75000

    4

    Plexiglas sheet 30 634 19000

    6. Bus ribbon(1.00 mm to 4.00

    mm)

    15 70/m 1050

    7. UV curable adhesive 1kg 700 700

    8. GSM module 1 1800 1800

    9. GPS Module 1 1900 1900

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    10. USB to SERIAL cable 2 250 500

    11 Microcontroller(ATMEGA128) 1 750 750

    12 Microcontroller(PIC16f877a) 2 200 400

    13 EEP ROM( IC 24c02e) 1 200 200

    14 Graphical LCD 2 600 1200

    15 Tachometer 1 2000 2000

    16 RF ID reader 1 2000 2000

    17 Microcontroller(ATMEGA16) 1 250 250

    18 P-Channel MOSFET 10 100 1000

    19 Sensor(DS18b20) 1 250 250

    20 LM35(Temperature Sensor) 1 100 100

    21 Relay(12V, 50A) 15 100 1500

    22 Electrical Wires 60m 120 7200

    24 Soldering wire 1Kg 1500 1500

    25 PCB(Glass Epoxy Clad Board) 10 220 2200

    26 Voltage Regulating

    IC(LM78XX)

    10 15 150

    27 Capacitor and Resistors 200 500

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    28 Clamp Meter(to measure DC

    current)

    1 2500 2500

    29 Crystal Oscillator(16MHz) 10 25 250

    30 EM lock 2 3000 6000

    31 Switches 50 3 150

    32 Electronic Component 700

    2,18,750

    Table 7.1 Cost Report for ECE components

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    7.2 Mechanical Components:

    S.No Description of Items with specifications Quantity

    USED

    Unit

    Price

    (Rs.)

    Cost (Rs.)

    1 Chassis : Original

    Tubular Pipes : AISI 1020

    a) 

    Length : 22 m, Diam. : 4cm,

    Thickness : 2 mm

     b)  L = 5 m, D = 2.5 cm, T = 3 mm

    HSS : AISI 4130 / 1020a)  L = 6 m, 4cmx4cmx2mm

     b)  L = 4 m, 5cmx5cmx1mm

    Aluminum Sheet (Flour):

    1.8mx1.3mx1mm

    1 30000 30000

    2 Suspension System :

    front Suspension:- independent suspension

    with mc pherson strut (Tata Nano)

    rear:-leaf spring with telescopic shock

    absorber (Tata Magic)

    1)suspension

    2)MS PLATE

    3)NUTS AND BOLTS

    2 set

    macpherson

    strut

    2 set leaf

    spring

    3500

    4200

    15,400

    3 Tyres :

    TATA NANO

    1)Tyres

    1)HUB

    2)RIM

    4 3000 12000

    4 Brakes :

    TATA NANO

    4 2500 10000

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    1)front and rear :-

    Hydraulic drum internal expanding type

    1)nuts and bolts

    2)Brake oil3)brake drum

    4)brake pads

    5 Steering system :

    TATA NANO

    Rack and pinion

    )rack and pinion

    2)steering column with rod

    3)steering wheel

    4)tie rods

    5)nuts and bolts

    1 7000 7000

    6 Body works :

    Glass fibre body

    1)glass fibre

    2)thermocole

    3)plaster of paris

    4)resin bond

    5)hardner

    6)sand paper

    7)Paint

    Glass fibre:10 kg

    Resin bond:-75 litre

    Hardner:-3 litre

    90000 90000

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    Table 7.2 Mechanical components Cost report

    7 Chassis Paint :

    Spray paint

    1)f1 spray paint

    2)primer3)paint thinner

    4)paint catalyst

    6000 6000

    8 welding electrode 10 packet 150 1500

    9 Fasteners 5000 5000

    10 Mild Steel Plate

    5 mm

    2mx2m

    1 2000 2000

    11 Seat :

    Front Seat (2)

    Rear Seat (2) and seat cover

    4 2000 8000

    12 Accessories(light,wiper,mirror,handle,lock) NA NA 7000

    13 Chassis : PVC Pipes for model

    40 m

    1 1000 1000

    14 Pipe bending machine 1 17000 17000

    Total Cost 2,11,900

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    Chapter 8

    Results & Discussion

     ________________________________________________________

    8.1 DETAIL SPECIFICATIONS & FEATURES:

    ENGINE AND TRANSMISSION:

    Table 8.1 Engine and transmission specification

    Motor Type Brushless DC Motor

    Motor Power & Voltage 2 KW, 48V

    Motor Torque 6.8 Nm

    Motor RPM 3000

    Battery Specification 48V, 80 Ah (2 sets)

    Transmission Automatic

    Fuel type Solar & Electric

    Drive Type Rear Wheel Drive

    Differential Gear Ratio 7:1

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    PERFORMANCE:

    Table 8.2 Performance data

    Mileage 200+ km in single charge

    Top Speed 40 km/h

    Charging Time (Solar) 4.5 hrs

    Charging Time (Electric) 2 hrs

    BRAKE, STEERING, SUSPENSIONS & TYRES:

    Table 8.3 Other specifications

    Brake (Front & Rear) Drum

    Steering Type & Steering Ratio Rack & Pinion, 16:1

    Minimum Turning Radius 4.5 m

    Suspension (Front & Rear) Macpherson strut, Leaf Spring

    with damper

    Tyre Size Radial 145/70 R-12

    Wheel Size (Front & rear) 12 in

    SEAT:

    Sitting Capacity 5

    Seat Material Foam

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    DIMENSIONS AND WEIGHT:

    Overall Length 3.63 m

    Overall Width 1.8 m

    Overall Height 1.45 m

    Overall Height (door

    opened)

    2.2 m

    Wheel Base & Track

    Width

    2.5 m & 1.55m

    (Rear), 1.5 m

    (Front)

    Ground Clearance 0.25 m

    Kerb Weight 500 Kg (approx.)

    DRIVELINE:

    Type Rear Wheel Drive

    Number of driveline

    modes

    1

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    EXTERIOR:

    Body Material Glass Fibre

    Frame AISI 1020 Mild Steel

    Body Style Luxury

    SUSPENSION:

    Front Macpherson strut

    Rear Leaf Spring with damper

    Product Warranty:

    Batteries 2 Years

    Solar Cells 25 Years 

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    Chapter 9

    Conclusion & Summary

     ________________________________________________________

    A Solar Car which has highest mileage and can be charged by home electricity.

    Fulfilling the demand of the Indian market Sun'sKaar has high efficiency, less pollution and

    reduced cost.

    A solar powered vehicle overcome the polluting nature of petroleum and diesel driven

    vehicles, also the reduced running costs of such a vehicle makes the prospects of fully fledged

    solar cars a particularly exciting one.

    9.1 Highlights:

      Works on Solar Energy.

      Mileage greater than any other vehicle present in India.

      Clean and pollution free.

     

    Economic.

      Cost Efficient.

    Solar Car can save 3 INR per km in comparison with petrol cars. Solar Hybrid Cars are the

    future of automotive industry.

    9.2 Advantages:

      The abundance of Solar Energy.

    Even in the middle of winter each square meter of land still receives a fair amount of

    solar radiation. Sunlight is everywhere and the resource is practically inexhaustible.

    Even during cloudy days we still receive some sunlight and it is this that can be used as

    a renewable resource.

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      You don’t pay for sunlight 

    Sunlight is totally free. There is of course the initial investment for the equipment. After

    the initial capital outlay you won’t be receiving a bill every month for the rest of your

    life from the electric utility.

      Solar energy is getting more cost effective 

    The technology for solar energy is evolving at an increasing rate. At present

     photovoltaic technology is still relatively expensive but the technology is improving and

     production is increasing. The result of this is to drive costs down. Payback times for the

    equipment are getting shorter and in some areas where the cost of electricity is high

     payback may be as short as five years.

      Solar energy is non-polluting 

    Solar energy is an excellent alternative for fossil fuels like coal and petroleum because

    solar energy is practically emission free while generating electricity. With solar energy

    the danger of further damage to the environment is minimized. The generation ofelectricity through solar power produces no noise. So noise pollution is also reduced.

      Accessibility of solar power in remote locations 

    Solar power can generate electricity no matter how remote the area as long as the sun

    shines there. Even in areas that are inaccessible to power cables solar power can

     produce electricity.

    Solar energy systems are virtually maintenance free. Once a photovoltaic array is

    setup it can last for decades. Once they are installed and setup there are practically zero

    recurring costs. If needs increase solar panels can be added with ease and with no major

    revamp. 

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    Chapter 10

    Pictures / Images

     ________________________________________________________

    Final

    Fig 10.1-Sunskaar at Auto expo

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    70 | P a g e  Fig 10.2-Sunskaar interior

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    Manufacturing Pics

    Fig 10.3-Pvc modelling

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    References:

    Book:

    1.  Heinz Heisler, Advanced Vehicle Technology, 2002, 2nd Eddition.

    2.  Milliken & Milliken, Race Car Vehicle Dynamics.

    3. 

    Springer.Vehicle.Dynmics,Theory & Application, 2008.

    Internet:

    1.  http://www.tribology-abc.com/calculators/t14_1.htm

    2.  http://www.carbibles.com/suspension_bible.html

    3.http://www.idsc.ethz.ch/Courses/vehicle_dynamics_and_design/11_0_0_Steering_Theroy.pd

    f

    4. http://en.wikipedia.org/wiki/Solar_car

    5. http://solarcar.stanford.edu/

    6. http://inventors.about.com/od/sstartinventions/a/Solar_Cars.htm

    7. http://solarcar.engin.umich.edu/

    8. http://craig.backfire.ca/pages/autos/horsepower

    9. http://www.speed-wiz.com/calculations/engine/index.htm

    10. http://www.thecartech.com/subjects/engine/engine_formulas.htm

    http://www.tribology-abc.com/calculators/t14_1.htmhttp://www.carbibles.com/suspension_bible.htmlhttp://www.carbibles.com/suspension_bible.htmlhttp://www.tribology-abc.com/calculators/t14_1.htm