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SULIT EXCEL I / PAPER 2 / YEAR 2009 No . Solution and Mark Scheme Sub Mark s Tota l Mark s 1 5 5 2 (a ) (b ) (c ) 1 3 3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah [Lihat sebelah SULIT N1 P1 K1 K1 N1 N1 K1 N1 K1 K1 P1

SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

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Page 1: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

EXCEL I / PAPER 2 / YEAR 2009

No. Solution and Mark Scheme Sub Marks

Total Marks

1

5 5

2

(a)

(b)

(c)

1

3

2 6

3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah [Lihat sebelahSULIT

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Page 2: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

3

(a)

(b)

3

3 6

4(a)

(b)

(c)

Gradient of AB = =

Equation of AB: y – 6 =

y = or equivalent.

Gradient of line = 3

Equation of perpendicular line passing through point C is y – 0 = 3(x – 3)

y = 3x + 9

Area of triangle ABC

=

=

= 24

3

3

2 8

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Page 3: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

5

(a)

(b)

(c)

Score 10-14 15-19 20-24 25-29 30-34

Frequency10

15 30 20 5

Use

Median = 22

1

3

3 7

6

(a)

(b)

Area of BCD = Area sector CAD – Area sector BOD – Area of AOB

=28.55 – 14.28 – 11.37 =

2

3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah [Lihat sebelahSULIT

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Page 4: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

6 8

7

(a)

(b)

(c)

(d)

SOR

POR

3

2

3

2 10

3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah SULIT

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Page 5: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

8(a)

(b)

(c)

(i) Gradient of QR =3

Gradient of PQ =

y – 1 =

(ii) Substitute into y + 3x – 22=0

x = 6y = 4Q(6, 4)

or

Coordinate S =( 12, 6)

TP = 3

x2+ y2 + 6x – 2y + 1 = 0

6

2

2 10

9

(a)Marks x Lower

BoundaryUpper

Boundaryf F

10 – 19 14.5 9.5 19.5 1 1

20 – 29 24.5 19.5 29.5 2 3

30 – 39 34.5 29.5 39.5 8 11

40 – 49 44.5 39.5 49.5 12 23

50 – 59 54.5 49.5 59.5 4 27

60 – 69 64.5 59.5 69.6 1 28

3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah [Lihat sebelahSULIT

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Page 6: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

(b)

(c)

Plot frequency against marks(Correct axes and uniform scales)

Shape of histogram

Show how to find the modal mark in histogram

Modal mark = 43 (from histogram)

L = 39.5, F = 11, =12, c = 10

Or corresponding (L, F, f)

4

3

3 10

10

(a)

6

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Page 7: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

(b) Area of sector ORS:

Area of :

4

10

11

(a)

(b) (i)

y = 3x

(ii)

3

2

3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah [Lihat sebelahSULIT

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Page 8: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

5 10

12

(a)

(b)

(c)

(d)

or

Since is obtuse, so /

/ / 9.54 cm

/

Area of

= 80.03 cm2

2

3

3

2 10

13

(a) (i)

(ii)

2

3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah SULIT

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Page 9: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

(b)

AC = 6.481m

(i) or

(ii)

KL = 6.114m

Area of

= 11.01m2

2

2

4 10

14

(a)

(b)

(c) (i)

(ii)

4

2

3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah [Lihat sebelahSULIT

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Page 10: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

4 10

15

(a)

(b)

(i)

(ii)

(c)

3

3

2

2 10

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Page 11: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

3472/2 © 2009 Hak Cipta Jabatan Pelajaran Negeri Sabah [Lihat sebelahSULIT

12

10

8

6

4

2

0

18

16

14

9.5

Modal Mark = 43

49.539.529.519.5

Frequency

Marks

Question 9(a)

59.5 69.5

Page 12: SULIT · Web viewEXCEL I / PAPER 2 / YEAR 2009 No. Solution and Mark Scheme Sub Marks Total Marks 1 5 5 2 (a) (b) (c) 1 3 2 6 3 (a) (b) 3 3 6 4 (a) (b) (c) Gradient of AB = = Equation

SULIT

CO-ORDINATOR

UNIT MATEMATIK MENENGAHSEKTOR PENGURUSAN AKADEMIK

LIST OF PANEL MEMBERS

NO. TEACHERS SCHOOL

1 SHIRNEY CHUA (Ketua) SMK KOLOMBONG, INANAM.

2 SUDIRMAN DARISE SMK BONGAWAN, MEMBAKUT.

3 AILEEN BEH CHIK HEANG SMK DATUK PETER MOJUNTIN, PENAMPANG.

4 PHOON CHIEW FUN SMK CHUNG HWA, TENOM.

5 TING KAI CHU MAKTAB SABAH, KOTA KINABALU.

6 SURIANIH SEWAN SMK SRI NANGKA, TUARAN.

7 SEAK SAIN YON SMK KONVEN ST. URSULA, TAWAU.

8 FARAH IBRAHIM SMK AGAMA, KOTA KINABALU.

9 ONG KHYE CHING SM KEN HWA, KENINGAU.