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Study & Analysis of Vapor and Gas Power Cycles
*The break up of other renewable energy sources (RES) is: wind power (34,293.48 MW), Solar power(23,022.83 MW), Biomass power & gasification (8,700.80 MW), Small hydro (4,493.20 MW), Waste-to-energy(138.30 MW).
#Facts• Thermal power is the "largest" source of power in India. There are
different types of thermal power plants based on the fuel used togenerate the steam such as coal, gas, and Diesel, natural gas. About71% of electricity consumed in India is generated by thermal powerplants.
• More than 62% of India's electricity demand is met through thecountry's vast coal reserves.
Classification of Thermodynamics Cycles
Heat Energy Mechanical EnergyPower Cycle (+)
Power Cycle (-)
Working Fluid
Gas Cycle: no phase-change of working fluid during cycle
Vapor Cycle: phase-change of working fluid during cycle
Actual Computer window of 210 MW Coal base Thermal Power Plant
Carnot Vapor Cycle
Analysis of Carnot Cycle
Several Impracticalities are associated with this cycle:
(Limitation of Carnot Cycle)
1. It is impractical to design a compressor that will handle two phases for isentropic compression
process(4-1).
2. The quality of steam decrease during isentropic expansion process(2-3) which do harm to
turbine blades.
3. The specific volume of steam is much higher than that of water which needs big equipments
and large amount of work input.
Rankine Vapor Cycle
4-6 Constant pressure heat addition in a boiler6-1 to Superheat Vapor1-2 Isentropic expansion in a turbine2-3 Constant pressure heat rejection in a condenser3-4 Isentropic compression in a pump
S
4
6
1
2
3
Simple Steam Power Plant
S
4
6
1
2
3
T
s
1
6
5
4
3 2
p
v
1654
32
p1
p2
Analysis of Rankine Vapor Cycle
4-5-6-1 Constant pressure heat addition in a boiler
1 1 4q h h
1-2 Isentropic expansion in a turbine
tT 1 2w h h
2-3 Constant pressure heat rejection in a condenser
2 2 3q h h
3-4 Isentropic compression in a pump
tP 4 3w h h
Efficiency
Because of uncompressibility of water
( )tP 4 3 tTw v p p w
4 3h h
o tT tP 1 2 1 2 s
o 1 2t
1 1 3
w w w q q h h w
w h h
q h h
0, 0k pE E
1 21 2
1 2
2t
1
Q QT T
S S
T1
T
Steam Rate (Steam Consumption)
s
o 1 2
3600 3600m
w h h
ms— the steam required to generate work of 1 kWh (kg/kWh)
, equipment size , investmenttd
o 1 2t
1 1 3
w h h
q h h
Entralpy of steam, turbine inlet
Entralpy of exhaust air , turbine outlet
Entralpy of condensed water
1
2
3
h
h
h
,1 1p t
2p
Influencing factors
1. - Pressure of Steam, Turbine Inlet1p
3
4
5
5’
1’ 1
22’
,1 2t p -Unchange
1p '1p
Two Cycles:
① 3-4-5-1-2-3
② 3-4-5’-1’-2’-3
Method of improving the efficiency of Rankine Vapor Cycle
3
4
5
5’
1’ 1
22’
1 tp
Disadvantages:
1p 1. x
decrease the turbine efficiency anderodes the turbine blades.
2. 1p Increase of requirements on pressurevessels and equipment investment.
2. - Temperature of Steam, Turbine Inlet1t
3
4
5
1
1’
2’2
6
,1 2p p -Unchange
1t '1t
Two Cycles:
① 3-4-5-6-1-2-3
② 3-4-5-6-1’-2’-3
3
4
51
1’
2’2
6
Advantages:
' 1 1 tT T i
ii it decreases the moisture contentof the steam at the turbine exit.
Disadvantages:
Superheating temperature is limitedby metallurgical considerations.
6001t ℃
3. - Condenser Pressure, Turbine Exit2p
,1 1t p -Unchange
2p '2p
Two Cycles:
① 1-2-3-4-5-6-1
② 1-2’-3’-4’-5-6-13
4
5
1
3’ 2’
2
6
4’
3
4
5
1
3’ 2’
2
6
4’
' 2 2 tT T i
iiDisadvantages:
i Condense pressure is limited
by the sink temperature.
ii It increases the moisture
content which is highly
undesirable.
Example
Consider a steam power plant operating on the ideal Rankine
cycle. The steam enters the turbine at 2.5MPa and 350℃ and
is condensed in the condenser at pressure of 70kPa. Determine
(a)The thermal efficiency of this power plant
(b)The thermal efficiency if steam is condensed at 10kPa
(c)The thermal efficiency if steam is superheated to 600 ℃
(d)The thermal efficiency if the boiler pressure is raised to 15MPa while
the turbine inlet temperature is maintain at 600 ℃
State 1:
State 2:
1 1
1
1
2.5MPa, 350
3128.2 kJ/kg
6.8442 kJ/kg K
℃p t
h
s
Ideal Rankine Cycle
2 2 1
2 2
2 2
70kPa,
' 1.1921kJ/(kg K), '' 7.4804kJ/(kg K)
' 376.77kJ/kg, " 2660.1kJ/kg
'
'' '
6.8442 1.1921 0.8988
7.4804 1.1921
x
p s s
s s
h h
s sx
s s
h2 ' ''
376.77 0.8988 2660.1 2767.7kJ/kg
h xh
State 4:
1 1 4
2 2 3
3128.2 381.83 2746.37
2767.7 376.77 2390.93
q h h
q h h
2
1
1 12.9% t
q
q
4 4 3
3 4 3
4 3
2.5MPa,
( ) 2.53kJ/kg
376.77 2.53
=381.83kJ/kg
tp
tp
p s s
w v p p
h h w
3
3
3
3
70kPa, Saturate Liquid
376.77kJ/kg
0.00104m /kg
p
h
v
State 3:
Irreversibility
• Flow friction
• Heat transfer under temperature
difference
• Heat loss to the surroundings
Actual Rankine Vapor Cycle
Actual cycle
2’2
1
56
1 2' 'tT
w h h
Turbine Efficiency
1 2
1 2
' '0.92tT
i
tT
w h h
w h h
Ideal Cycle
1 20
3600
h hN
Actual Cycle
1 20
'
3600
i i
h hN N
Actual Rankine Vapor Cycle
Analysis of Actual Rankine Vapor Cycle
Ideal Regenerative Cycle
Boiler Turbine
Regenerator
Condenser
Mixing Chamber
Pump II Pump I
1
27
34
56
ExtractingRegeneration
1
Analysis Ideal Regenerative Cycle
3(4) 2
7
1
6
5
1kg
akg
(1-a)kg
T
s
( ) ( )( )
( ) ( )( )
7 5 5 4
5 4
7 5
0 1 7 7 2 tp
1 1 5
0t
1
a h h 1 a h h
h ha
h h
w h h 1 a h h w
q h h
w
q
( ) ( )
2 3t Rankine
1 3 1 7
h h1
ah h h h
1 a
>0
Ideal Regenerative Cycle
Boiler Turbine
Regenerator
Cond-enser
Mixing Chamber
Pump II Pump I
1
27
34
56
8
93 2
7
1
6
5
T
s
4
89
1
1
Ideal Reheat Cycle
3 c 2
a1
5
4
6 b
Analysis Ideal Reheat Cycle
bp intermediate pressure
( ) ( )
( ) ( )
1 b a 2t
1 3 a b
h h h h
h h h h
Regenerative-Reheat Cycle