Upload
meissha-ayu-ardini
View
226
Download
0
Embed Size (px)
Citation preview
7/30/2019 Structure Elucidation From XRD 1
1/34
1
Structure elucidation fromXRD
X-rays are electromagnetic waves with a wavelength in the range of interatomicdistances (0.1-10 )
topics
Structure analysis by X-ray diffraction fromcrystals
Crystallography
X-ray diffraction from polycrystalline samples(powders); Evaluation of the intensities of X-rays diffracted
from polycrystalline samples; Elucidation of simple inorganic crystal structures
starting from the model structures andcomparison of the intensities calculated for themodel structures with the observed intensities;
7/30/2019 Structure Elucidation From XRD 1
2/34
2
What is X-ray Diffraction?
7/30/2019 Structure Elucidation From XRD 1
3/34
3
7/30/2019 Structure Elucidation From XRD 1
4/34
4
Practical aspect
3 basic components of an X-ray dif fractometer
1.X-ray source 2. Specimen 3. X-ray detector
1. X-Ray source
Generated by directing anelectron beam of highvoltage at a metal targetinside an evacuated x-raytube
Cu K ~ 8.04 keV(=0.154184 nm) is the mostused metal target due to itshigh intensity
3. Detector
3 main types: proportional,scintillation, and solid-state
The most used isproportional
2. Specimen
Quantity ~ a few mg Grain size 50m
(passed 325 meshsieve)
Applied as a thin layer ofpowder/film onto a non-
diffracting material, suchas microscope glassslide
7/30/2019 Structure Elucidation From XRD 1
5/34
5
Solid matter
crystalline
The atoms andmolecules are arrangedin a random way similarto the disorder we find in
a liquid do not formcrystallites. Glasses areamorphous materials.Small particles with nolong-range order (100)
The atoms arearranged in aregular pattern,and there is assmallest volume
element that byrepetition in threedimensionsdescribes thecrystal (a unitcell).
Long range order(>103 molecules)
polycrystallineSolids which containmany small, randomlyoriented and joinedcrystallites/grains
2 (o)10 20 30 40 50 60 70 80 90
Intensit
y
(a.u)
2 h
3 h
4 h
5 h
A [101]
A
AA A
Am
Bnon-crystalline(amorphous)
single crystalSolid which containssingle crystallite
7/30/2019 Structure Elucidation From XRD 1
6/34
6
Single crystal polycrystalline amorphous
long-range order
consists of some
single crystalregion (grains)
separated bygrain boundaries
not ordered short-range
order
Polymers can also present ordered region as incrystalline materials, called crystallite
crystallite region
amorphous region
7/30/2019 Structure Elucidation From XRD 1
7/34
7
XRD can be used to provide information about thestructure of amorphous or non-crystalline materials, such
as glass
7/30/2019 Structure Elucidation From XRD 1
8/34
8
7/30/2019 Structure Elucidation From XRD 1
9/34
9
constructive interference results in diffraction line, but destructive interference does not
7/30/2019 Structure Elucidation From XRD 1
10/34
10
monochromatic/single wavelength
with highest intensity is used asthe X-ray source
7/30/2019 Structure Elucidation From XRD 1
11/34
11
In powder or polycrystalline diffraction it is
important to have a sample with a smoothplane surface.
If possible, grind the sample down to particlesof about 0.002 mm to 0.005 mm crosssection.
The ideal sample is homogeneous and thecrystallites are randomly distributed random distribution of all possible h,k,l planes
The sample is pressed into a sample holderso that we have a smooth flat surface.
Only crystallites having reflecting planes (h,k, l)parallel to the specimen surface will contribute tothe reflected intensities.
If we have a truly random sample, each possiblereflection from a given set of h, k, l planes anequal number of crystallites contributing to it.
We only have to rock the sample through theglancing angle THETA in order to produce allpossible reflections.
7/30/2019 Structure Elucidation From XRD 1
12/34
12
X-ray Diffraction Pattern
Consists of a series of peaks
The peak intensity as the ordinate (y axis) expressedas an arbitrary units
The measured diffraction angle, 2, along the abscissa
The as-recorded XRD pattern generally have abackground, then it is usually substracted and thepeaks smoothened
Sources information: Powder Diffraction File (PDF) JCPDS (database of standard XRD pattern byInternational Centre for Diffraction Data)
Crystallography: reviews
7/30/2019 Structure Elucidation From XRD 1
13/34
13
7/30/2019 Structure Elucidation From XRD 1
14/34
14
7/30/2019 Structure Elucidation From XRD 1
15/34
15
7/30/2019 Structure Elucidation From XRD 1
16/34
16
7/30/2019 Structure Elucidation From XRD 1
17/34
17
About 95% of all solid materials can be described ascrystalline
When X-rays interact with a crystalline substance(phase) gets a diffraction patternIn 1919 A.W.Hull gave a paper titled, A New Method ofChemical Analysis. Here he pointed out that .everycrystalline substance gives a pattern; the same substancealways gives the same pattern; and in a mixture ofsubstances each produces its pattern independently ofthe others. The X-ray diffraction pattern of a pure substance afingerprint finger print identification
The powder diffraction method is thus ideally suited forcharacterization and identification of
crystalline/polycrystalline phases
Today about 50,000 inorganic and 25,000 organic singlecomponent, crystalline phases, diffraction patterns havebeen collected and stored on magnetic or optical media asstandardsThe main use of powder diffraction is to identifycomponents in a sample by a search/match procedureThe areas under the peak are related to the amount of
each phase present in the sampleFor single-phase materials the crystal structure can beobtained directly using X-Ray diffraction (XRD)XRD can be used :
for phase identification (With the help of a database ofknown structures)
to determine crystal size, strain and preferredorientation of polycrystalline materials
the related technique of X-ray reflection enablesaccurate determination of film thickness
7/30/2019 Structure Elucidation From XRD 1
18/34
18
Structure analysis by X-ray diffraction fromcrystals
7/30/2019 Structure Elucidation From XRD 1
19/34
19
7/30/2019 Structure Elucidation From XRD 1
20/34
20
7/30/2019 Structure Elucidation From XRD 1
21/34
21
XRD patterns of furnace materials and reference patterns of identified phases
7/30/2019 Structure Elucidation From XRD 1
22/34
22
7/30/2019 Structure Elucidation From XRD 1
23/34
23
Applications:
Identification
of crystallinephases
A
A A A
A
AA
TiO2 has 3 major
crystalline
phases, anatase
(A), rutile (R) and
brookite (B) with
fully anatase (A)as the crystalline
phase
TiO2 with fully
anatase (A) as thecrystalline phase
TiO2 with anatase (A) and rutile
(R) as the crystalline phases
7/30/2019 Structure Elucidation From XRD 1
24/34
24
7/30/2019 Structure Elucidation From XRD 1
25/34
25
Peak intensitiesEvaluation of the intensities of X-rays diffracted
from polycrystalline samples evaluatingcrystallinity
taking the sum total of relative intensities of
ten individual characteristic peaks1 thentaking the ratio over the correspondingrelative intensities of standard materials
E.g.:
Comparing crystallinity of flyash-basedzeolite-A using XRD and IR spectroscopy
1CURRENT SCIENCE, VOL. 89, NO. 12, 25 DECEMBER 2005
7/30/2019 Structure Elucidation From XRD 1
26/34
26
% crystallinity =(AD4R)/(ATO4)
% crystallinity = (IR sample)/(IR standard)
72.8% 85%
98.6%
98.6%
98.6%
100%
7/30/2019 Structure Elucidation From XRD 1
27/34
27
72.8%83.2%
92%
93.3%
96.2%
100%
Crystallinity = (A ratio of 560 over 464 cm-1 bands of sample/reference) x 100%
cos
KD =
7/30/2019 Structure Elucidation From XRD 1
28/34
28
Applications:
Determination
of Crystal Size
Scherrer equation:
Bcrystallites = (k)/(L cos )k constant ~ 1 (precision error 10%)
L average crystal s ize (nm)
wavelength of the X-rays used (nm) Bragg angle (radians)B fu ll width at half maximum (FWHM,
radians)
Example: anatase TiO2Cu = 0.15406 nmL1 = 0.0061 1=25.28 B1 = 25.3 nmL2 = 0.0061 2=37.8 B2 = 25.26 nm
Different crystallite sizes
7/30/2019 Structure Elucidation From XRD 1
29/34
29
determination and refinement oflattice parameters (indexing)
)(
4
sin 222
2
22
lkh
a
++=
)(sin2222lkhC ++=
dividing the above equation with the first reflection angle gives the ratio of hkl
relationship between Miller indices and diffraction angles
)(
)(
sin
sin2
1
2
1
2
1
222
12
2
lkh
lkh
++
++=
the ratio of hkl define the possible Miller indices: ratio = h2 + k2 + l2
if there are some possible hkl, the highest number comes firstAfter indexing, one of the peaks can be used to calculate the cell parameters.As the error in measuring the diffraction angles is a systematic error, the lastreflection data will be used
7/30/2019 Structure Elucidation From XRD 1
30/34
30
exercise 1: indexing XRD data (cubic)
43.830
60.093
67.213
70.634
56.331
63.705
33.602
27.302
10010.027919.213
48.266
38.995
Miller indicesratiosin22 1. define the Millerindices
2. calculate thelatticeparameters
lattice type and systematic absenceson cubic system
destructive interferences occurringbetween the diffracted waves intensitycancels out
eg:
7/30/2019 Structure Elucidation From XRD 1
31/34
31
For example MoO3 crystallizes in thin plates (like sheetsof paper) these crystals will pack with the flat surfacesin a parallel orientation.
Comparing the intensity between a randomly orienteddiffraction pattern and a preferred oriented diffractionpattern can look entirely different.
Quantitative analysis depend on intensity ratios whichare greatly distorted by preferred orientation.
Careful sample preparation is most important to dealwith preferred orientation samples
The following illustrations show the Mo O3 spectra'scollected by using transmission , Debye-Scherrercapillary and reflection mode.
7/30/2019 Structure Elucidation From XRD 1
32/34
32
TiO2 film layered on SnO2 (S) thin f ilm
with anatase (A) as the crystalline
phases
7/30/2019 Structure Elucidation From XRD 1
33/34
33
7/30/2019 Structure Elucidation From XRD 1
34/34
ZnO nanorod