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Structural Dynamics Lecture 8 Outline of Lecture 8 Multi-Degree-of-Freedom Systems (cont.) Symmetric Structures. Vibrations due to Indirectly Acting Dynamic Loads. Tuned Mass Dampers. Formulation of 2DOF Model. 1 Formulation of 2DOF Model. Analysis and Design of Tuned Mass Dampers.

Structural Dynamics Lecture 8 Outline of Lecture 8 ·  · 2010-01-22Structural Dynamics Lecture 8 Outline of Lecture 8 Multi-Degree-of-Freedom Systems (cont.) Symmetric Structures

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Page 1: Structural Dynamics Lecture 8 Outline of Lecture 8 ·  · 2010-01-22Structural Dynamics Lecture 8 Outline of Lecture 8 Multi-Degree-of-Freedom Systems (cont.) Symmetric Structures

Structural Dynamics

Lecture 8

Outline of Lecture 8

� Multi-Degree-of-Freedom Systems (cont.)

� Symmetric Structures.

� Vibrations due to Indirectly Acting Dynamic Loads.

� Tuned Mass Dampers.

� Formulation of 2DOF Model.

1

� Formulation of 2DOF Model.

� Analysis and Design of Tuned Mass Dampers.

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Structural Dynamics

Lecture 8

� Symmetric StructuresOften a structure possess some symmetry planes, which can be used to reduce the number of degrees of freedom of the system. System reduction based on symmetry is not related with loss of accuracy.

System reduction requires the existence of one or more symmetry planes

� Multi-Degree-of-Freedom Systems (cont.)

2

System reduction requires the existence of one or more symmetry planes in the structure. In structural dynamics symmetry is required with respect to:

The dynamic loads and the initial conditions are not assumed to fulfill any symmetry or anti-symmetry conditions.

� Geometry.

� Boundary conditions.

� Stiffness distribution.

� Damping distribution.

� Mass distribution.

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Structural Dynamics

Lecture 8

3

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Structural Dynamics

Lecture 8

Fig. 1 shows a plane structure with 10 degrees of freedom, which fulfill the indicated symmetry conditions. The dynamic loads may be partioned into symmetric and anti-symmetric load distributions as shown on Fig. 1a.

The anti-symmetric load distribution causes zero vertical displacement and a point of inflection at the cross-sections originally placed in the symmetric plane. Hence, the anti-symmetric vibrations may be analyzed by the system with 5 degrees of freedom shown in Fig. 1b. Notice that the

4

the system with 5 degrees of freedom shown in Fig. 1b. Notice that the mass is related to the horizontal degree of freedom , and that the vertical load placed in the symmetry plane can be totally ignored.

The symmetric load distribution causes zero horizontal displacement and zero tangential slopes at the cross-sections in the symmetry plane. Then, symmetric vibrations may be analyzed by the system with 5 degrees of freedom shown in Fig. 1c.

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Structural Dynamics

Lecture 8

The mass is now related to the vertical degree of freedom , and the horizontal load acting in the symmetry plane is ignored.

It follows from the example that if a system has a symmetry plane, the system of degrees of freedom can be reduced to two equivalent systems of degrees of freedom.

The calculation time of a dynamic system typically increases proportional

5

The calculation time of a dynamic system typically increases proportionalto . Then, the saving in computional effort for structures with a single symmetry plane is reduced by a factor .

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Structural Dynamics

Lecture 8

� Example 1: Reduction of a symmetric 2DOF system to 2 SDOF systems.

6

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Structural Dynamics

Lecture 8

The 2DOF system shown in Fig. 2 is dynamically symmetric about the mid-point. The dynamic loads and inertial conditions may be partioned into anti-symmetric and symmetric components as shown.

7

The anti-symmetric load and anti-symmetric initial conditions cause the masses to move in the same direction with the same displacement as shown on Fig. 2. Then, the spring and damper between the masses are not deformed, and may be disregarded. Hence, can be analyzed by the SDOF system shown on Fig. 3, corresponding to the equation of motion:

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Structural Dynamics

Lecture 8

The symmetric loads and initial conditions cause the masses to move in opposite directions with the same displacement as shown on Fig. 2.

8

During symmetric vibration, points at the symmetric line must be at rest. This can be achieved by replacing the spring with the constant and the damper with the constant with 2 equivalent springs and dampers in series with the constants and as shown on Fig. 4.

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Structural Dynamics

Lecture 8

The spring force on the masses in the original system during symmetric motions is equal to . The spring forces on the masses for the system shown on Fig. 4 is equal to . These must be equal, leading to:

9

Similarly, the damping force on the masses in the original system during symmetric motions is equal to . The damper force on the masses for the system shown on Fig. 4 is equal . These must be equal, leading to:

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Structural Dynamics

Lecture 8

Then, can be analyzed by the SDOF system shown on Fig. 5,

10

Then, can be analyzed by the SDOF system shown on Fig. 5, corresponding to the equation of motion:

The original degrees of freedom are recovered from the solution toand , obtained from (1) and (4):

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Structural Dynamics

Lecture 8

(5) unveales and as modal coordinates, cf. Lecture 5, Eq. (46). Actually, the eigenmodes of the system are:

� Vibrations due to Indirectly Acting Dynamic Loads

11

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Structural Dynamics

Lecture 8

An MDOF system is exposed to an external dynamic force acting indirectly on the masses via the linear elastic structure. The motion of the masses are described by the degrees of freedom measured from the static equilibrium state, see Fig. 6.

Additionally, an auxiliary degree of freedom is introduced co-directional to the dynamic force .

12

The deformations , are brought forward as a sum of contributions from the external force acting at and from the inertial forces and the damping forces , acting in the positive and negative direction of the degrees of freedom . Then, by the use of the force method the following identities may be formulated:

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Structural Dynamics

Lecture 8

13

where:

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Structural Dynamics

Lecture 8

(7), (8) and (9) may be written on the following matrix form:

where:

14

Upon pre-multiplication with , (11) attains the form:

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Structural Dynamics

Lecture 8

� Example 2: Indirectly acting dynamic load on a 2DOF system.

15

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Structural Dynamics

Lecture 8

Fig. 7 shows a plane framed structure made up of massless Bernoulli-Euler beams with the bending stiffness . At the free end is attached a point mass and a vertical acting linear viscous damper with the damper constant . The structure is exposed to a horizontal dynamic load at the midst of the vertical beam.

The system has degrees of freedom and defined as the horizontal and vertical displacement of the point mass as shown in Fig. 7.

16

horizontal and vertical displacement of the point mass as shown in Fig. 7. Additionally, a horizontal auxiliary degree at the dynamic force is introduced.

The flexibility coefficient and are calculated by the use of the principle of complementary virtual work, cf. Lecture 3, Eq. (54):

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Structural Dynamics

Lecture 8

The stiffness matrix becomes:

The equations of motion become, cf. (14):

17

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Structural Dynamics

Lecture 8

� Tuned Mass Dampers

18

A tuned mass damper (TMD) is a linear SDOF oscillator with a mass , a spring with the constant and a viscous damper with the damper constant , attached to a given MDOF structure. The TMD is referred to as the secondary system, and the MDOF system as the primary system.

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Structural Dynamics

Lecture 8

The idea is to transfer mechanical energy from the primary system to the secondary system, so the primary system only perform moderate vibrations. The secondary system is allowed to undergo substantial vibrations, which are dissipated by the damper .

The tuning of the mass damper refers to the selection of the parameters, and in a way that maximum mechanical energy is transferred

from the primary system to the secondary system for a given dynamic

19

from the primary system to the secondary system for a given dynamic loading. Here, we shall presume that the external dynamic loads on the primary structure are harmonically varying, cf. Lecture 6, Eq. (2):

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Structural Dynamics

Lecture 8

� Formulation of 2DOF model

20

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Structural Dynamics

Lecture 8

A TMD can only damp a single mode of the structural response effectively.

If several modes are dominating the response a corresponding number of mass dampers must be attached, each tuned to a separate mode.

Fig. 9 shows a TMD acting in the direction of the th degree of freedom. The TMD is supposed to damp the mode with the eigenmode

shown on Fig. 9a. Although the fundamental mode has been depicted,

21

shown on Fig. 9a. Although the fundamental mode has been depicted, may be any eigenmode. The only requirement is that the th component of

fulfills:

(21) implies that the TMD is able to perform a work on the considered mode. In this case the mode is said to be controllable.

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Structural Dynamics

Lecture 8

The modal decomposition of the displacement vector is assumed to be dominated by the mode to be damped:

where is the modal coordinate of the critical mode. (22) implies that the displacement of the primary structure at the point of attachment of the

22

the displacement of the primary structure at the point of attachment of the TMD becomes:

The TMD is cut free from the structure, and the internal force is applied as an external force on the structure and the TMD, with the signs shown on Fig. 9b. is denoted the control force.

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Structural Dynamics

Lecture 8

Totally, the primary structure is loaded with the external dynamic load vector and the control force acting in the direction if the th degree of freedom . Then, the equation of motion for the modal coordinate becomes, cf. Lecture 5, Eqs. (69), (70):

23

� : Modal mass. .

� : Modal damping. .

� : Modal stiffness. .

� : Modal load of external loads. .

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Structural Dynamics

Lecture 8

Notice that the modal load from the control force becomes . With the dynamic load vector given by (19) the modal load from the external loads becomes:

24

where complex amplitude of the modal load is given as:

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Structural Dynamics

Lecture 8

Use of (23) in (24) provides the following equation of motion formulated in the displacement of the point of attachment of the TMD:

25

, , and are physical quantities (i.e. independent of the normalization of the eigenmode ). These are only equal to the modal mass, the modal damping and the modal load, if is normalized so the th component . The complex force amplitude caused by the external dynamic load becomes , where is given by (26).

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Structural Dynamics

Lecture 8

The equation of the free TMD with the control force acting in the opposite direction of the displacement degree of freedom of the damper mass becomes, see Fig. 9b:

26

The internal control force is related to selected degrees of freedom as:

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Structural Dynamics

Lecture 8

Elimination of in (27) and (29) by means of (30) provides the following equations of motion of the system:

(31) may be recasted into the following matrix equation of motion:

27

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Structural Dynamics

Lecture 8

The TMD will only damp the primary structure, if performs a negative net work on the primary structure during the period , see Fig. 9b:

The control force may very well perform a positive net work on other modes than the controlled one, so these modes are excited rather than

28

modes than the controlled one, so these modes are excited rather than damped. This phenomena is denoted control spillover.

Normally, the modal damping of the primary structure is very low (else there are no need of the TMD). Hence, this damping will be ignored in the following analysis:

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Structural Dynamics

Lecture 8

� Analysis and Design of Tuned Mass Dampers

The stationary harmonic response of the system (32) is given by, cf. Lecture 6, Eqs. (4-7):

29

where the complex amplitudes and of and are determined from the linear equations:

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Structural Dynamics

Lecture 8

is the complex amplitude of the excitation defined next to Eq. (28). From (37) the following solutions are obtained for and :

30

where is the determinant of the coefficient matrix in (37), given as:

The following parameters are introduced:

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Structural Dynamics

Lecture 8

indicates the undamped angular eigenfrequency of the considered mode of the primary structure. represents the relevant mass ratio. and may be interpreted as the angular eigenfrequency and damping ratio of the secondary system, when the primary system is fixed ( ). Then, the solutions (38) for the complex amplitudes may be written in the following non-dimensional forms:

31

Notice that denotes the quasi-static displacement amplitude of the

primary structure for . Hence, denotes the dynamic

amplification of the primary structure, cf. Lecture 2, Eq. (42).

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Lecture 8

32

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Structural Dynamics

Lecture 8

Fig. 11 shows the dynamic amplification factor of the primary system for the tuning , and for various values of . All curves attains

the value for due to the normalization with respect to

the quasi-static response.

For infinite resonance peaks exist at the angular frequencies and , which represent the undamped angular

33

frequencies and , which represent the undamped angular eigenfrequencies of the 2DOF system (32). The dynamic amplification factor follows from (41) for :

and are determined as the values of for which the denominator of (42) vanishes, i.e. as solution to the 2nd order equation:

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Structural Dynamics

Lecture 8

For the damper is locking the relative motion between the primary and the secondary system, and the combined system acts as an undamped SDOF system with the mass and the stiffness . The amplification factor follows from (41) for :

34

The angular resonance frequency becomes:

For , 2 resonance peaks appears at angular frequencies slightly aboveand below , as shown on Fig. 11.

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Structural Dynamics

Lecture 8

As first demonstrated by Den Hartog the family of amplification curves (41) obtained for varying damping ratio possesses the remarkable property that they all passes through two points and placed at the angular excitation frequencies and , where:

35

The angular frequencies and are essential at the optimal tuning of the damper. Next, these are determined.

(41a) is written on the form:

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Structural Dynamics

Lecture 8

where:

36

From (47) follows

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Lecture 8

(49) is independent of , if:

37

The plus sign leads to the unique solution , which corresponds to the quasi-static response. The solutions searched for are obtained for the minus sign:

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Structural Dynamics

Lecture 8

and are the two solutions of (51). The sum of these becomes:

The amplifications factors at the points and are independent of, and hence can be calculated from (44) valid for :

38

where the sign refers to point and the sign to point . The amplification factor at these points are required to be identical:

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Structural Dynamics

Lecture 8

The tuning angular frequency follows from the identity of the right hand sides of (52) and (54):

39

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Lecture 8

40

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Structural Dynamics

Lecture 8

We still need one more fixation of the dynamic amplification curve in order to specify the damping ratio . Krenk suggested a simple criteria for this by requiring that the amplification factor at the angular frequency

should be equal to the amplification factor at the angular frequenciesand .

At first, the amplification factor at and is determined. For the tuning (55), Eq. (51) attains the form:

41

tuning (55), Eq. (51) attains the form:

where (45) has been used in the last statement. (56) has the solution:

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Structural Dynamics

Lecture 8

(57) is inserted into (44) to provide:

Next, the amplification factor is calculated at the angular frequency by means of (41). After insertion of given by (45) and given by (55), the following result is obtained after some reductions:

42

(55), the following result is obtained after some reductions:

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Structural Dynamics

Lecture 8

Finally, equating (58) and (59) provides the following solution for :

We are interested in an equivalent modal damping ratio of the primary

43

We are interested in an equivalent modal damping ratio of the primary structure as a measure of the effect of the TMD. At resonancethe amplification factor is , cf. Lecture 2, Eq. (24). Additionally, with the considered calibration the amplification factor is flat in the interval as shown on Fig. 12, so the value at is approximately given by (58). Using , it follows:

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Structural Dynamics

Lecture 8

Similarly, given by (60) may be approximated as:

This concludes the analysis.

44

This concludes the analysis.

The design procedure goes in the reverse order. At first a demanded damping ratio of the primary structure is prescribed. Then, the necessary damping ratio of the secondary structure is determined from (62). Next, the mass ratio is determined from (60). Then, can be calculated from (55). Finally, , , can be determined from (40). The various steps in the design procedure have been summarized in Box 1.

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Structural Dynamics

Lecture 8

Box 1 : Design procedure of tuned mass damper

An MDOF linear structure defined by the mass matrix and the stiffness matrix shall be damped in a specific mode with the mode shape and the angular eigenfrequency by means of a tuned mass damper with the mass , the damper constant and the spring stiffness . The damper is acting co-directional to the th degree of freedom with the mode shape component .

45

freedom with the mode shape component .

At the design of the tuned mass damper, i.e. the determination of , and , the following steps are followed:

1. Determine the mass and stiffness parameters and of the primary system by Eq. (28):

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Lecture 8

2. Specify the required modal damping of the considered mode of the primary system.

3. Calculate the damping ratio of the secondary system from Eq. (62):

4. Calculate the mass ratio from Eq. (60):

46

4. Calculate the mass ratio from Eq. (60):

5. Calculate the angular frequency of the secondary system from Eq. (55):

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Lecture 8

6. Calculate , and from Eq. (40):

47

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Structural Dynamics

Lecture 8

Summary of Lecture 8

� Symmetric Structures.

Symmetry is required with respect to:

� Geometry.

� Boundary conditions.

48

Computation efforts are reduced by approximately a factor for each symmetry plane. 3 Symmetry planes means a reduction factor of .

� Boundary conditions.

� Stiffness distribution.

� Damping distribution.

� Mass distribution.

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Structural Dynamics

Lecture 8

� Vibrations due to Indirectly Acting Dynamic Loads

� Dynamic load is not acting directly on the masses.

� Auxiliary degrees of freedom are introduced specifying the displacement of the load.

The resulting equations of motion is obtained on the standard form:

49

� : Vector of flexibility coefficients at the degrees of freedom due to

a unit load at the indirectly acting load.