StoichiometryStoichiometry

55

Problem 13Problem 13Balance the EquationBalance the Equation

• What mass of H2SO4 is produced from the reaction of 6.58 grams of SO3 and 1.64 grams of H2O?????

SO3 + H2O H2SO4H2SO4+SO3 H2O

Correct! Correct! SO3 + H2O H2SO41 Sulfur, 2 Hydrogen, 4 oxygen = 2 Hydrogen, 1 Sulfur, 4 Oxygen

Step 1 of Equation 1Step 1 of Equation 1

6.58 g SO3 x __1 mol__80.86 g SO3

6.58 g SO3 x ___65 mols__` 81.34 g SO3

6.58 g SO3 x ____1 mol___101.25 g SO3

Correct!Correct!

Good Job

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Work

Step 2 of Equation 1Step 2 of Equation 1

1 mol x 265.17 g H2SO4

1 mol 2 mols

1 mol x 98.08 g H2SO4

1 mol 1 mol

1 mol x 121.55 g H2SO4

1 mol 1 mol

Excellent! Excellent!

Congratulations!

From now on…

If you get an answer correct, you will be forwarded to the next question

Step 3 of Equation 1Step 3 of Equation 1

(6.58 + 98.08)(80.07) = 8.01 g H2SO4

(6.58 x 98.08)(80.06) = 8.06 g H2SO4

(7.0 x 97.99)(80.06) = 2.25 g H2SO4

Equation 2 of Problem 13Equation 2 of Problem 13

Repeated QuestionRepeated QuestionWhat mass of H2SO4 is produced from the What mass of H2SO4 is produced from the

reaction of 6.58 g of SOreaction of 6.58 g of SO33 and 1.64 g of H and 1.64 g of H22O?O?

Step 1 of Equation 2Step 1 of Equation 2

1.64 g H2O x 1 mol 18.02 g H2O

1.64 g H2O x 1 mol 21.71 g H2O

1.64 g H2O x 1 mol 19.65 g H2O

Step 2 of Equation 2Step 2 of Equation 2

1 mol x 145.23 g H2SO4

1 mol

1 mol x 98.08 g H2SO4

2 mols

1 mol x 98.08 g H2SO4

1 mol

Step 3 of Equation 2Step 3 of Equation 2

A. 8.9 g H2O

B. 9.7 g H2O

C. 4.2 g H2O

The Final QuestionThe Final Question

• Which compound is the limiting factor???

A. SO3

B. H2SO4

Yeah, you are done!Yeah, you are done!

WRONG ANSWER!WRONG ANSWER!