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Statistics
Decay Probability
• Radioactive decay is a statistical process.
– Assume N large for continuous function
• Express problem in terms of probabilities for a single event.
– Probability of decay p
– Probability of survival q
– Time dependent
tep 1
teNN 0
teq
1 qp
Combinatorics
• The probability that n specific occurrences happen is the product of the individual occurrences.
– Other events don’t matter.
– Separate probability for negative events
• Arbitrary choice of events require permutations.
• Exactly n specific events happen at p:
• No events happen except the specific events:
• Select n arbitrary events from a pool of N identical types.
npP
nNqP
)!(!
!
nNn
N
n
N
Bernoulli Process
• Treat events as a discrete trials.
– N separate trials
– Trials independent
– Binary outcome of trial
– Probability same for all trials.
• This defines a Bernoulli process.
Typical Problem• 10 atoms of 42K with a half-life
of 12.4 h is observed for 3 h. What is the probability that exactly 3 atoms decay?
Answer• Probability of 1 decay,
• And 3 arbitrary atoms decay from the 10 and 7 do not:
136.03
10 73
qpP
154.011 /)2ln( Ttt eep
Binomial Distribution
• The general form of the Bernoulli process is the binomial distribution.
– Terms same as binomial expansion
• Probabilities are normalized.
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NN
nn qpP
mathworld.wolfram.com
Mean and Standard Deviation
• The mean of the binomial distribution:
• Consider an arbitrary x, and differentiate, and set x = 1.
• The standard deviation of the binomial distribution:
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nn qp
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Disintegration Counts
• In counting experiments there is a factor for efficiency .
– Probability that a measurement is recorded
Typical Problem• A sample has 10 atoms of 42K
in an experiment with = 0.32. What is the expected count rate over 3 h?
Answer• Use the mean of the observable
count, convert to rate.
• 10(0.32)(0.154)/3 h = 0.163 h-1.
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tepq 11
teNtr tc /)1(/
More Counts
• Consider a source of 42K with an activity of 37 Bq, in a counter with = 0.32 measured in 1 s intervals.
• What is the mean count rate?
• What is the standard deviation of the count rate?
• The mean disintegration rate is just the activity, rd = 37 Bq.
– The count rate is
• Decay constant is = ln2 / T = 0.056 h-1 = 1.55 x 10-5 s-1.
– The probability of decay is
• Number of atoms is N = rd / = 2.4 x 106.
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1s4.3)1( ppNc
51055.11 tep
Poisson Distribution
• Many processes have a a large pool of possible events, but a rare occurrence for any individual event.
– Large N, small n, small p
• This is the Poisson distribution.
– Probability depends on only one parameter Np
– Normalized when summed from n =0 to .
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2
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Poisson Properties
• The mean and standard deviation are simply related.
– Mean = Np, standard deviation 2 = ,
• Unlike the binomial distribution the Poisson function has values for n > N.
Poisson Away From Zero
• The Poisson distribution is based on the mean = Np.
– Assumed N >> 1, N >> n.
• Now assume that n >> 1, large and Pn >> 0 only over a narrow range.
• This generates a normal distribution.
• Let x = n – .
• Use Stirling’s formula
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Normal Distribution
• The full normal distribution separates mean and standard deviation parameters.
• Tables provide the integral of the distribution function.
• Useful benchmarks:
– P(|x - | < 1 = 0.683
– P(|x - | < 2 = 0.954
– P(|x - | < 3 = 0.997
Typical Problem• Repeated counts are made in 1-
min intervals with a long-lived source. The observed mean is 813 counts with = 28.5 counts. What is the probability of observing 800 or fewer counts?
Answer• This is about -0.45.
• Look up P((x-)/ < -0.45)
– P = 0.324
22 2/
2)(
xexf
Cumulative Probability
• Statistical processes can be described for large numbers.
– Can we model one event?
– No two events are equal
• Probability distributions typically reflect incidence in an infinitessimal region.
– Integrate over a range
• Consider an event with a 500 keV incident photon on soft tissue with attenuation = 0.091 cm-1.
• The probability of an interaction in 2 cm is
• P = 1 – 0.834 = 0.166
• How does one simulate this?
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0
x
c dxxPP0 1 )(
Random Numbers
• To simulate a statistical process one needs a random selection from the possible choices.
• Algorithms can generate pseudo-random numbers.
– Uncorrelated over a large range of trials.
– Randomness limited for large sets or fixed starts
• Linear Congruential Generator
• Start with a seed value, X0.
– Select integers a, b.
• For a given Xn,
– Xn+1 = (aXn + b) mod m
• The maximum number of random values is m.
Random Distribution
• A selected random number is usually generated in a large range of integers.
– Uniform over the range
• Normalize values to select a narrow range.
– Usually from 0 to 1
• Convert range to match a distribution.
• To select a number with a normal distribution:
– Take two random numbers R1, R2 from 1 to N.
– Apply algorithm with
– (Box-Mueller algorithm)
NRr ii /
21 ln22cos rrx
Monte Carlo Method
• The Monte Carlo method simulates complicated systems.
• Use random numbers with distribution functions to select a value.
• Test that value to see if it meets certain conditions.
• Simple Monte Carlo for .
– Select a pair of random numbers from 0 to 1.
– Sum the squares and count if it’s less than 1.
– Multiply the fraction that succeed by 4.
Interaction Simulation
Typical Problem• A 100 keV neutron beam is
incident on a mouse (3 cm thick). Calculate the energy deposited at different depths.
Data Table• H =0.777 cm-1
• O =0.100 cm-1
• C =0.0406 cm-1
• N =0.00555 cm-1
• Total =0.92315 cm-1
• Simulate one neutron.
• Find the distance of penetration by inverting the probability.
• Find the nucleus struck.
– Normalize the i to the total possible tot.
• Select the energy of recoil and angle.
• Repeat for new distance.
itot
rx 1ln1
Fitting Tests
• Collected data points will approximate the physical relationship with large statistics.
• Limited statistics require fits of the data to a functional form.
Least Squares
• Assume that the data fits to a straight line.
• Use a mean square error to determine closeness of fit.
• Minimize the mean square error.
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021
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021
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Nb
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Polynomial Fit
• The procedure for a least squares fit applies to any polynomial.
– n+1 parameters ak
• Minimize error expression Q.
• Requires simultaneous solutions to a set of n+1 equations.
n
k
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k j
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k j
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Q
Exponential Fit
• The least squares fit can be applied to other functions.
• For a single exponential a fit can be made on the log.
• For the sum of exponentials consider constants a, b.
– Select initial values
– Taylor’s series to linearize
– Find hk that minimize Q
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k
xbk
keaxy1
)(
bxay lnln
bxaey
n
kk
kkjkj h
b
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kkk hbb 0
Chi Squared Test
• Fitting is based on a limited statistical sample.
• A chi-squared test measures the data deviation from the fit.
– Normally distributed
– Mean k for k degrees of freedom
• Divide the sample into n classes with probabilities pi and frequencies mi.
• The test is
n
i i
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Npm
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1(
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2
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