# Statis Momen

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step 1

step 2 MOMEN INERSIA. I Rumus Umum :

= 12274.3

step 3 MOMEN LAWAN, W Rumus Umum :

= 1523.71 cm³

= 724.385 cm³

step 4 TEGANGAN :

cm4

y1

y2

5

25

5

20

z1

z2

yb = 16,94

ya = 8,06

)Ukuran daam cm!

"#

∫ =   dA I    . 2

ρ

2

2

3

22

2

1

3

11   ... 12

1 ...

12

1  z  AII hb z  AI hb Ix

tot    +++=

y

I  W    =

a  ATAS   y

Ix

W    =

b

BAWAH   y

Ix W    =

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y1

z\$3

y2

ya = 8,06

yb = 16,94

z\$2

z\$1

20

5

25

5

"#

)Ukuran daam cm!

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1) TEGANGAN GESER, t  Rumus Umum :

a!. %aya\$ )&'ns!

1200 ) 25 ( 5 ( 5.56 ! = 2.7157 k*cm+

25 ( 12274.3056

1200 ) 5 ( 20 ( 6.94 ! = 13.5785 k*cm+

5 ( 12274.3056

1200 ) 5 (  ( 8.47 ! = 14.0349 k*cm+

5 ( 12274.3056

2) TEGANGAN NORMAL, Rumus Umum :

= / = = 8.89k*cm+

 225

3) TEGANGAN LENTUR, Rumus Umum :

a! . %'ra as == m'n n'a b'rar s'ra aas 'rark )!

= 720000 = 472.532 k*cm+ )!

1523.7

b! . %'ra ,aa == m'n n'a b'rar s'ra aas 'r'kan )!

= 720000 = 993.946 k*cm+ )!

724.39

τa =

τb =

τc =

5

I b

S  D

.

.

=τ

N σ

A

P  =σ

N σ

M  σ    W

M  =σ

ATAS

I  I   M

W   M

=σ

BAWAH

I  I

M  W

M  −

=σ

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ambar >aram

?kk @rdna >aram

>aram ?'. 's'r sca'

2.7157 100 0.027157001 13.5785 100 0.135785007

14.0349 100 0.140348892

>aram ?'. /rma sca'

8.88889 100 0.088888889

8.88889 100 0.088888889

>aram ?'. #'nur sca'

472.532 10000 0.047253182

993.946 10000 0.099394625

ya =8,06

yb = 16,94

z\$2

z\$1

20

5

25

5

y1

z\$3

y2

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Parameter

b1 = 25 cm

h1 = 5 cm

b2 = 5 cm

h2 = 20 cm

STATIS MOMEN KE TEPI ATAS, (ya)

C = 25 ( 5 = 125 cm+

CC = 5 ( 20 = 100 cm+

y1 = 5 * 2 = 2.5 cm

y2 = 20  5 = 15 cm

2

ya = C.y1  CC.y = 8.05556 cm C  CC

yb = )205!  ya = 16.9444 cm

z1 = ya  y1 = 5.55556 cm

z2 = y2  ya = 6.94444 cm

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z\$1 = ya  y1 = 5.55556 cm

z\$2 = y2  ya = 6.94444 cm

z\$3 = yb*2 = 8.47222 cm

b3 = 5 cm

h3 = yb cm

= 16.9 cm

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>k'au : > = 1.2 

= 1200 k

>k'au : / = 2 

2000 k

=

= C  CC

= 225 cm+

>k'au : = 7.2 .m

720000 k.cm

= 1523.71 cm³

= 724.385 cm³

 a

b 1 .

1   b

2 .

2

 C  C

- ?%

- ,-D

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8/160 ?A ?A. A%AR

8

14

13,5792,716

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C = 600 ( 200 = 120000 mm2

CC = 200 ( 500 = 100000 mm2

y1 = 200 * 2 = 100 cm

y2 = 500  200 = 450 cm

2

ya = C.y1  CC.y2 = 259.091 cm

C  CC 

yb = )205!  ya = 440.909 cm



600

50 10 0 1 00 1 00 1 00 1 00

50

50

100

50

200

50 100

50

50

150

250

350

450

550

650

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12/160 ?A. #A/?UR ?A. /BR#

993,946

472,5328,889

14

3,579

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b = 250 fc' = 25 N/mm2

h = 500 fy = 400 N/mm2

d' = 50 D = 19 mm

As tul = 2!"52# mm2

d = h \$ d'

d = 450 As = 50"5%2 As' = 50"5%2

d \$ h/2 = 200

d \$ d' = 400

0"5 & fc' & h & b & d \$ h/2( ) As' & fy & d \$ d'( %%#,!4!,#9!"#5 200"00

0"5 & fc' & h & b ) As ) As'( & fy !!!%#1"9%#%#55

b = 250 fc' = 25 N/mm2

h = %00 fy = 400 N/mm2

d' = 50 D = 19 mm

As tul = 2!"52# mm2

d = h \$ d'

d = 550 As = 50"5%2 As' = 50"5%2

d \$ h/2 = 250

d \$ d' = 500

0"5 & fc' & h & b & d \$ h/2( ) As' & fy & d \$ d'( 9%%,992,242"19 250"00

0"5 & fc' & h & b ) As ) As'( & fy !%#9%"9%#%#55

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b = 250 fc' = 25 N/mm2

h = 500 fy = 400 N/mm2

d' = 40 D = 19 mm

As tul = 2!"52# mm2

d = h \$ d'

d = 4%0 As = 50"5%2

As' = 50"5%2

d \$ h/2 = 210

d \$ d' = 420

0"5 & fc' & h & b & d \$ h/2( ) As' & fy & d \$ d'( #00,#10,9!"44 210"00

0"5 & fc' & h & b ) As ) As'( & fy !!!%#1"9%#%#55

b = 250 fc' = 25 N/mm2

h = 500 fy = 400 N/mm2

d' = 50 D = 19 mm

As tul = 2!"52# mm2

d = h \$ d'

d = 450 As = 11!4"115   ==>PERHATAN JIKA TULA As' = 50"5%2

d \$ h/2 = 200

d \$ d' = 400

0"5 & fc' & h & b & d \$ h/2( ) As' & fy & d \$ d'( %%#,!4!,#9!"#5 19!"4!

0"5 & fc' & h & b ) As ) As'( & fy !4501!0"4%!5%214

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b = 250 fc' = 25 N/mm2

h = %00 fy = 400 N/mm2

d' = 40 D = 19 mm

As tul = 2!"52# mm2

d = h \$ d'

d = 5%0 As = 11!4"115

As' = 50"5%2

d \$ h/2 = 2%0

d \$ d' = 520

0"5 & fc' & h & b & d \$ h/2( ) As' & fy & d \$ d'( 1,005,%#1,9!1" 252"59

0"5 & fc' & h & b ) As ) As'( & fy !91!0"4%!5%214

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NGAN TIDAK SERAGAM

ACER: ,ARA%AR @A RD ?U#//  E/ #A,CD ,/E@  UNTUK MENCAPAI KESEIMBANGAN (LEBIH DEKAT KE AS YANG BESAR)

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b = 250 mm fc' = 2# N/mm2

h = %00 mm fy = 400 N/mm2

d' = 50 mm D = 1% mm As tul = 201"0%192929# mm2

d = h \$ d'

d = 550 mm As = ! D 1% %0!"15#9492

As' = ! D 1% %0!"15#9492

Statis Momen terhadap t!an"an tari#\$ As %

d \$ h/2 = 250 mm

d \$ d' = 500 mm

d * = 0"5 & fc' & h & b & d \$ h/2( ) As' & fy & d \$ d'( = 91,2%2,15#"90 =

0"5 & fc' & h & b ) As ) As'( & fy !,925,04"%!

Statis Momen terhadap tepi atas &!o# te"' Te#an &eton %

d * = 0"5 & fc' & h & b &  h/2( ) As' & fy & d'( ) As & fy & d( 11##51459"4##42 =

0"5 & fc' & h & b ) As ) As'( & fy !,925,04"%!

Statis Momen terhadap t!an"an te#an\$ As( %

h/2 \$ d' = 250 mm

d \$ d' = 500 mm

d * = 0"5 & fc' & h & b & h/2 \$ d'( ) As & fy & d \$ d'( = 91,2%2,15#"90 =

0"5 & fc' & h & b ) As ) As'( & fy !,925,04"%!

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Statis Momen terhadap titi# ) %

& = 125 mm d+- .+-s t+l +m+. bt 3 3+

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