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STANDARD DEVIATIONSTANDARD DEVIATION
Quartiles from Frequency Tables
10 Apr 202310 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
StatisticsStatisticsw
ww
.math
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Reminder !
S5 Int2
Range : The difference between highest and Lowest values. It is a measure of spread.
Median : The middle value of a set of data.When they are two middle values the median is half way between them.
Mode : The value that occurs the most in a set of data. Can be more than one value.
10 Apr 202310 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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S5 Int2
Standard DeviationStandard DeviationFor a FULL set of DataFor a FULL set of Data
The range measures spread. Unfortunately any big change in either the largest value or smallest scorewill mean a big change in the range, even though
onlyone number may have changed.
The semi-interquartile range is less sensitive to a single number changing but again it is only really
based on two of the score.
10 Apr 202310 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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S5 Int2
Standard DeviationStandard DeviationFor a FULL set of DataFor a FULL set of Data
A measure of spread which uses all the data is the
Standard Deviation
The deviation of a score is how much the score differs from the mean.
Score Deviation(Deviation)2
70
72
75
78
80
Totals 375
Example 1 :Find the standard deviation of these fivescores 70, 72, 75, 78, 80.
S5 Int2
Standard DeviationStandard DeviationFor a FULL set of DataFor a FULL set of Data
Step 1 : Find the mean
375 ÷ 5 = 75Step 3 : (Deviation)2
10 Apr 202310 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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-5
-3
0
3
5
0
25
9
0
9
25
68
Step 2 : Score - MeanStep 4 : Mean square deviation
68 ÷ 5 = 13.6
Step 5 :
Take the square root of step 4
√13.6 = 3.7
Standard Deviation is 3.7 (to 1d.p.)
Example 2 :Find the standard deviation of these sixamounts of money £12, £18, £27, £36, £37, £50.
S5 Int2
Standard DeviationStandard DeviationFor a FULL set of DataFor a FULL set of Data
Step 1 : Find the mean
180 ÷ 6 = 30
10 Apr 202310 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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Step 2 : Score - Mean
Step 3 : (Deviation)2
Step 4 : Mean square deviation
962 ÷ 6 = 160.33
Score Deviation(Deviation)2
12
18
27
36
37
50
Totals 180
-18
-12
-3
6
7
20
324
144
9
36
49
400
0 962
Step 5 :
Take the square root of step 4
√160.33 = 12.7 (to 1d.p.)
Standard Deviation is £12.70
10 Apr 202310 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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S5 Int2
Standard DeviationStandard DeviationFor a FULL set of DataFor a FULL set of Data
When Standard Deviationis LOW it means the data values are close to the
MEAN.
When Standard Deviationis HIGH it means the data values are spread out from
the MEAN.
Mean Mean
10 Apr 202310 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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S5 Int2
Standard DeviationStandard DeviationFor a Sample of DataFor a Sample of Data
In real life situations it is normal to work with a sample of data ( survey / questionnaire ).
We can use two formulae to calculate the sample deviation.
2( )
1
x xs
n
s = standard deviationn = number in sample∑ = The sum of
22
1
xx
nsn
x = sample mean
We will use this version because it is easier to use in
practice !
Example 1a : Eight athletes have heart rates 70, 72, 73, 74, 75, 76, 76 and 76.
10 Apr 202310 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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S5 Int2
Standard DeviationStandard DeviationFor a Sample of DataFor a Sample of Data
Heart rate (x)
x2
70
72
73
74
75
76
76
76
Totals
4900
5184
5329
5476
5625
5776
5776
5776
∑x2 = 43842∑x = 592
Step 2 :
Square all the values and find the
total
Step 3 :
Use formula to calculate sample deviation
22
1
xx
nsn
259243842
88 1
s
43842 43808
7s
4.875s
2.2 ( 1 . .) s to d p
Step 1 :
Sum all the values
Q1a. Calculate the mean :
592 ÷ 8 = 74
Q1a. Calculate the sample deviation
Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Heart rate (x)
x2
80
81
83
90
94
96
96
100
Totals
6400
6561
6889
8100
8836
9216
9216
10000
65218 64800
7s
418s
20.4 1 . .) ( s to d p
Example 1b : Eight office staff train as athletes. Their Pulse rates are 80, 81, 83, 90, 94, 96, 96 and 100 BPM
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S5 Int2
Standard DeviationStandard DeviationFor a Sample of DataFor a Sample of Data
∑x = 720
22
1
xx
nsn
272065218
88 1
s
Q1b(ii) Calculate the sample deviation
Q1b(i) Calculate the mean :
720 ÷ 8 = 90
∑x2 = 65218
10 Apr 202310 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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S5 Int2
Standard DeviationStandard DeviationFor a Sample of DataFor a Sample of Data
Q1b(iii) Who are fitter the athletes or staff.
Compare meansAthletes are fitter
StaffAthletes
2.2 1 . .) ( s to d p
74 Mean BPM 90 Mean BPM
20.4 1 . .) ( s to d p
Q1b(iv) What does the deviation tell us.Staff data is more
spread out.