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SSC MOCK TEST – 124 – 1 [Answer with Solution]1. (A) The young one of a baboon is called an infant while

the young one of an beaver is called a kitten.

2. (D) The series is a, ab, abc, a, ab, abc, ...

3. (D) 7 13 25 49 97 ?

+6 +12 +24 +49 +96

×2 ×2 ×2 ×2

? = 97 + 96 = 193

4. (B) The letters in the series are moving four placesback in the alphabetical series. So, the next lettersin the series will be FBX.

5. (D)

G J X U M P R O S V

+6 +6+6 +6

–6–6

6. (C) 17 150 167 1500 1667 15000

+150 +1500 +15000

16667

×10 ×10

7. (D) Gourd, Pumpkin and French Beans grow on vineswhile Jackfruit grows on trees.

8. (C) Sum of the digits of 272 is 11. While in rest of thethree option, sum of the digits of the numbers is10.

9. (C) Animals in options (A), (B) and (D) are mammalswhile hen is a bird.

10. (D)

O6 km 8 km

6 km 6 km

14 km Ravi

8 km

Rakesh

Let O be the initial position of Ravi and Rakesh.

Distance between Ravi and Rakesh

= 2 214 14 14 2 km

11. (A) The order of the height of five given persons willbe:

Anil > Karan > Mukesh and Anil > Sunil > Rakesh

Hence, Anil is the tallest among the five.

12. (B) Option (B) is the answer since the given word hasa single 'N' while TOURNAMENT uses 'N' twice.

13. (C) In the series D F J P X the number of lettersskipped between adjacent letters in consecutiveodd numbers starting from 1.

D 2 F 4 J 6 P 8 X

14. (A) Total members = 2 + 3 + 4 × 2 + 4 × 5 = 33.

15. (D) P(16 4 T(20)

L(12) 4 H(8)

A(1) 4 E(5)

N(14) 4 J(10)

E(5) 4 I(9)

T(20) 4 P(16)

Similarly,

S(19) 4 (W(23)

Q(17) 4 M(13)

U(21) 4 Y(25)

A(1) 4 W(23)

R(18) 4 V(22)

E(5) 4 A(1)

16. (A) In column 1,

52 = 25, 122 = 144 5 × 12 ÷ 2 = 30

In column 2,

72 = 49, 142 = 196 7 × 14 ÷ 2 = 49

Similarly, in column 3,

92 = 81, 162 = 256 9 × 16 ÷ 2 = 72.

17. (D) 7 15 30 59 116 229

+8 +15 +29 +57 +113

8×2–1 15×2–1 29×2–1 57×2–1

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18. (B) 27 13 51 29 63 37

14÷2=7 22÷2=11 26÷2= 13

19. (A)GlovesThings

Warm

As is clear from the Venn diagram, only conclusion(III) follows.

20. (B)

21. (D) Universe contains millions of galaxies and galaxycontains millions of stars and planets.

22. (C) 1 and 5 are opposite but in option (A) they areadjacent. Similarly, 3 and 6 are opposite but inoption (B) they are adjacent. Similarly, 2 and 4are opposite but in option (D) they are adjacent.Hence, option (C) is correct.

23. (C)

24. (A)

25. (C) For matrix,

B – 45, 62

O – 25, 46

R – 22, 63

N – 33, 53

Option options,

BORN 62, 46, 22, 53.

26. (A) 30

20

8

5/2

1×5/2 ×5/2

5302

Total money spend = 5302

× 9 = 292.50

27. (C)

28. (A)

29. (A)

30. (D) Fixed price + 5 km = 350 .......... (i)

Fixed price + 20 km = 800 .......... (ii)

Eq. (i) – (ii)

15 km = 450

1 km charge = ` 30

Putting in (i)

So, fixed price = 350 – 30 × 5 = ` 200

31. (C) ATQ,45 man = 25 women9 man = 5 women

Man 5Women 9

Let, Man = 50Women = 90

Married Man = 50 × 45

100 = 22.5

Married Women = 90 × 25

100 = 22.5

Total adults who are married = 45Total adults who are not married = 140 – 45 = 95

So, % 95

140×100

= 95014

= 67.85%

32. (D) Let, B = 221, C = 1, a = 133. (A) ATQ,

CP ×37 1 51.802 100 100

CP = ` 280

34. (B)18 3

647 47

Given

Quantity Cheaked Total 47 : 3 = 50×20 ×20940 1000 gram

35. (B) After taking out 8 ltrs.Ratio will remain same to 5 : 3So, Alcohal in new mixture of 32 ltrs.

= 58

×32 = 20

Water in new mixture of = 38

×32 = 12

New quantity of water = 12 + 8 = 20So, Alcohal : Water

20 : 20= 1 : 1

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36. (A) Let Distance = 120×4 = 480 km

Time taken = 12020

= 6 hrs.

for Ist side

For IInd side = 12030

= 4 hrs.

IIIrd side = 12040

= 3 hrs.

IVth side = 12060

= 2 hrs.

Average speed = total distance

total time

= 480

6 4 3 2 = 32

37. (C)

2 3

69I II

18

= To make it 34

flat = 34

× 185 = 2h 42 min

38. (A) an + bn is always divisible by a +b

if x is odd number

So,17 29 46

23 23 = 2

So, remainder = zero

39. (C) 10 k3 10242 10 10100

10 k10 30 22 10 10 2 10

1032 = 10k

k = 32

40. (D) A B 650

Relative speed (A+B) = 65010

= 65 km/h

A + B = 65 km/h .......... (i)

Now,

Distance covered by (A + B) in 8 hour

8 × 65 = 520 km

Remain distance = 650 – 520 = 130

130 km distance is covered by A in 4 hour 20 min.

speed of A = 130

4hrs20 min

= 130 313

= 30 km/hrs.

speed of B = 65 – 30 = 35 km/ hrs.

41. (A)

96

A32

C24

43

B48

2

work done by A = 4 ×3 = 12

work done by B = 2× (4+2) = 12

work done by C = 96 – (12+12) = 72

work done by

A B C

12 12 72

1 1 6 = 8

×810 ×810

4860 6480 (given)

42. (B) timep taken by pipe A to fill the tank = 48 hour.

time taken by B to likage the tank of its fulleffeciency

= 45 1002 75 = 30 hour

240

48 30

–85

A B

ATQ,

capicity = 240 × 3 × 14

= 180

Now, A + B = 5 – 8 = –3 unit/hour

Require time = 180

3 = 60 hour

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Answer Key1. (A) 2. (D) 3. (D) 4. (B) 5. (D)6. (C) 7. (D) 8. (C) 9. (C) 10. (D)11. (A) 12. (B) 13. (C) 14. (A) 15. (D)16. (A) 17. (D) 18. (B) 19. (A) 20. (B)21. (D) 22. (C) 23. (C) 24. (A) 25. (C)26. (A) 27. (C) 28. (A) 29. (A) 30. (D)31. (C) 32. (D) 33. (A) 34. (B) 35. (B)36. (A) 37. (C) 38. (A) 39. (C) 40. (D)41. (A) 42. (B) 43. (D) 44. (D) 45. (B)46. (B) 47. (B) 48. (C) 49. (B) 50. (A)51. (B) 52. (C) 53. (B) 54. (D) 55. (C)56. (D) 57. (A) 58. (A) 59. (D) 60. (C)61. (B) 62. (C) 63. (A) 64. (B) 65. (A)66. (A) 67. (D) 68. (D) 69. (B) 70. (C)71. (D) 72. (C) 73. (C) 74. (A) 75. (A)76. (A) 77. (B) 78. (B) 79. (B) 80. (C)81. (C) 82. (C) 83. (C) 84. (B) 85. (C)86. (A) 87. (A) 88. (C) 89. (B) 90. (B)91. (B) 92. (A) 93. (A) 94. (C) 95. (C)96. (D) 97. (B) 98. (A) 99. (D) 100.(C)

43. (D)

A

B

C

P T70° 45°

65°

70°

PAC + BAC + BAT = 180°

PAC = 180° – 65° – 45° = 70°

PAC = ABC = 70° (alternate angles)

44. (D) EF || DC (given)

EGF ~ CGD ( by A–A)

EG EFGC CD

5 EF

10 18

EF = 9cm.

45. (B) A

CB D

P R Q

APR ~ ABD ( by A–A)

AP ARAB AD

3 4.55 AD AD = 7.5 cm

46. (B) cos2 + cos2 = 2

= = 0º

tan7 + sin8 = 0

47. (B) cot 90º = 0

hence 0

48. (C) Let, a = s , b = s, c = 0

Now, 2 2 2 2

2 2

s s s s s 0 ss s 0

= 1

49. (B) put n = 1

sum = 1–12

= 12

So, option (B)

50. (A) As rate is same-annualy, so

Time will be doubled

Amount Principle

1331 1000

Taking square root

11 10

So 1

10 × 100 = 10% half yearly

or

20% per annualy