SSC 52 (2)

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Centres at:MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR BORDER JAIPUR GURGAON

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1. (C)2. (B)

3. (A) Second is more intense form of the first.

4. (C)24 : 48 :242 : :

2 4

484

Number digits and difference of digits

make the third digit.

5. (D) INDIA: (3, 2) means 3 vowels and 2

consonants. Similarly in WOMEN 2 vowels

and 3 consonent.

6. (B) In other all have needles.

7. (B) Except it others need specified group size.

8. (B) Except it others are the forms of carbon.

9. (B) Except it all others are the staff of any

educational institution.

10. (D) Except it if we add one to any number, we

get a prime number.

E.g.; 18 + 1 = 19 (Prime number)

28 + 1 = 29 (Prime number)

30 + 1 = 31 (Prime number)

26 + 1 = 27 (Not a prime number)

11. (A)

12. (B) A, B, C reaches to triple positions and

saturate again they start decreasing to

single.

13. (A) taking from back side

( 2 + 1), ( 3 + 2), ( 4 + 3), ( 5 + 4), ( 6 + 5)

14. (C) Series follow the following rule.

( 2 + 3), ( 3 + 2), ( 2 + 3), ( 3 + 2) ....

15. (B) Series :

a a b b c c / a a a b b b c c c / a a a a

16. (D) H

So,

O

B

T

O

E

R

L

E

8 +15

2

+

+

20

15

+

+

5

18

+

+

12

5

=

=

60

40

5 (No.

= 36

in BORE

of letters)

(No. of letters)

= 55

(17-18.) 2 8 9 read from paper2 7 6 tea from field. 8 5 wall paper

Hence, 2 means 'from'

8 means 'paper'

9 means 'read'

5 means 'wall' and7 means 'tea or field'

6 means 'tea or field'

17. (A)

18. (C)

SSC MOCK TEST 52 (SOLUTION)

19. (B)

N

W E

S

EW

NB

S40m

A East C

40m

20.(A) In a simple year day of first date andthe last date is same thus answer willbe Friday.

21. (C) Because 'Electron' and Nucleus exist in

atom.

22. (C)

Fathers

Sons

All fathers are the sonsbut all sons are not fathersand daughters are not sons or fathers.thus Answer option in 'D'

23. (A) 2 5 = 1010 3 2 = 28Similarly,4 5 = 2020 3 2 = 58

24. (A) 97

63 , 7

7

49 , 5

7

35

Similarly,

99

81 , 7

9

63 , 7

9

45

25. (C)26. (C)

U

DE, RS, ST, RT, AE, NR (6)

N D E R S T A N D

27. (A)

28. (B)332842812

665685624

=

79

158= 2 1H2

29. (B) Here '' '', +, '' and + Hence 100 10 1000 1000 + 100 10

can be written as 100 10 1000 100 10 = 1000 1000 + 10 10 = 0 (zero)

30. (B)31. (A)32. (D)

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33. (C) Faces which appears together cannot beopposite to each other faces which appear

with ' ' are O, * , so opposite of ' ' is'' Answer.

34. (D)35. (A) Any person > A > D > C > B36. (B) F 5 = 4(S 5) ..........(i)

F + 5 = 2(S + 5) ........(ii)F 5 = 4S 20F = 4S 15 .......(i)Putting the value of F in (ii)

4S 15 + 5 = 2 (S + 5)4S 10 = 2S + 10 2S = 20 S = 10

Putting S = 10 in F 5 = 4 (S 5)

F 5 = 4 (10 5) F 5 = 4 5 F 5 = 20 F = 25

37. (B) Conclusion - I is not related with thestatements and conclusion - II is true.

38. (D) Both the conclusions are true in the lightof statements.

39. (A)B

B Bor

B

T

T C

C

CT

St- (I)

St- (II)

Thus conclusion - I is the part of abovepossibilities and it is correct.Conclusion - II is doubtful.

40. (A) In all other figures, the arrow headsappear on the extended sides of the mainelement.

41. (C) In each of the other figures, two area areinside the square and two are outside thesquare.

42. (A) The outer element rotates 135CW andinner element rotates 135 ACW.

43. (B) The upper element rotates through 180

and its head gets inverted. The lowerelement gets vertically inverted.

44. (A)45. (B)46. (A)

47. (B) 3,Series: 10, 29,

9

61, 185, 373

2 + 3 3 + 2 2 + 3 3 + 2 2 + 3

48. (A) 61, 52, 64, 94,63

46, 18

16 25 46 49 64 8142

52

62

72

82

92

Series:

In place of 64 there must be 63.

49. (C) 2, 5, 14, 27,12

58,121Series:

50. (B) The numerical group of REAP will beR = 56, 68, 77, 86, 95E = 00, 20, 31, 44A = 01, 13, 22, 32, 43P = 59, 66, 77, 86, 95

51. (B)

352

32

2

32

3

=352

)32)(32(

)32(2

)32)(32(

)32(3

=352

34

324

34

336

=352

)324()336(

=352

324336

=

352

352

= 1

52. (A) ab= 125 ab= 53

a = 5 & b= 3Now,

(a b)a+ b 4 = (5 3)5 + 3 4= 24= 16

53. (A) Suppose the Ist number is xThen, 2nd number = 100 x

HCF LCM = Ist number 2nd number5 495 = x(100 x)

x2 100x+ 2475 = 0 x= 45 or x= 55Required difference = 55 45 = 10

54. (A) Let the total capacity of the tank be xl.Then,

3

x= 80

x = 240

5

1part of the tank holds =

5

1 240 = 48 l.

55. (B)

5

45

31

21

=

9

151

21

=

3

51

21

=

3

53

21

= 1 + 8

32

= 1 + 4

3

= 4

7

56. (C) Let the four numbers be x, 2x, 3xand 4x.Then,

x+ 2x+ 3x+ 4x = 2010x = 20

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x = 2Ist number + 4th number = x+ 4x

= 5x

= 5 2 = 10

57. (D) )]75.0(75.01[75.01

)75.0(

=25.0

])75.0(75.01)[75.01()75.0( 23

=25.0

)75.0(1)75.0( 333 =

25.0

1= 4 = 2

58. (B) Let the SP of each article = `x.Then,

CP of 12 articles = `8 x= `8x

SP of 12 articles = `12 x= `12x

% profit =CP

CPSP 100

=x

xx

8

812 100

=x

x

8

4 100 = 50%

59. (B) x+ y = 3(x y)

y+ 3y = 2x

x = 2yNow,

)(2

322 yx

xy

=

)4(2

2322 yy

yy

= 2

2

6

6

y

y= 1

60. (B) Total age of 12 players = 12 25 = 300 yrs

Total age including captain's age= 13 26= 338 yrs

Age of the captain = 338 300= 38 years

61. (D) Speed of the aeroplane = 280 km/hr

Time = 4 hrsDistance covered by it = 280 4

= 1120 kmSpeed of the aeroplane (when it covers

the same distance in 14

1hours)

=

4

11

1120=

5

41120= 896 km/hrs.

62. (C) Total time

= 80

600

+ 40

800

+ 400

500

+ 50

100

=8

246hours

Average Speed =

8

246

100500800600

=246

82000=

123

8000

= 65123

5km/hrs.

63. (B) Let the number of coins of denominations

= `1 = 2xand the number of coins of denominations

= 50 paise = 3x

and the number of coins of denominations

= 25 paise = 4x

ATQ,

2x 1 +2

3x+

4

4x= 180

1

2x+

2

3x+

1

x= 180

2

234 xxx = 180

x =9

2180= 40

No. of 50 paise coins = 3x= 3 40 = 12064. (C) Let xcm be the side of the square.

Then,

Its diagonal = x2

a = x2

x =2

a

Area of the square = (side)2

=

2

2

a=

2

2asq. unit.

No. of 50 paise coins = 3x= 3 40 = 120

65. (C) Part filled by A and B in 1 hour

=12

1+

15

1=

60

45 =

60

9=

20

3

Part filled by A & C in the next 1 hour

=12

1+

1

20=

60

35 =

60

8=

15

2

Part filled in 2 hours

=

20

3+

15

2=

60

89 =

60

17

Part filled in 6 hours

= 3 60

17=

60

51

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Remaining part

= 1

60

51=

60

9=

20

3

20

3part is filled in 1 hour.

Total time taken = (6 + 1) = 7 hours

66. (C) Let the sides of the rectangular plot be 5xm

and 4xm

its area = 5x 4x

500 = 20x2

20

500= x2

x =25

= 5

Perimeter = 2(5x+ 4x)

= 2 9x= 18 5 = 90 m

67. (C) Circumference of the wheel

= 2 r

= 2 7

22 21

= 132 cm

= 1.32 m

Distance covered = 1056 m

No. of revolution =32.1

1056

= 800 revolutions

68. (D)r = 5 cm

l = 7 cm

Sector area =2

rl=

2

57= 17.5 cm2.

69. (C) l = 16 m

b = 12 m

h =3

32m

Longest rod = 222 hbl

=

222

3

321216

=9

1024144256

=9

1024400

= 9

10243600

=9

4624=

3

68= 22

3

2m

70. (D) Volume of the metallic cone

=

3

1 r2h

=3

1 202 10 cm3

Volume of I spherical ball

=3

4 23cm3

No. of balls =222

3

4

1020203

1

=32

4000

= 125

71. (D) Income Ist year = `2x(say)

Income 2nd year = `3x

But it is given = `45,000

3x = `45,000

2x = `30,000Let expense Ist year = 5y

expense 2nd year = 9y

5y = `25,000

y = `5000

Expenses 2nd year = `45,000

Total expense = `(25,000 + 45,000)

=`

70,000Total income = `(45,000 + 30,000)

= `75,000Total savings for the two years

= `(75,000 70,000)

= `500072. (C) h = 50 cm

r = 24 cm

l = 22 rh

= 22 2450 = 5762500

= 3076 = 55.46Current surface area of the conical tank

= r l=3.14 24 55.46= 4179.60 cm2

=10000

60.4179m2

= 0.471960 m2

Cost of painting = `0.471960 35

= `16.50 (approx)

73. (A) Radius of the cylindrical tank =

2

35cm

Quantity of water drawn off= 11 ltires= 11 1000 cm3

= 11000 cm3

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Let 'h' be the height of the tank.ATQ,

r2h = 11000

7

27

2

35

2

35 h= 11000

h=353522

22711000

= 11.43 cm

Decrease in the water level = 11.43 cm.74. (D) Let the three consecutive odd natural

number be x, x+ 2 and x+ 4Then,

x+ (x+ 2) + (x+ 4)= 147

3x+ 6 = 147

x = 3

6147

=3

141= 47

Middle number = (x+ 2) = (47 + 2) = 4975. (B) Let the three numbers be x, yand z.

Then, x+ y+ z = 60 3 = 180

Again,

x=4

1(y+ z)

x + 4x= 180

x=5

180= 36

First number = 3676. (A) 5 men 6 = 10 women 5

3 men = 5 womenNow,

5 women + 3 men= 5 women + 5 women

[3 men = 5 women]= 10 women

10 women complete the work in 5 days.

Time taken by 5 women & 3 men tocomplete the work = 5 days77. (C) Single Equivalent discount ( for successive

discount of 10% and 30%)

= 10 + 30 100

1030= 37%

78. (A) LCM of 4, 6, 8, 14 = 168 seconds = 2 minutes 48 seconds

Bells will ring again at 12 + 2 min 48 sec= 12 hrs 2 min 48 seconds

79. (D) 3 4 = 43 44 = 12 256

4 6 = 34 36 =12 216

615 = 26 215 =12 225 and 12 245

Biggest = 12 256 = 3 4

80. (B) Let the cost price of the goods be `100.

Marked price = `125

SP = 90% of 125 =`

112.5% profit = (112.5 100)% = 12.5%81. (B) Let r

1and r

2be the rates of interest from

two different sources.ATQ,

SI1 SI

2= 13.50

100

31500 1r

100

31500 2r= 13.50

100

31500[r

1 r

2] = 13.50

r1

r2

=31500

10050.13

=

4500

1350= 0.3%

82. (D) x =2

3

x

1=

3

2

On applying C & D,

x

x

1

1=

32

32

= )32)(32(

)32( 2

= 1

)32( 2

x

x

1

1=

1

32

Again applying C & D,

xx

xx

11

11=

132

132

=

31

33

=3 (1 3 )

1 3

= 3

83. (B) Required time =

Total Distance

Relative Speed

=)105(

1200

minutes

=15

1200= 80 minutes

84. (B) Let the original fraction bey

x

3

2.

Then,

y

x

3

62 =

3

2

y

x

3

2

(2x 6) 3 = 4x6x 4x = 18

x= 9

Numerator = 2x= 2 9 = 18.

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85. (C) (x 2) is a factor of x3 2bx2+ bx 1.

f(2) = 0

23 2b 22+ b 2 1 = 0

8 8b+ 2b 1 = 06b+ 7 = 0

b=6

7

86. (A) For no solution.

2

1

a

a=

2

1

b

b

2

1

c

c

5

1=

m

2

7

3

m= 10

87. (B) 32 is a root of x2+px 6 = 0

( 32 )2+p 32 6 = 0

12 6 = P 32

P =32

6= 3

Also, x2+px+ q= 0 has equal roots.

x2+ 3x+ q = 0 has equal roots.

Discriminant = 0

( 3 )2

4 1 q= 0

q=4

3

88. (D) Smallest integers between 200 and 2000divisible by 7 = 203 & greatest =1995a= 203, d= 7, a

n= 1995

an = a+ (n 1)d

1995 = 203 + (n 1)7

n=7

2031995 + 1

n= 257

89. (C) Area of isoscles triangle

=4

b224 ba

=4

1222 12104

=4

12144400

= 3 16= 48 m2.

Area of the quailateral = area of the isosceles

4

3 a2 = 48

a2 =3

448

= 16 4 3

= 64 3 m

a2 = 110.848 m

a = 848.118 m

= 10.5 m

90. (B) Area of the quadrilateral =2

1 d(P

1+ P

2)

=2

1 50 (29 + 21)

=2

1 50 50

= 1250 m2.

[ d:- diagonal of the quadrilateral P1& P2are perpendiculars from other two vertices]

91. (A) Each angle of a regular polygon

=n

n )42( 90

135 =n

n )42( 90

[where 'n' is the number of sides of theregular polygon]

135n = 180n 360 360 = 180n 135n 360 = 45n

n =45

360= 8

n = 892. (B) Let the equal sides of the right triangle

be xm.

A

B C

xm

xm

Then,x2+ x2 = (hypotenuse)2

22x = hypotenuse = AC

Its perimeter = AB + BC + AC

22 + 2= x+ x+ x2 = )22( x

= 2 ( 2 + 1)x

x = )12(2

222

= )12(2

)12(2

= 2 m

Hypotenuse = x2 = 2 2 = 2m

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SSC MOCK TEST 52 (ANSWER KEY)

1. C

2. B

3. A

4. C

5. D

6. B

7. B

8. B

9. B

10. D11. A

12. B

13. A

14. C

15. B

16. D

17. A

18. C

19. B

20. A

21. C22. C

23. A

24. A

25. C

26. C

27. A

28. B

29. B

30. B

31. A

32. D

33 C

34. D

35. A36. B

37. B

38. D

39. A

40. A

41. C

42. A

43. B

44. A

45. B

46. A47. B

48. A

49. C

50. B

51. B

52. A

53. A

54. A

55. B

56. C

57. D

58. B

59. B

60. B61. D

62. C

63. B

64. C

65. C

66. C

67. C

68. D

69. C

70. D

71. D72. C

73. A

74. D

75. B

76. A

77. C

78. A

79. D

80. B

81. B

82. D

83. B

84. B

85. C86. A

87. B

88. D

89. C

90. B

91. A

92. B

93. A

94. D

95. B

96. B97. A

98. B

99. D

100. D

101. C

102. A

103. C

104. B

105. B

106. C

107. D

108. A

109. B

110. D111. D

112. A

113. C

114. D

115. A

116. B

117. C

118. D

119. C

120. B

121. B122. B

123. B

124. D

125. C

126. C

127. D

128. A

129. D

130. D

131. C

132. D

133. C

134. B

135. D136. B

137. A

138. C

139. B

140. C

141. C

142. A

143. D

144. A

145. A

146. C147. D

148. A

149. A

150. D

151. B

152. A

153. A

154. D

155. C

156. D

157. B

158. D

159. C

160. A161. C

162. B

163. D

164. C

165. D

166. B

167. D

168. D

169. B

170. A

171. D172. C

173. A

174. B

175. C

176. D

177. B

178. B

179. C

180. D

181. D

182. B

183. C

184. A

185. A186. D

187. A

188. D

189. B

190. B

191. B

192. C

193. D

194. D

195. D

196. C197. D

198. A

199. D

200. B

178 (B); Add 'a' before 'far'

179 (C); Remove 'to'

180 (D);

181 (D);

182 (B); Change 'about writing' into 'to write'

183 (C); Change 'appreciating' into 'appreciated'

184 (A); Change 'had' into 'would have'

185 (A); Put 'not only' after 'the judges'

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SSC 52 (2)