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Saad Bashir Alvi 1
SQL Tutorial
Saad Bashir Alvi 2
Topics to be covered
CREATE INSERT UPDATE SELECT ALTER DROP
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First Example
Movie Database movies actors casting
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Tables of Movie Database
Field Name Type Notesid INTEGER An arbitrary unique identifier.
title CHAR(70) The name of the film.
yr DECIMAL(4) Year of first release.
score FLOAT Average of all the votes cast for the film.
votes INTEGER The number of votes cast for this film.
actor actorField Name Type Notes
id INTEGER An arbitrary unique identifier.
name CHAR(30) The name of the actor.
casting castingField Name Type Notes
INTEGER
INTEGER A reference to the actor table.
movie movie
movieid A reference to the movie table.
actorid
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Topics to be covered
CREATE INSERT UPDATE SELECT ALTER DROP
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Creating Database
create table movie (id int NOT NULL primary key, title varchar(70), yr decimal(4), score float, votes integer);
create table actor(id int NOT NULL primary key, name varchar(30));
create table casting(movieid int, actorid int, ord integer, primary key (movieid, actorid));
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Topics to be covered
CREATE
INSERT UPDATE SELECT ALTER DROP
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Populating Database
insert into table movie(id, title, yr, score, votes) values (1, “Lione King”, 2001, 5, 20000);
insert into actor(id, name) values (1, “Sambda”); insert into casting(movieid, actorid, ord) values
(1, 1, 5);
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Topics to be covered
CREATE INSERT
UPDATE SELECT ALTER DROP
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Updating Record
update table movie set title = “Lion King” where id = 1;
update table actor set name = “simba” where id = 1;
update table casting set ord = 1 where movieid = 1 and actorid = 1;
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Topics to be covered
CREATE INSERT UPDATE
SELECT ALTER DROP
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Selecting records
Problem: Select the year that Athens hosted the Olympic games.
Gamesyr city
2000 sydney
2004 Athens
2008 Biejing
2012 London
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Selecting records
Problem: Select the year that Athens hosted the Olympic games.
Solution: select yr, city from Games where city = 'Athens';
Gamesyr city
2000 sydney
2004 Athens
2008 Biejing
2012 London
yr city2004 Athens
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Select with GROUP BY
Problem: Select the continents hosting the Olympics with the count of the number of games held.
Gamesyr city continent
2000 Australia
2004 Athens Europe
2008
2012 London Europe
sydney
Biejing Aisa
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Select with GROUP BY
Problem: Select the continents hosting the Olympics with the count of the number of games held.
Solution: select continent, count(yr) from Games group by continent;
Gamesyr city continent
2000 sydney Australia
2004 Athens Europe
2008 Biejing Aisa
2012 London Europe
continent count(yr)
Australia 1
Asia 1
Europe 2
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Select with aggregate functions
Database bbc(name, region, area, population, gdp)
Problem: Give the total GDP of 'Africa'
name region area population gdpAfghanistan South Aisa 652225 2600000
Albania Europe 28728 320000 665600000................
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Select with aggregate functions
Database bbc(name, region, area, population, gdp)
Problem: Give the total GDP of 'Africa' Solution:
select sum(gdp) from bbc where region = 'Africa'
sum(gdp)
410196200000
name region area population gdpAfghanistan South Aisa 652225 2600000
Albania Europe 28728 320000 665600000................
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Select with aggregate functions
Database bbc(name, region, area, population, gdp)
Problem: How many countries have an area of at least 1000000
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Select with aggregate functions
Database bbc(name, region, area, population, gdp)
Problem: How many countries have an area of at least 1000000
Solution: select count(name) from bbc where area >= 1000000
count(name)
29
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Select with aggregate functions
Database bbc(name, region, area, population, gdp)
Problem: What is the total population of ('France','Germany','Spain')
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Select with aggregate functions
Database bbc(name, region, area, population, gdp)
Problem: What is the total population of ('France','Germany','Spain')
Solution: select sum(population) from bbc where name = 'France' or name = 'Germany' or name = 'Spain'
sum(population)
187300000
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Select with aggregate functions
Database bbc(name, region, area, population, gdp)
Problem: For each region show the region and number of countries with populations of at least 10 million.
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Select with aggregate functions
Database bbc(name, region, area, population, gdp)
Problem: For each region show the region and number of countries with populations of at least 10 million.
Solution: select region, count(name) from bbc where population >= 10000000 group by region region count(name)
Africa 21Americas 3
Asia 20Australia 1Europe 16
Middle East 10North America 3South America 6
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Select with join
Problem: We want to find the year and country where the games took place.
Gamesyr city
1896 Athens
1948 London
2004 Athens
2008 Biejing
2012 London
Cityname country
sydney Australia
Athens Greece
Biejing China
London UK
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Select with join
Problem: We want to find the year and country where the games took place.
Solution: SELECT games.yr, city.country FROM games JOIN city ON (games.city = city.name)
Gamesyr city
1896 Athens
1948 London
2004 Athens
2008 Biejing
2012 London
Cityname country
sydney Australia
Athens Greece
Biejing China
London UK
yr country
1896 Greece
1948 UK
2004 Greece
2008 China
2012 UK
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: Find the title and artist who recorded the song 'Alison'
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: Find the title and artist who recorded the song 'Alison'
Solution: SELECT title, artist
FROM album JOIN track ON (album.asin=track.album) WHERE song = 'Alison'
title artist
Elvis CostelloThe Very Best Of Elvis Costello And The Attraction
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: Show the song for each track on the album 'Blur'
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: Show the song for each track on the album 'Blur'
Solution: select song FROM album JOIN track ON (album.asin=track.album) where title = 'Blur'
song
Beetlebum
Song 2
Country sad ballad man
.....................
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: For each album show the title and the total number of track.
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: For each album show the title and the total number of track.
Solution: SELECT title, COUNT(*) FROM album JOIN track ON (asin=album) GROUP BY title
title COUNT(*)
"Music from the Motion Picture ""Purple Rain""" 9
(What's The Story) Morning Glory? 12
..Baby One More Time [ENHANCED CD] 11
.....................
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: For each album show the title and the total number of tracks containing the word 'Heart'.
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: For each album show the title and the total number of tracks containing the word 'Heart'.
Solution: SELECT title, COUNT(*) FROM album JOIN track ON (asin=album) where song like "%Heart%" GROUP BY title
title COUNT(*)
"Music from the Motion Picture ""Purple Rain""" 1
(What's The Story) Morning Glory? 4
..Baby One More Time [ENHANCED CD] 2
.....................
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: Find the songs that appear on more than 2 albums. Include a count of the number of times each shows up.
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: Find the songs that appear on more than 2 albums. Include a count of the number of times each shows up.
Solution: select song, count(*) FROM album JOIN track ON (album.asin=track.album) group by song having count(*) > 2 song COUNT(*)
Angel 3
Best is yet to come 3
Changes 3
.....................
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: A "good value" album is one where the price per track is less than 50 cents. Find the good value album - show the title, the price and the number of tracks.
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Select with join
Database album(asin, title, artist, price, release, label, rank) track(album, dsk, posn, song)
Problem: A "good value" album is one where the price per track is less than 50 cents. Find the good value album - show the title, the price and the number of tracks.
Solution: select title, price, count(*) FROM album JOIN track ON (album.asin=track.album) group by title having price/count(*) < .5 title price COUNT(*)
Angel 11.98 25
Best is yet to come 14.99 50
Changes 22.98 46
.....................
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Select with join
Database movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord)
Problem: List the films in which 'Harrison Ford' has appeared
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Select with join
Database movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord)
Problem: List the films in which 'Harrison Ford' has appeared
Solution: select title from movie join casting on id = movieid where actorid = (select id from actor where name = 'Harrison Ford') title
What Lies Beneath
Random Hearts
Air Force One
.....................
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Select with join
Database movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord)
Problem: List the films together with the leading star for all 1962 films
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Select with join
Database movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord)
Problem: List the films together with the leading star for all 1962 films
Solution: select title, name from movie, actor, casting where yr = '1962' and ord = 1 and movie.id = casting.movieid and actor.id = casting.actorid title name
Kid Galahad Elvis Presley
The Man Who Shot Liberty Valance John Wayne
Mothra Frankie Sakai
.....................
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Select with join
Database movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord)
Problem: Which were the busiest years for 'John Travolta'. Show the number of movies he made for each year.
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Select with join
Database movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord)
Problem: Which were the busiest years for 'John Travolta'. Show the number of movies he made for each year.
Solution: select yr, count(*) from movie, casting, actor where actor.id = casting.actorid and movie.id = casting.movieid and actor.name = 'John Travolta' group by yr order by count(*) desc limit 1
yr count(*)
1997 2
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Select with join
Database movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord)
Problem: List the 1978 films by order of cast list size.
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Select with join
Database movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord)
Problem: List the 1978 films by order of cast list size.
Solution: select title, count(actor.id) from movie, actor, casting where actor.id = casting.actorid and movie.id = casting.movieid and yr = 1978 group by title order by count(actor.id) desc
title count(*)
Kid Galahad 16
The Man Who Shot Liberty Valance 13
Mothra 8
.....................
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Topics to be covered
CREATE INSERT UPDATE SELECT
ALTER DROP
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ALTER
ALTER TABLE actor add column age integer; ALTER TABLE actor change age newage
integer; ALTER TABLE actor drop column age;
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Topics to be covered
CREATE INSERT UPDATE SELECT ALTER
DROP
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DROP
drop table movie;
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Thanks and Good luck for your exams