Five-Minute Check (over Lesson 6–5)

Then/Now

New Vocabulary

Key Concept: Remainder Theorem

Example 1:Synthetic Substitution

Example 2:Real-World Example: Find Function Values

Key Concept: Factor Theorem

Example 3:Use the Factor Theorem

Over Lesson 6–6

A. A

B. B

C. C

D. D A B C D

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A. (2c)(4c2 + cg + g2)

B. (2c – g)(4c2 + 2cg + g2)

C. (c – g)(2c + g + g2)

D. prime

Factor 8c3 – g3. If the polynomial is not factorable, write prime.

Over Lesson 6–6

A. A

B. B

C. C

D. D A B C D

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A. (2a – 3z)(5x – c)

B. (2a – 6z)(2a + b + c)

C. (5x + 6z)(2a – b – c)

D. prime

Factor 12az – 6bz – 6cz + 10ax – 5bx – 5cx. If the polynomial is not factorable, write prime.

Over Lesson 6–6

A. A

B. B

C. C

D. D A B C D

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A. (8x + y)(m + n)(m – n)

B. (4x + y)(2x – y2)(m + n)(m – n)

C. (2x + y)(4x2 – 2xy + y2)(m + n)(m – n)

D. prime

Factor 8x3m2 – 8x3n2 + y3m2 – y3n2. If the polynomial is not factorable, write prime.

Over Lesson 6–6

A. A

B. B

C. C

D. D A B C D

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Solve 16d4 – 48d2 + 32 = 0.

A.

B.

C.

D.

Over Lesson 6–6

A. A

B. B

C. C

D. D A B C D

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A. 16

B. 8

C. –2

D. –4

Solve k3 + 64 = 0.

Over Lesson 6–6

A. A

B. B

C. C

D. D A B C D

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A. 2 ft

B. 3 ft

C. 4 ft

D. 6 ft

The width of a box is 3 feet less than the length. The height is 4 feet less than the length. The volume of the box is 36 cubic feet. Find the length of the box.

You used the Distributive Property and factoring to simplify algebraic expressions. (Lesson 5–3)

• Evaluate functions by using synthetic substitution.

• Determine whether a binomial is a factor of a polynomial by using synthetic substitution.

• synthetic substitution

• depressed polynomial

Synthetic Substitution

If f(x) = 2x4 – 5x2 + 8x – 7, find f(6).

Method 1 Synthetic Substitution

Answer: The remainder is 2453. Thus, by using synthetic substitution, f(6) = 2453.

By the Remainder Theorem, f(6) should be the remainder when you divide the polynomial by x – 6.

2 12 67 410 2453

Notice that there is no x3 term. A zero is placed in this position as a placeholder.

2 0 –5 8 –7

12 72 402 2460

Synthetic Substitution

Method 2 Direct Substitution

Replace x with 6.

Answer: By using direct substitution, f(6) = 2453.

Original function

Replace x with 6.

Simplify.

A. A

B. B

C. C

D. D A B C D

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A. 20

B. 34

C. 88

D. 142

If f(x) = 2x3 – 3x2 + 7, find f(3).

Find Function Values

COLLEGE The number of college students from the United States who study abroad can be modeled by the function S(x) = 0.02x

4 – 0.52x

3 + 4.03x

2 + 0.09x + 77.54, where x is the number of years since 1993 and S(x) is the number of students in thousands. How many U.S. college students will study abroad in 2011?

Answer: In 2011, there will be about 451,760 U.S. college students studying abroad.

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 616,230 students

B. 638,680 students

C. 646,720 students

D. 659,910 students

HIGH SCHOOL The number of high school students in the United States who hosted foreign exchange students can be modeled by the function F(x) = 0.02x

4 – 0.05x

3 + 0.04x

2 – 0.02x, where x is the number of years since 1999 and F(x) is the number of students in thousands. How many U.S. students will host foreign exchange students in 2013?

Use the Factor Theorem

Determine whether x – 3 is a factor of x3 + 4x2 – 15x – 18. Then find the remaining factors of the polynomial.

The binomial x – 3 is a factor of the polynomial if 3 is a zero of the related polynomial function. Use the factor theorem and synthetic division.

1 7 6 0

1 4 –15 –18

3 21 18

Use the Factor Theorem

Since the remainder is 0, (x – 3) is a factor of the polynomial. The polynomial x3 + 4x2 – 15x –18 can be factored as (x – 3)(x2 + 7x + 6). The polynomial x2 + 7x + 6 is the depressed polynomial. Check to see if this polynomial can be factored.

x2 + 7x + 6 = (x + 6)(x + 1) Factor the trinomial.

Answer: So, x3 + 4x2 – 15x – 18 = (x – 3)(x + 6)(x + 1).

Use the Factor Theorem

Check You can see that the graph of the related function f(x) = x3 + 4x2 – 15x – 18 crosses the x-axis at 3, –6, and –1. Thus, f(x) = (x – 3)[x – (–6)][x – (–1)].

A. A

B. B

C. C

D. D A B C D

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A. yes; (x + 5)(x + 1)

B. yes; (x + 5)

C. yes; (x + 2)(x + 3)

D. x + 2 is not a factor.

Determine whether x + 2 is a factor of x3 + 8x2 + 17x + 10. If so, find the remaining factors of the polynomial.