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Splash Screen. Five-Minute Check (over Lesson 4–4) CCSS Then/Now New Vocabulary Example 1:Equation with Rational Roots Example 2:Equation with Irrational Roots Key Concept: Completing the Square Example 3:Complete the Square Example 4:Solve an Equation by Completing the Square - PowerPoint PPT Presentation
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Five-Minute Check (over Lesson 4–4)
CCSS
Then/Now
New Vocabulary
Example 1: Equation with Rational Roots
Example 2: Equation with Irrational Roots
Key Concept: Completing the Square
Example 3: Complete the Square
Example 4: Solve an Equation by Completing the Square
Example 5: Equation with a ≠ 1
Example 6: Equation with Imaginary Solutions
Over Lesson 4–4
A. 5
B.
C.
D.
Over Lesson 4–4
A.
B.
C.
D.
Over Lesson 4–4
A. 2 + 9i
B. 8 + 5i
C. 2 – 9i
D. –8 – 5i
Simplify (5 + 7i) – (–3 + 2i).
Over Lesson 4–4
A. ± 5i
B. ± 3i
C. ± 3
D. ± 3i – 3
Solve 7x2 + 63 = 0.
Over Lesson 4–4
A. x = 6, y = –7
B. x = –6, y = 7
C. x = –2, y = 3
D. x = 2, y = –3
What are the values of x and y when (4 + 2i) – (x + yi) = (2 + 5i)?
Content Standards
N.CN.7 Solve quadratic equations with real coefficients that have complex solutions.
F.IF.8.a Use the process of factoring and completing the square in a quadratic function to show zeros, extreme values, and symmetry of the graph, and interpret these in terms of a context.
Mathematical Practices
7 Look for and make use of structure.
You factored perfect square trinomials.
• Solve quadratic equations by using the Square Root Property.
• Solve quadratic equations by completing the square.
• completing the square
Equation with Rational Roots
Solve x
2 + 14x + 49 = 64 by using the Square Root Property.
Original equation
Factor the perfect square trinomial.
Square Root Property
Subtract 7 from each side.
Equation with Rational Roots
x = 1 x = –15 Solve each equation.
Answer: The solution set is {–15, 1}.
x = –7 + 8 or x = –7 – 8 Write as two equations.
Check: Substitute both values into the original equation.
x
2 + 14x + 49 = 64 x
2 + 14x + 49 = 64
??1
2 + 14(1) + 49 = 64 (–15)
2 + 14(–15) + 49 = 64??
1 + 14 + 49 = 64 225 + (–210) + 49 = 64
64 = 64 64 = 64
A. {–1, 9}
B. {11, 21}
C. {3, 13}
D. {–13, –3}
Solve x
2 – 16x + 64 = 25 by using the Square Root Property.
Equation with Irrational Roots
Solve x
2 – 4x + 4 = 13 by using the Square Root Property.
Square Root Property
Original equation
Factor the perfect square trinomial.
Add 2 to each side.
Write as two equations.
Use a calculator.
Equation with Irrational Roots
x
2 – 4x + 4 = 13 Original equation
x
2 – 4x – 9 = 0 Subtract 13 from each side.
y = x
2 – 4x – 9 Related quadratic function
Answer: The exact solutions of this equation are The approximate solutions are 5.61 and –1.61. Check these results by finding and graphing the related quadratic function.
Equation with Irrational Roots
Check Use the ZERO function of a graphing calculator. The approximate zeros of the related function are –1.61 and 5.61.
Solve x
2 – 4x + 4 = 8 by using the Square Root Property.
A.
B.
C.
D.
Complete the Square
Find the value of c that makes x
2 + 12x + c a perfect square. Then write the trinomial as a perfect square.
Step 1 Find one half of 12.
Answer: The trinomial x2 + 12x + 36 can be written as (x + 6)2.
Step 2 Square the result of Step 1. 62 = 36
Step 3 Add the result of Step 2 to x
2 + 12x + 36x
2 + 12x.
A. 9; (x + 3)2
B. 36; (x + 6)2
C. 9; (x – 3)2
D. 36; (x – 6)2
Find the value of c that makes x2 + 6x + c a perfect square. Then write the trinomial as a perfect square.
Solve an Equation by Completing the Square
Solve x2 + 4x – 12 = 0 by completing the square.
x2 + 4x – 12 = 0 Notice that x2 + 4x – 12 is not a perfect square.
x2 + 4x = 12Rewrite so
the left side is of the form x2 + bx.
x2 + 4x + 4 = 12 + 4
add 4 to
each side. (x + 2)2 = 16Write the
left side as a perfect square by factoring.
Solve an Equation by Completing the Square
x + 2 = ± 4 Square Root Property
Answer: The solution set is {–6, 2}.
x = – 2 ± 4Subtract 2
from each side.
x = –2 + 4 or x = –2 – 4 Write as two equations.
x = 2 x = –6 Solve each equation.
Solve x2 + 6x + 8 = 0 by completing the square.
A.
B.
C.
D.
Equation with a ≠ 1
Solve 3x2 – 2x – 1 = 0 by completing the square.
3x2 – 2x – 1 = 0 Notice that 3x2 – 2x – 1 is not a perfect square.Divide by the coefficient of the quadratic term, 3.
Add to each side.
Equation with a ≠ 1
Write the left side as a perfect square by factoring. Simplify the right side.
Square Root Property
Equation with a ≠ 1
Answer:
x = 1 Solve each equation.
or Write as two equations.
Solve 2x2 + 11x + 15 = 0 by completing the square.
A.
B.
C.
D.
Equation with Imaginary Solutions
Solve x
2 + 4x + 11 = 0 by completing the square.
Notice that x
2 + 4x + 11 is not a perfect square.
Rewrite so the left side is of the form x
2 + bx.
Since , add 4 to each side.
Write the left side as a perfect square.
Square Root Property
Equation with Imaginary Solutions
Subtract 2 from each side.
Solve x
2 + 4x + 5 = 0 by completing the square.
A.
B.
C.
D.