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Section 4.1 β Special Right Triangles and Trigonometric Ratios 1
2312 - Section 4.1 Special Triangles and Trigonometric Ratios
First we review some conventions involving triangles and known facts. It is common to label angles of a triangle with capital letters ( Ex.: π΄, π΅, and πΆ) and then sides with low case letters π, π, and π with side π opposite angle π΄, side π opposite angle π΅, and side π opposite angle πΆ.
The sum of measures of three angles of a triangle is 180Β°. An acute angle of a triangle is an angle that measures between 0Β°and 90Β°. A right angle is a 90Β° angle. A right triangle has one right angle. Two other angles are always acute and complementary, i.e. their measures add up to 90Β°. The side opposite the right angle is called hypotenuse, two other sides are called legs. In this section, we will work with some special right triangles before moving on to defining the six trigonometric functions. If we are given a right triangle and we are interested in finding a missing side, we can apply Pythagoreanβs Theorem
π2 + π2 = π2
Example 1: In right triangle π·ππΊ with the right angle π find ππΊ if π·πΊ = 4β5 and π·π = 4.
Section 4.1 β Special Right Triangles and Trigonometric Ratios 2
Two special triangles are 30Β° β 60Β° β 90Β° triangles and 45Β° β 45Β° β 90Β° triangles. In such triangles, sides are proportional. You need to know the length of one side only to find the remaining sides.
ππΒ° β ππΒ° β ππΒ° Triangles ππΒ° β ππΒ° β ππΒ° Triangles
Example 2:
a) Given: Right βπ΄π΅πΆ with β πΆ = 90Β° and β π΄ = 45Β°; π΄πΆ = 7. Find: π΄π΅ and π΅πΆ.
45q
B
A
C
Section 4.1 β Special Right Triangles and Trigonometric Ratios 3
b) Given: Right βπ΄π΅πΆ with β πΆ = 90Β° and β π΄ = 60Β°; π΄πΆ = 9. Find: π΄π΅ and π΅πΆ.
c) Given: Right βπ΄π΅πΆ with β πΆ = 90Β° and β π΄ = 45Β°; π΄π΅ = 8. Find: π΄πΆ and π΅πΆ.
d) Given: Right βπ΄π΅πΆ with β πΆ = 90Β° and β π΄ = 60Β°; π΄π΅ = 20. Find: π΅πΆ
A
B
60Β°
45q
B
A
A
B
60Β°
C
C
C
Section 4.1 β Special Right Triangles and Trigonometric Ratios 4
Example 3: Find π΄πΆ if β π΄ = 30Β°, β π· = 45Β°, and π΅π· = 8.
Section 4.1 β Special Right Triangles and Trigonometric Ratios 5
The Six Trigonometric Functions of an Angle A trigonometric function is a ratio of the lengths of the sides of a triangle. If we fix an angle, then as to that angle, there are three sides, the adjacent side, the opposite side, and the hypotenuse. We have six different combinations of these three sides, so there are six trigonometric functions. The inputs for the trigonometric functions are angles and the outputs are real numbers. Let T be an acute angle in a right triangle. Side Hypotenuse opposite to angle T T Side adjacent to angle T
Sine Function:
sin π =πππππ‘β ππ π‘βπ π πππ πππππ ππ‘π π
πππππ‘β ππ βπ¦πππ‘πππ π
Cosine Function:
cos π =πππππ‘β ππ π‘βπ π πππ ππππππππ‘ π‘π π
πππππ‘β ππ βπ¦πππ‘πππ π
Tangent Function:
tan π =πππππ‘β ππ π‘βπ π πππ πππππ ππ‘π π
πππππ‘β ππ π‘βπ π πππ ππππππππ‘ π‘π π
Cotangent Function:
cot π = πππππ‘β ππ π‘βπ π πππ ππππππππ‘ π‘π π
πππππ‘β ππ π‘βπ π πππ πππππ ππ‘π π
Secant Function:
sec π = πππππ‘β ππ βπ¦πππ‘πππ π
πππππ‘β ππ π‘βπ π πππ ππππππππ‘ π‘π π
Cosecant Function:
csc π = πππππ‘β ππ βπ¦πππ‘πππ π
πππππ‘β ππ π‘βπ π πππ πππππ ππ‘π π
Note: For acute angles, the values of the trigonometric functions are always positive since they are ratios of lengths.
Section 4.1 β Special Right Triangles and Trigonometric Ratios 6
sin π = πππππ ππ‘π
βπ¦πππ‘πππ’π π
cos π = ππππππππ‘βπ¦πππ‘πππ’π π
tan π = πππππ ππ‘πππππππππ‘
cot π = ππππππππ‘πππππ ππ‘π
sec π = βπ¦πππ‘πππ πππππππππ‘
csc π = βπ¦πππ‘πππ ππππππ ππ‘π
Example 4: Suppose you are given this triangle. Find the six trigonometric functions of angle π΅ and angle πΆ.
C b
9 7
B
A
Section 4.1 β Special Right Triangles and Trigonometric Ratios 7
Example 5: Suppose that π is an acute angle in a right triangle and sec π = 5β34
. Find sin π and cot π.
Section 4.1 β Special Right Triangles and Trigonometric Ratios 8
Cofunctions A special relationship exists between sine and cosine, tangent and cotangent, secant and cosecant. The relationship can be summarized as follows:
Function of π = Cofunction of the complement of π
Recall that two angles are complementary if their sum is 90Β°. In example considered earlier, angles π΅ and πΆ are complementary, since π΄ = 90Β°. Notice that sin πΆ = cos π΅ and π΅ = cos πΆ. The same will be true of any pair of cofunctions. Cofunction relationships
sin π΄ = cos(90Β° β π΄) cos π΄ = sin(90Β° β π΄) tan π΄ = cot(90Β° β π΄) cot π΄ = tan(90Β° β π΄) sec π΄ = csc(90Β° β π΄) csc π΄ = sec(90Β° β π΄)
Example 6: Fill in the blanks a) sin 60Β° = cos _____
b) csc 15Β° = ______