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Factoring into Special Products
Multiply the following polynomials.
(𝑥 + 3)(𝑥! − 3𝑥 + 9) (2𝑥 − 5𝑦)(4𝑥! + 10𝑥𝑦 + 25𝑦!)
𝑥! − 3𝑥 + 9 4𝑥! + 10𝑥𝑦 + 25𝑦!
𝑥 2𝑥
+3 −5𝑦
Product: _________________ Product: _________________
What do you notice is special about each of the terms in the final products?
______________________________________________________________________________
______________________________________________________________________________
How are each of the terms in the final products related to the terms in the binomial factors?
______________________________________________________________________________
______________________________________________________________________________
How are each of the terms in the binomial factors related to the terms in the trinomial factors?
______________________________________________________________________________
______________________________________________________________________________
Using the patterns seen above, factor the following binomials (referred to as a sum of cubes and difference of cubes).
𝑥! + 1000 27ℎ! − 216𝑝!
! + ! ! − !
( + )( − + ) ( − )( + + )
We can now determine the formulas for factoring expressions that look like a sum or difference of two cubes. Allow the first term being cubed to be “F” and the last term being cubed to be “L”.
𝑭𝒊𝒓𝒔𝒕 𝟑 + 𝑳𝒂𝒔𝒕 𝟑 𝑭𝒊𝒓𝒔𝒕 𝟑 − 𝑳𝒂𝒔𝒕 𝟑
( )( ) ( )( )
Multiply the following polynomials.
(𝑥 + 4)(𝑥 − 4) (3𝑥 − 7𝑦)(3𝑥 + 7𝑦)
𝑥 − 4 3𝑥 + 7𝑦
𝑥 3𝑥
+4 −7𝑦
Product: _________________ Product: _________________
What do you notice is special about each of the terms in the final products?
______________________________________________________________________________
______________________________________________________________________________
How are each of the terms in the final products related to the terms in the binomial factors?
______________________________________________________________________________
______________________________________________________________________________
What do you notice about the signs in the binomial factors compared to the signs in the products?
______________________________________________________________________________
______________________________________________________________________________
Using the patterns seen above, factor the following binomials (referred to as a difference of squares).
𝑥! − 144 25𝑎! − 81𝑏!
! − ! ! − !
( + ) ( − ) ( + ) ( − )
We can now determine the formula for factoring expressions that look like a difference of two squares. Allow the first term being squared to be “F” and the last term being squared to be “L”.
𝑭𝒊𝒓𝒔𝒕 𝟐 − 𝑳𝒂𝒔𝒕 𝟐
( ) ( )